ÒÑÖªFexO¾§ÌåµÄ¾§°û½á¹¹ÎªNaClÐÍ£¬ÓÉÓÚ¾§ÌåȱÏÝ£¬xµÄֵСÓÚ1¡£²âÖªFexO¾§ÌåÃܶȦÑΪ5.719 kg¡¤cm-3,¾§°û±ß³¤Îª4.28¡Á10-10 m(ÌúÏà¶ÔÔ×ÓÖÊÁ¿Îª55.9£¬ÑõÏà¶ÔÔ×ÓÖÊÁ¿Îª16)¡£Çó£º
£¨1£©FexOÖÐxµÄÖµ£¨¾«È·ÖÁ0.01£©¡£
£¨2£©¾§ÌåÖеÄFe·Ö±ðΪFe2+ºÍFe3+£¬ÔÚFe2+ºÍFe3+µÄ×ÜÊýÖУ¬Fe2+ËùÕ¼·ÖÊýΪ¶àÉÙ£¿£¨¾«È·ÖÁ0.001£©
£¨3£©Ð´³ö´Ë¾§ÌåµÄ»¯Ñ§Ê½¡£
£¨4£©ÃèÊöFeÔڴ˾§ÌåÖÐÕ¼¾Ý¿Õ϶µÄ¼¸ºÎÐÎ×´£¨¼´ÓëO2-¾àÀë×î½üÇҵȾàÀëµÄÌúÀë×ÓΧ³ÉµÄ¿Õ¼äÐÎ×´£©¡£
£¨5£©ÔÚ¾§ÌåÖУ¬ÌúÔªËصÄÀë×Ó¼ä×î¶Ì¾àÀëΪ¶àÉÙ£¿
£¨1£©0.92 (2)0.826 (3)O (4)Õý°ËÃæÌå £¨5£©3.03¡Á10-10 m
½âÎö£º(1)ÓÉNaCl¾§°û½á¹¹¿ÉÖª£¬1 mol NaCl¾§°ûÖк¬ÓÐ4 mol NaCl£¬¹ÊÔÚFexO¾§ÌåÖÐ1 mol FexO¾§°ûÖк¬ÓÐ4 mol FexO¡£ÉèFexOµÄĦ¶ûÖÊÁ¿ÎªM g¡¤mol-1£¬¾§°ûµÄÌå»ýΪV¡£ÔòÓУº4M=¦ÑV,´úÈëÊý¾Ý½âµÃM=67.4 g¡¤mol-1£¬Ôòx=0.92¡££¨2£©ÉèFe2+Ϊy¸ö£¬Fe3+ÔòΪ£¨0.92-y£©¸ö£¬ÓÉÕý¸º»¯ºÏ¼Û´úÊýºÍΪÁã¿ÉµÃ£º2x+3(0.92-y)=2,Ôòy=0.76¡£Fe2+ËùÕ¼µÄ·ÖÊýΪ0.76/0.92=0.826¡£(3)ÓÉÓÚFe2+Ϊ0.76£¬ÔòFe3+Ϊ£¨0.92-0.76£©=0.16,¹Ê»¯Ñ§Ê½ÎªFe2+0.76Fe3+0.16O¡££¨4£©ÓëO2-¾àÀë×î½üÇҵȾàÀëµÄÌúÀë×ÓÓÐ6¸ö£¬Õâ6¸öÌúÀë×ÓËùΧ³ÉµÄ¼¸ºÎÐÎ×´ÈçÏÂͼËùʾ£¬ÓÉͼ¿ÉÖªFeÔÚ¾§ÌåÖÐÕ¼¾Ý¿Õ϶µÄ¼¸ºÎÐÎ״ΪÕý°ËÃæÌå¡£
£¨5£©¾§ÌåÖÐFe¡ªFe×î¶Ì¾àÀër=¡Á¾§°û±ß³¤=3.03¡Á10-10 m¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º¼ªÁÖÊ¡³¤´ºÍâ¹úÓïѧУ2011£2012ѧÄê¸ß¶þÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔÌâ ÌâÐÍ£º022
(1)ÈÛµã·ÐµãHF________HI£»ÔÒò£º________£®
(2)¸÷ÖÖº¬ÑõËáHClO¡¢HClO3¡¢H2SO3¡¢HClO4µÄËáÐÔÓÉÇ¿µ½ÈõÅÅÁÐΪ________£®
(3)ÏÂÁÐ4ÖÖÎïÖÊÈÛµã·ÐµãÓɸߵ½µÍÅÅÁÐΪ________(ÌîÐòºÅ)£®
¢Ù½ð¸Õʯ(C£C)¢ÚÕà(Ge£Ge)
¢Û¾§Ìå¹è(Si£Si)¢Ü½ð¸ÕÉ°(Si£C)
(4)¾§Ìå¾ßÓйæÔòµÄ¼¸ºÎÍâÐΣ¬¾§ÌåÖÐ×î»ù±¾µÄÖظ´µ¥Ôª³Æ֮Ϊ¾§°û£®NaCl¾§Ìå½á¹¹ÈçÏÂͼËùʾ£®¾§ÌåÖÐÿ¸öNa£«Í¬Ê±ÎüÒý×Å________¸öCl££¬ÓÉÕâЩCl£¹¹³ÉµÄ¼¸ºÎ¹¹ÐÍΪ________¾§ÌåÖÐÔÚÿ¸öCl£ÖÜΧÓëËü×î½Ó½üÇÒ¾àÀëÏàµÈµÄCl£¹²ÓÐ________¸ö£®
(5)ijԪËصļ¤·¢Ì¬Ô×ӵĵç×ÓÅŲ¼Ê½Îª1s22s22p63s23p34s1£¬Ôò¸ÃÔªËØ»ù̬Ô×ӵĵç×ÓÅŲ¼Ê½Îª________£»Æä×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïµÄ»¯Ñ§Ê½ÊÇ________£®
(6)ijԪËØÔ×ӵļ۵ç×Ó¹¹ÐÍΪ3d104S2£¬ËüÊôÓÚµÚ________ÖÜÆÚ£¬ÊÇ________×壬________ÇøÔªËØ£¬ÔªËØ·ûºÅÊÇ________£®¸ÃÔ×ÓºËÍâÓÐ________¸öÄܼ¶£¬µç×ÓÔƵÄÐÎ×´ÓÐ________ÖÖ£®
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄ꼪ÁÖÊ¡³¤´ºÍâ¹úÓïѧУ¸ß¶þÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ
£¨1£©¡¢ÈÛµã·ÐµãHF HI£»ÔÒò£º
£¨2£©¡¢¸÷ÖÖº¬ÑõËáHClO¡¢HClO3¡¢H2SO3¡¢HClO4µÄËáÐÔÓÉÇ¿µ½ÈõÅÅÁÐΪ
£¨3£©¡¢ÏÂÁÐ4ÖÖÎïÖÊÈÛµã·ÐµãÓɸߵ½µÍÅÅÁÐΪ________ £¨ÌîÐòºÅ£©
¢Ù½ð¸Õʯ£¨C¡ªC£©¢ÚÕࣨGe¡ªGe£©
¢Û¾§Ìå¹è£¨Si¡ªSi£©¢Ü½ð¸ÕÉ°£¨Si¡ªC£©
£¨4£©¾§Ìå¾ßÓйæÔòµÄ¼¸ºÎÍâÐΣ¬¾§ÌåÖÐ×î»ù±¾µÄÖظ´µ¥Ôª³Æ֮Ϊ¾§°û¡£NaCl¾§Ìå½á¹¹ÈçͼËùʾ¡£
¾§ÌåÖÐÿ¸öNa+ͬʱÎüÒý×Å______¸öCl-£¬ÓÉÕâЩ Cl-¹¹³ÉµÄ¼¸ºÎ¹¹ÐÍΪ ¾§ÌåÖÐÔÚÿ¸öCl-ÖÜΧÓëËü×î½Ó½üÇÒ¾àÀëÏàµÈµÄCl-¹²ÓÐ________¸ö¡£
£¨5£©Ä³ÔªËصļ¤·¢Ì¬Ô×ӵĵç×ÓÅŲ¼Ê½Îª1s2s2p3s3p4s£¬Ôò¸ÃÔªËØ»ù̬Ô×ӵĵç×ÓÅŲ¼Ê½Îª £»Æä×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïµÄ»¯Ñ§Ê½ÊÇ
£¨6£©Ä³ÔªËØÔ×ӵļ۵ç×Ó¹¹ÐÍΪ3d104S2£¬ËüÊôÓÚµÚ ÖÜÆÚ£¬ÊÇ ×壬 ÇøÔªËØ£¬ÔªËØ·ûºÅÊÇ ¡£¸ÃÔ×ÓºËÍâÓÐ ¸öÄܼ¶£¬µç×ÓÔƵÄÐÎ×´ÓÐ ÖÖ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ì¼ªÁÖÊ¡¸ß¶þÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
£¨1£©¡¢ÈÛµã·ÐµãHF HI£»ÔÒò£º
£¨2£©¡¢¸÷ÖÖº¬ÑõËáHClO¡¢HClO3¡¢H2SO3¡¢HClO4µÄËáÐÔÓÉÇ¿µ½ÈõÅÅÁÐΪ
£¨3£©¡¢ÏÂÁÐ4ÖÖÎïÖÊÈÛµã·ÐµãÓɸߵ½µÍÅÅÁÐΪ________ £¨ÌîÐòºÅ£©
¢Ù½ð¸Õʯ£¨C¡ªC£©¢ÚÕࣨGe¡ªGe£©
¢Û¾§Ìå¹è£¨Si¡ªSi£©¢Ü½ð¸ÕÉ°£¨Si¡ªC£©
£¨4£©¾§Ìå¾ßÓйæÔòµÄ¼¸ºÎÍâÐΣ¬¾§ÌåÖÐ×î»ù±¾µÄÖظ´µ¥Ôª³Æ֮Ϊ¾§°û¡£NaCl¾§Ìå½á¹¹ÈçͼËùʾ¡£
¾§ÌåÖÐÿ¸öNa+ͬʱÎüÒý×Å______¸öCl-£¬ÓÉÕâЩ Cl-¹¹³ÉµÄ¼¸ºÎ¹¹ÐÍΪ ¾§ÌåÖÐÔÚÿ¸öCl-ÖÜΧÓëËü×î½Ó½üÇÒ¾àÀëÏà µÈµÄCl-¹²ÓÐ________¸ö¡£
£¨5£©Ä³ÔªËصļ¤·¢Ì¬Ô×ӵĵç×ÓÅŲ¼Ê½Îª1s2s2p3s3p4s£¬Ôò¸ÃÔªËØ»ù̬Ô×ӵĵç×ÓÅŲ¼Ê½Îª £»Æä×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïµÄ»¯Ñ§Ê½ÊÇ
£¨6£©Ä³ÔªËØÔ×ӵļ۵ç×Ó¹¹ÐÍΪ3d104S2£¬ËüÊôÓÚµÚ ÖÜÆÚ£¬ÊÇ ×壬 ÇøÔªËØ£¬ÔªËØ·ûºÅÊÇ ¡£¸ÃÔ×ÓºËÍâÓÐ ¸öÄܼ¶£¬µç×ÓÔƵÄÐÎ×´ÓÐ ÖÖ
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com