¼î´æÔÚÏ£¬Â±´úÌþÓë´¼·´Ó¦Éú³ÉÃÑ£¨R-O-R@^@^@£©£º
R£­X£«R@^@^@OHR£­O£­R@^@^@£«HX
»¯ºÏÎïA¾­ÏÂÁÐËIJ½·´Ó¦¿ÉµÃµ½³£ÓÃÈܼÁËÄÇâ߻ૣ¬·´Ó¦¿òͼÈçÏÂ

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©1mol AºÍ1mol H2ÔÚÒ»¶¨Ìõ¼þÏÂÇ¡ºÃ·´Ó¦£¬Éú³É±¥ºÍÒ»Ôª´¼Y£¬YÖÐ̼ԪËصÄÖÊÁ¿·ÖÊýԼΪ65%£¬ÔòYµÄ·Ö×ÓʽΪ________¡£
£¨2£©µÚ¢Ù¢Ú²½·´Ó¦ÀàÐÍ·Ö±ðΪ¢Ù_______£¬¢Ú_______¡£
£¨3£©»¯ºÏÎïB¾ßÓеĻ¯Ñ§ÐÔÖÊ£¨Ìîд×Öĸ´úºÅ£©ÊÇ_______¡£
a£®¿É·¢ÉúÑõ»¯·´Ó¦
b£®Ç¿Ëá»òÇ¿¼îÌõ¼þϾù¿É·¢ÉúÏûÈ¥·´Ó¦
c£®¿É·¢Éúõ¥»¯·´Ó¦
d£®´ß»¯Ìõ¼þÏ¿ɷ¢Éú¼Ó¾Û·´Ó¦
£¨4£©Ð´³öC¡¢DºÍEµÄ½á¹¹¼òʽ£ºC_______¡¢D_______ºÍE_______¡£
£¨5£©Ð´³ö»¯ºÏÎïCÓëNaOHË®ÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º______________¡£
£¨6£©Ð´³öËÄÇâß»à«Á´×´ÃÑÀàµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º______________¡£
£¨1£©C4H10O
£¨2£©¢Ù¼Ó³É£»¢ÚÈ¡³É
£¨3£©abc
£¨4£©C£º£»D£»E£º
£¨5£©£¨£©
£¨6£©CH2£½CHOCH2CH3¡¢CH2£½C(CH3)OCH3¡¢CH2£½CHCH2OCH3¡¢CH3CH£½CHOCH3
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

¢ñ£º¼î´æÔÚÏ£¬Â±´úÌþÓë´¼·´Ó¦Éú³ÉÃÑ£¨R-O-R¡ä£©£ºR-X+R¡äOH
KOH/ÊÒÎÂ
R-O-R¡ä+HX»¯ºÏÎïA¾­ÏÂÁÐËIJ½·´Ó¦¿ÉµÃµ½³£ÓÃÈܼÁËÄÇâ ß»à«£¬·´Ó¦¿òͼÈçͼһËùʾ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©1mol AºÍ1mol H2ÔÚÒ»¶¨Ìõ¼þÏÂÇ¡ºÃ·´Ó¦£¬Éú³É±¥ºÍÒ»Ôª´¼Y£¬YÖÐ̼ԪËصÄÖÊÁ¿·ÖÊýԼΪ65%£¬ÔòYµÄ·Ö×ÓʽΪ
C4H10O
C4H10O
£®A·Ö×ÓÖÐËùº¬¹ÙÄÜÍŵÄÃû³ÆÊÇ
ôÇ»ù¡¢Ì¼Ì¼Ë«½¡
ôÇ»ù¡¢Ì¼Ì¼Ë«½¡
£®AµÄ½á¹¹¼òʽΪ
CH2=CHCH2CH2OH
CH2=CHCH2CH2OH
£®
£¨2£©µÚ¢Ù¢Ú²½·´Ó¦ÀàÐÍ·Ö±ðΪ¢Ù
¼Ó³É·´Ó¦
¼Ó³É·´Ó¦
£¬¢Ú
È¡´ú·´Ó¦
È¡´ú·´Ó¦
£®
£¨3£©»¯ºÏÎïB¾ßÓеĻ¯Ñ§ÐÔÖÊ£¨Ìîд×Öĸ´úºÅ£©ÊÇ
abc
abc
£®
a£®¿É·¢ÉúÑõ»¯·´Ó¦    b£®Ç¿Ëá»òÇ¿¼îÌõ¼þϾù¿É·¢ÉúÏûÈ¥·´Ó¦
c£®¿É·¢Éúõ¥»¯·´Ó¦    d£®´ß»¯Ìõ¼þÏ¿ɷ¢Éú¼Ó¾Û·´Ó¦
£¨4£©Ð´³öC¡¢DºÍEµÄ½á¹¹¼òʽ£ºC
¡¢D
¡¢E
£®
£¨5£©Ð´³ö»¯ºÏÎïCÓëNaOHË®ÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
+NaOH
Ë®
+NaBr
+NaOH
Ë®
+NaBr
£®
£¨6£©Ð´³öËÄÇâß»à«Á´×´ÃÑÀàµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º
CH2=CHOCH2CH3¡¢CH2=CHCH2OCH3¡¢CH3CH=CHOCH3¡¢CH2=C£¨CH3£©OCH3
CH2=CHOCH2CH3¡¢CH2=CHCH2OCH3¡¢CH3CH=CHOCH3¡¢CH2=C£¨CH3£©OCH3
£®
¢ò£ºÄ³ÌþÀ໯ºÏÎïAµÄÖÊÆ×ͼ±íÃ÷ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª84£¬ºìÍâ¹âÆ×±íÃ÷·Ö×ÓÖк¬ÓÐ̼̼˫¼ü£¬ºË´Å¹²ÕñÇâÆ×±íÃ÷·Ö×ÓÖÐÖ»ÓÐÒ»ÖÖÀàÐ͵ÄÇ⣮
£¨1£©AµÄ½á¹¹¼òʽΪ
£¨CH3£©2C=C£¨CH3£©2
£¨CH3£©2C=C£¨CH3£©2
£»
£¨2£©AÖÐ̼ԭ×ÓÊÇ·ñ¶¼´¦ÓÚͬһƽÃ棿
ÊÇ
ÊÇ
£¨Ìî¡°ÊÇ¡±»ò¡°²»ÊÇ¡±£©£»
£¨3£©ÔÚͼ¶þÖУ¬D1¡¢D2»¥ÎªÍ¬·ÖÒì¹¹Ì壬E1¡¢E2»¥ÎªÍ¬·ÖÒì¹¹Ì壮
·´Ó¦¢ÚµÄ»¯Ñ§·½³ÌʽΪ
£¨CH3£©2C£¨Cl£©C£¨Cl£©£¨CH3£©2+2NaOH
´¼
¡÷
CH2=C£¨CH3£©-C£¨CH3£©=CH2+2NaCl+2H2O
£¨CH3£©2C£¨Cl£©C£¨Cl£©£¨CH3£©2+2NaOH
´¼
¡÷
CH2=C£¨CH3£©-C£¨CH3£©=CH2+2NaCl+2H2O
£»C µÄ»¯Ñ§Ãû³ÆÊÇ
2£¬3-¶þ¼×»ù-1£¬3-¶¡¶þÏ©
2£¬3-¶þ¼×»ù-1£¬3-¶¡¶þÏ©
£»E2µÄ½á¹¹¼òʽÊÇ
HOCH2C£¨CH3£©=C£¨CH3£©CH2OH
HOCH2C£¨CH3£©=C£¨CH3£©CH2OH
£»¢Ü¡¢¢ÞµÄ·´Ó¦ÀàÐÍÒÀ´ÎÊÇ
¼Ó³É·´Ó¦
¼Ó³É·´Ó¦
£»
È¡´ú·´Ó¦
È¡´ú·´Ó¦
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¼î´æÔÚÏ£¬Â±´úÌþÓë´¼·´Ó¦Éú³ÉÃÑ(R¡ªO¡ªR¡ä)£º

»¯ºÏÎïA¾­ÏÂÁÐËIJ½·´Ó¦¿ÉµÃµ½³£ÓÃÈܼÁËÄÇâ߻ૣ¬·´Ó¦¿òͼÈçÏ£º

ÇëÍê³ÉÏÂÁÐÎÊÌ⣺

(1)1 mol AºÍ1 mol H2ÔÚÒ»¶¨Ìõ¼þÏÂÇ¡ºÃ·´Ó¦£¬Éú³É±¥ºÍÒ»Ôª´¼Y£¬YÖÐ̼ԪËصÄÖÊÁ¿·ÖÊýԼΪ65%£¬ÔòYµÄ·Ö×ÓʽΪ____________£¬A·Ö×ÓÖÐËùº¬¹ÙÄÜÍŵÄÃû³ÆÊÇ____________£¬AµÄ½á¹¹¼òʽΪ____________¡£

(2)µÚ¢Ù¢Ú²½·´Ó¦ÀàÐÍ·Ö±ðΪ£º¢Ù______________________£¬¢Ú______________________¡£

(3)»¯ºÏÎïB¾ßÓеĻ¯Ñ§ÐÔÖÊ(Ìîд×Öĸ´úºÅ)ÊÇ____________¡£

a.¿É·¢ÉúÑõ»¯·´Ó¦                             b.Ç¿Ëá»òÇ¿¼îÌõ¼þϾù¿É·¢ÉúÏûÈ¥·´Ó¦

c.¿É·¢Éúõ¥»¯·´Ó¦                             d.´ß»¯Ìõ¼þÏ¿ɷ¢Éú¼Ó¾Û·´Ó¦

(4)д³öC¡¢DºÍEµÄ½á¹¹¼òʽ£ºC_______________¡¢DºÍE_______________¡£

(5)д³ö»¯ºÏÎïCÓëNaOHË®ÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_____________________________¡£

(6)д³öËÄÇâß»à«Á´×´ÃÑÀàµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º__________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¼î´æÔÚÏ£¬Â±´úÌþÓë´¼·´Ó¦Éú³ÉÃÑ(R¡ªO¡ªR¡ä)£»

R¡ªX+R¡äOHR¡ªO¡ªR¡ä+HX

»¯ºÏÎïA¾­ÏÂÁÐËIJ½·´Ó¦¿ÉµÃµ½³£ÓÃÈܼÁËÄÇâ߻ૣ¬·´Ó¦¿òͼÈçͼ1-4-27

ͼ1-4-27

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)1 mol AºÍ1 mol H2ÔÚÒ»¶¨Ìõ¼þÏÂÇ¡ºÃ·´Ó¦£¬Éú³É±¥ºÍÒ»Ôª´¼Y£¬YÖÐ̼ԪËصÄÖÊÁ¿·ÖÊýԼΪ65%£¬ÔòYµÄ·Ö×ÓʽΪ_____________________________________________£¬

A·Ö×ÓÖÐËùº¬¹ÙÄÜÍŵÄÃû³ÆÊÇ____________________________________________£¬

AµÄ½á¹¹¼òʽΪ________________________________________________________¡£

(2)µÚ¢Ù¢Ú²½·´Ó¦ÀàÐÍ·Ö±ðΪ¢Ù__________________¢Ú__________________¡£

(3)»¯ºÏÎïB¾ßÓеĻ¯Ñ§ÐÔÖÊ(Ìîд×Öĸ´úºÅ)ÊÇ_________¡£

a.¿É·¢ÉúÑõ»¯·´Ó¦

b.Ç¿Ëá»òÇ¿¼îÌõ¼þϾù¿É·¢ÉúÏûÈ¥·´Ó¦

c.¿É·¢Éúõ¥»¯·´Ó¦

d.´ß»¯Ìõ¼þÏ¿ɷ¢Éú¼Ó¾Û·´Ó¦

(4)д³öC¡¢DºÍEµÄ½á¹¹¼òʽ£º

C__________________¡¢DºÍE__________________

(5)д³ö»¯ºÏÎïCÓëNaOHË®ÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º

____________________________________________________________________

(6)д³öËÄÇâß»à«Á´×´ÃÑÀàµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º___________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¼î´æÔÚÏ£¬Â±´úÌþÓë´¼·´Ó¦Éú³ÉÃÑ(R¡ªO¡ªR¡ä):

»¯ºÏÎïA¾­ÏÂÁÐËIJ½·´Ó¦¿ÉµÃµ½³£ÓÃÈܼÁËÄÇâ߻ૣ¬·´Ó¦¿òͼÈçÏ£º

ÇëÍê³ÉÏÂÁÐÎÊÌ⣺

(1)1 mol AºÍ1 mol H2ÔÚÒ»¶¨Ìõ¼þÏÂÇ¡ºÃ·´Ó¦£¬Éú³É±¥ºÍÒ»Ôª´¼Y£¬YÖÐ̼ԪËصÄÖÊÁ¿·ÖÊýΪ65%£¬ÔòYµÄ·Ö×ÓʽΪ________________£¬A·Ö×ÓÖÐËùº¬¹ÙÄÜÍŵÄÃû³ÆÊÇ_______________£¬AµÄ½á¹¹¼òʽΪ_______________¡£

(2)µÚ¢Ù¢Ú²½·´Ó¦ÀàÐÍ·Ö±ðΪ¢Ù_______________£¬¢Ú_______________¡£

(3)»¯ºÏÎïB¾ßÓеĻ¯Ñ§ÐÔÖÊ(Ìîд×Öĸ´úºÅ)ÊÇ_______________¡£

a.¿É·¢ÉúÑõ»¯·´Ó¦

b.Ç¿Ëá»òÇ¿¼îÌõ¼þϾù¿É·¢ÉúÏûÈ¥·´Ó¦

c.¿É·¢Éúõ¥»¯·´Ó¦

d.´ß»¯Ìõ¼þÏ¿ɷ¢Éú¼Ó¾Û·´Ó¦

(4)д³öC¡¢DºÍEµÄ½á¹¹¼òʽ£º

C_____________¡¢DºÍE______________________________¡£

(5)д³ö»¯ºÏÎïCÓëNaOHË®ÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_______________________________¡£

(6)д³öËÄÇâß»à«Á´×´ÃÑÀàµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º____________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄ꼪ÁÖÊ¡³¤´ºÊÐʮһÖи߶þÏÂѧÆÚÆÚ³õ¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨12·Ö£©ÒÑÖª¼î´æÔÚÏ£¬Â±´úÌþÓë´¼·´Ó¦Éú³ÉÃÑ(R1¡ªO--R2)£º

»¯ºÏÎïA¾­ÏÂÁÐËIJ½·´Ó¦¿ÉµÃµ½³£¼ûÈܼÁËÄÇâ߻ૣ¬·´Ó¦¿òͼÈçÏÂ

Çë»Ø´ðÏÂÁÐÎÊÌ⣺                          
(1)1molAºÍ1molH2ÔÚÒ»¶¨Ìõ¼þÏÂÇ¡ºÃ·´Ó¦£¬Éú³É±¥ºÍÒ»Ôª´¼Y£¬YÖÐ̼ԪËصÄÖÊÁ¿·ÖÊýԼΪ65%£¬ÔòYµÄ·Ö×ÓʽΪ             £¬AÖÐËùº¬¹ÙÄÜÍŵÄÃû³ÆÊÇ               AµÄ½á¹¹¼òʽ                     
(2)µÚ¢Ù¢Û²½·´Ó¦ÀàÐÍÊÇ¢Ù                  ¢Û                        
(3)ÒÑÖªEµÄºË´Å¹²ÕñÇâÆ×ÖгöÏÖÁ½×é·å,д³öCÉú³ÉEµÄ»¯Ñ§·½³Ìʽ                   
(4)AÓкܶàÒì¹¹Ìå,ÆäÖÐÄܺÍÇâÑõ»¯Í­·´Ó¦Éú³ÉºìÉ«³ÁµíµÄÓР                   ÖÖ

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸