a£®CH3CH2OH(g)£«H2O(g)£½4H2(g)£«2CO(g) ¦¤H1£½+256.6 kJ¡¤mol£­1

b£®2CH3CH2OH(g)£«O2(g)£½6H2(g)£«4CO(g) ¦¤H2£½+27.6 kJ¡¤mol£­1

ÔòÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A. Éý¸ßaµÄ·´Ó¦Î¶ȣ¬ÒÒ´¼µÄת»¯ÂÊÔö´ó

B. ÓÉb¿ÉÖª£ºÒÒ´¼µÄȼÉÕÈÈΪ13.8 kJ¡¤mol£­1

C. 2H2(g)£«O2(g)£½2H2O(g) ¦¤H£½£«485.6 kJ¡¤mol£­1

D. ÖÆÈ¡µÈÁ¿µÄÇâÆø£¬Í¾¾¶bÏûºÄµÄÄÜÁ¿¸ü¶à

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄê½­ËÕÊ¡ÑγÇÊи߶þѧҵˮƽģÄ⣨һ£©»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÎÒ¹úÊ׷ɵij¤Õ÷ÆߺÅÔËÔØ»ð¼ý²ÉÓÃÒºÑõºÍúÓÍ×÷ΪÍƽø¼Á¡£ÃºÓÍÊôÓÚ(¡¡¡¡)

A. ´¿¾»Îï B. »ìºÏÎï C. Ñõ»¯Îï D. µ¥ÖÊ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ì½­ËÕÊ¡³£ÖÝÊиßÈýµÚÒ»´ÎÄ£Ä⿼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

¼îʽ´ÎÂÈËáþ[Mga(ClO)b(OH)c¡¤xH2O]ÊÇÒ»ÖÖÓпª·¢¼ÛÖµµÄ΢ÈÜÓÚË®µÄÎÞ»ú¿¹¾ú¼Á¡£ÎªÈ·¶¨¼îʽ´ÎÂÈËáþµÄ×é³É£¬½øÐÐÈçÏÂʵÑ飺

¢Ù ׼ȷ³ÆÈ¡1.685g¼îʽ´ÎÂÈËáþÊÔÑùÓÚ250mL׶ÐÎÆ¿ÖУ¬¼ÓÈë¹ýÁ¿µÄKIÈÜÒº£¬ÓÃ×ãÁ¿ÒÒËáËữ£¬ÓÃO.8000mol/LNa2S2O3±ê×¼ÈÜÒºµÎ¶¨ÖÁÖյ㣨Àë×Ó·½³ÌʽΪ2S2O32-£«I2=2I-£«S4O62-£©£¬ÏûºÄ25.00mL¡£

¢Ú ÁíÈ¡1.685g¼îʽ´ÎÂÈËáþÊÔÑù£¬ÓÃ×ãÁ¿ÒÒËáËữ£¬ÔÙÓÃ×ãÁ¿3%H2O2ÈÜÒº´¦ÀíÖÁ²»ÔÙ²úÉúÆøÅÝ(H2O2±»ClO-Ñõ»¯ÎªO2)£¬Ï¡ÊÍÖÁ1000mL¡£ÒÆÈ¡25.00mLÈÜÒºÖÁ׶ÐÎÆ¿ÖУ¬ÔÚÒ»¶¨Ìõ¼þÏÂÓÃ0.020 00mol/L EDTA(Na2H2Y)±ê×¼ÈÜÒºµÎ¶¨ÆäÖеÄMg2+£¨Àë×Ó·½³ÌʽΪMg2++H2Y2-=MgY2-+2H+) £¬ÏûºÄ25.00 mL

£¨1£©²½Öè¢Ù ÖÐÐèÒªÓõ½µÄָʾ¼ÁÊÇ_______¡£

£¨2£©²½Öè¢Ú ÖÐÈôµÎ¶¨¹ÜÔÚʹÓÃǰδÓÃEDTA±ê×¼ÈÜÒºÈóÏ´£¬²âµÃµÄMg2+ÎïÖʵÄÁ¿½«____£¨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°²»±ä¡±£©¡£

£¨3£©Í¨¹ý¼ÆËãÈ·¶¨¼îʽ´ÎÂÈËáþµÄ»¯Ñ§Ê½£¨Ð´³ö¼ÆËã¹ý³Ì£©¡£____

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ì½­ËÕÊ¡³£ÖÝÊиßÈýµÚÒ»´ÎÄ£Ä⿼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

»¯Ñ§ÓëÉú²ú¡¢Éú»î¡¢Éç»áÃÜÇÐÏà¹Ø¡£ÏÂÁÐÓйØ˵·¨´íÎóµÄÊÇ

A. ´Óº£Ë®ÖпÉÌáȡþ£¬µç½âÈÛÈÚÂÈ»¯Ã¾¿ÉÖƵýðÊôþ

B. Ó¦Óøߴ¿¶Èµ¥ÖʹèÖƳɹ⵼ÏËά£¬Ìá¸ßÐÅÏ¢´«ÊäËÙ¶È

C. ÑÐÖƸßÐÔÄܵÄÄÍÄ¥ÂÖÌ¥£¬¿É¼õÉÙPM2.5µÈϸ¿ÅÁ£ÎïµÄ²úÉú

D. ¿ª·¢¶þÑõ»¯Ì¼ÖƳɵÄÈ«½µ½âËÜÁÏ£¬»º½âÈÕÒæÑÏÖصġ°°×É«ÎÛȾ¡±

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìɽ¶«Ê¡ÁÙÒÊÊиßÈýÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁÐÓйØ˵·¨ÖÐÕýÈ·µÄÊÇ

A. ÒÑÖª25¡æʱNH4CNÈÜÒºÏÔ¼îÐÔ,Ôò25¡æʱµÄµçÀëƽºâ³£ÊýK(NH3¡¤H2O)>K(HCN)

B. ÓÉË®µçÀë³öµÄc(H£«)=10£­12mol¡¤L£­1µÄÈÜÒºÖÐ:Na£«¡¢Ba£²£«¡¢HCO3£­¡¢Cl£­¿ÉÒÔ´óÁ¿¹²´æ

C. ÒÑÖªKsp(AgCl)=1.56¡Á10£­10£¬ Ksp(Ag2CrO4)=9.0¡Á10£­12¡£Ïòº¬ÓÐCl£­¡¢CrO4£²£­ÇÒŨ¶È¾ùΪ0.010 mol¡¤L-1ÈÜÒºÖÐÖðµÎ¼ÓÈë0.010 mol¡¤L-1µÄAgNO3ÈÜҺʱ£¬CrO4£²£­ÏȲúÉú³Áµí

D. ³£ÎÂÏÂpH=7µÄCH3COOHºÍNaOH»ìºÏÈÜÒºÖУ¬c(Na£«)>c(CH3COO£­)

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìɽ¶«Ê¡ÁÙÒÊÊиßÈýÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÉèNAΪ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµ¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ( )

A. 136gÈÛÈÚµÄKHSO4Öк¬ÓÐ2NA¸öÑôÀë×Ó

B. 40gH218OÓë40gD2OËùº¬µÄÖÐ×ÓÊý¾ùΪ20NA

C. 1molFe·Ö±ðÓë×ãÁ¿µÄÏ¡ÁòËáºÍÏ¡ÏõËᷴӦתÒƵç×ÓÊý¾ùΪ2NA

D. ±ê×¼×´¿öÏ£¬22.4LNOºÍ11.2LO2»ìºÏºóÆøÌåµÄ·Ö×Ó×ÜÊýΪNA

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄêɽ¶«Ê¡¼ÃÄÏÊиßÒ»ÏÂѧÆÚ¿ªÑ§¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁйØÓÚÔªËØÖÜÆÚ±íºÍÔªËØÖÜÆÚÂɵÄ˵·¨´íÎóµÄÊÇ( )

A. Li¡¢Na¡¢KÔªËصÄÔ­×ÓºËÍâµç×Ó²ãÊýËæן˵çºÉÊýµÄÔö¼Ó¶øÔö¶à

B. µÚ¶þÖÜÆÚÔªËØ´ÓLiµ½F£¬·Ç½ðÊôÐÔÖð½¥ÔöÇ¿

C. ÒòΪNa±ÈKÈÝÒ×ʧȥµç×Ó£¬ËùÒÔNa±ÈKµÄ»¹Ô­ÐÔÇ¿

D. OÓëSΪͬÖ÷×åÔªËØ£¬ÇÒO±ÈSµÄ·Ç½ðÊôÐÔÇ¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄêɽ¶«Ê¡¼ÃÄÏÊиßÒ»ÏÂѧÆÚ¿ªÑ§¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ijÈÜÒºÖпÉÄܺ¬ÓÐH+¡¢Na+¡¢NH4+¡¢Mg2+¡¢Fe3+¡¢Al3+¡¢SO42-¡¢CO32-µÈÀë×Ó¡£µ±Ïò¸ÃÈÜÒºÖмÓÈëÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄNaOHÈÜҺʱ£¬·¢ÏÖÉú³É³ÁµíµÄÎïÖʵÄÁ¿ËæNaOHÈÜÒºµÄÌå»ý±ä»¯µÄͼÏñÈçͼËùʾ¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨ £©

A. Ô­ÈÜÒºÖк¬ÓеÄÑôÀë×ÓÊÇH+¡¢NH4+¡¢Mg2+¡¢Al3+

B. Ô­ÈÜÒºÖÐÒ»¶¨º¬ÓÐSO42-ºÍNa+

C. Ô­ÈÜÒºÖк¬ÓеÄFe3+ºÍAl3+µÄÎïÖʵÄÁ¿Ö®±ÈΪ1£º1

D. ·´Ó¦×îºóÐγɵÄÈÜÒºÖк¬ÓеÄÈÜÖÊΪNa2SO4

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄê½­ËÕÊ¡¸ß¶þÏÂѧÆÚѧҵˮƽģÄ⻯ѧÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÖøÃû»¯Ñ§¼ÒÕÅÇàÁ«½ÌÊÚ¾«È·²âµÃî÷(In)ÔªËصÄÏà¶ÔÔ­×ÓÖÊÁ¿Îª114.8£¬¸ÃÖµ±»¹ú¼ÊÔ­×ÓÁ¿Î¯Ô±»áÈ·ÈÏΪбê×¼¡£InÖк¬ÓеÄÖÐ×ÓÊýÊÇ

A. 49 B. 64 C. 113 D. 114.8

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸