îÑÌú¿ó£¨Ö÷Òª³É·ÖÊÇFeTiO3£¬îÑËáÑÇÌú£©ÎªÖ÷ÒªÔ­ÁÏÒ±Á¶½ðÊôîѵĹ¤ÒµÉú²úÁ÷³ÌÈçͼËùʾ£®

£¨1£©ÉÏÊöÉú²úÁ÷³ÌÖмÓÈëÌúмµÄÄ¿µÄÊÇ
½«Fe3+»¹Ô­ÎªFe2+
½«Fe3+»¹Ô­ÎªFe2+
£®
£¨2£©¸±²úÆ·ÊÇ
FeSO4?7H2O
FeSO4?7H2O
£®
£¨3£©Ð´³öÓÉTiO2+Ë®½âÉú³ÉH2TiO3µÄÀë×Ó·½³Ìʽ
TiO2++H2OH2TiO3+2H+
TiO2++H2OH2TiO3+2H+
£®¸Ã²½ÖèÖУ¬¼ÓÈȵÄÄ¿µÄÊÇ
´Ù½øTiO2+µÄË®½â
´Ù½øTiO2+µÄË®½â
£®
£¨4£©ÓÉTiO2ת»¯ÎªTiCl4µÄ·½³ÌʽÊÇ£ºTiO2£¨s£©+2Cl2£¨g£©+2C£¨s£©
 ¸ßΠ
.
 
TiCl4£¨g£©+2CO £¨g£©£¬¸Ã·´Ó¦µÄƽºâ³£Êý±í´ïʽK=
c(TiCl4)¡Ác2(CO)
c2(Cl2)
c(TiCl4)¡Ác2(CO)
c2(Cl2)
£®
TiCl4µÄ°Ù·Öº¬Á¿Ëæζȵı仯ÈçͼËùʾ£¬Éý¸ßζÈʱ£¬KÖµ
Ôö´ó
Ôö´ó
£¨Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±»ò¡°²»±ä¡±£©

£¨5£©¼ºÖª£º¢ÙMg £¨s£©+Cl2£¨g£©=MgCl2£¨s£©£»¡÷H=-642kJ?mol-1
¢ÚTi£¨s£©+2Cl2£¨g£©=TiCl4£¨g£©£»¡÷H=-815kJ?mol-1
д³öÓÉTiCl4ºÍþÖÆÈ¡½ðÊôîѵÄÈÈ»¯Ñ§·½³Ìʽ
TiCl4£¨g£©+2Mg£¨s£©=Ti£¨s£©+2MgCl2£¨s£©¡÷H=-469kJ?mol-1
TiCl4£¨g£©+2Mg£¨s£©=Ti£¨s£©+2MgCl2£¨s£©¡÷H=-469kJ?mol-1
£®
·ÖÎö£º£¨1£©Å¨ÁòËá¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬ÓëFe2+·´Ó¦Éú³ÉFe3+£¬¼ÓÈëÌú·Û¿É½«Fe3+»¹Ô­³ÉFe2+£»
£¨2£©¹ýÂ˺óÂËÒºÖк¬ÓÐFeSO4£»
£¨3£©TiO2+µÄË®½âΪÎüÈȹý³Ì£»
£¨4£©¸ù¾Ýƽºâ³£ÊýµÈÓÚÉú³ÉÎïŨ¶ÈÃÝÖ®»ý³ýÒÔ·´Ó¦ÎïŨ¶ÈÃÝÖ®»ý¼ÆË㣻
£¨5£©ÀûÓøÇ˹¶¨ÂɼÆË㣮
½â´ð£º½â£º£¨1£©Å¨ÁòËá¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬ÓëFe2+·´Ó¦Éú³ÉFe3+£¬¼ÓÈëÌú·Û¿É½«Fe3+»¹Ô­³ÉFe2+£¬¹Ê´ð°¸Îª£º½«Fe3+»¹Ô­ÎªFe2+£»
£¨2£©¹ýÂ˺óÂËÒºÖк¬ÓÐFeSO4£¬½á¾§ºó¿ÉµÃµ½FeSO4?7H2O¾§Ì壬¹Ê´ð°¸Îª£ºFeSO4?7H2O£»
£¨3£©TiO2+µÄË®½âΪÎüÈȹý³Ì£¬¼ÓÈÈ´Ù½øË®½âµÄ½øÐУ¬Ë®½â·½³ÌʽΪTiO2++H2OH2TiO3+2H+£¬
¹Ê´ð°¸Îª£ºTiO2++H2OH2TiO3+2H+£»´Ù½øTiO2+µÄË®½â£»
£¨4£©Æ½ºâ³£ÊýµÈÓÚÉú³ÉÎïŨ¶ÈÃÝÖ®»ý³ýÒÔ·´Ó¦ÎïŨ¶ÈÃÝÖ®»ý£¬ÓÉ·½³Ìʽ¿ÉµÃk=
c(TiCl4)¡Ác2(CO)
c2(Cl2)
£¬ÓÉͼÏó¿ÉÖª£¬Éý¸ßζÈTiCl4µÄ°Ù·Öº¬Á¿¼õС£¬ËµÃ÷Éý¸ßζÈƽºâÏòÕý·´Ó¦·½ÏòÒƶ¯£¬Ôòƽºâ³£ÊýÔö´ó£¬
¹Ê´ð°¸Îª£ºk=
c(TiCl4)¡Ác2(CO)
c2(Cl2)
£»Ôö´ó£»
£¨5£©¼ºÖª£º¢ÙMg £¨s£©+Cl2£¨g£©=MgCl2£¨s£©¡÷H=-642kJ?mol-1£¬
¢ÚTi£¨s£©+2Cl2£¨g£©=TiCl4£¨g£©¡÷H=-815kJ?mol-1£¬
ÀûÓøÇ˹¶¨Âɽ«2¡Á¢Ù-¢Ú¿ÉµÃ£ºTiCl4£¨g£©+Mg £¨s£©=Ti£¨s£©+MgCl2£¨s£©£»¡÷H=-469kJ?mol-1£¬
¹Ê´ð°¸Îª£ºTiCl4£¨g£©+Mg £¨s£©=Ti£¨s£©+MgCl2£¨s£©¡÷H=-469kJ?mol-1£®
µãÆÀ£º±¾Ì⿼²é¹¤ÒÕÁ÷³Ì£¬ÌâÄ¿ÄѶÈÖеȣ¬±¾Ìâ×¢Òâ·ÖÎöÁ÷³Ì¸÷·´Ó¦ÎïµÄת»¯£¬ÌâÖп¼²éµã½Ï¶à£¬Ñ§Ï°ÖÐ×¢ÖØÏà¹Ø֪ʶ¡¢·½·¨µÄ»ýÀÛ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º058

ÖйúÎ÷²¿µØÇø×ÔÈ»×ÊÔ´·á¸»£¬ÔÚ¿ó²ú×ÊÔ´ÖУ¬îÑ¡¢Í­¡¢¹¯¡¢Ç¦¡¢Ð¿µÈ30¶àÖÖ¿ó²ú´¢Á¿¾ÓÈ«¹úµÚÒ»£¬ÅÊÖ¦»¨µÄ·¯îÑÌú¿ó¡¢ÔÆÄϵÄÎý¿óµÈÔÚÈ«¹ú¶¼Õ¼Ê®·ÖÖØÒªµÄµØλ£®

(1)·¯îÑÌú¿óµÄÖ÷Òª³É·Ö¿ÉÓû¯Ñ§Ê½À´±íʾ£¬ÆäÖÐVÏÔÕý£«5¼Û£¬TiÏÔ£«4¼Û£¬FeÏÔ£«¼Û£¬ÔòxµÄÖµÊÇ_______(Óú¬a¡¢b¡¢cµÄ´úÊýʽ±íʾ)£®

(2)¾­·ÖÀë·¯îÑÌú¿óʯ×îÖտɵᢵÈÎïÖÊ£¬ÊÔд³ö£¬¸úAl·Û·´Ó¦µÄ»¯Ñ§·½³Ìʽ_____________£®

(3)ÒÑÖª£®Ä³Ñ§ÉúÐËȤС×éÉè¼ÆÒ»Ì×ʵÑé×°ÖÃÀûÓÃÉÏÊö·´Ó¦ÒÔÖƵã¬×°ÖÃÖÐβÆø´¦Àí²¿·ÖÈçͼ¢ñËùʾ£¬Æ¿ÖÐÓ¦¼ÓÈë_____________ÈÜÒº£¬ÔÚµ¼¹Ü¿ÚB´¦Ó¦______________£®

(4)×°ÖÃͼ¢ò¿ÉÓÃÓÚÊÕ¼¯ÏÂÁÐÆøÌåÖеÄ_________________(Ìî×Öĸ)£®

A£®CO

B£®HCl

C£®

D£®

E£®

F£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÎïÀí½ÌÑÐÊÒ ÌâÐÍ£º058

ÖйúÎ÷²¿µØÇø×ÔÈ»×ÊÔ´·á¸»£¬ÔÚ¿ó²ú×ÊÔ´ÖУ¬îÑ¡¢Í­¡¢¹¯¡¢Ç¦¡¢Ð¿µÈ30¶àÖÖ¿ó²ú´¢Á¿¾ÓÈ«¹úµÚÒ»£¬ÅÊÖ¦»¨µÄ·¯îÑÌú¿ó¡¢ÔÆÄϵÄÎý¿óµÈÔÚÈ«¹ú¶¼Õ¼Ê®·ÖÖØÒªµÄµØλ£®

(1)·¯îÑÌú¿óµÄÖ÷Òª³É·Ö¿ÉÓû¯Ñ§Ê½À´±íʾ£¬ÆäÖÐVÏÔÕý£«5¼Û£¬TiÏÔ£«4¼Û£¬FeÏÔ£«¼Û£¬ÔòxµÄÖµÊÇ_______(Óú¬a¡¢b¡¢cµÄ´úÊýʽ±íʾ)£®

(2)¾­·ÖÀë·¯îÑÌú¿óʯ×îÖտɵᢵÈÎïÖÊ£¬ÊÔд³ö£¬¸úAl·Û·´Ó¦µÄ»¯Ñ§·½³Ìʽ_____________£®

(3)ÒÑÖª£®Ä³Ñ§ÉúÐËȤС×éÉè¼ÆÒ»Ì×ʵÑé×°ÖÃÀûÓÃÉÏÊö·´Ó¦ÒÔÖƵã¬×°ÖÃÖÐβÆø´¦Àí²¿·ÖÈçͼ¢ñËùʾ£¬Æ¿ÖÐÓ¦¼ÓÈë_____________ÈÜÒº£¬ÔÚµ¼¹Ü¿ÚB´¦Ó¦______________£®

(4)×°ÖÃͼ¢ò¿ÉÓÃÓÚÊÕ¼¯ÏÂÁÐÆøÌåÖеÄ_________________(Ìî×Öĸ)£®

A£®CO

B£®HCl

C£®

D£®

E£®

F£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸