·ÖÎö£ºÑÎËáͬÁ¿£¬ÓÉÓÚµÚ¶þ×éʵÑéËùµÃÆøÌå¶àÓÚµÚÒ»×éʵÑ飬˵Ã÷¼ÓÈë»ìºÏÎï9.2 gʱÑÎËá¹ýÁ¿£¬µÚ¶þ×éÓëµÚÈý×éËùµÃÆøÌåÏàµÈ£¬ËµÃ÷µÚ¶þ×éÑÎËáÍêÈ«·´Ó¦£¬Éú³É3.36L¶þÑõ»¯Ì¼ÐèÒª»ìºÏÎïµÄÖÊÁ¿Îª
¡Á9.2g=13.8g£¬¹ÊµÚ¶þ×é»ìºÏÎïÓÐÊ£Óࣻ
µÚ¶þ×éʵÑéÖÐÑβ»×㣬»ìºÏÎïÓÐÊ£Ó࣬µÚ¶þ×éʵÑéÖз¢Éú·´Ó¦H
++HCO
3-¨TCO
2¡ü+H
2O£¬Éú³É¶þÑõ»¯Ì¼µÄÎïÖʵÄÁ¿Îª
=0.15mol£¬ÓÉ·½³Ìʽ¿ÉÖªn£¨HCl£©=n£¨CO
2£©£¬¾Ý´Ë¼ÆËãÑÎËáµÄÎïÖʵÄÁ¿Å¨¶È£»
µÚÒ»×éʵÑéÖлìºÏÎïÍêÈ«·´Ó¦£¬ÑÎËá¹ýÁ¿£¬·¢Éú·´Ó¦H
++HCO
3-¨TCO
2¡ü+H
2O£¬Éú³É¶þÑõ»¯Ì¼µÄÎïÖʵÄÁ¿Îª
=0.1mol£¬
Éè9.2 g»ìºÏÎïÖÐNaHCO
3¡¢KHCO
3µÄÎïÖʵÄÁ¿·Ö±ðΪxmolºÍymol£¬
¸ù¾Ý̼ԪËØÊغã¿ÉÖªn£¨CO
2£©=n£¨NaHCO
3£©+n£¨KHCO
3£©£¬
ÔÙÀûÓûìºÏÎïÖÊÁ¿Áз½³Ì¼ÆËãx¡¢yµÄÖµ£¬½ø¶ø¼ÆËã»ìºÏÎïÖÐNaHCO
3µÄÖÊÁ¿·ÖÊý£®
½â´ð£º½â£ºÑÎËáͬÁ¿£¬ÓÉÓÚµÚ¶þ×éʵÑéËùµÃÆøÌå¶àÓÚµÚÒ»×éʵÑ飬˵Ã÷¼ÓÈë»ìºÏÎï9.2 gʱÑÎËá¹ýÁ¿£¬µÚ¶þ×éÓëµÚÈý×éËùµÃÆøÌåÏàµÈ£¬ËµÃ÷µÚ¶þ×éÑÎËáÍêÈ«·´Ó¦£¬Éú³É3.36L¶þÑõ»¯Ì¼ÐèÒª»ìºÏÎïµÄÖÊÁ¿Îª
¡Á9.2g=13.8g£¬¹ÊµÚ¶þ×é»ìºÏÎïÓÐÊ£Ó࣬
A£®µÚ¶þ×éʵÑéÖÐÑβ»×㣬»ìºÏÎïÓÐÊ£Ó࣬µÚ¶þ×éʵÑéÖз¢Éú·´Ó¦H
++HCO
3-¨TCO
2¡ü+H
2O£¬Éú³É¶þÑõ»¯Ì¼µÄÎïÖʵÄÁ¿Îª
=0.15mol£¬ÓÉ·½³Ìʽ¿ÉÖªn£¨HCl£©=n£¨CO
2£©=0.15mol£¬ÑÎËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ
=3mol/L£¬¹ÊAÕýÈ·£»
B£®ÑÎËáͬÁ¿£¬ÓÉÓÚµÚ¶þ×éʵÑéËùµÃÆøÌå¶àÓÚµÚÒ»×éʵÑ飬˵Ã÷¼ÓÈë»ìºÏÎï9.2 gʱÑÎËá¹ýÁ¿£¬¹ÊBÕýÈ·£»
C£®µÚÒ»×éʵÑéÖлìºÏÎïÍêÈ«·´Ó¦£¬ÑÎËá¹ýÁ¿£¬·¢Éú·´Ó¦H
++HCO
3-¨TCO
2¡ü+H
2O£¬Éú³É¶þÑõ»¯Ì¼µÄÎïÖʵÄÁ¿Îª
=0.1mol£¬
Éè9.2 g»ìºÏÎïÖÐNaHCO
3¡¢KHCO
3µÄÎïÖʵÄÁ¿·Ö±ðΪxmolºÍymol£¬
¸ù¾Ý̼ԪËØÊغã¿ÉÖª£ºx+y=0.1mol£¬»ìºÏÎïÖÊÁ¿Îª9.2g£¬
ËùÒÔ84x+100y=9.2g£¬
ÁªÁ¢·½³Ì½âµÃx=0.05 mol£¬y=0.05 mol£¬
ÄܼÆËãNaHCO
3µÄÖÊÁ¿·ÖÊý£¬¹ÊC´íÎó£»
D£®ÓÉCÖмÆËã¿ÉÖª£¬»ìºÏÎïÖÐNaHCO
3ºÍKHCO
3µÄÎïÖʵÄÁ¿Ö®±ÈΪ1£º1£¬¹ÊDÕýÈ·£¬
¹ÊÑ¡£ºC£®