ÂÁ·ÛºÍÑõ»¯Ìú·ÛÄ©µÄ»ìºÏÎïÖƳɵÄÂÁÈȼÁ¿ÉÓÃÓÚº¸½Ó¸Ö¹ì£®ÏÖÈ¡²»Í¬ÖÊÁ¿µÄ¸ÃÂÁÈȼÁ·Ö±ðºÍ100mlͬÎïÖʵÄÁ¿Å¨¶ÈµÄNaOHÈÜÒº·´Ó¦£¬ËùÈ¡ÂÁÈȼÁµÄÖÊÁ¿Óë²úÉúÆøÌåµÄÌå»ý¹ØϵÈçÏÂ±í£¨ÆøÌåÌå»ý¾ùÔÚ±ê×¼×´¿öϲⶨ£©£º
¢Ù¢Ú¢Û¢Ü
ÂÁÈȼÁÖÊÁ¿/g5g10g15g20g
ÆøÌåÌå»ý/L2.24L4.48L6.72L6.72L
ÊÔÍê³ÉÏÂÁмÆË㣺
£¨1£©NaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È______£®
£¨2£©¸ÃÂÁÈȼÁÖÐÂÁµÄÖÊÁ¿·ÖÊý______£®
£¨3£©20g¸ÃÂÁÈȼÁ·¢ÉúÂÁÈÈ·´Ó¦ÀíÂÛÉϲúÉúÌúµÄÖÊÁ¿ÊǶàÉÙ£¿£¨Ð´³ö²½Ö裩

½â£º£¨1£©ÓÉ¢Û¢Ü×ãÊý¾Ý¿ÉÖª£¬¢Û×éÖÐNaOHÍêÈ«·´Ó¦£¬¢Û×éÖÐÇâÆøµÄÎïÖʵÄÁ¿Îª=0.3mol£¬Ôò£º
2Al+2NaOH+2H2O=2NaAlO2+3H2¡ü
2 3
n£¨NaOH£© 0.3mol
ËùÒÔn£¨NaOH£©=0.2mol£¬¹ÊÇâÑõ»¯ÄÆÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ=2mol/L£¬
¹Ê´ð°¸Îª£º2mol/L£»
£¨2£©¢Ù¢Ú×é½ðÊôAlÍêÈ«·´Ó¦£¬ÓɵڢÚ×ãÊý¾Ý¼ÆË㣬Ôò£º
2Al+2NaOH+2H2O=2NaAlO2+3H2¡ü
2 3
n£¨Al£© =0.2mol
¹Ên£¨Al£©==mol£¬Ôòm£¨Al£©=mol¡Á27g/mol=3.6g£¬
¹ÊAlµÄÖÊÁ¿·ÖÊýΪ¡Á100%=36%£¬
¹Ê´ð°¸Îª£º36%£»
£¨3£©20gÂÁÈȼÁÖУºm£¨Al£©=20¡Á36%=7.2g£¬¼´ n£¨Al£©==0.267mol£¬
m£¨Fe2O3£©=20-7.2=12.8g£¬¼´n£¨Fe2O3£©==0.08mol£¬
ÓÉ·½³Ìʽ2Al+Fe2O32Fe+Al2O3¿ÉÖª£¬0.08molFe2O3ÍêÈ«·´Ó¦ÐèÒª0.16molAl£¬¹ÊAl¹ýÁ¿£¬Fe2O3ÍêÈ«·´Ó¦£¬ÓÉÌúÔªËØÊغã¿ÉÖªn£¨Fe£©=2n£¨Fe2O3£©=0.16mol£¬¹Êm£¨Fe£©=0.16mol¡Á56g/mol=8.96g£¬
´ð£º20g¸ÃÂÁÈȼÁ·¢ÉúÂÁÈÈ·´Ó¦ÀíÂÛÉϲúÉúÌúµÄÖÊÁ¿ÊÇ8.96g£®
·ÖÎö£º£¨1£©ÓÉ¢Û¢Ü×ãÊý¾Ý¿ÉÖª£¬¢Û×éÖÐNaOHÍêÈ«·´Ó¦£¬¸ù¾Ýn=¼ÆËãÇâÆøµÄÎïÖʵÄÁ¿£¬ÔÙ¸ù¾Ý·½³Ìʽ¼ÆËãn£¨NaOH£©£¬¸ù¾Ýc=¼ÆËãÇâÑõ»¯ÄÆÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È£»
£¨2£©¢Ù¢Ú×é½ðÊôAlÍêÈ«·´Ó¦£¬ÓɵڢÚ×ãÊý¾Ý¼ÆË㣬¸ù¾Ý·½³Ìʽ¼ÆËãAlµÄÖÊÁ¿£¬ÔÚÀûÓÃÖÊÁ¿·ÖÊý¶¨Òå¼ÆË㣻
£¨3£©¼ÆËã20gÂÁÈȼÁÖÐAlµÄÖÊÁ¿£¬Ñõ»¯ÌúµÄÖÊÁ¿£¬½øÐйýÁ¿¼ÆË㣬¸ù¾Ý²»×ãÁ¿µÄÎïÖÊËãÉú³ÉFeµÄÖÊÁ¿£®
µãÆÀ£º±¾Ì⿼²é»ìºÏÎïµÄÓйؼÆË㣬ÄѶÈÖеȣ¬¹Ø¼üÊǸù¾Ý¹ÌÌåÖÊÁ¿ÓëÆøÌå¹Øϵȷ¶¨ÍêÈ«·´Ó¦µÄÎïÖÊ£¬£¨3£©ÖÐ×¢ÒâÐèÒª½øÐйýÁ¿¼ÆË㣮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©ÏÂÁÐÓйØʵÑéµÄ˵·¨¡¢²Ù×÷»ò½áÂÛ²»ÕýÈ·µÄÊÇ            £¨ÌîÐòºÅ£©

    A£®ÖƱ¸Fe(OH)3½ºÌåʱ£¬Ó¦Íù·ÐË®Öеμӱ¥ºÍFeCl3 ÈÜÒº£¬²¢¼ÌÐø¼ÓÈȵ½ÈÜÒº³ÊºìºÖɫΪֹ¡£

    B£®²â¶¨ÖкÍÈÈʵÑéÖУ¬Ã¿´ÎʵÑé¾ùÓ¦²âÁ¿Èý¸öζȣ¬¼´ÑÎËáÆðʼζȣ¬NaOHÈÜÒºµÄÆðʼζȺͷ´Ó¦ºóÈÜÒºµÄ×î¸ßζȡ£

    C£®ÔÚÒ»¶¨ÎïÖʵÄÁ¿ÈÜÒºÅäÖƵĹý³ÌÖУ¬Ã»ÓÐÏ´µÓÉÕ±­ºÍ²£Á§°ô¡¢¶¨ÈÝʱ¼ÓË®³¬¹ýÁ˿̶ÈÏß¡¢ÈÝÁ¿Æ¿Ã»ÓиÉÔï¾ù»áʹËùÅäÈÜҺŨ¶ÈÆ«µÍ¡£

    D£®ÍùFeCl3ÈÜÒºÖеÎÈëKI¡ªµí·ÛÈÜÒº£¬ÈÜÒº±äÀ¶É«¡£

E£®ÂÁ·ÛºÍÑõ»¯Ã¾»òÑõ»¯Ìú·ÛÄ©»ìºÏ£¬¸ßξùÄÜ·¢ÉúÂÁÈÈ·´Ó¦¡£

F£®ÑéÖ¤AgNO3ÈÜÒºÖÐÊÇ·ñ»ìÓÐAl(NO3)3£¬¿É¼ÓÈë¹ýÁ¿°±Ë®£¬ÈçÓа×É«³Áµí£¬Ôò»ìÓÐAl(NO3)3

G£®Ï¡ÊÍŨÁòËáʱ£¬Òª½«Ë®ÑØÈÝÆ÷±Ú»ºÂý×¢ÈëŨÁòËáÖУ¬²¢Óò£Á§°ô²»¶Ï½Á°è¡£

£¨2£©ÊµÑéÊÒÅäÖÆ500ml 0.1 mol/LµÄNa2CO3ÈÜÒº£¬ÐèÓÃÍÐÅÌÌìƽ³Æȡ̼ËáÄÆ·ÛÄ©     g¡£

ÅäÖÆʱӦѡÓõÄÒÇÆ÷ÓУ¬ÍÐÅÌÌìƽ¡¢Ò©³×¡¢ÉÕ±­¡¢Á¿Í²¡¢              ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©ÏÂÁÐÓйØʵÑéµÄ˵·¨¡¢²Ù×÷»ò½áÂÛ²»ÕýÈ·µÄÊÇ           £¨ÌîÐòºÅ£©

    A£®ÖƱ¸Fe(OH)3½ºÌåʱ£¬Ó¦Íù·ÐË®Öеμӱ¥ºÍFeCl3ÈÜÒº£¬²¢¼ÌÐø¼ÓÈȵ½ÈÜÒº³ÊºìºÖɫΪֹ¡£

    B£®²â¶¨ÖкÍÈÈʵÑéÖУ¬Ã¿´ÎʵÑé¾ùÓ¦²âÁ¿Èý¸öζȣ¬¼´ÑÎËáÆðʼζȣ¬NaOHÈÜÒºµÄÆðʼζȺͷ´Ó¦ºóÈÜÒºµÄ×î¸ßζȡ£

    C£®ÔÚÒ»¶¨ÎïÖʵÄÁ¿ÈÜÒºÅäÖƵĹý³ÌÖУ¬Ã»ÓÐÏ´µÓÉÕ±­ºÍ²£Á§°ô¡¢¶¨ÈÝʱ¼ÓË®³¬¹ýÁ˿̶ÈÏß¡¢ÈÝÁ¿Æ¿Ã»ÓиÉÔï¾ù»áʹËùÅäÈÜҺŨ¶ÈÆ«µÍ¡£

    D£®ÍùFeCl3ÈÜÒºÖеÎÈëKI¡ªµí·ÛÈÜÒº£¬ÈÜÒº±äÀ¶É«¡£

E£®ÂÁ·ÛºÍÑõ»¯Ã¾»òÑõ»¯Ìú·ÛÄ©»ìºÏ£¬¸ßξùÄÜ·¢ÉúÂÁÈÈ·´Ó¦¡£

F£®ÑéÖ¤AgNO3ÈÜÒºÖÐÊÇ·ñ»ìÓÐAl(NO3)3£¬¿É¼ÓÈë¹ýÁ¿°±Ë®£¬ÈçÓа×É«³Áµí£¬Ôò»ìÓÐAl(NO3)3

G£®Ï¡ÊÍŨÁòËáʱ£¬Òª½«Ë®ÑØÈÝÆ÷±Ú»ºÂý×¢ÈëŨÁòËáÖУ¬²¢Óò£Á§°ô²»¶Ï½Á°è¡£

£¨2£©ÊµÑéÊÒÅäÖÆ500ml 0.1 mol/LµÄNa2CO3ÈÜÒº£¬ÐèÓÃÍÐÅÌÌìƽ³Æȡ̼ËáÄÆ·ÛÄ©    g¡£

ÅäÖÆʱӦѡÓõÄÒÇÆ÷ÓУ¬ÍÐÅÌÌìƽ¡¢Ò©³×¡¢ÉÕ±­¡¢Á¿Í²¡¢             ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011½ìºÚÁú½­´óÇìʵÑéÖÐѧ¸ßÈýÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

£¨1£©ÏÂÁÐÓйØʵÑéµÄ˵·¨¡¢²Ù×÷»ò½áÂÛ²»ÕýÈ·µÄÊÇ           £¨ÌîÐòºÅ£©

A£®ÖƱ¸Fe(OH)3½ºÌåʱ£¬Ó¦Íù·ÐË®Öеμӱ¥ºÍFeCl3ÈÜÒº£¬²¢¼ÌÐø¼ÓÈȵ½ÈÜÒº³ÊºìºÖɫΪֹ¡£
B£®²â¶¨ÖкÍÈÈʵÑéÖУ¬Ã¿´ÎʵÑé¾ùÓ¦²âÁ¿Èý¸öζȣ¬¼´ÑÎËáÆðʼζȣ¬NaOHÈÜÒºµÄÆðʼζȺͷ´Ó¦ºóÈÜÒºµÄ×î¸ßζȡ£
C£®ÔÚÒ»¶¨ÎïÖʵÄÁ¿ÈÜÒºÅäÖƵĹý³ÌÖУ¬Ã»ÓÐÏ´µÓÉÕ±­ºÍ²£Á§°ô¡¢¶¨ÈÝʱ¼ÓË®³¬¹ýÁ˿̶ÈÏß¡¢ÈÝÁ¿Æ¿Ã»ÓиÉÔï¾ù»áʹËùÅäÈÜҺŨ¶ÈÆ«µÍ¡£
D£®ÍùFeCl3ÈÜÒºÖеÎÈëKI¡ªµí·ÛÈÜÒº£¬ÈÜÒº±äÀ¶É«¡£
E£®ÂÁ·ÛºÍÑõ»¯Ã¾»òÑõ»¯Ìú·ÛÄ©»ìºÏ£¬¸ßξùÄÜ·¢ÉúÂÁÈÈ·´Ó¦¡£
F£®ÑéÖ¤AgNO3ÈÜÒºÖÐÊÇ·ñ»ìÓÐAl(NO3)3£¬¿É¼ÓÈë¹ýÁ¿°±Ë®£¬ÈçÓа×É«³Áµí£¬Ôò»ìÓÐAl(NO3)3
G£®Ï¡ÊÍŨÁòËáʱ£¬Òª½«Ë®ÑØÈÝÆ÷±Ú»ºÂý×¢ÈëŨÁòËáÖУ¬²¢Óò£Á§°ô²»¶Ï½Á°è¡£
£¨2£©ÊµÑéÊÒÅäÖÆ500ml 0.1mol/LµÄNa2CO3ÈÜÒº£¬ÐèÓÃÍÐÅÌÌìƽ³Æȡ̼ËáÄÆ·ÛÄ©    g¡£
ÅäÖÆʱӦѡÓõÄÒÇÆ÷ÓУ¬ÍÐÅÌÌìƽ¡¢Ò©³×¡¢ÉÕ±­¡¢Á¿Í²¡¢             ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄêºÚÁú½­´óÇìʵÑéÖÐѧ¸ßÈýÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

£¨1£©ÏÂÁÐÓйØʵÑéµÄ˵·¨¡¢²Ù×÷»ò½áÂÛ²»ÕýÈ·µÄÊÇ            £¨ÌîÐòºÅ£©

    A£®ÖƱ¸Fe(OH)3½ºÌåʱ£¬Ó¦Íù·ÐË®Öеμӱ¥ºÍFeCl3 ÈÜÒº£¬²¢¼ÌÐø¼ÓÈȵ½ÈÜÒº³ÊºìºÖɫΪֹ¡£

    B£®²â¶¨ÖкÍÈÈʵÑéÖУ¬Ã¿´ÎʵÑé¾ùÓ¦²âÁ¿Èý¸öζȣ¬¼´ÑÎËáÆðʼζȣ¬NaOHÈÜÒºµÄÆðʼζȺͷ´Ó¦ºóÈÜÒºµÄ×î¸ßζȡ£

    C£®ÔÚÒ»¶¨ÎïÖʵÄÁ¿ÈÜÒºÅäÖƵĹý³ÌÖУ¬Ã»ÓÐÏ´µÓÉÕ±­ºÍ²£Á§°ô¡¢¶¨ÈÝʱ¼ÓË®³¬¹ýÁ˿̶ÈÏß¡¢ÈÝÁ¿Æ¿Ã»ÓиÉÔï¾ù»áʹËùÅäÈÜҺŨ¶ÈÆ«µÍ¡£

    D£®ÍùFeCl3ÈÜÒºÖеÎÈëKI¡ªµí·ÛÈÜÒº£¬ÈÜÒº±äÀ¶É«¡£

E£®ÂÁ·ÛºÍÑõ»¯Ã¾»òÑõ»¯Ìú·ÛÄ©»ìºÏ£¬¸ßξùÄÜ·¢ÉúÂÁÈÈ·´Ó¦¡£

F£®ÑéÖ¤AgNO3ÈÜÒºÖÐÊÇ·ñ»ìÓÐAl(NO3)3£¬¿É¼ÓÈë¹ýÁ¿°±Ë®£¬ÈçÓа×É«³Áµí£¬Ôò»ìÓÐAl(NO3)3

G£®Ï¡ÊÍŨÁòËáʱ£¬Òª½«Ë®ÑØÈÝÆ÷±Ú»ºÂý×¢ÈëŨÁòËáÖУ¬²¢Óò£Á§°ô²»¶Ï½Á°è¡£

£¨2£©ÊµÑéÊÒÅäÖÆ500ml 0.1 mol/LµÄNa2CO3ÈÜÒº£¬ÐèÓÃÍÐÅÌÌìƽ³Æȡ̼ËáÄÆ·ÛÄ©     g¡£

ÅäÖÆʱӦѡÓõÄÒÇÆ÷ÓУ¬ÍÐÅÌÌìƽ¡¢Ò©³×¡¢ÉÕ±­¡¢Á¿Í²¡¢              ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸