һƿ³ÎÇå͸Ã÷µÄÈÜÒº£¬¿ÉÄܺ¬ÓÐÏÂÁÐÀë×ÓÖеÄÒ»ÖÖ»ò¼¸ÖÖ£ºFe2+¡¢Fe3+¡¢Ba2+¡¢Al3+¡¢NH4+¡¢SO42-¡¢ HCO3-¡¢NO3-¡¢Cl-È¡ÈÜÒº½øÐÐÈçÏÂʵÑ飺

¢ÙÈÜÒºµÎÔÚÀ¶É«Ê¯ÈïÊÔÖ½ÉÏ£¬ÊÔÖ½³ÊºìÉ«¡£

¢ÚÈ¡ÉÙÁ¿ÈÜҺŨËõºó¼ÓÈëͭƬºÍŨÁòËá¹²ÈÈ£¬Óкì×ØÉ«ÆøÌåÉú³É¡£

¢ÛÈ¡ÉÙÁ¿ÈÜÒº£¬¼ÓÈëÓÃÏõËáËữµÄÂÈ»¯±µÈÜÒº£¬²úÉú°×É«³Áµí¡£

¢ÜÁí½«¢ÛÖеijÁµí¹ýÂ˳ö£¬ÂËÒºÖмÓÈëÏõËáÒøÈÜÒº£¬Éú³É°×É«³Áµí

¢ÝÁíÈ¡Ô­ÈÜÒº£¬ÖðµÎ¼ÓÈëÇâÑõ»¯ÄÆÈÜÒºÖÁ¹ýÁ¿£¬ÏÈ¿´µ½Éú³É³Áµí£¬ËæÖ®¸Ã³Áµí²¿·ÖÈܽ⣬²¢³ÊºìºÖÉ«¡£

¸ù¾ÝÉÏÊöʵÑéÏÖÏóÍƶϣº

£¨1£©ÈÜÒºÖп϶¨´æÔÚµÄÀë×ÓÓР                            ¡£

£¨2£©ÈÜÒºÖп϶¨²»´æÔÚµÄÀë×ÓÓР                              ¡£

£¨3£©ÈÜÒºÖв»ÄÜÈ·¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÓР                         ¡£

£¨4£©¶ÔÉÏÊöʵÑé²Ù×÷×öºÎ¸Ä½ø£¬²ÅÄÜÈ·¶¨£¨3£©ÖеÄÀë×ÓÊÇ·ñ´æÔÚ                   

                                                                           

 

 

£¨1£©ÈÜÒºÖп϶¨´æÔÚµÄÀë×ÓÓР  Fe3+¡¢Al3+¡¢NO3¡ª¡¢SO42¡ª        ¡£

£¨2£©ÈÜÒºÖп϶¨²»´æÔÚµÄÀë×ÓÓÐ HCO3¡ª¡¢Ba2+¡¢Fe2+             ¡£

£¨3£©ÈÜÒºÖв»ÄÜÈ·¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÓР  NH4+¡¢Cl¡ª   £¨ÒÔÉ϶ԵÄÀë×Óÿ¸ö1·Ö£© ¡£

£¨4£©°Ñ¢Û²½ÖеÄÂÈ»¯±µ¸ÄÓÃÏõËá±µ£¬ÔÙ²Ù×÷¢Ü¾Í¿ÉÒÔÈ·¶¨Cl£»µÄ´æÔÚ£»¶Ô²Ù×÷¢ÝµÄÈÜÒº¼ÓÈÈ£¬ÓÃʪÈóµÄºìɫʯÈïÊÔÖ½·ÅÔÚÊԹܿڣ¬¿´ÊÔÖ½ÊÇ·ñ±äÀ¶¼´¿ÉÈ·¶¨NH4+¡£»òÔÙÁíÈ¡ÉÙÁ¿Ô­ÈÜÒºÓÚÊÔ¹ÜÖв¢¼ÓÈë×ãÁ¿µÄNaOHÈÜÒº¼ÓÈÈ£¬ÓÃʪÈóµÄºìɫʯÈïÊÔÖ½·ÅÔÚÊԹܿڣ¬¿´ÊÔÖ½ÊÇ·ñ±äÀ¶¼´¿ÉÈ·¶¨NH4+¡££¨ÆäËûºÏÀí´ð°¸Ò²¿É£©    £¨4·Ö£©

 

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

һƿ³ÎÇå͸Ã÷µÄÈÜÒº£¬¿ÉÄܺ¬ÓÐÏÂÁÐÀë×ÓÖеļ¸ÖÖ£ºFe2+¡¢Fe3+¡¢Ba2+¡¢Al3+¡¢N
H
+
4
¡¢S
O
2-
4
¡¢HC
O
-
3
¡¢N
O
-
3
ºÍCl-£®¶Ô´ËÈÜÒº½øÐÐÈçÏÂʵÑ飺
¢Ù½«Ô­ÈÜÒºµÎµ½À¶É«Ê¯ÈïÊÔÖ½ÉÏ£¬ÊÔÖ½³ÊºìÉ«£®¢Ú½«ÉÙÁ¿Ô­ÈÜҺŨËõºóÔÙ¼ÓÈëͭƬºÍŨÁòËá¹²ÈÈ£¬Óкì×ØÉ«ÆøÌåÉú³É£®¢ÛÈ¡ÉÙÁ¿Ô­ÈÜÒº£¬¼ÓÈëÓÃÏõËáËữµÄÂÈ»¯±µÈÜÒº£¬²úÉú°×É«³Áµí£®¢ÜÁí½«¢ÛÖеijÁµí¹ýÂ˳öÀ´£¬ÏòÂËÒºÖмÓÈëÏõËáÒøÈÜÒº£¬Éú³É°×É«³Áµí£®¢ÝÈ¡ÉÙÁ¿Ô­ÈÜÒº£¬ÖðµÎ¼ÓÈëÇâÑõ»¯ÄÆÈÜÒºÖÁ¹ýÁ¿£¬ÏÈ¿´µ½Éú³É³Áµí£¬ËæÖ®¸Ã³Áµí²¿·ÖÈܽ⣬²¢³ÊºìºÖÉ«£®
¸ù¾ÝÉÏÊöʵÑéÏÖÏóÍƶϣº
£¨1£©ÈÜÒºÖп϶¨´æÔÚµÄÀë×ÓÓÐ
Fe3+¡¢NO3-¡¢Al3+¡¢SO42-
Fe3+¡¢NO3-¡¢Al3+¡¢SO42-
£®
£¨2£©ÈÜÒºÖп϶¨²»´æÔÚµÄÀë×ÓÓÐ
HCO3-¡¢Ba2+¡¢Fe2+£¬
HCO3-¡¢Ba2+¡¢Fe2+£¬
£®
£¨3£©ÈÜÒºÖв»ÄÜÈ·¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÓÐ
NH4+¡¢C1-
NH4+¡¢C1-
£®
£¨4£©¶ÔÉÏÊöʵÑé²Ù×÷ÈçºÎ¸Ä½ø£¬²ÅÄÜÈ·¶¨£¨3£©ÖеÄÀë×ÓÊÇ·ñ´æÔÚ£º
°Ñ²Ù×÷¢ÛÖеÄÂÈ»¯±µÈÜÒº»»³ÉÏõËá±µÈÜÒº£¬ÔÙ½øÐвÙ×÷¢Ü£¬¿ÉÒÔÈ·¶¨C1-´æÔÚ£»¶Ô²Ù×÷¢ÝÖеÄÈÜÒº¼ÓÈÈ£¬°ÑʪÈóµÄºìɫʯÈïÊÔÖ½·ÅÔÚÊԹܿڣ¬¿´ÊÔÖ½ÊÇ·ñ±äÀ¶£¬¼´¿ÉÈ·¶¨ÓÐÎÞNH4+
°Ñ²Ù×÷¢ÛÖеÄÂÈ»¯±µÈÜÒº»»³ÉÏõËá±µÈÜÒº£¬ÔÙ½øÐвÙ×÷¢Ü£¬¿ÉÒÔÈ·¶¨C1-´æÔÚ£»¶Ô²Ù×÷¢ÝÖеÄÈÜÒº¼ÓÈÈ£¬°ÑʪÈóµÄºìɫʯÈïÊÔÖ½·ÅÔÚÊԹܿڣ¬¿´ÊÔÖ½ÊÇ·ñ±äÀ¶£¬¼´¿ÉÈ·¶¨ÓÐÎÞNH4+
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

һƿ³ÎÇå͸Ã÷µÄÈÜÒº£¬¿ÉÄܺ¬ÓÐÏÂÁÐÀë×ÓÖеÄÒ»ÖÖ»ò¼¸ÖÖ£ºFe2+¡¢Fe3+¡¢Ba2+¡¢Al3+¡¢NH4+¡¢SO42-¡¢ HCO3-¡¢NO3-¡¢Cl-È¡ÈÜÒº½øÐÐÈçÏÂʵÑ飺

¢ÙÈÜÒºµÎÔÚÀ¶É«Ê¯ÈïÊÔÖ½ÉÏ£¬ÊÔÖ½³ÊºìÉ«¡£

¢ÚÈ¡ÉÙÁ¿ÈÜҺŨËõºó¼ÓÈëͭƬºÍŨÁòËá¹²ÈÈ£¬Óкì×ØÉ«ÆøÌåÉú³É¡£

¢ÛÈ¡ÉÙÁ¿ÈÜÒº£¬¼ÓÈëÓÃÏõËáËữµÄÂÈ»¯±µÈÜÒº£¬²úÉú°×É«³Áµí¡£

¢ÜÁí½«¢ÛÖеijÁµí¹ýÂ˳ö£¬ÂËÒºÖмÓÈëÏõËáÒøÈÜÒº£¬Éú³É°×É«³Áµí

¢ÝÁíÈ¡Ô­ÈÜÒº£¬ÖðµÎ¼ÓÈëÇâÑõ»¯ÄÆÈÜÒºÖÁ¹ýÁ¿£¬ÏÈ¿´µ½Éú³É³Áµí£¬ËæÖ®¸Ã³Áµí²¿·ÖÈÜ ½â£¬²¢³ÊºìºÖÉ«¡£

¸ù¾ÝÉÏÊöʵÑéÏÖÏóÍƶϣº

£¨1£©ÈÜÒºÖп϶¨´æÔÚµÄÀë×ÓÓР                                ¡£

£¨2£©ÈÜÒºÖп϶¨²»´æÔÚµÄÀë×ÓÓР                              ¡£

£¨3£©ÈÜÒºÖв»ÄÜÈ·¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÓР                        ¡£

£¨4£©¶ÔÉÏÊöʵÑé²Ù×÷×öºÎ¸Ä½ø£¬²ÅÄÜÈ·¶¨£¨3£©ÖеÄÀë×ÓÊÇ·ñ´æÔÚ                   

                                                                            

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010Ä긣½¨Ê¡ÕÄÖÝÈýÖиßÈýÉÏѧÆÚµÚ¶þ´ÎÔ¿¼ÊÔ¾í»¯Ñ§ÊÔÌâ ÌâÐÍ£ºÌî¿ÕÌâ

һƿ³ÎÇå͸Ã÷µÄÈÜÒº£¬¿ÉÄܺ¬ÓÐÏÂÁÐÀë×ÓÖеÄÒ»ÖÖ»ò¼¸ÖÖ£ºFe2+¡¢Fe3+¡¢Ba2+¡¢Al3+¡¢NH4+¡¢SO42-¡¢ HCO3-¡¢NO3-¡¢Cl-È¡ÈÜÒº½øÐÐÈçÏÂʵÑ飺
¢ÙÈÜÒºµÎÔÚÀ¶É«Ê¯ÈïÊÔÖ½ÉÏ£¬ÊÔÖ½³ÊºìÉ«¡£
¢ÚÈ¡ÉÙÁ¿ÈÜҺŨËõºó¼ÓÈëͭƬºÍŨÁòËá¹²ÈÈ£¬Óкì×ØÉ«ÆøÌåÉú³É¡£
¢ÛÈ¡ÉÙÁ¿ÈÜÒº£¬¼ÓÈëÓÃÏõËáËữµÄÂÈ»¯±µÈÜÒº£¬²úÉú°×É«³Áµí¡£
¢ÜÁí½«¢ÛÖеijÁµí¹ýÂ˳ö£¬ÂËÒºÖмÓÈëÏõËáÒøÈÜÒº£¬Éú³É°×É«³Áµí
¢ÝÁíÈ¡Ô­ÈÜÒº£¬ÖðµÎ¼ÓÈëÇâÑõ»¯ÄÆÈÜÒºÖÁ¹ýÁ¿£¬ÏÈ¿´µ½Éú³É³Áµí£¬ËæÖ®¸Ã³Áµí²¿·ÖÈÜ ½â£¬²¢³ÊºìºÖÉ«¡£
¸ù¾ÝÉÏÊöʵÑéÏÖÏóÍƶϣº
£¨1£©ÈÜÒºÖп϶¨´æÔÚµÄÀë×ÓÓР                           ¡£
£¨2£©ÈÜÒºÖп϶¨²»´æÔÚµÄÀë×ÓÓР                             ¡£
£¨3£©ÈÜÒºÖв»ÄÜÈ·¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÓР                       ¡£
£¨4£©¶ÔÉÏÊöʵÑé²Ù×÷×öºÎ¸Ä½ø£¬²ÅÄÜÈ·¶¨£¨3£©ÖеÄÀë×ÓÊÇ·ñ´æÔÚ                   
                                                                           

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010Ä긣½¨Ê¡¸ßÈýÉÏѧÆÚµÚ¶þ´ÎÔ¿¼ÊÔ¾í»¯Ñ§ÊÔÌâ ÌâÐÍ£º×ÛºÏÌâ

һƿ³ÎÇå͸Ã÷µÄÈÜÒº£¬¿ÉÄܺ¬ÓÐÏÂÁÐÀë×ÓÖеÄÒ»ÖÖ»ò¼¸ÖÖ£ºFe2+¡¢Fe3+¡¢Ba2+¡¢Al3+¡¢NH4+¡¢SO42-¡¢ HCO3-¡¢NO3-¡¢Cl-È¡ÈÜÒº½øÐÐÈçÏÂʵÑ飺

¢ÙÈÜÒºµÎÔÚÀ¶É«Ê¯ÈïÊÔÖ½ÉÏ£¬ÊÔÖ½³ÊºìÉ«¡£

¢ÚÈ¡ÉÙÁ¿ÈÜҺŨËõºó¼ÓÈëͭƬºÍŨÁòËá¹²ÈÈ£¬Óкì×ØÉ«ÆøÌåÉú³É¡£

¢ÛÈ¡ÉÙÁ¿ÈÜÒº£¬¼ÓÈëÓÃÏõËáËữµÄÂÈ»¯±µÈÜÒº£¬²úÉú°×É«³Áµí¡£

¢ÜÁí½«¢ÛÖеijÁµí¹ýÂ˳ö£¬ÂËÒºÖмÓÈëÏõËáÒøÈÜÒº£¬Éú³É°×É«³Áµí

¢ÝÁíÈ¡Ô­ÈÜÒº£¬ÖðµÎ¼ÓÈëÇâÑõ»¯ÄÆÈÜÒºÖÁ¹ýÁ¿£¬ÏÈ¿´µ½Éú³É³Áµí£¬ËæÖ®¸Ã³Áµí²¿·ÖÈÜ ½â£¬²¢³ÊºìºÖÉ«¡£

¸ù¾ÝÉÏÊöʵÑéÏÖÏóÍƶϣº

£¨1£©ÈÜÒºÖп϶¨´æÔÚµÄÀë×ÓÓР                             ¡£

£¨2£©ÈÜÒºÖп϶¨²»´æÔÚµÄÀë×ÓÓР                               ¡£

£¨3£©ÈÜÒºÖв»ÄÜÈ·¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÓР                         ¡£

£¨4£©¶ÔÉÏÊöʵÑé²Ù×÷×öºÎ¸Ä½ø£¬²ÅÄÜÈ·¶¨£¨3£©ÖеÄÀë×ÓÊÇ·ñ´æÔÚ                   

                                                                           

 

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸