ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ
A£®ÎüÈÈ·´Ó¦Ò»¶¨ÐèÒª¼ÓÈȲÅÄÜ·¢Éú£¬·ÅÈÈ·´Ó¦²»ÐèÒª´ÓÍâ½çÎüÊÕÈκÎÄÜÁ¿¾ÍÄÜ·¢Éú
B£®°éÓÐÄÜÁ¿±ä»¯µÄÎïÖʱ仯¶¼ÊÇ»¯Ñ§±ä»¯
C£®ÓÉC(ʯī) ¡ú C(½ð¸Õʯ)£»¦¤H£½+11.9 kJ/ mol¿ÉÖª£¬½ð¸Õʯ±ÈʯīÎȶ¨
D£®ÔÚÏ¡ÈÜÒºÖУºH+£¨aq£©+OH£­£¨aq£©£½H2O£¨l£©£»¦¤H£½£­57.3 kJ/ mol£¬Èô½«º¬0.5 mol H2SO4µÄŨÁòËáÓ뺬1 mol NaOHµÄÈÜÒº»ìºÏ£¬·Å³öµÄÈÈÁ¿´óÓÚ57.3 kJ
D
·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬»¹ÊÇÎüÈÈ·´Ó¦£¬Óë·´Ó¦Ìõ¼þÎ޹أ¬Ñ¡ÏîA²»ÕýÈ·£»Ñ¡ÏîB²»ÕýÈ·£¬°éËæÄÜÁ¿±ä»¯µÄ²»Ò»¶¨ÊÇ»¯Ñ§±ä»¯£»Ê¯Ä«×ª»¯Îª½ð¸Õʯ£¬ÊýÎüÈÈ·´Ó¦£¬Òò´ËʯīµÄÄÜÁ¿µÍÓÚ½ð¸ÕʯµÄ£¬ËùÒÔʯī±È½ð¸ÕʯÎȶ¨£»ÓÉÓÚŨÁòËáÈÜÓÚË®·Å³ö´óÁ¿µÄÈÈ£¬Òò´ËÑ¡ÏîDÕýÈ·£¬´ð°¸Ñ¡D¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£º¼ÆËãÌâ

ÒÑÖª£º2H2 ( g ) + O2 ( g ) = 2H2O ( l );  ¡÷H = £­571.6kJ/mol
2H2 ( g ) + O2 ( g ) = 2H2O ( g );  ¡÷H = £­483.6kJ/mol
CH4 ( g ) + 2O2 ( g ) = 2H2O ( l ) + CO2 ( g );  ¡÷H = £­890 kJ/mol
±ê×¼×´¿öÏ£¬È¡¼×ÍéºÍÇâÆøµÄ»ìºÏÆøÌå11.2 LÍêȫȼÉÕºó»Ö¸´µ½³£Î£¬Ôò·Å³öµÄÈÈÁ¿Îª203.32kJ£¬ÊÔÇó»ìºÏÆøÌåÖм×ÍéºÍÇâÆøÌå»ý±È¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

¢ñ£¨1£©ÔÚ101kPaʱ£¬H2ÔÚ1.00molO2ÖÐÍêȫȼÉÕÉú³É2.00molҺ̬H2O,·Å³ö571.6kJµÄÈÈÁ¿£¬±íʾH2ȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ________________________________¡£
£¨2£©1.00L 1.00mol/L H2SO4ÈÜÒºÓë2.00L 1.00mol/L NaOHÈÜÒºÍêÈ«·´Ó¦£¬·Å³ö114.6kJµÄÈÈÁ¿£¬¸Ã·´Ó¦µÄ·´Ó¦ÈÈΪ_____________________£¬±íʾÆäÖкÍÈȵÄÈÈ»¯Ñ§·½³ÌʽΪ________________________  _¡£
¢ò£ºNOºÍCO¶¼ÊÇÆû³µÎ²ÆøÖеÄÓк¦ÎïÖÊ£¬ËüÃÇÄÜ»ºÂýµØÆð·´Ó¦£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2CO£«2NO=N2£«2CO2£¬ÎªÁË¿ØÖÆ´óÆøÎÛȾ£¬Ìá³öÏÂÁн¨Ò飺
A.ʹÓô߻¯¼Á        B.¸Ä±äѹǿ      C.Ìá¸ß·´Ó¦Î¶È
ÄãÈÏΪ¿ÉÐеķ½·¨ÊÇ             £¬ÀíÓÉÊÇ                                        

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨5·Ö£©°Ñú×÷ΪȼÁÏ¿Éͨ¹ýÏÂÁÐÁ½ÖÖ;¾¶£º
;¾¶¢ñ  C(s)+O2(g)=====CO2(g)£»¦¤H1£¼0    ¢Ù
;¾¶¢ò ÏÈÖƳÉˮúÆø£º
C(s)+H2O(g)=====CO(g)+H2(g)£»¦¤H2£¾0    ¢Ú
ÔÙȼÉÕˮúÆø£º
2CO(g)+O2(g)=====2CO2(g)£»¦¤H3£¼0            ¢Û
2H2(g)+O2(g)=====2H2O(g)£»¦¤H4£¼0       ¢Ü
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1);¾¶¢ñ·Å³öµÄÈÈÁ¿ÀíÂÛÉÏ_________(Ìî¡°´óÓÚ¡±¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±);¾¶¢ò·Å³öµÄÈÈÁ¿¡£
(2)¦¤H1¡¢¦¤H2¡¢¦¤H3¡¢¦¤H4µÄÊýѧ¹ØϵʽÊÇ_______________¡£
(3)£®ÒÑÖª£º¢Ù C(s)£«O2(g)£½CO2(g)£»        DH£½¡ª393.5 kJ¡¤mol-1
¢Ú 2CO(g)£«O2(g)£½2CO2(g)£»        DH£½-566 kJ¡¤mol-1
¢Û TiO2(s)£«2Cl2(g)£½TiCl4(s)£«O2(g)£»   DH£½+141 kJ¡¤mol-1
ÔòTiO2(s)£«2Cl2(g)£«2C(s)£½TiCl4(s)£«2CO(g)µÄDH£½                ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

°×Á×ÓëÑõ¿É·¢ÉúÈçÏ·´Ó¦£ºP4£«5O2===P4O10.ÒÑÖª¶ÏÁÑÏÂÁл¯Ñ§¼üÐèÒªÎüÊÕµÄÄÜÁ¿·Ö±ðΪ£ºP¡ªP a kJ/mol¡¢P¡ªO b kJ/mol¡¢P==="O" c kJ/mol¡¢O==="O" d kJ/mol.
¸ù¾ÝÓÒͼËùʾµÄ·Ö×ӽṹºÍÓйØÊý¾Ý¹ÀËã¸Ã·´Ó¦µÄ¦¤H£¬ÆäÖÐÕýÈ·µÄÊÇ
A£®(4c£«12b£­6a£­5d) kJ/mol
B£®(6a£«5d£­4c£­12b) kJ/mol
C£®(4c£«12b£­4a£­5d) kJ/mol
D£®(4a£«5d£­4c£­12b) kJ/mol

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÒÑÖª£º
£¨1£©Zn£¨s£©+1/2O2£¨g£©=ZnO£¨s£©£»¦¤H=£­348.3kJ/mol
£¨2£©2Ag£¨s£©+1/2 O2£¨g£©= Ag2O£¨s£©£»¦¤H= £­31.0kJ/mol
ÔòZn£¨s£©+ Ag2O£¨s£©= ZnO£¨s£©+ 2Ag£¨s£©µÄ¦¤HµÈÓÚ£¨     £©
A£®£­317.3kJ/molB£®£­379.3kJ/molC£®£­332.8 kJ/molD£®+317.3 kJ/mol

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨6·Ö£©Ð´³öÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£º
£¨1£©SiH4ÊÇÒ»ÖÖÎÞÉ«µÄÆøÌ壬Óöµ½¿ÕÆøÄÜ·¢Éú±¬Õ¨ÐÔ×Ôȼ£¬Éú³ÉSiO2ºÍҺ̬H2O£¬ÒÑÖªÊÒÎÂÏÂ2g SiH4×Ôȼ·Å³öÈÈÁ¿89.2kJ£¬ÆäÈÈ»¯Ñ§·½³ÌʽΪ£º                        £»
£¨2£©ÔÚ25¡æ¡¢101kPaÏ£¬ÔÚÏ¡ÈÜÒºÖУ¬Ç¿ËáÇ¿¼î·´Ó¦Éú³É1mol Һ̬ˮ·ÅÈÈ57.3kJ¡£Ð´³öÏ¡ÁòËáÓëÉÕ¼îÈÜÒº·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ______________       _________   __£»
£¨3£©ÒÑÖª60g C(s)Óë¸ßÎÂË®ÕôÆø·´Ó¦ÖÆÈ¡COºÍH2ʱÎüÊÕ657.5KJÈÈÁ¿£¬Ð´³öÈÈ»¯Ñ§·½³Ìʽ                                             ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÒÑÖªÔÚ101kPaʱ£ºCH4£¨g£©£«2O2(g)=CO2(g)+2H2O(g)   ¦¤H=£­820 kJ¡¤mol£­1¡£ÔòÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
A£®CH4£¨g£©£«2O2(g)=CO2(g)+2H2O(l)¦¤H£¾£­820 kJ¡¤mol£­1
B£®CH4µÄȼÉÕÈÈÊÇ820 kJ
C£®1mol CH4ºÍ2mol O2µÄ¼üÄÜÖ®ºÍ´óÓÚ1mol CO2ºÍ2mol H2OµÄ¼üÄÜÖ®ºÍ
D£®11£®2L£¨±ê×¼×´¿ö£©CH4ÍêȫȼÉÕÉú³ÉÆø̬ˮʱ·Å³ö410kJÈÈÁ¿¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

[2012¡¤½­Ãŵڶþ´Îµ÷ÑÐ]ÓйØÄÜÁ¿µÄÅжϻò±íʾ·½·¨ÕýÈ·µÄÊÇ£¨   £©
A£®ÓÉ£ºH+(aq)£«OH£­(aq)£½H2O(l)¡÷H£½£­57.3kJ/mol£¬¿ÉÖª£ºº¬1mol CH3COOHµÄÈÜÒºÓ뺬1mol NaOHµÄÈÜÒº»ìºÏ£¬·Å³öÈÈÁ¿µÈÓÚ57.3 kJ
B£®´ÓC£¨Ê¯Ä«£©£½C£¨½ð¸Õʯ£©¡÷H£½£«1.9kJ/mol£¬¿É֪ʯī±È½ð¸Õʯ¸üÎȶ¨
C£®µÈÖÊÁ¿µÄÁòÕôÆøºÍÁò¹ÌÌå·Ö±ðÍêȫȼÉÕ£¬ºóÕ߷ųöÈÈÁ¿¸ü¶à
D£®2gH2ÍêȫȼÉÕÉú³ÉҺ̬ˮ·Å³ö285.8kJÈÈÁ¿£¬ÔòÇâÆøȼÉÕµÄÈÈ»¯Ñ§·½³ÌʽΪ£º2H2(g)£«O2(g)£½2 H2O(l)¡÷H£½£­285.8kJ/mol

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸