[s1] ÔÚÒ»ºãκãѹÃܱÕÈÝÆ÷ÖУ¬A¡¢BÆøÌå¿É½¨Á¢ÈçÏÂƽºâ£º2A(g)+2B(g)      C(g)+3D(g)ÏÖ·Ö±ð´ÓÁ½Ìõ;¾¶½¨Á¢Æ½ºâ£ºI¡¢A¡¢BµÄÆðʼÁ¿¾ùΪ2mol£»II¡¢C¡¢DµÄÆðʼÁ¿·Ö±ðΪ2molºÍ6mol¡£ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ         £¨    £©

    A£®´ïµ½Æ½ºâʱ£¬Í¾¾¶IµÄÆøÌåÃܶÈΪ;¾¶IIÃܶȵÄ1/2

    B£®I¡¢IIÁ½Í¾¾¶×îÖմﵽƽºâʱ£¬ÌåϵÄÚ¸÷ÆøÌåµÄŨ¶È²»Í¬

    C£®´ïµ½Æ½ºâʱ£¬Í¾¾¶IºÍ;¾¶IIÌåϵÄÚ»ìºÏÆøÌåƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»Í¬

    D£®I¡¢IIÁ½Í¾¾¶×îÖմﵽƽºâʱ£¬ÌåϵÄÚ»ìºÏÆøÌåµÄ°Ù·Ö×é³ÉÏàͬ

 

 [s1]8£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?·ðɽ¶þÄ££©2012Äê2ÔÂ27ÈÕÉîÛÚÐû³Æ½øÈë¡°200ÍòÁ¾Æû³µÊ±´ú¡±£¬Æû³µÎ²ÆøÒѳÉΪÖØÒªµÄ¿ÕÆøÎÛȾÎ
£¨1£©Æû³µÄÚȼ»ú¹¤×÷ʱÒýÆð·´Ó¦£ºN2£¨g£©+O2£¨g£©?2NO£¨g£©£¬Êǵ¼ÖÂÆû³µÎ²ÆøÖк¬ÓÐNOµÄÔ­ÒòÖ®Ò»£®T¡æʱ£¬Ïò5LÃܱÕÈÝÆ÷ÖгäÈë8mol N2ºÍ9molO2£¬5minºó´ïƽºâʱNOÎïÖʵÄÁ¿Îª6mol£¬¸Ã·´Ó¦µÄËÙÂʦԣ¨NO£©Îª
0.24mol?L-1?min-1
0.24mol?L-1?min-1
£»¼ÆËã¸ÃÌõ¼þϵÄƽºâ³£Êý
1.2
1.2
£®
£¨2£©ºãκãÈÝ£¬ÄÜ˵Ã÷·´Ó¦ 2NO£¨g£©?N2£¨g£©+O2£¨g£© ´ïµ½Æ½ºâµÄÊÇ
AC
AC
£¨Ìî´úºÅ£©£®
A£®µ¥Î»Ê±¼äÄÚÏûºÄ2mol NO£¬Í¬Ê±ÏûºÄ1mol N2     
B£®NO¡¢N2¡¢O2µÄŨ¶ÈÖ®±ÈΪ2£º1£º1
C£®N2µÄŨ¶È²»ÔÙ·¢Éú±ä»¯                 
D£®ÈÝÆ÷ÄÚÆøÌåÃܶȲ»ÔÙ·¢Éú±ä»¯
£¨3£©H2»òCO¿ÉÒÔ´ß»¯»¹Ô­NOÒÔ´ïµ½Ïû³ýÎÛȾµÄÄ¿µÄ£º
¢ÙÒÑÖª£ºN2£¨g£©+O2£¨g£©=2NO£¨g£©¡÷H=+180.5kJ/mol
2H2£¨g£©+O2£¨g£©=2H2O£¨l£©¡÷H=-571.6kJ/mol
ÔòH2£¨g£©ÓëNO£¨g£©·´Ó¦Éú³ÉN2£¨g£©ºÍH2O£¨l£©µÄÈÈ»¯Ñ§·½³ÌʽΪ£º
2H2£¨g£©+2NO£¨g£©=N2£¨g£©+2H2O£¨l£©¡÷H=-752.1kJ?mol-1
2H2£¨g£©+2NO£¨g£©=N2£¨g£©+2H2O£¨l£©¡÷H=-752.1kJ?mol-1
£®
¢Úµ±ÖÊÁ¿Ò»¶¨Ê±£¬Ôö´ó¹ÌÌå´ß»¯¼ÁµÄ±íÃæ»ý¿ÉÌá¸ß»¯Ñ§·´Ó¦ËÙÂÊ£®ÈçͼÊÇ·´Ó¦£º2NO£¨g£©+2CO£¨g£©?2CO2£¨g£©+N2£¨g£© ÖÐNOµÄŨ
¶ÈËæζȣ¨T£©¡¢´ß»¯¼Á±íÃæ»ý£¨S£©ºÍʱ¼ä£¨t£©µÄ±ä»¯ÇúÏߣ¬¾Ý´ËÅжϸ÷´Ó¦µÄ¡÷H
£¼
£¼
0 £¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°ÎÞ·¨È·¶¨¡±£©£®Èô´ß»¯¼ÁµÄ±íÃæ»ýS1£¾S2£¬ÔÚͼÖл­³öNOµÄŨ¶ÈÔÚT1¡¢S2Ìõ¼þÏ´ﵽƽºâ¹ý³ÌÖеı仯ÇúÏߣ¬²¢×¢Ã÷Ìõ¼þ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄê¹ã¶«Ê¡ÉîÛÚÊÐÄÏɽÇø¸ßÈýÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º¼ÆËãÌâ

2012Äê2ÔÂ27ÈÕÉîÛÚÐû³Æ½øÈë¡°200ÍòÁ¾Æû³µÊ±´ú¡±£¬Æû³µÎ²ÆøÒѳÉΪÖØÒªµÄ¿ÕÆøÎÛȾÎï¡£

£¨1£©Æû³µÄÚȼ»ú¹¤×÷ʱÒýÆð·´Ó¦£ºN2(g)+O2(g)2NO(g)£¬Êǵ¼ÖÂÆû³µÎ²ÆøÖк¬ÓÐNOµÄÔ­ÒòÖ®Ò»¡£T¡æʱ£¬Ïò2LÃܱÕÈÝÆ÷ÖгäÈë4mol N2ºÍ6molO2£¬5minºó´ïƽºâʱNOÎïÖʵÄÁ¿Îª4mol£¬¸Ã·´Ó¦µÄËÙÂÊv(N 2)Ϊ         £»¼ÆËã¸ÃÌõ¼þϵÄƽºâ³£Êý£¨Ð´³ö¼ÆËã¹ý³Ì£©¡£

£¨2£©ºãκãÈÝ£¬ÄÜ˵Ã÷·´Ó¦ 2NO(g)  N2(g)+O2(g) ´ïµ½Æ½ºâµÄÊÇ        £¨Ìî´úºÅ£©¡£

A£®NO¡¢N2¡¢O2µÄŨ¶ÈÖ®±ÈΪ2¡Ã1¡Ã1

B£®N2µÄŨ¶È²»ÔÙ·¢Éú±ä»¯

C£®µ¥Î»Ê±¼äÄÚÏûºÄ2 mol NO£¬Í¬Ê±ÏûºÄ1 mol N2

D£®ÈÝÆ÷ÄÚÆøÌåÃܶȲ»ÔÙ·¢Éú±ä»¯

£¨3£©H2»òCO¿ÉÒÔ´ß»¯»¹Ô­NOÒÔ´ïµ½Ïû³ýÎÛȾµÄÄ¿µÄ£º

¢ÙÒÑÖª£ºN2(g)+ O2(g) = 2NO(g)      ¡÷H = +180.5kJ/mol

H2(g)+1/2O2(g) = H2O(l)     ¡÷H = ¡ª285.8kJ/mol

ÔòH2(g)ÓëNO(g)·´Ó¦Éú³ÉN2(g)ºÍH2O(l)µÄÈÈ»¯Ñ§·½³ÌʽΪ                          ¡£

¢Úµ±ÖÊÁ¿Ò»¶¨Ê±£¬Ôö´ó¹ÌÌå´ß»¯¼ÁµÄ±íÃæ»ý¿ÉÌá¸ß»¯Ñ§·´Ó¦ËÙÂÊ¡£ÏÂͼÊÇ·´Ó¦£º2NO(g) + 2CO(g) 2CO2(g)+ N2(g) ÖÐNOµÄŨ¶ÈËæζÈ(T)¡¢´ß»¯¼Á±íÃæ»ý(S)ºÍʱ¼ä(t)µÄ±ä»¯ÇúÏߣ¬¾Ý´ËÅжϸ÷´Ó¦µÄ¡÷H       0 (Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°ÎÞ·¨È·¶¨¡±)¡£Èô´ß»¯¼ÁµÄ±íÃæ»ýS1£¾S2 £¬ÔÚÏÂͼÖл­³öNOµÄŨ¶ÈÔÚT1¡¢S2 Ìõ¼þÏ´ﵽƽºâ¹ý³ÌÖеı仯ÇúÏߣ¬²¢×¢Ã÷Ìõ¼þ¡£

 

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄê½­Î÷Ê¡ÄϲýÊаËÒ»ÖÐѧ¡¢ºé¶¼ÖÐѧ¡¢ÂéÇðÖÐѧ¸ß¶þ£¨ÉÏ£©ÆÚÖл¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

2012Äê2ÔÂ27ÈÕÉîÛÚÐû³Æ½øÈë¡°200ÍòÁ¾Æû³µÊ±´ú¡±£¬Æû³µÎ²ÆøÒѳÉΪÖØÒªµÄ¿ÕÆøÎÛȾÎ
£¨1£©Æû³µÄÚȼ»ú¹¤×÷ʱÒýÆð·´Ó¦£ºN2£¨g£©+O2£¨g£©?2NO£¨g£©£¬Êǵ¼ÖÂÆû³µÎ²ÆøÖк¬ÓÐNOµÄÔ­ÒòÖ®Ò»£®T¡æʱ£¬Ïò5LÃܱÕÈÝÆ÷ÖгäÈë8mol N2ºÍ9molO2£¬5minºó´ïƽºâʱNOÎïÖʵÄÁ¿Îª6mol£¬¸Ã·´Ó¦µÄËÙÂʦԣ¨NO£©Îª______£»¼ÆËã¸ÃÌõ¼þϵÄƽºâ³£Êý______£®
£¨2£©ºãκãÈÝ£¬ÄÜ˵Ã÷·´Ó¦ 2NO£¨g£©?N2£¨g£©+O2£¨g£© ´ïµ½Æ½ºâµÄÊÇ______£¨Ìî´úºÅ£©£®
A£®µ¥Î»Ê±¼äÄÚÏûºÄ2mol NO£¬Í¬Ê±ÏûºÄ1mol N2     
B£®NO¡¢N2¡¢O2µÄŨ¶ÈÖ®±ÈΪ2£º1£º1
C£®N2µÄŨ¶È²»ÔÙ·¢Éú±ä»¯                 
D£®ÈÝÆ÷ÄÚÆøÌåÃܶȲ»ÔÙ·¢Éú±ä»¯
£¨3£©H2»òCO¿ÉÒÔ´ß»¯»¹Ô­NOÒÔ´ïµ½Ïû³ýÎÛȾµÄÄ¿µÄ£º
¢ÙÒÑÖª£ºN2£¨g£©+O2£¨g£©=2NO£¨g£©¡÷H=+180.5kJ/mol
2H2£¨g£©+O2£¨g£©=2H2O£¨l£©¡÷H=-571.6kJ/mol
ÔòH2£¨g£©ÓëNO£¨g£©·´Ó¦Éú³ÉN2£¨g£©ºÍH2O£¨l£©µÄÈÈ»¯Ñ§·½³ÌʽΪ£º______£®
¢Úµ±ÖÊÁ¿Ò»¶¨Ê±£¬Ôö´ó¹ÌÌå´ß»¯¼ÁµÄ±íÃæ»ý¿ÉÌá¸ß»¯Ñ§·´Ó¦ËÙÂÊ£®ÈçͼÊÇ·´Ó¦£º2NO£¨g£©+2CO£¨g£©?2CO2£¨g£©+N2£¨g£© ÖÐNOµÄŨ
¶ÈËæζȣ¨T£©¡¢´ß»¯¼Á±íÃæ»ý£¨S£©ºÍʱ¼ä£¨t£©µÄ±ä»¯ÇúÏߣ¬¾Ý´ËÅжϸ÷´Ó¦µÄ¡÷H______0 £¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°ÎÞ·¨È·¶¨¡±£©£®Èô´ß»¯¼ÁµÄ±íÃæ»ýS1£¾S2£¬ÔÚͼÖл­³öNOµÄŨ¶ÈÔÚT1¡¢S2Ìõ¼þÏ´ﵽƽºâ¹ý³ÌÖеı仯ÇúÏߣ¬²¢×¢Ã÷Ìõ¼þ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010Äê9Ô·ݰÙÌ⾫Á·£¨2£© ÌâÐÍ£ºµ¥Ñ¡Ìâ

 [s1] ÔÚÒ»ºãκãѹÃܱÕÈÝÆ÷ÖУ¬A¡¢BÆøÌå¿É½¨Á¢ÈçÏÂƽºâ£º2A(g)+2B(g)       C(g)+3D(g)ÏÖ·Ö±ð´ÓÁ½Ìõ;¾¶½¨Á¢Æ½ºâ£ºI¡¢A¡¢BµÄÆðʼÁ¿¾ùΪ2mol£»II¡¢C¡¢DµÄÆðʼÁ¿·Ö±ðΪ2molºÍ6mol¡£ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ         £¨    £©

    A£®´ïµ½Æ½ºâʱ£¬Í¾¾¶IµÄÆøÌåÃܶÈΪ;¾¶IIÃܶȵÄ1/2

    B£®I¡¢IIÁ½Í¾¾¶×îÖմﵽƽºâʱ£¬ÌåϵÄÚ¸÷ÆøÌåµÄŨ¶È²»Í¬

    C£®´ïµ½Æ½ºâʱ£¬Í¾¾¶IºÍ;¾¶IIÌåϵÄÚ»ìºÏÆøÌåƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»Í¬

    D£®I¡¢IIÁ½Í¾¾¶×îÖմﵽƽºâʱ£¬ÌåϵÄÚ»ìºÏÆøÌåµÄ°Ù·Ö×é³ÉÏàͬ

 


 [s1]8£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸