½ðÊôÄøÓй㷺µÄÓÃ;´ÖÄøÖк¬ÓÐÉÙÁ¿Fe¡¢Zn¡¢Cu¡¢PtµÈÔÓÖÊ£¬¿ÉÓõç½â·¨ÖƱ¸¸ß´¿¶ÈµÄÄø£¬ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ£¨ÒÑÖª£ºÑõ»¯ÐÔFe2+£¼Ni2+£¼Cu2+£©( )
A£®Ñô¼«·¢Éú»¹Ô·´Ó¦£¬Æäµç¼«·´Ó¦Ê½£ºNi2+ + 2e¡ªNi
B£®µç½â¹ý³ÌÖУ¬Ñô¼«ÖÊÁ¿µÄ¼õÉÙÓëÒõ¼«ÖÊÁ¿µÄÔö¼ÓÏàµÈ
C£®µç½âºó£¬ÈÜÒºÖдæÔڵĽðÊôÑôÀë×ÓÖ»ÓÐFe2+ ºÍZn2+
D£®µç½âºó£¬µç½â²Ûµ×²¿µÄÑô¼«ÄàÖÐÖ»ÓÐCuºÍPt
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄêºÓÄÏÊ¡¸ß¶þÉϵÚÒ»´Î¿¼ÊÔ»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ëÂ(N2H4)ÊÇ»ð¼ý·¢¶¯»úµÄȼÁÏ£¬ËüÓëN2O4·´Ó¦Ê±£¬N2O4ΪÑõ»¯¼Á£¬Éú³ÉµªÆøºÍË®ÕôÆø¡£ÒÑÖª£º
N2(g)£«2O2(g)£½N2O4(g) ¦¤H£½£«8.7 kJ/mol£¬
N2H4(g)£«O2(g)£½N2(g)£«2H2O(g) ¦¤H£½£534.0 kJ/mol£¬
ÏÂÁбíʾë¸úN2O4·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£¬ÕýÈ·µÄÊÇ( )
A£®2N2H4(g)£«N2O4(g)£½3N2(g) £«4H2O(g) ¦¤H£½£542.7 kJ/mol
B£®2N2H4(g)£«N2O4(g)£½3N2(g)£«4H2O(g) ¦¤H£½£1059.3 kJ/mol
C£®N2H4(g)£«N2O4(g)£½N2(g)£«2H2O(g) ¦¤H£½£1076.7 kJ/mol
D£®2N2H4(g)£«N2O4(g)£½3N2(g)£«4H2O(g) ¦¤H£½£1076.7 kJ/mol
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìÕã½Ê¡ÉÜÐËÊиßÈýÉÏѧÆÚÊÊÓ¦ÐÔ¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÒÇÆ÷Ãû³ÆΪ¡°ÕôÁóÉÕÆ¿¡±µÄÊÇ£¨ £©
A. B. C. D.
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìɽ¶«Ê¡ëøÖÝÊиßÈýÉÏѧÆÚ10ÔÂÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
¹Û²ìÏÂÁм¸¸ö×°ÖÃʾÒâͼ£¬ÓйØÐðÊöÕýÈ·µÄÊÇ £¨ £©
A£®×°ÖâÙÖÐÑô¼«ÉÏÎö³öºìÉ«¹ÌÌå
B£®×°ÖâڵĴý¶ÆÌúÖÆÆ·Ó¦ÓëµçÔ´¸º¼«ÏàÁ¬
C£®×°ÖâÛÖÐÍâµç·µç×ÓÓÉa¼«Á÷Ïòb¼«
D£®×°ÖâܵÄÑô¼«·´Ó¦Îª£º2H+ + 2e¡ª = H2¡ü
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìɽ¶«Ê¡ëøÖÝÊиßÈýÉÏѧÆÚ10ÔÂÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÏÂͼËùʾװÖÃÖУ¬ÒÑÖªµç×ÓÓÉb¼«Ñص¼ÏßÁ÷Ïòп¡£ÏÂÁÐÅжÏÕýÈ·µÄÊÇ ( )
A£®¸Ã×°ÖÃÖÐCu¼«ÎªÑô¼«
B£®Ò»¶Îʱ¼äºóпƬÖÊÁ¿¼õÉÙ
C£®b¼«·´Ó¦µÄµç¼«·´Ó¦Ê½ÎªH2£2e££«2OH£===2H2O
D£®µ±Í¼«µÄÖÊÁ¿±ä»¯Îª32 gʱ£¬a¼«ÉÏÏûºÄµÄO2µÄÌå»ýΪ5.6 L
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìɽ¶«Ê¡ëøÖÝÊиßÈýÉÏѧÆÚ10ÔÂÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ ( )
A£®Èκλ¯Ñ§·´Ó¦¶¼°éËæ×ÅÄÜÁ¿µÄ±ä»¯
B£®Éý¸ßζȻò¼ÓÈë´ß»¯¼Á£¬¿ÉÒԸı仯ѧ·´Ó¦µÄ·´Ó¦ÈÈ
C£®»¯Ñ§·´Ó¦ÖеÄÄÜÁ¿±ä»¯¶¼ÊÇÒÔÈÈÁ¿µÄÐÎʽÌåÏÖ
D£®2CO(g)£«O2(g)£½2CO2(g) ¡÷H<0£¬Ôò56g COºÍ32g O2Ëù¾ßÓеÄ×ÜÄÜÁ¿Ð¡ÓÚ88g CO2Ëù¾ßÓеÄ×ÜÄÜÁ¿
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ì½Î÷Ê¡¸ßÈýÉÏѧÆÚµÚÒ»´ÎÁª¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ʵÑéÊÒ´Óº¬ÂÈ»¯ÄÆ¡¢ÏõËá¼Ø»ìºÏÒºÖÐÌáÈ¡KNO3µÄ¹ý³ÌÈçÏÂͼËùʾ¡£ÏÂÁзÖÎöÕýÈ·µÄÊÇ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ì¹óÖÝÊ¡¸ßÈýÉϵڶþ´ÎÄ£Ä⻯ѧÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
¡¾»¯Ñ§¡ª¡ªÑ¡ÐÞ2£º»¯Ñ§Óë¼¼Êõ¡¿
ij¹¤³§ÓÃÈíÃ̿󣨺¬MnO2Ô¼70% ¼°A12O3£©ºÍÉÁп¿ó£¨º¬ZnSÔ¼80£¥¼°FeS£©¹²Í¬Éú²úMnO2ºÍZn£¨¸Éµç³ØÔÁÏ£©¡£
ÒÑÖª£º¢ÙAÊǵĻìºÏÒº¡£
¢ÚIVÖеĵç½â·½³ÌʽΪ£º
£¨l£©AÖÐÊôÓÚ»¹Ô²úÎïµÄÊÇ________________________¡£
£¨2£©¼ÓÈËMnCO3¡¢Zn2£¨OH£©2CO3µÄ×÷Óà ________________________¡£
IIÐèÒª¼ÓÈȵÄÔÒòÊÇ£º____________________¡£CµÄ»¯Ñ§Ê½ÊÇ _______________¡£
£¨3£©¸ÃÉú²úÖгýµÃµ½MnO2ºÍZnÒÔÍ⣬»¹¿ÉµÃµ½µÄ¸±²úÆ·ÊÇ_________________¡£
£¨4£©Èç¹û²»¿¼ÂÇÉú²úÖеÄËðºÄ£¬³ý¿óʯÍ⣬Ð蹺ÂòµÄ»¯¹¤ÔÁÏÊÇ_____________¡£
£¨5£©Òª´ÓNa2SO4ÈÜÒºÖеõ½Ã¢Ïõ£¨Na2SO4¡¤10H2O£©£¬Ðè½øÐеIJÙ×÷ÓÐÕô·¢Å¨Ëõ¡¢___________¡¢¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔïµÈ¡£
£¨6£©´ÓÉú²úMnO2ºÍZnµÄ½Ç¶È¼ÆË㣬ÈíÃÌ¿óºÍÉÁп¿óµÄÖÊÁ¿±È´óÔ¼ÊÇ__________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄ꼪ÁÖÊ¡¸ßÒ»ÉÏÆÚ³õ»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÏÂÁÐÈÜÒºÖеÄÂÈÀë×ÓŨ¶ÈÓë50 mL 1 mol¡¤L£1µÄAlCl3ÈÜÒºÖÐÂÈÀë×ÓŨ¶ÈÏàµÈµÄÊÇ
A£®75 mL 2 mol¡¤L£1µÄCaCl2 B£®75 mL 1 mol¡¤L£1µÄNH4Cl
C£®150 mL 1 mol¡¤L£1µÄNaCl D£®150 mL 3 mol¡¤L£1µÄKCl
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com