ÔڵؿÇÄÚ£¬Éî¶ÈÿÔö¼Ó1km£¬Ñ¹Ç¿´óÔ¼Ôö¼Ó25 250kPa¡«30 300kPa£¬ÔÚÕâÑùµÄѹǿÏ£¬¶Ô¹ÌÌåÎïÖʵÄƽºâ»á·¢Éú½Ï´óÓ°Ï죮È磺
|
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÔڵؿÇÄÚ£¬Éî¶ÈÿÔö¼Ó1 km£¬Ñ¹Ç¿Ô¼Ôö¼Ó25 250 kPa¨D30 300 kPa£¬Õâ¶Ô¹ÌÌåÎïÖʵÄƽºâ»á·¢Éú½Ï´óµÄÓ°Ïì¡£È磺
CaAl2Si2O8+Mg2SiO4CaMg2Al2Si3O12
(¸Æ³¤Ê¯) £¨Ã¾éÏéʯ£© £¨¸ÆþʯÁñʯ£©
Ãܶȣº
£¨2.70 g?cm-3£© (3.22 g?cm-3) (3.50 g?cm-3)
ÔòÔڵؿÇÇøÓò¸ßѹÌõ¼þÏ£¬ÓÐÀûÓÚ( )
A.¸Æ³¤Ê¯Éú³É B.þéÏéʯÉú³É
C.¸Æ³¤Ê¯ÓëþéÏéʯ¹²´æ D.¸ÆþʯÁñʯÉú³É
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
(1)ÓÃÑõ»¯ÎïµÄÐÎʽ±íʾÆ仯ѧʽΪ£º
¸Æ³¤Ê¯______________£¬Ã¾éÏéʯ______________£¬Ê¯Áñ×Óʯ______________¡£
(2)д³ö¸Æ³¤Ê¯ºÍþéÏéʯ·´Ó¦×ª»¯ÎªÊ¯Áñ×ÓʯµÄ»¯Ñ§·½³Ìʽ__________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÔڵؿÇÄÚ£¬Éî¶ÈÿÔö¼Ó1 km£¬Ñ¹Ç¿Ô¼Ôö¼Ó25 250 kPa¡ª30 300 kPa£¬Õâ¶Ô¹ÌÌåÎïÖʵÄƽºâ»á·¢Éú½Ï´óµÄÓ°Ïì¡£È磺
CaAl2Si2O8 + Mg2SiO4CaMg2Al2Si3O12
(¸Æ³¤Ê¯) £¨Ã¾éÏéʯ£© £¨¸ÆþʯÁñʯ£©
Ãܶȣº£¨2.70 g¡¤cm-3£© (3.22 g¡¤cm-3) (3.50 g¡¤cm-3)
ÔòÔڵؿÇÇøÓò¸ßѹÌõ¼þÏ£¬ÓÐÀûÓÚ( )
A.¸Æ³¤Ê¯Éú³É B.þéÏéʯÉú³É
C.¸Æ³¤Ê¯ÓëþéÏéʯ¹²´æ D.¸ÆþʯÁñʯÉú³É
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê¸ßÈýÉÏѧÆÚµ¥Ôª²âÊÔ£¨6£©»¯Ñ§ÊÔ¾í£¨ÐÂÈ˽̰棩 ÌâÐÍ£ºÑ¡ÔñÌâ
ÔڵؿÇÄÚ£¬Éî¶ÈÿÔö¼Ó1km£¬Ñ¹Ç¿Ô¼Ôö¼Ó25250¡«30300kPa£¬Õâ¶Ô¹ÌÌåÎïÖʵÄƽºâ»á·¢Éú½Ï´óµÄÓ°Ïì¡£È磺CaAl2Si2O8£«Mg2SiO4 CaMg2Al2Si3O12
£¨¸Æ³¤Ê¯£© £¨Ã¾éÏéʯ£© £¨¸Æþ£©Ê¯Áñ×Óʯ
Ãܶȣ¨g/cm3£© 2£®70 3£®22 3£®50
ÔòÔڵؿÇÇøÓò¸ßѹÌõ¼þÏ£¬ÓÐÀûÓÚ £¨ £©
A£®¸Æ³¤Ê¯Éú³É B£®Ã¾éÏéʯÉú³É
C£®¸Æ³¤Ê¯ºÍþéÏéʯ¹²´æ D£®£¨¸Æþ£©Ê¯Áñ×ÓʯÉú³É
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com