Question

18£®Ð´³öÏÂÁз´Ó¦µÄ·½³Ìʽ
£¨1£©1£¬3-¶¡¶þÏ©Óëäå·¢Éú1£¬4¼Ó³ÉCH₂=CHCH=CH₂+Br₂¡úCH₂BrCH=CHCH₂Br£»
£¨2£©±½·ÓÄÆÈÜÒºÖÐͨÈëÉÙÁ¿CO₂C₆H₅ONa+CO₂+H₂O¡úC₆H₅OH¡ý+NaHCO₃£»
£¨3£©ÒÒÈ©ÓëÐÂÖÆÇâÑõ»¯Í­×ÇÒº¼ÓCH₃CHO+2Cu£¨OH£©₂$\stackrel{¡÷}{¡ú}$CH₃COOH+Cu₂O¡ý+2H₂O£»
£¨4£©1£¬2--¶þÂÈÒÒÍéÓëÇâÑõ»¯ÄÆÈÜÒº¼ÓÈÈClCH₂CH₂Cl+2NaOH$\stackrel{¡÷}{¡ú}$HOCH₂CH₂OH+2NaCl£»
£¨5£©2-ÂȱûÍéÓëNaOHµÄÒÒ´¼ÈÜÒº¹²ÈÈCH₃CHClCH₃+NaOH$¡ú_{¡÷}^{´¼}$CH₃CH=CH₂¡ü+NaCl+H₂O£®

Answer 1

·ÖÎö £¨1£©1£¬3-¶¡¶þÏ©º¬ÓÐ2¸ö̼̼˫¼ü£¬·¢Éú1£¬2¼Ó³É»ò1£¬4¼Ó³É£¬·¢Éú1£¬4¼Ó³ÉÉú³ÉCH₂BrCH=CHCH₂Br£»
£¨2£©±½·ÓÄÆÈÜÒººÍ¶þÑõ»¯Ì¼·´Ó¦Éú³É±½·ÓºÍ̼ËáÇâÄÆ£»
£¨3£©ÒÒÈ©ÓëÐÂÖÆÇâÑõ»¯Í­·¢ÉúÑõ»¯·´Ó¦Éú³ÉÒÒËá¡¢Ñõ»¯ÑÇÍ­ºÍË®£»
£¨4£©1£¬2-¶þÂÈÒÒÍéÓëNaOHµÄË®ÈÜÒº¹²ÈÈ£¬·¢ÉúË®½â·´Ó¦Éú³ÉÒÒ¶þ´¼£»
£¨5£©Â±´úÌþ·¢ÉúÏûÈ¥·´Ó¦µÄ½á¹¹Ìص㣺Óë-XËùÁ¬Ì¼ÏàÁÚ̼ÉÏÓÐÇâÔ­×ӵIJÅÄÜ·¢ÉúÏûÈ¥·´Ó¦£¬Ðγɲ»±¥ºÍ¼ü£®

½â´ð ½â£º£¨1£©1£¬3-¶¡¶þÏ©º¬ÓÐ2¸ö̼̼˫¼ü£¬·¢Éú1£¬2¼Ó³É»ò1£¬4¼Ó³É£¬·¢Éú1£¬4¼Ó³ÉµÄ·½³ÌʽΪCH₂=CHCH=CH₂+Br₂¡úCH₂BrCH=CHCH₂Br£¬
¹Ê´ð°¸Îª£ºCH₂=CHCH=CH₂+Br₂¡úCH₂BrCH=CHCH₂Br£»
£¨2£©Ì¼ËáµÄËáÐԱȱ½·ÓµÄËáÐÔÇ¿£¬ËùÒÔ±½·ÓÄÆͨÈë¶þÑõ»¯Ì¼Éú³É±½·ÓºÍ̼ËáÇâÄÆ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºC₆H₅ONa+CO₂+H₂O¡úC₆H₅OH¡ý+NaHCO₃£¬
¹Ê´ð°¸Îª£ºC₆H₅ONa+CO₂+H₂O¡úC₆H₅OH¡ý+NaHCO₃£»
£¨3£©ÒÒÈ©ÓëÐÂÖÆÇâÑõ»¯Í­·¢ÉúÑõ»¯·´Ó¦Éú³ÉÒÒËá¡¢Ñõ»¯ÑÇÍ­ºÍË®£¬¸Ã·´Ó¦Îª£ºCH₃CHO+2Cu£¨OH£©₂$\stackrel{¡÷}{¡ú}$CH₃COOH+Cu₂O¡ý+2H₂O£¬
¹Ê´ð°¸Îª£ºCH₃CHO+2Cu£¨OH£©₂$\stackrel{¡÷}{¡ú}$CH₃COOH+Cu₂O¡ý+2H₂O£»
£¨4£©Â±´úÌþÔÚÇâÑõ»¯ÄƵÄË®ÈÜÒºÖз¢ÉúË®½â·´Ó¦Éú³É´¼À࣬ËùÒÔ1£¬2-¶þÂÈÒÒÍéÓëÇâÑõ»¯ÄÆË®ÈÜÒº¹²ÈÈ¿ÉÒÔÉú³ÉÒÒ¶þ´¼£¨HOCH₂CH₂OH£©£¬·´Ó¦·½³ÌʽΪ£º
ClCH₂CH₂Cl+2NaOH$\stackrel{¡÷}{¡ú}$HOCH₂CH₂OH+2NaCl£¬
¹Ê´ð°¸Îª£ºClCH₂CH₂Cl+2NaOH$\stackrel{¡÷}{¡ú}$HOCH₂CH₂OH+2NaCl£»
£¨5£©2-ÂȱûÍéÓëNaOHÒÒ´¼ÈÜÒº¹²ÈÈ£¬Á¬Â±Ô­×ÓµÄ̼ԭ×ÓµÄÏàÁÚ̼ԭ×ÓÉϵÄÒ»¸öÇâÔ­×ӺͱËØÔ­×ÓͬʱÏûÈ¥Éú³ÉÏ©Ìþ£¬·´Ó¦Îª£ºCH₃CHClCH₃+NaOH$¡ú_{¡÷}^{´¼}$CH₃CH=CH₂¡ü+NaCl+H₂O£¬
¹Ê´ð°¸Îª£ºCH₃CHClCH₃+NaOH$¡ú_{¡÷}^{´¼}$CH₃CH=CH₂¡ü+NaCl+H₂O£®

µãÆÀ ±¾Ì⿼²éÁËÓлúÎïÖʵÄÐÔÖÊÓ¦Ó㬿¼²éÁË»¯Ñ§·½³ÌʽµÄÊéд£¬ÕÆÎÕÓлúÎï¹ÙÄÜÍŵÄÐÔÖÊÊÇÊéд»¯Ñ§·½³ÌʽµÄ¹Ø¼ü£¬ÌâÄ¿ÄѶȲ»´ó£®