A.2H2(g)+O2(g)2H2O(g) ¦¤H1
2H2(g)+O2(g) 2H2O(l) ¦¤H2
B.S(g)+O2(g) SO2(g) ¦¤H1
S(s)+O2(g) SO2(g) ¦¤H2
C.C(s)+O2(g)
CO(g) ¦¤H1
C(s)+O2(g) CO2(g) ¦¤H2
D.H2(g)+Cl2(g) 2HCl(g) ¦¤H1
H2(g)+
Cl2(g)
HCl(g) ¦¤H2
BD
½âÎö£º·´Ó¦·Å³ö»òÎüÊÕµÄÈÈÁ¿¶àÉÙ£¬¸ú·´Ó¦ÎïºÍÉú³ÉÎïµÄ¾Û¼¯×´Ì¬ÓÐÃÜÇйØϵ¡£AÖÐÁ½Ê½½öÉú³ÉË®µÄ״̬²»Í¬£¬ÓÉÓÚÉú³ÉҺ̬ˮ±ÈÉú³ÉÆø̬ˮ·ÅÈȶ࣬ËùÒÔ|¦¤H2|£¾|¦¤H1|£¬¦¤H2£¼¦¤H1£»BÖÐÁ½Ê½½öÁòµÄ״̬²»Í¬£¬ÓÉÓÚ¹Ì̬Áò±ä³ÉÆø̬ÁòÒªÎüÊÕÈÈÁ¿£¬ËùÒÔ|¦¤H1|£¾|¦¤H2|£¬¦¤H2£¾¦¤H1£»CÖйÌ̬̼ÓëÑõÆøÍêÈ«·´Ó¦Éú³É¶þÑõ»¯Ì¼£¬·Å³öµÄÈÈÁ¿|¦¤H2|´óÓÚÉú³ÉÒ»Ñõ»¯Ì¼·Å³öµÄÈÈÁ¿|¦¤H1|£¬¦¤H2£¼¦¤H1£»DÖÐÁ½Ê½¸÷ÎïÖʵÄÎïÖʵÄÁ¿²»Í¬£¬|¦¤H1|=2|¦¤H2|£¬¦¤H2£¾¦¤H1¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
2mNA |
M |
2mNA |
M |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2006£2007ºÓ¶«ÈýÖиßÈý»¯Ñ§½ÌѧÖÊÁ¿¼ì²âÌâ ÌâÐÍ£º022
ÏÂÁÐÓйØʵÑé»ò×ö·¨ÖУ¬ÕýÈ·µÄÊÇ(ÌîÐòºÅ£¬´íÑ¡µ¹¿Û·Ö)________£®
A¡¢ÅäÖÆ480mL 1.0mol¡¤L£1NaOHÈÜҺʱ£¬Ðè³ÆÈ¡NaOH¹ÌÌåµÄÖÊÁ¿Îª20.0g
B¡¢Ó÷ÖÒºµÄ·½·¨·ÖÀë±½ºÍË®µÄ»ìºÏÎï
C¡¢Í¬ÎÂͬѹÏ£¬µÈÖÊÁ¿µÄÁòÔÚ×ãÁ¿µÄÑõÆøÖбÈÔÚ×ãÁ¿µÄ¿ÕÆøÖÐȼÉշųöµÄÈÈÁ¿¶à
D¡¢½«mgCOºÍH2µÄ»ìºÏÆøÌåÍêȫȼÉÕºóͨ¹ý¹ýÁ¿µÄNa2O2¹ÌÌå(ÆøÌå³ä·Ö·´Ó¦)£¬¹ÌÌåÔöÖØmg
E¡¢¿ÕÆø·¨ÊÕ¼¯Ò»Æ¿¸ÉÔïµÄ°±Æø×öÅçȪʵÑ飬×îºóÒºÌå³äÂúÕû¸öÈÝÆ÷
F¡¢Ö½ÔÚʹÓÃÇ°ÐèÓÃÕôÁóˮʪÈó£¬È»ºó½øÐÐÏàÓ¦ÊÔÑé
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
£¨1£©¢Ùд³öNaHSO4ÔÚË®ÈÜÒºÖеĵçÀë·½³Ìʽ______£®
¢ÚCO2ͨÈë×ãÁ¿ÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄÀë×Ó·´Ó¦·½³Ìʽ______£®
¢ÛOH-+H+=H2O¸ÄдΪ»¯Ñ§·½³Ìʽ______£®
Cu2++Fe=Fe2++Cu¸ÄдΪ»¯Ñ§·½³Ìʽ______£®
£¨2£©¢ÙͬÎÂͬѹÏ£¬Ä³Æ¿³äÂúÑõÆøʱÖÊÁ¿Îª116g£¬³äÂú¶þÑõ»¯Ì¼Ê±£¬ÖÊÁ¿Îª122g£¬³äÂúÆøÌåAʱÖÊÁ¿Îª114g£¬AµÄĦ¶ûÖÊÁ¿Îª______£®
¢ÚÏÖÓÐm gijÆøÌ壬ËüÓÉË«Ô×Ó·Ö×Ó¹¹³É£¬ËüµÄĦ¶ûÖÊÁ¿ÎªM g/mol£®Èô°¢·ü¼ÓµÂÂÞ³£ÊýÓÃNA±íʾ£¬Ôò¸ÃÆøÌåËùº¬Ô×Ó×ÜÊýΪ______¸ö£®
£¨3£©ÏÂÁÐʵÑé²Ù×÷Öв»ÕýÈ·µÄÊÇ______£¨¶àÑ¡£©£®
A£®Ó÷ÖÒºµÄ·½·¨·ÖÀëË®ºÍÆûÓ͵ĻìºÏÎï
B£®ÓùýÂ˵ķ½·¨·ÖÀë±¥ºÍʳÑÎË®Óëɳ×ӵĻìºÏÎï
C£®ÕôÁóʱ£¬Ó¦Ê¹Î¶ȼÆË®ÒøÇò²åÈëÒºÃæÒÔÏÂ
D£®Õô·¢½á¾§Ê±Ó¦½«ÈÜÒºÕô¸ÉºóÔÙÍ£Ö¹¼ÓÈÈ
E£®·ÖҺʱ£¬·ÖҺ©¶·Ï²ãÒºÌå´ÓÏ¿ڷųö£¬ÉϲãÒºÌå´ÓÉÏ¿Úµ¹³ö£®
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
£¨1£©·úÀï°ºÊÇfreonµÄÒôÒëÃû£¬·úÀï°ºµÄÉÌÒµ´úºÅ¿ÉÓÃHFC-nmp±íʾ£¬ÆäÖÐÊý×ÖnµÈÓÚ̼Ô×ÓÊýÄ¿¼õ1(Èç¹ûÊÇ0¾ÍÊ¡ÂÔ)£¬Êý×ÖmµÈÓÚÇâÔ×ÓÊýÄ¿¼Ó1£¬Êý×ÖpµÈÓÚ·úÔ×ÓÊý£¬ÂÈÔ×ÓÊýÄ¿²»ÁС£·úÀï°ºCH2F-CHF2µÄ´úºÅΪ £¬ËüÊôÓÚ (Ñ¡ÌA£®Ò»Â±´úÌþ B£®¶à±´úÌþ C£®±¥ºÍ±´úÌþ D£®²»±¥ºÍ±´úÌþ E£º·¼Ïã±´úÌþ)ÀàÓлúÎÆäͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽΪ ¡£
£¨2£©ÓÉÓÚ·úÀï°ºÎÞ¶¾£¬»¯Ñ§ÐÔÖÊÓÖ¼«ÆäÎȶ¨£¬±»´óÁ¿ÓÃÓÚÖÆÀä¼Á¡¢Ãð»ð¼Á¡¢·¢ÅݼÁµÈ¡£µ«´óÆøÖеķúÀï°ºÔÚƽÁ÷²ãÖÐÊÜ×ÏÍâÏßÕÕÉ䣬»á·Ö½â²úÉúClÔ×Ó£¬¶øClÔ×Ó»¯Ñ§ÐÔÖʱȽϻîÆãº
ÉÏÊö·´Ó¦µÄ×Ü·´Ó¦Îª Æä·´Ó¦¹ý³ÌÖУ¬ClÔ×ÓÆð ×÷Óá£
£¨3£©½ü¼¸ÄêÊÐÃæÉÏÍƳöµÄ±ùÏäвúÆ·¡ª¡ªÎÞ·ú±ùÏ䣬Ö÷ÒªÊÇΪÁË £¨µ¥Ñ¡£©
A£®·úÀï°º¼Û¸ñ¸ß£¬ÎªÁ˾¼Ã B£®±£»¤Éú̬×ÔÈ»»·¾³
C£®±£»¤ÈËÀàÉú´æ»·¾³ D£®ÎüÊÕºÍ×èµ²×ÏÍâÏß
£¨4£©Ê¯ÓͲúÆ·ÁѽâËùµÃÁѽâÆøµÄƽ¾ù×é³É¿É±íʾΪCnHm£¨m>2n£©£¬¾²â¶¨Ä³ÁѽâÆøÖи÷ÆøÌåµÄÌå»ý·ÖÊý·Ö±ðΪ£º¼×Í顪4%¡¢ÒÒÏ©¡ª50%¡¢±ûÏ©¡ª10%¡¢ÆäÓàΪ¶¡¶þÏ©ºÍÇâÆø£¨ÆøÌåÌå»ý¾ùÔÚͬÎÂͬѹϲⶨ£©¡£ÈôµÃµ½50 molÒÒÏ©£¬x mol¶¡¶þÏ©ºÍy molÇâÆø¡£
Ôòx+y= £¬ n / m = £¨ÇëÓú¬xµÄʽ×Ó±íʾ£©¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com