¸õ»¯Ñ§·á¸»¶à²Ê£¬ÓÉÓÚ¸õ¹âÔó¶ÈºÃ£¬³£½«¸õ¶ÆÔÚÆäËû½ðÊô±íÃ棬ͬÌú¡¢Äø×é³É¸÷ÖÖÐÔÄܵIJ»Ðâ¸Ö¡£K2Cr2O7ºÍCrO3´óÁ¿ÓÃÓÚ÷·¸ï¡¢Ó¡È¾¡¢ÑÕÁÏ¡¢µç¶ÆµÈ¹¤ÒµÖУ¬Êǹ¤ÒµÉÏÔì³É¸õÎÛȾµÄÖ÷ÒªÔ­Òò¡£½üÆÚ±©¹âµÄ¡°¶¾½ºÄÒ¡±Ê¼þÖУ¬¾ÍÊÇÒòΪÓù¤ÒµÆ¤¸ïµÄϽÅÁÏ»òÆÆƤЬµÈΪԭÁÏÖƳɵĹ¤ÒµÃ÷½º±»Ã°³ä³ÉʳÓÃÃ÷½ºÖƳɽºÄÒ£¬Ôì³É½ºÄÒÄڵĸõÑÏÖس¬±ê¡£

£¨1£©CrO3µÄÈÈÎȶ¨ÐԽϲ¼ÓÈÈʱÖ𲽷ֽ⣬Æä¹ÌÌå²ÐÁôÂÊËæζȵı仯ÈçͼËùʾ¡£ 

   ¢ÙA µãʱʣÓà¹ÌÌåµÄ³É·ÖÊÇ        £¨Ìѧʽ£©¡£

   ¢Ú´Ó¿ªÊ¼¼ÓÈȵ½ 750K ʱ×Ü·´Ó¦·½³ÌʽΪ                              ¡£

£¨2£©Cr(¢ö)Ö÷ÒªÒÔCrO42£­ºÍCr2O72£­ÐÎ̬´æÔÚ£¬ÔÚËáÐÔÌõ¼þϾßÓкÜÇ¿µÄÑõ»¯ÐÔ£¬ËüÃÇÔÚÈÜÒºÖдæÔÚÈçÏÂת»¯£ºks5u

CrO42£­(»ÆÉ«)+2H+  Cr2O72£­(³ÈÉ«£©+H2O£»K=4.2¡Á1014¡£ÈôҪʹÈÜÒºÓÉ»ÆÉ«±ä³ÈÉ«£¬ÔòÓ¦²ÉÈ¡µÄ´ëÊ©ÊÇ              ¡£

     A£®¼ÓNaOH       B£®¼ÓÑÎËá       C£®¼ÓÁòËá       D£®¼ÓAgNO3

£¨3£©¹¤Òµ·ÏË®Öг£º¬ÓÐÒ»¶¨Á¿µÄCr(¢ö)£¬¶¾ÐԽϴó£¬ËüÃÇ»á¶ÔÈËÀ༰Éú̬ϵͳ²úÉúºÜ´óË𺦡£¾»»¯´¦Àí·½·¨Ö®Ò»Êǽ«º¬Cr2O72£­µÄ·ÏË®·ÅÈëµç½â²ÛÄÚ£¬ÓÃÌú×÷Ñô¼«£¬¼ÓÈëÊÊÁ¿µÄNaCl½øÐеç½â£ºÑô¼«ÇøÉú³ÉµÄFe2£«ºÍCr2O72£­·¢Éú·´Ó¦£¬Éú³ÉµÄFe3£«ºÍCr3£«ÔÚÒõ¼«ÇøÓëOH£­½áºÏÉú³ÉFe(OH)3ºÍCr(OH)3³ÁµíÒÔ³ýÈ¥[ÒÑÖªKspFe(OH)3£½4.0¡Á10£­38£¬KspCr(OH)3£½6.0¡Á10£­31]¡£

  ¢Ùµç½â¹ý³ÌÖÐ NaCl µÄ×÷ÓÃÊÇ                                ¡£ks5u

  ¢Úд³öÑô¼«µÄµç¼«·´Ó¦Ê½                                    ¡£ 

  ¢Ûд³öFe2£«ºÍCr2O72£­·¢Éú·´Ó¦Éú³ÉFe3£«ºÍCr3£«µÄÀë×Ó·´Ó¦·½³Ìʽ                   ¡£

  ¢ÜÒÑÖªµç½âºóµÄÈÜÒºÖÐc(Fe3£«)=2.0¡Á10£­13 mol¡¤L£­1£¬ÔòÈÜÒºÖÐc(Cr3£«)Ϊ   mol¡¤L£­1¡£

£¨1£©¢ÙCr3O8 £¨»òCrO2.67) £¨2·Ö£©¡¡ ¢Ú 4CrO32Cr2O3£«3O2¡ü£¨2·Ö£©

£¨2£©C £¨2·Ö£©

(3) ¢Ù ÔöÇ¿ÈÜÒºµÄµ¼µçÐÔ £¨1·Ö£© ¡¡¢ÚFe-2e£­=Fe2+¡¡¡¡ £¨1·Ö£©

¡¡¡¡ ¢Û6Fe2++Cr2O72-+14H+=6Fe3++2Cr3++7H2O £¨2·Ö£© ¢Ü3.0¡Á10£­6 ¡¡£¨2·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨2012?õ·ÁêÊÐÄ£Ä⣩¸õ»¯Ñ§·á¸»¶à²Ê£¬ÓÉÓÚ¸õ¹âÔó¶ÈºÃ£¬³£½«¸õ¶ÆÔÚÆäËû½ðÊô±íÃ棬ͬÌú¡¢Äø×é³É¸÷ÖÖÐÔÄܵIJ»Ðâ¸Ö£¬CrO3´óÁ¿µØÓÃÓÚµç¶Æ¹¤ÒµÖУ®
£¨1£©CrO3¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬Óöµ½ÓлúÎÈç¾Æ¾«£©Ê±£¬ÃÍÁÒ·´Ó¦ÒÔÖÁ×Å»ð£¬ÈôÔÚÁòËáÈÜÒºÖÐÒÒ´¼±»Ñõ»¯³ÉÒÒËᣬCrO3±»»¹Ô­³ÉÂÌÉ«µÄÁòËá¸õ[Cr2£¨SO4£©3]£®Ôò¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ
4CrO3+3CH3CH2OH+12H+¨T4Cr3++3CH3COOH+9H2O
4CrO3+3CH3CH2OH+12H+¨T4Cr3++3CH3COOH+9H2O
£®
£¨2£©´æÔÚƽºâ£º2CrO42¡¥£¨»ÆÉ«£©+2H+?Cr2O72¡¥£¨³ÈÉ«£©+H2O
¢ÙÈôƽºâÌåϵµÄpH=2£¬ÔòÈÜÒºÏÔ
³ÈÉ«
³ÈÉ«
É«£®
¢ÚÄÜ˵Ã÷¸Ã·´Ó¦´ïƽºâ״̬µÄÊÇ
bc
bc
£®
a£®Cr2O72¡¥ºÍCrO42¡¥µÄŨ¶ÈÏàͬ
b£®2VÕý£¨Cr2O72¡¥£©=VÄ棨CrO42¡¥£©
c£®ÈÜÒºµÄÑÕÉ«²»±ä
£¨3£©ÔÚͼװÖÃÖУ¬¹Û²ìµ½Í¼1×°ÖÃÍ­µç¼«ÉϲúÉú´óÁ¿µÄÎÞÉ«ÆøÅÝ£¬¶øͼ2×°ÖÃÖÐÍ­µç¼«ÉÏÎÞÆøÌå²úÉú£¬¸õµç¼«ÉϲúÉú´óÁ¿ÓÐÉ«ÆøÌ壮ÓÉͼ1Öª½ðÊô¸õµÄ»î¶¯ÐÔ±ÈÍ­
Ç¿
Ç¿
£¨ÌîÇ¿£¬Èõ£©£¬Í¼2×°ÖÃÖиõµç¼«µÄµç¼«·´Ó¦Ê½£º
NO3-+4H++3e¡¥=NO¡ü+2H2O
NO3-+4H++3e¡¥=NO¡ü+2H2O
£®

£¨4£©CrO3ºÍK2Cr2O7¾ùÒ×ÈÜÓÚË®£¬ÕâÊǹ¤ÒµÉÏÔì³É¸õÎÛȾµÄÖ÷ÒªÔ­Òò£®¾»»¯´¦Àí·½·¨Ö®Ò»Êǽ«º¬+6¼ÛCrµÄ·ÏË®·ÅÈëµç½â²ÛÄÚ£¬ÓÃÌú×÷Ñô¼«£¬¼ÓÈëÊÊÁ¿µÄNaCl½øÐеç½â£ºÑô¼«ÇøÉú³ÉµÄFe2+ºÍCr2O72¡¥·¢Éú·´Ó¦£¬Éú³ÉµÄFe3+ºÍCr3+ÔÚÒõ¼«ÇøÓëOH¡¥½áºÏÉú³ÉFe£¨OH£©3ºÍCr£¨OH£©3³Áµí³ýÈ¥[ÒÑÖªKspFe£¨OH£©3=4.0¡Á10-38£¬KspCr£¨OH£©3=6.0¡Á10-31]£®
¢Ùµç½â¹ý³ÌÖÐNaClµÄ×÷ÓÃÊÇ
ÔöÇ¿ÈÜÒºµÄµ¼µçÐÔ
ÔöÇ¿ÈÜÒºµÄµ¼µçÐÔ
£®
¢ÚÒÑÖªµç½âºóµÄÈÜÒºÖÐc£¨Fe3+£©Îª2.0¡Á10-13mol/L£¬ÔòÈÜÒºÖÐc£¨Cr3+£©Îª£º
3.0¡Á10¡¥6
3.0¡Á10¡¥6
mol/L£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøº¬¸õ»¯ºÏÎïÓж¾£¬¶ÔÈËÐóΣº¦ºÜ´ó£®Òò´Ëº¬¸õ·ÏË®±ØÐë½øÐд¦Àí²ÅÄÜÅÅ·Å£®
ÒÑÖª£º¾«Ó¢¼Ò½ÌÍø
£¨1£©ÔÚº¬+6¼Û¸õµÄ·ÏË®ÖмÓÈëÒ»¶¨Á¿µÄÁòËáºÍÁòËáÑÇÌú£¬Ê¹+6¼Û¸õ»¹Ô­³É+3¼Û¸õ£»ÔÙµ÷½ÚÈÜÒºpHÔÚ6¡«8Ö®¼ä£¬Ê¹Fe3+ºÍCr3+ת»¯ÎªFe£¨OH£©3¡¢Cr£¨OH£©3³Áµí¶ø³ýÈ¥£®
¢Ùд³öCr2O
 
2-
7
ÓëFeSO4ÈÜÒºÔÚËáÐÔÌõ¼þÏ·´Ó¦µÄÀë×Ó·½³Ìʽ£º
 
£®
¢ÚÓÃÀë×Ó·½³Ìʽ±íʾÈÜÒºpH²»Äܳ¬¹ý10µÄÔ­Òò£º
 
£®
£¨2£©½«º¬+6¼Û¸õµÄ·ÏË®·ÅÈëµç½â²ÛÄÚ£¬ÓÃÌú×÷Ñô¼«£¬¼ÓÈëÊÊÁ¿µÄÂÈ»¯ÄƽøÐеç½â£®Ñô¼«ÇøÉú³ÉµÄFe2+ºÍCr2O
 
2-
7
·¢Éú·´Ó¦£¬Éú³ÉµÄFe3+ºÍCr3+ÔÚÒõ¼«ÇøÓëOH-½áºÏ³ÉÇâÑõ»¯Îï³Áµí¶ø³ýÈ¥£®
¢Ùд³öÒõ¼«µÄµç¼«·´Ó¦Ê½£º
 
£®
¢Úµç½â·¨ÖмÓÈëÂÈ»¯ÄƵÄ×÷ÓÃÊÇ
 
£®
£¨3£©¸õ»¯Ñ§·á¸»¶à²Ê£¬ÓÉÓÚ¸õ¹âÔó¶ÈºÃ£¬³£½«¸õ¶ÆÔÚÆäËû½ðÊô±íÃ棬ͬÌú¡¢Äø×é³É¸÷ÖÖÐÔÄܵIJ»Ðâ¸Ö£¬CrO3´óÁ¿µØÓÃÓÚµç¶Æ¹¤ÒµÖУ®
¢ÙCrO3¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬Óöµ½ÓлúÎÈç¾Æ¾«£©Ê±£¬ÃÍÁÒ·´Ó¦ÒÔÖÁ×Å»ð£¬Èô¸Ã¹ý³ÌÖÐÒÒ´¼±»Ñõ»¯³ÉÒÒËᣬCrO3±»»¹Ô­³ÉÂÌÉ«µÄÁòËá¸õ[Cr2£¨SO4£©3]£®Ôò¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
 
£®
¢ÚCrO3µÄÈÈÎȶ¨ÐԽϲ¼ÓÈÈʱÖ𲽷ֽ⣬Æä¹ÌÌå²ÐÁôÂÊËæζȵı仯ÈçͼËùʾ£¬ÔòBµãʱʣÓà¹ÌÌåµÄ³É·ÖÊÇ
 
£¨Ìѧʽ£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍø¸õ»¯Ñ§·á¸»¶à²Ê£¬ÓÉÓÚ¸õ¹âÔó¶ÈºÃ£¬³£½«¸õ¶ÆÔÚÆäËû½ðÊô±íÃ棬ͬÌú¡¢Äø×é³É¸÷ÖÖÐÔÄܵIJ»Ðâ¸Ö£¬CrO3´óÁ¿µØÓÃÓÚµç¶Æ¹¤ÒµÖУ®
£¨1£©CrO3¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬Óöµ½ÓлúÎÈç¾Æ¾«£©Ê±£¬ÃÍÁÒ·´Ó¦ÒÔÖÁ×Å»ð£¬Èô¸Ã¹ý³ÌÖÐÒÒ´¼±»Ñõ»¯³ÉÒÒËᣬCrO3±»»¹Ô­³ÉÂÌÉ«µÄÁòËá¸õ[Cr2£¨SO4£©3]£®Ôò¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
 
£®
£¨2£©CrO3µÄÈÈÎȶ¨ÐԽϲ¼ÓÈÈʱÖ𲽷ֽ⣬Æä¹ÌÌå²ÐÁôÂÊËæζȵı仯ÈçͼËùʾ£®
¢ÙA µãʱʣÓà¹ÌÌåµÄ³É·ÖÊÇ
 
£¨Ìѧʽ£©£®
¢Ú´Ó¿ªÊ¼¼ÓÈȵ½ 750K Ê±×Ü·´Ó¦·½³ÌʽΪ
 
_£®
£¨3£©CrO3ºÍ K2Cr2O7¾ùÒ×ÈÜÓÚË®£¬ÕâÊǹ¤ÒµÉÏÔì³É¸õÎÛȾµÄÖ÷ÒªÔ­Òò£®¾»»¯´¦Àí·½·¨Ö®Ò»Êǽ«º¬+6¼Û Cr µÄ·ÏË®·ÅÈëµç½â²ÛÄÚ£¬ÓÃÌú×÷Ñô¼«£¬¼ÓÈëÊÊÁ¿µÄNaCl½øÐеç½â£ºÑô¼«ÇøÉú³ÉµÄFe2+ºÍCr2O72-·¢Éú·´Ó¦£¬Éú³ÉµÄFe3+ºÍCr3+ÔÚÒõ¼«ÇøÓëOH-½áºÏÉú³É Fe£¨OH£©3 ºÍCr£¨OH£©3³Áµí³ýÈ¥[ÒÑÖª KspFe£¨OH£©3=4.0¡Á10-38£¬KspCr£¨OH£©3=6.0¡Á10-31]£®
¢Ùµç½â¹ý³ÌÖРNaCl µÄ×÷ÓÃÊÇ
 
£®
¢ÚÒÑÖªµç½âºóµÄÈÜÒºÖÐc£¨Fe3+£©Îª2.0¡Á10-13 mol?L-1£¬ÔòÈÜÒºÖÐc£¨Cr3+£©Îª
 
mol?L-1£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê½­ËÕÊ¡¸ßÈýÏÂѧÆÚÖÊÁ¿¼ì²â£¨Èý£©»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨11·Ö£©¸õ»¯Ñ§·á¸»¶à²Ê£¬ÓÉÓÚ¸õ¹âÔó¶ÈºÃ£¬³£½«¸õ¶ÆÔÚÆäËû½ðÊô±íÃ棬ͬÌú¡¢Äø×é³É¸÷ÖÖÐÔÄܵIJ»Ðâ¸Ö£¬CrO3´óÁ¿µØÓÃÓÚµç¶Æ¹¤ÒµÖС£

£¨1£©CrO3¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬Óöµ½ÓлúÎÈç¾Æ¾«£©Ê±£¬ÃÍÁÒ·´Ó¦ÒÔÖÁ×Å»ð£¬Èô¸Ã¹ý³ÌÖÐÒÒ´¼±»Ñõ»¯³ÉÒÒËᣬCrO3±»»¹Ô­³ÉÂÌÉ«µÄÁòËá¸õ[Cr2(SO4)3]¡£Ôò¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º

____________                                           ¡£

£¨2£©CrO3µÄÈÈÎȶ¨ÐԽϲ¼ÓÈÈʱÖ𲽷ֽ⣬Æä¹ÌÌå²ÐÁôÂÊËæζȵı仯ÈçÏÂͼËùʾ¡£

¢ÙA µãʱʣÓà¹ÌÌåµÄ³É·ÖÊÇ_________          £¨Ìѧʽ£©¡£

¢Ú´Ó¿ªÊ¼¼ÓÈȵ½ 750K ʱ×Ü·´Ó¦·½³ÌʽΪ______________________          _¡£

£¨3£©CrO3ºÍ K2Cr2O7¾ùÒ×ÈÜÓÚË®£¬ÕâÊǹ¤ÒµÉÏÔì³É¸õÎÛȾµÄÖ÷ÒªÔ­Òò¡£¾»»¯´¦Àí·½·¨Ö®Ò»Êǽ«º¬£«6¼Û Cr µÄ·ÏË®·ÅÈëµç½â²ÛÄÚ£¬ÓÃÌú×÷Ñô¼«£¬¼ÓÈëÊÊÁ¿µÄNaCl½øÐеç½â£ºÑô¼«ÇøÉú³ÉµÄFe2+ºÍCr2O72£­·¢Éú·´Ó¦£¬Éú³ÉµÄFe3+ºÍCr3+ÔÚÒõ¼«ÇøÓëOH£­½áºÏÉú³É Fe(OH)3 ºÍCr(OH)3³Áµí³ýÈ¥[ÒÑÖª KspFe(OH)3£½4.0¡Á10£­38£¬KspCr(OH)3£½6.0¡Á10£­31]¡£

¢Ùµç½â¹ý³ÌÖÐ NaCl µÄ×÷ÓÃÊÇ__________________________¡£

¢ÚÒÑÖªµç½âºóµÄÈÜÒºÖÐc(Fe3+)Ϊ2.0¡Á10£­13 mol¡¤L£­1£¬ÔòÈÜÒºÖÐc(Cr3+)Ϊ       mol¡¤L£­1¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêÕã½­Ê¡¸ßÈýÏÂѧÆÚµÚÒ»´ÎͳÁ·»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

(16·Ö)£®¸õ»¯Ñ§·á¸»¶à²Ê£¬ÓÉÓÚ¸õ¹âÔó¶ÈºÃ£¬³£½«¸õ¶ÆÔÚÆäËû½ðÊô±íÃ棬ͬÌú¡¢Äø×é³É¸÷ÖÖÐÔÄܵIJ»Ðâ¸Ö£¬CrO3´óÁ¿µØÓÃÓÚµç¶Æ¹¤ÒµÖС£

£¨1£©ÔÚÏÂͼװÖÃÖУ¬¹Û²ìµ½Í¼1×°ÖÃÍ­µç¼«ÉϲúÉú´óÁ¿µÄÎÞÉ«ÆøÅÝ£¬¶øͼ 2×°ÖÃÖÐÍ­µç¼«ÉÏÎÞÆøÌå²úÉú£¬¸õµç¼«ÉϲúÉú´óÁ¿ÓÐÉ«ÆøÌå¡£ÓÉͼ 1 Öª½ðÊô¸õµÄ»î¶¯ÐÔ±ÈÍ­_____(ÌîÇ¿£¬Èõ)£¬Í¼ 2×°ÖÃÖиõµç¼«µÄµç¼«·´Ó¦Ê½             

£¨2£©CrO3¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬Óöµ½ÓлúÎÈç¾Æ¾«£©Ê±£¬ÃÍÁÒ·´Ó¦ÒÔÖÁ×Å»ð£¬Èô¸Ã¹ý³ÌÖÐÒÒ´¼±»Ñõ»¯³ÉÒÒËᣬ CrO3±»»¹Ô­³ÉÂÌÉ«µÄÁòËá¸õ[Cr2(SO4)3]¡£Ôò¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____________________________________________________________¡£

 (3)´æÔÚƽºâ£º2CrO42¡ª£¨»ÆÉ«£©+2H+Cr2O72¡ª£¨³ÈÉ«£©+H2O

¢ÙÈôƽºâÌåϵµÄpH=2£¬ÔòÈÜÒºÏÔ            É«.

¢ÚÄÜ˵Ã÷µÚ¢Ù²½·´Ó¦´ïƽºâ״̬µÄÊÇ             ¡£

a£®Cr2O72¡ªºÍCrO42¡ªµÄŨ¶ÈÏàͬ  b£®2v (Cr2O72¡ª) =v (CrO42¡ª)   c£®ÈÜÒºµÄÑÕÉ«²»±ä

£¨4£©CrO3ºÍ K2Cr2O7¾ùÒ×ÈÜÓÚË®£¬ÕâÊǹ¤ÒµÉÏÔì³É¸õÎÛȾµÄÖ÷ÒªÔ­Òò¡£¾»»¯´¦Àí·½·¨Ö®Ò»Êǽ«º¬£«6¼Û Cr µÄ·ÏË®·ÅÈëµç½â²ÛÄÚ£¬ÓÃÌú×÷Ñô¼«£¬¼ÓÈëÊÊÁ¿µÄNaCl½øÐеç½â£ºÑô¼«ÇøÉú³ÉµÄFe2+ºÍCr2O72£­·¢Éú·´Ó¦£¬Éú³ÉµÄFe3+ºÍCr3+ÔÚÒõ¼«ÇøÓëOH£­½áºÏÉú³É Fe(OH)3 ºÍCr(OH)3³Áµí³ýÈ¥[ÒÑÖª KspFe(OH)3£½4.0¡Á10-38£¬KspCr(OH)3£½6.0¡Á10-31]¡£

¢Ùµç½â¹ý³ÌÖÐ NaCl µÄ×÷ÓÃÊÇ__________________________¡£

¢ÚÒÑÖªµç½âºóµÄÈÜÒºÖÐc(Fe3+)Ϊ2.0¡Á10£­13 mol¡¤L1£¬ÔòÈÜÒºÖÐc(Cr3+)Ϊ____ mol¡¤L-1¡£

£¨5£©CrO3µÄÈÈÎȶ¨ÐԽϲ¼ÓÈÈʱÖ𲽷ֽ⣬Æä¹ÌÌå²ÐÁôÂÊËæζȵı仯ÈçÏÂͼËùʾ¡£

´Ó¿ªÊ¼¼ÓÈȵ½ 750K ʱ×Ü·´Ó¦·½³ÌʽΪ_______________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸