ºãÎÂÏ£¬½«a mol N2Óëb mol H2µÄ»ìºÏÆøÌåͨÈëÒ»¸ö¹Ì¶¨ÈÝ»ýµÄÃܱÕÈÝÆ÷ÖУ¬·¢Éú·´Ó¦£º

N2(g) + 3H2(g)2NH3(g)

£¨1£©Èô·´Ó¦½øÐе½Ä³Ê±¿Ìtʱ£¬nt£¨N2£©=13 mol£¬nt£¨NH3£©=6 mol£¬¼ÆËãa=               ¡£

£¨2£©·´Ó¦´ïµ½Æ½ºâʱ£¬»ìºÏÆøÌåµÄÌå»ýΪ716.8 L£¨±ê×¼×´¿öÏ£©£¬ÆäÖÐNH3µÄº¬Á¿£¨Ìå»ý·ÖÊý£©Îª25%¡£¼ÆËãƽºâʱNH3µÄÎïÖʵÄÁ¿=                ¡£

£¨3£©Ô­»ìºÏÆøÌåÓëƽºâ»ìºÏÆøÌåµÄ×ÜÎïÖʵÄÁ¿Ö®±Èn£¨Ê¼£©¡Ãn£¨Æ½£©=              ¡£

£¨4£©Ô­»ìºÏÆøÌåÖУ¬a¡Ãb=              ¡£

£¨5£©´ïµ½Æ½ºâʱ£¬N2ºÍH2µÄת»¯ÂÊÖ®±È£¬¦Á£¨N2£©¡Ã¦Á£¨H2£©=                  ¡£

£¨6£©Æ½ºâ»ìºÏÆøÌåÖУ¬n£¨N2£©¡Ãn£¨H2£©¡Ãn£¨NH3£©=                 ¡£

 

£¨1£©16

£¨2£©8 mol

£¨3£©5¡Ã4

£¨4£©2¡Ã3

£¨5£©1¡Ã2

£¨6£©3¡Ã3¡Ã2

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚºãÎÂÏ£¬½«a mol N2Óëb mol H2µÄ»ìºÏÆøÌåͨÈëÒ»¸ö¹Ì¶¨ÈÝ»ýµÄÃܱÕÈÝÆ÷ÖУ¬·¢ÉúÈçÏ·´Ó¦£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©
£¨1£©·´Ó¦½øÐе½Ä³Ê±¿Ìtʱ£¬nt£¨N2£©=13mol£¬nt£¨NH3£©=6mol£¬¼ÆËãaµÄÖµ
16
16
£®
£¨2£©·´Ó¦´ïƽºâʱ£¬»ìºÏÆøÌåµÄÌå»ýΪ716.8L£¨ÕÛËã³É±ê¿öÏ£©£¬ÆäÖÐNH3µÄº¬Á¿£¨Ìå»ý·ÖÊý£©Îª25%£®¼ÆËãƽºâʱNH3µÄÎïÖʵÄÁ¿
8mol
8mol
£®
£¨3£©Ô­»ìºÏÆøÌåÓëƽºâ»ìºÏÆøÌå×ÜÎïÖʵÄÁ¿Ö®±È£¨Ð´³ö×î¼ò±È£¬ÏÂͬ£©n£¨Ê¼£©£ºn£¨Æ½£©=
5£º4
5£º4
£®
£¨4£©Ô­»ìºÏÆøÌåÖÐa£ºb=
2£º3
2£º3
£®
£¨5£©´ïµ½Æ½ºâʱ£¬N2ºÍH2µÄת»¯ÂÊÖ®±È¦Á£¨N2£©£º¦Á£¨H2£©=
1£º2
1£º2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ºãÎÂÏ£¬½«a mol N2Óëb mol H2µÄ»ìºÏÆøÌåͨÈëÒ»¸ö¹Ì¶¨ÈÝ»ýµÄÃܱÕÈÝÆ÷ÖУ¬·¢ÉúÈçÏ·´Ó¦£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©£¬·´Ó¦´ïƽºâʱ£¬»ìºÏÆøÌåµÄÌå»ýΪ716.8L£¨±ê×¼×´¿öÏ£©£¬ÆäÖÐNH3µÄº¬Á¿£¨Ìå»ý·ÖÊý£©Îª25%£®¼ÆË㣺
£¨1£©´ïµ½Æ½ºâʱ£¬ÏûºÄN2µÄÎïÖʵÄÁ¿£¬n£¨N2£©=
16mol
16mol

£¨2£©Ô­»ìºÏÆøÌåÓëƽºâ»ìºÏÆøÌåµÄѹǿ֮±È£¨Ð´³ö×î¼òÕûÊý±È£©£¬p£¨Ê¼£©£ºp£¨Æ½£©=
5£º4
5£º4
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ºãÎÂÏ£¬½«a mol N2Óëb mol H2µÄ»ìºÏÆøÌåͨÈëÒ»¸ö¹Ì¶¨ÈÝ»ýµÄÃܱÕÈÝÆ÷ÖУ¬·¢ÉúÈçÏ·´Ó¦£ºN2£¨g£©+3H2£¨g£©?2NH3£¨g£©
£¨1£©Èô·´Ó¦½øÐе½Ä³Ê±¿Ìtʱ£¬nt£¨N2£©=13mol£¬nt£¨NH3£©=6mol£¬Ôòa=
16
16

£¨2£©·´Ó¦´ïƽºâʱ£¬»ìºÏÆøÌåµÄÌå»ýΪ716.8L£¨±ê¿öÏ£©£¬ÆäÖÐNH3µÄº¬Á¿£¨Ìå»ý·ÖÊý£©Îª25%£®ÔòƽºâʱNH3µÄÎïÖʵÄÁ¿Îª
8mol
8mol
£®
£¨3£©Ô­»ìºÏÆøÌåÓëƽºâ»ìºÏÆøÌåµÄ×ÜÎïÖʵÄÁ¿Ö®±ÈΪ
5£º4
5£º4
£®
£¨4£©Æ½ºâ»ìºÏÆøÌåÖУ¬n£¨N2£©£ºn£¨H2£©£ºn£¨NH3£©µÈÓÚ
3£º3£º2
3£º3£º2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ºãÎÂÏ£¬½«a mol N2Óëb mol H2µÄ»ìºÏÆøÌåͨÈëÒ»¸ö¹Ì¶¨ÈÝ»ýµÄÃܱÕÈÝÆ÷ÖУ¬·¢Éú¿ÉÄæ·´Ó¦£ºN2£¨g£©+3H2£¨g£©¨T2NH3£¨g£©£®
£¨1£©Èô·´Ó¦½øÐе½Ä³Ê±¿Ìtʱ£¬nt£¨N2£©=13mol£¬nt£¨NH3£©=6mol£¬¼ÆËãaµÄÖµ£®
£¨2£©·´Ó¦´ïµ½Æ½ºâʱ£¬»ìºÏÆøÌåµÄÌå»ýΪ716.8L£¨±ê×¼×´¿öÏ£©£¬ÆäÖÐNH3µÄº¬Á¿£¨Ìå»ý·ÖÊý£©Îª25%£¬¼ÆËãƽºâʱN2µÄת»¯ÂÊ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ºãÎÂÏ£¬½«a mol N2Óëb molH2µÄ»ìºÏÆøÌåͨÈëµ½Ò»¸ö¹Ì¶¨ÈÝ»ýµÄÃܱÕÈÝÆ÷ÖУ¬·¢ÉúÈçÏ·´Ó¦£ºN2 £¨g£©+3H2£¨g£©
´ß»¯¼Á
¸ßθßѹ
2NH3£¨g£©£¬Çë¼ÆËã²¢Ìî¿Õ£º
£¨1£©Èô·´Ó¦µ½Ê±¿Ìtʱ£¬n £¨N2£©=13mol£¬n £¨NH3£©=6mol£¬Ôòa=
16
16
mol£»
£¨2£©ÉÏÊö»ìºÏÆøÌå·´Ó¦´ïƽºâʱ£¬»ìºÏÆøÌåµÄÌå»ýΪ716.8L£¨±ê¿öÏ£©£¬ÆäÖÐNH3µÄÌå»ý·ÖÊýΪ25%£¬ÔòÔ­»ìºÏÆøÌåÓëƽºâ»ìºÏÆøÌåµÄÎïÖʵÄÁ¿Ö®±Èn£¨Ê¼£©£ºn£¨Æ½£©=
5£º4
5£º4
£¨Ð´³ö×î¼òÕûÊý±È£¬ÏÂͬ£©£»Ô­»ìºÏÆøÌåÖУ¬a£ºb=
2£º3
2£º3
£»´ïµ½Æ½ºâʱ£¬N2ºÍH2µÄת»¯ÂʦÁ£¨N2£©£º¦Á£¨H2£©=
1£º2
1£º2
£»Æ½ºâ»ìºÏÆøÌåÖУ¬n£¨N2£©£ºn£¨H2£©£ºn£¨NH3£©=
3£º3£º2
3£º3£º2
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸