£¨6·Ö£©(1)ÔڽྻµÄÊÔ¹ÜÖмÓÈëÉÙÁ¿ÏõËáÒøÈÜÒº£¬ÔÙÖðµÎµÎ¼ÓÏ¡°±Ë®£¬ÏÖÏóÊÇÏÈÉú³É°×É«³Áµí£¬·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ¢Ù______________________________ £»¼ÌÐøµÎ¼ÓÖÁ³ÁµíÇ¡ºÃÈܽ⣬¼´µÃÒø°±ÈÜÒº£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ¢Ú_______________________________________£»
(2)ÆÏÌÑÌÇ·Ö×ÓÖк¬ÓÐÈ©»ù£¬ÊôÓÚ¶àôÇ»ùÈ©£¬¹¤ÒµÉϳ£ÓÃÀ´Öƾµ¡£Ïò£¨1£©ÖÐËùµÃµÄÒø°±ÈÜÒºÖеÎÈëÉÙÁ¿ÆÏÌÑÌÇÈÜÒº£¬»ìºÏ¾ùÔȺ󣬷ÅÔÚˮԡÖмÓÈÈ3min¡«5min£¬¼´¿ÉÔÚÊÔ¹ÜÄÚ±ÚÉÏÐγÉÒø¾µ£¬Ôò´Ë·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ¢Û£¨ÆÏÌÑÌǵĽṹ¼òʽÓÃGCHO±íʾ£©£º____________________________________________________¡£

(ÿ¸ö»¯Ñ§·½³Ìʽ¸÷2 ·Ö£¬±¾Ìâ¹²6·Ö)
¢Å¢Ù Ag++NH3¡¤H2O=AgOH¡ý+NH4+  ¢ÚAgOH+2NH3=[Ag(NH3)2]++OH-
¢ÛGCHO+2Ag(NH3)2OHGCOOH+2Ag¡ý+4NH3+H2O
»òGCHO+2Ag(NH3)2OHGCOONH4+2Ag¡ý+3NH3+H2O

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©ÔÚº¸½ÓÍ­Æá°üÏßµÄÏßͷʱ£¬³£ÏÈ°ÑÏßÍ··ÅÔÚ»ðÉÏÉÕһϣ¬ÒÔ³ýÈ¥Æá²ã£¬²¢Á¢¼´Ôھƾ«ÖÐպһϣ¬ÔÙº¸½Ó£®ÎªÊ²Ã´ÒªÓþƾ«´¦ÀíºóÔÙº¸½Ó£¬ÊÔÓû¯Ñ§·½³ÌʽÀ´ËµÃ÷£º
2Cu+O2
  ¡÷  
.
 
2CuO£¬CuO+CH3CH2OH
  ¡÷  
.
 
Cu+CH3CHO+H2O
2Cu+O2
  ¡÷  
.
 
2CuO£¬CuO+CH3CH2OH
  ¡÷  
.
 
Cu+CH3CHO+H2O
£®
£¨2£©ÏÖÓÃÏõËáÒøÈÜÒººÍ°±Ë®ÅäÖÆÒø°±ÈÜÒº£¬Çë¼òÊöÅäÖƹý³Ì£º
ÔڽྻµÄÊÔ¹ÜÖмÓÈë1mL2%µÄÏõËáÒøÈÜÒº£¬±ßÕñµ´±ßÖðµÎ¼ÓÈë2%µÄÏ¡°±Ë®£¬ÖÁ×î³õ²úÉúµÄ°×É«³ÁµíÇ¡ºÃÈܽâΪֹ£¬ÖƵÃÒø°±ÈÜÒº
ÔڽྻµÄÊÔ¹ÜÖмÓÈë1mL2%µÄÏõËáÒøÈÜÒº£¬±ßÕñµ´±ßÖðµÎ¼ÓÈë2%µÄÏ¡°±Ë®£¬ÖÁ×î³õ²úÉúµÄ°×É«³ÁµíÇ¡ºÃÈܽâΪֹ£¬ÖƵÃÒø°±ÈÜÒº
£®
£¨3£©Ð´³öÒÒÈ©·¢ÉúÒø¾µ·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
CH3CHO+2Ag£¨NH3£©2OH
¡÷
CH3COONH4+2Ag+3NH3+H2O
CH3CHO+2Ag£¨NH3£©2OH
¡÷
CH3COONH4+2Ag+3NH3+H2O
£®
£¨4£©×ö¹ýÒø¾µÊµÑéµÄÊԹܣ¬¿ÉÒÔÓÃÏÂÁÐ
A
A
ÊÔ¼Á½øÐÐÇåÏ´£¨ÌîÐòºÅ£©£®
A£®Ï¡ÏõËá¡¡ B£®Ï¡ÑÎËá¡¡ C£®Ï¡ÁòËá¡¡¡¡ D£®ÁòËáÍ­ÈÜÒº£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨6·Ö£©(1)ÔڽྻµÄÊÔ¹ÜÖмÓÈëÉÙÁ¿ÏõËáÒøÈÜÒº£¬ÔÙÖðµÎµÎ¼ÓÏ¡°±Ë®£¬ÏÖÏóÊÇÏÈÉú³É°×É«³Áµí£¬·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ¢Ù______________________________ £»¼ÌÐøµÎ¼ÓÖÁ³ÁµíÇ¡ºÃÈܽ⣬¼´µÃÒø°±ÈÜÒº£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ¢Ú_______________________________________£»

(2)ÆÏÌÑÌÇ·Ö×ÓÖк¬ÓÐÈ©»ù£¬ÊôÓÚ¶àôÇ»ùÈ©£¬¹¤ÒµÉϳ£ÓÃÀ´Öƾµ¡£Ïò£¨1£©ÖÐËùµÃµÄÒø°±ÈÜÒºÖеÎÈëÉÙÁ¿ÆÏÌÑÌÇÈÜÒº£¬»ìºÏ¾ùÔȺ󣬷ÅÔÚˮԡÖмÓÈÈ3min¡«5min£¬¼´¿ÉÔÚÊÔ¹ÜÄÚ±ÚÉÏÐγÉÒø¾µ£¬Ôò´Ë·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ¢Û£¨ÆÏÌÑÌǵĽṹ¼òʽÓÃGCHO±íʾ£©£º____________________________________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º09-10Äê½­Î÷°×ðØÖÞÖÐѧ¸ß¶þÏÂѧÆÚÆÚÄ©ÊÔÌâ ÌâÐÍ£ºÌî¿ÕÌâ

£¨6·Ö£©(1)ÔڽྻµÄÊÔ¹ÜÖмÓÈëÉÙÁ¿ÏõËáÒøÈÜÒº£¬ÔÙÖðµÎµÎ¼ÓÏ¡°±Ë®£¬ÏÖÏóÊÇÏÈÉú³É°×É«³Áµí£¬·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ¢Ù______________________________ £»¼ÌÐøµÎ¼ÓÖÁ³ÁµíÇ¡ºÃÈܽ⣬¼´µÃÒø°±ÈÜÒº£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ¢Ú_______________________________________£»

(2)ÆÏÌÑÌÇ·Ö×ÓÖк¬ÓÐÈ©»ù£¬ÊôÓÚ¶àôÇ»ùÈ©£¬¹¤ÒµÉϳ£ÓÃÀ´Öƾµ¡£Ïò£¨1£©ÖÐËùµÃµÄÒø°±ÈÜÒºÖеÎÈëÉÙÁ¿ÆÏÌÑÌÇÈÜÒº£¬»ìºÏ¾ùÔȺ󣬷ÅÔÚˮԡÖмÓÈÈ3min¡«5min£¬¼´¿ÉÔÚÊÔ¹ÜÄÚ±ÚÉÏÐγÉÒø¾µ£¬Ôò´Ë·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ¢Û£¨ÆÏÌÑÌǵĽṹ¼òʽÓÃGCHO±íʾ£©£º____________________________________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(1)ÔڽྻµÄÊÔ¹ÜÖмÓÈëÉÙÁ¿ÏõËáÒøÈÜÒº£¬ÔÙÖðµÎµÎ¼ÓÏ¡°±Ë®£¬ÏÖÏóÊÇÏÈÉú³É°×É«³Áµí£¬·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ¢Ù______________________________ £»¼ÌÐøµÎ¼ÓÖÁ³ÁµíÇ¡ºÃÈܽ⣬¼´µÃÒø°±ÈÜÒº£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ¢Ú_______________________________________£»

(2)ÆÏÌÑÌÇ·Ö×ÓÖк¬ÓÐÈ©»ù£¬ÊôÓÚ¶àôÇ»ùÈ©£¬¹¤ÒµÉϳ£ÓÃÀ´Öƾµ¡£Ïò£¨1£©ÖÐËùµÃµÄÒø°±ÈÜÒºÖеÎÈëÉÙÁ¿ÆÏÌÑÌÇÈÜÒº£¬»ìºÏ¾ùÔȺ󣬷ÅÔÚˮԡÖмÓÈÈ3min¡«5min£¬¼´¿ÉÔÚÊÔ¹ÜÄÚ±ÚÉÏÐγÉÒø¾µ£¬Ôò´Ë·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ¢Û£¨ÆÏÌÑÌǵĽṹ¼òʽÓÃGCHO±íʾ£©£º____________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸