ÏòÌå»ýΪ2LµÄÈÝÆ÷ÖмÓÈë1mol N2ºÍ6mol H2½øÐпÉÄæ·´Ó¦£º£¬ºó²âµÃN2µÄÎïÖʵÄÁ¿Îª0.6mol£¬Ôò£º
£¨1£©2minÄÚ£¬N2µÄÎïÖʵÄÁ¿¼õÉÙÁË0.4mol£¬H2µÄÎïÖʵÄÁ¿¼õÉÙÁË____________mol£¬NH3µÄÎïÖʵÄÁ¿Ôö¼ÓÁË__________mol¡£
£¨2£©ÈôÓÃN2µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊ£¬Ôò__________¡£
£¨3£©ÈôÓÃH2µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊ£¬Ôò__________¡£
£¨4£©ÈôÓÃNH3µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊ£¬Ôò__________¡£
£¨5£©Í¨¹ýÉÏÊö¼ÆË㣬ÄãÓÐʲô·¢ÏÖ£¿______________________
£¨1£©1.2£»0.8¡¡¡¡
£¨2£©0.1¡¡¡¡
£¨3£©0.3¡¡¡¡
£¨4£©0.2¡¡¡¡¡¡
£¨5£©»¯Ñ§·´Ó¦Öи÷ÖÖÎïÖʵķ´Ó¦ËÙÂÊÖ®±ÈµÈ»¯Ñ§¼ÆÁ¿ÊýÖ®±È
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚÒ»¶¨Ìõ¼þÏ£¬ÏòÌå»ýΪ2LµÄÈÝÆ÷ÖмÓÈë2mol O2ºÍ3mol SO2½øÐпÉÄæ·´Ó¦£º
2SO2£¨l£©+O2£¨l£©2SO3£¨l£©£¬2minºó²âµÃO2µÄÎïÖʵÄÁ¿Îª1.6mol£¬Ôò£º
£¨1£©2minÄÚ£¬SO2µÄÎïÖʵÄÁ¿¼õÉÙÁË
0.8mol
0.8mol
£¬SO3µÄÎïÖʵÄÁ¿Ôö¼ÓÁË
0.8mol
0.8mol
£»
£¨2£©ÈôÓÃO2µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊ£¬ÔòV£¨O2£©=
0.1mol/£¨L£®min£©
0.1mol/£¨L£®min£©
£»
£¨3£©ÈôÓÃSO3µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊ£¬ÔòV£¨SO3£©=
0.2mol/£¨L£®min£©
0.2mol/£¨L£®min£©
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚÒ»¶¨Ìõ¼þÏ£¬ÏòÌå»ýΪ2LµÄÈÝÆ÷ÖмÓÈë2mol O2ºÍ3mol SO2ʹ֮·´Ó¦Éú³ÉSO3ÆøÌ壺2SO2+O22SO3£¬2minʱ£¬²âµÃO2µÄÎïÖʵÄÁ¿Îª1.6mol£¬Ôò£º
£¨1£©2minÄÚ£¬Æ½¾ù·´Ó¦ËÙÂÊv£¨O2£©=
0.1mol/£¨L?min£©
0.1mol/£¨L?min£©
£» v£¨SO3£©=
0.2mol/£¨L?min£©
0.2mol/£¨L?min£©
£®
£¨2£©2minʱ£¬SO2µÄŨ¶ÈΪ
1.1mol/L
1.1mol/L

£¨3£©Èô2minʱ²âµÃÉÏÊö·´Ó¦·Å³öQ kJµÄÈÈÁ¿£¬ÊÔд³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ
2SO2£¨g£©+O2£¨g£©2SO3£¨g£©¡÷H=-2.5QkJ?mol-1
2SO2£¨g£©+O2£¨g£©2SO3£¨g£©¡÷H=-2.5QkJ?mol-1
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨7·Ö£©ÏòÌå»ýΪ2LµÄÈÝÆ÷ÖмÓÈë1mol N2ºÍ6mol H2½øÐпÉÄæ·´Ó¦£ºN2+3H2 2NH3£¬ºó²âµÃN2µÄÎïÖʵÄÁ¿Îª0.6mol£¬Ôò£º

£¨1£©2minÄÚ£¬N2µÄÎïÖʵÄÁ¿¼õÉÙÁË0.4mol£¬H2µÄÎïÖʵÄÁ¿¼õÉÙÁË________mol£¬NH3µÄÎïÖÊÁ¿Ôö¼ÓÁË________mol¡£

£¨2£©ÈôÓÃN2µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊΪ      mol/(L¡¤min)¡£

£¨3£©ÈôÓÃH2µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊΪ      mol/(L¡¤min)¡£

£¨4£©ÈôÓÃNH3µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊΪ     mol/(L¡¤min)¡£

£¨5£©Í¨¹ýÉÏÊö¼ÆË㣬ÄãÓÐʲô·¢ÏÖ£¿____________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄê°²»ÕÊ¡·ÊÎ÷Å©ÐËÖÐѧ¸ßÒ»ÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨7·Ö£©ÏòÌå»ýΪ2LµÄÈÝÆ÷ÖмÓÈë1mol N2ºÍ6mol H2½øÐпÉÄæ·´Ó¦£ºN2+3H2 2NH3£¬ºó²âµÃN2µÄÎïÖʵÄÁ¿Îª0.6mol£¬Ôò£º
£¨1£©2minÄÚ£¬N2µÄÎïÖʵÄÁ¿¼õÉÙÁË0.4mol£¬H2µÄÎïÖʵÄÁ¿¼õÉÙÁË________mol£¬NH3µÄÎïÖÊÁ¿Ôö¼ÓÁË________mol¡£
£¨2£©ÈôÓÃN2µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊΪ     mol/(L¡¤min)¡£
£¨3£©ÈôÓÃH2µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊΪ     mol/(L¡¤min)¡£
£¨4£©ÈôÓÃNH3µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊΪ    mol/(L¡¤min)¡£
£¨5£©Í¨¹ýÉÏÊö¼ÆË㣬ÄãÓÐʲô·¢ÏÖ£¿____________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ì°²»ÕÊ¡¸ßÒ»ÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨7·Ö£©ÏòÌå»ýΪ2LµÄÈÝÆ÷ÖмÓÈë1mol N2ºÍ6mol H2½øÐпÉÄæ·´Ó¦£ºN2+3H2 2NH3£¬ºó²âµÃN2µÄÎïÖʵÄÁ¿Îª0.6mol£¬Ôò£º

£¨1£©2minÄÚ£¬N2µÄÎïÖʵÄÁ¿¼õÉÙÁË0.4mol£¬H2µÄÎïÖʵÄÁ¿¼õÉÙÁË________mol£¬NH3µÄÎïÖÊÁ¿Ôö¼ÓÁË________mol¡£

£¨2£©ÈôÓÃN2µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊΪ      mol/(L¡¤min)¡£

£¨3£©ÈôÓÃH2µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊΪ      mol/(L¡¤min)¡£

£¨4£©ÈôÓÃNH3µÄŨ¶È±ä»¯À´±íʾ¸Ã·´Ó¦µÄ·´Ó¦ËÙÂÊΪ     mol/(L¡¤min)¡£

£¨5£©Í¨¹ýÉÏÊö¼ÆË㣬ÄãÓÐʲô·¢ÏÖ£¿____________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸