º£ÑóÖ²ÎïÈ纣´ø¡¢º£ÔåÖк¬ÓдóÁ¿µÄµâÔªËØ£¬µâÔªËØÒÔµâÀë×ÓµÄÐÎʽ´æÔÚ¡£ÊµÑéÊÒÀï´Óº£ÔåÖÐÌáÈ¡µâµÄÁ÷³ÌÈçÏÂͼ£º

(1)ʵÑéÊÒ±ºÉÕº£´ø£¬ÐèÒªÏÂÁÐÒÇÆ÷ÖеÄ________(Ìî×Öĸ)¡£

a£®ÊԹܠ b£®ÉÕ±­

c£®ÛáÛö  d£®ÄàÈý½Ç

e£®ÌúÈý½Å¼Ü  f£®¾Æ¾«µÆ

(2)Ö¸³öÌáÈ¡µâµÄ¹ý³ÌÖÐÓйصÄʵÑé²Ù×÷Ãû³Æ£º¢Ù________£¬¢Û__________¡£

(3)ÌáÈ¡µâµÄ¹ý³ÌÖУ¬¿ÉÑ¡ÔñµÄÓлúÊÔ¼ÁÊÇ________¡£

A£®¼×±½¡¢¾Æ¾«  B£®ËÄÂÈ»¯Ì¼¡¢±½

C£®ÆûÓÍ¡¢ÒÒËá  D£®ÆûÓÍ¡¢¸ÊÓÍ

(4)Ϊʹº£Ôå»ÒÖеâÀë×Óת»¯ÎªµâµÄÓлúÈÜÒº£¬ÊµÑéÊÒÓÐÉÕ±­¡¢²£Á§°ô¡¢¼¯ÆøÆ¿¡¢¾Æ¾«µÆ¡¢µ¼¹Ü¡¢Ô²µ×ÉÕÆ¿¡¢Ê¯ÃÞÍøÒÔ¼°±ØÒªµÄ¼Ð³ÖÒÇÆ÷¡¢ÎïÆ·£¬ÉÐȱÉٵIJ£Á§ÒÇÆ÷ÓÐ______¡¢______________¡£

(5)С×éÓÃCCl4ÝÍÈ¡µâË®Öеĵ⣬ÔÚÓÒͼµÄ·ÖҺ©¶·ÖУ¬Ï²ãÒºÌå³Ê______É«£»ËûÃÇ´ò¿ª·ÖҺ©¶·»îÈû£¬È´Î´¼ûÒºÌåÁ÷Ï£¬Ô­Òò¿ÉÄÜÊÇ

________________________________________________________________________¡£

(6)´Óº¬µâµÄÓлúÈÜÒºÖÐÌáÈ¡µâºÍ»ØÊÕÓлúÈܼÁ£¬»¹Ðë¾­¹ýÕôÁó£¬Ö¸³öÏÂÃæʵÑé×°ÖÃͼÖеĴíÎóÖ®´¦£º

¢Ù________________________________________________________________________£»

¢Ú________________________________________________________________________£»

¢Û________________________________________________________________________¡£

(7)½øÐÐÉÏÊöÕôÁó²Ù×÷ʱ£¬Ê¹ÓÃˮԡ¼ÓÈȵÄÔ­ÒòÊÇ_______________________________£¬

×îºó¾§Ì¬µâÔÚ________Àï¾Û¼¯¡£


´ð°¸¡¡(1)cdef¡¡(2)¹ýÂË¡¡ÝÍÈ¡·ÖÒº¡¡(3)B

(4)·ÖҺ©¶·¡¡ÆÕͨ©¶·

(5)×Ϻ졡·ÖҺ©¶·ÉÏ¿Ú»îÈûС¿×δÓë¿ÕÆøÏàͨ

(6)¢ÙȱʯÃÞÍø¡¡¢ÚζȼƲ嵽ÁËÒºÌåÖС¡¢ÛÀäÄý¹Ü½ø³öË®µÄ·½Ïòµßµ¹

(7)ʹÕôÁóÉÕÆ¿ÊÜÈȾùÔÈ£¬¿ØÖƼÓÈÈζȲ»ÖÁ¹ý¸ß¡¡ÕôÁóÉÕÆ¿


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


½ðÊôÄƶÖÃÔÚ¿ÕÆøÖлᷢÉúһϵÁб仯£ºÒø°×É«½ðÊôÄÆ  (NaOH______)  

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


Na2CO3µÄÖÆÈ¡·½·¨¼°×ÛºÏʵÑé̽¾¿

(1)ÎÒ¹ú»¯Ñ§¼ÒºîµÂ°ñ¸Ä¸ï¹úÍâµÄ´¿¼îÉú²ú¹¤ÒÕ£¬ÆäÉú²úÁ÷³Ì¿É¼òÒª±íʾÈçÏ£º

¢ÙÍù±¥ºÍʳÑÎË®ÖÐÒÀ´ÎͨÈë×ãÁ¿µÄNH3¡¢CO2(°±¼î·¨)£¬¶ø²»ÏÈͨCO2ÔÙͨNH3µÄÔ­ÒòÊÇ________________________________________________________________________¡£

¢Ú´ÓÉú²úÁ÷³Ìͼ¿ÉÖª£¬¿ÉÑ­»·ÀûÓõÄÎïÖÊÊÇ________¡£

¢Ûд³ö³Áµí³ØÖС¢ìÑÉÕ¯Öз´Ó¦µÄ»¯Ñ§·½³Ìʽ___________________________¡£

(2)ÈçºÎÓÃCO2ºÍ50 mL 2 mol·L£­1 NaOHÈÜÒºÖÆÈ¡50 mL 1 mol·L£­1 Na2CO3ÈÜÒº£¿

¢Ùд³ö¼òÒªµÄʵÑé²½Ö裺_________________________________________________¡£

¢Úд³öÓйط´Ó¦µÄ»¯Ñ§·½³Ìʽ£º______________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


X¡¢Y¡¢Z¡¢W¡¢RÊÇ5ÖÖ¶ÌÖÜÆÚÔªËØ£¬ÆäÔ­×ÓÐòÊýÒÀ´ÎÔö´ó¡£XÊÇÖÜÆÚ±íÖÐÔ­×Ӱ뾶×îСµÄÔªËØ£¬YÔ­×Ó×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµç×ÓÊýµÄ3±¶£¬Z¡¢W¡¢R´¦ÓÚͬһÖÜÆÚ£¬RÓëY´¦ÓÚͬһ×壬Z¡¢WÔ­×ӵĺËÍâµç×ÓÊýÖ®ºÍÓëY¡¢RÔ­×ӵĺËÍâµç×ÓÊýÖ®ºÍÏàµÈ¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)

A£®ÔªËØY¡¢Z¡¢W¾ßÓÐÏàͬµç×Ó²ã½á¹¹µÄÀë×Ó£¬Æä°ë¾¶ÒÀ´ÎÔö´ó

B£®ÔªËØX²»ÄÜÓëÔªËØYÐγɻ¯ºÏÎïX2Y2

C£®ÔªËØY¡¢R·Ö±ðÓëÔªËØXÐγɵĻ¯ºÏÎïµÄÈÈÎȶ¨ÐÔ£ºXmY>XmR

D£®ÔªËØW¡¢RµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎﶼÊÇÇ¿Ëá

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁзÖÀëÎïÖʵķ½·¨ÖУ¬ÀûÓÃÁËÎïÖʵķеãµÄÊÇ(¡¡¡¡)

A£®ÕôÁó  B£®ÝÍÈ¡  C£®Öؽᾧ  D£®Õô·¢

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁгýÔÓ·½°¸´íÎóµÄÊÇ(¡¡¡¡)

Ñ¡Ïî

±»Ìá´¿µÄÎïÖÊ

ÔÓÖÊ

³ýÔÓÊÔ¼Á

³ýÔÓ·½·¨

A

CO(g)

CO2(g)

NaOHÈÜÒº¡¢Å¨H2SO4

Ï´Æø

B

NH4Cl(aq)

Fe3£«(aq)

NaOHÈÜÒº

¹ýÂË

C

Cl2(g)

HCl(g)

±¥ºÍʳÑÎË®¡¢Å¨H2SO4

Ï´Æø

D

Na2CO3(s)

NaHCO3(s)

×ÆÉÕ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÒÔϳýÔÓ·½·¨(À¨ºÅÄÚΪÉÙÁ¿ÔÓÖÊ)ÖУ¬´íÎóµÄÊÇ(¡¡¡¡)

A£®NaCl(Na2CO3)£ºÈܽ⣬µÎÈë×ãÁ¿ÑÎËᣬÕô·¢½á¾§

B£®Na2SO4(NH4Cl)£º¼ÓÈÈ¡¢Éý»ª

C£®CO2(CO)£ºÍ¨¹ý×ÆÈÈCuO·ÛÄ©

D£®H2(NH3)£ºÍ¨¹ýʢŨH2SO4µÄÏ´ÆøÆ¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


1919Ä꣬LangmuirÌá³öµÈµç×ÓÔ­Àí£ºÔ­×ÓÊýÏàͬ¡¢µç×Ó×ÜÊýÏàͬµÄ·Ö×Ó£¬»¥³ÆΪµÈµç×ÓÌå¡£µÈµç×ÓÌåµÄ½á¹¹ÏàËÆ¡¢ÎïÀíÐÔÖÊÏà½ü¡£

(1)¸ù¾ÝÉÏÊöÔ­Àí£¬½öÓɵÚ2ÖÜÆÚÔªËØ×é³ÉµÄ¹²¼Û·Ö×ÓÖУ¬»¥ÎªµÈµç×ÓÌåµÄÊÇ________ºÍ________£»________ºÍ

________________________¡£

(2)´Ëºó£¬µÈµç×ÓÔ­ÀíÓÖÓÐËù·¢Õ¹¡£ÀýÈ磬ÓɶÌÖÜÆÚÔªËØ×é³ÉµÄ΢Á££¬Ö»ÒªÆäÔ­×ÓÊýÏàͬ£¬¸÷Ô­×Ó×îÍâ²ãµç×ÓÊýÖ®ºÍÏàͬ£¬Ò²¿É»¥³ÆΪµÈµç×ÓÌ壬ËüÃÇÒ²¾ßÓÐÏàËƵĽṹÌØÕ÷¡£ÔÚ¶ÌÖÜÆÚÔªËØ×é³ÉµÄÎïÖÊÖУ¬ÓëNO»¥ÎªµÈµç×ÓÌåµÄ·Ö×ÓÓÐ________¡¢________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


½ðÊôÍ­µ¥¶ÀÓ백ˮ»òµ¥¶ÀÓë¹ýÑõ»¯Çⶼ²»ÄÜ·´Ó¦£¬µ«¿ÉÓ백ˮºÍ¹ýÑõ»¯ÇâµÄ»ìºÏÈÜÒº·´Ó¦£¬ÆäÔ­ÒòÊÇ______________________________________________£¬

·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸