Question

£¨12·Ö£©£¨1£©ÔÚŨÏõËáÖзÅÈëͭƬ¡£
¢Ù¿ªÊ¼·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ___________________________________
¢ÚÈôÍ­ÓÐÊ£Ó࣬Ôò·´Ó¦½«Òª½áÊøʱµÄ·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ         ¡£
¢Û´ý·´Ó¦Í£Ö¹ºó£¬ÔÙ¼ÓÈëÉÙÁ¿µÄ25%µÄÏ¡ÁòËᣬÕâʱͭƬÉÏÓÖÓÐÆøÅݲúÉú£¬ÆäÔ­ÒòÊÇ
_____________________________________________________¡£
(2) ÔÚ100mL»ìºÏËáÖУ¬c£¨HNO₃£© = 0£®4mol¡¤L^-1£¬c£¨H₂SO₄£© = 0£®2mol¡¤L^-1£¬ÏòÆäÖмÓÈë2£®56gÍ­·Û£¬Î¢ÈÈ£¬´ý³ä·Ö·´Ó¦ºó£¬ÈÜÒºÖÐCu^2£«µÄÎïÖʵÄÁ¿Å¨¶ÈΪ         ¡£
£¨3£©14gÍ­ÒøºÏ½ðÓë¹ýÁ¿µÄijŨ¶ÈµÄÏõËáÈÜÒº·´Ó¦£¬´ý·Å³öµÄÆøÌåÓë1.12L£¨±ê×¼×´¿öÏ£©ÑõÆø»ìºÏͨÈëË®ÖУ¬Ç¡ºÃÈ«²¿±»Ë®ÎüÊÕ£¬ÔòºÏ½ðÖÐÍ­µÄÖÊÁ¿ÊÇ        ¡£

Answer 1

(12·Ö)
£¨1£©¢Ù Cu + 4HNO₃£¨Å¨£©= Cu£¨NO₃£©₂ + 2NO₂¡ü + 2H₂O £¨2·Ö£©
¢Ú3Cu + 8H^£« + 2NO₃^£­ =3Cu^2£« + 2NO¡ü + 4H₂O£¨2·Ö£©
¢ÛÔÙ¼ÓÈëÏ¡H₂SO₄£¬H^£«ÓëNO₃^¨D¹¹³ÉÁËÑõ»¯Ìõ¼þ¡££¨2·Ö£©
£¨2£©0.15mol¡¤L^-1 £¨3·Ö£©
£¨3£©3£®2g£¨3·Ö£©

£¨1£©Í­ÓëÏõËá·´Ó¦ÓëÆäŨ¶ÈÓйأº
Cu + 4HNO₃£¨Å¨£©= Cu£¨NO₃£©₂ + 2NO₂¡ü + 2H₂O
3Cu + 8HNO₃£¨Ï¡£©="3" Cu£¨NO₃£©₂ + 2NO¡ü + 4H₂O
¢Û´ý·´Ó¦Í£Ö¹ºó£¬ÔÙ¼ÓÈëÉÙÁ¿µÄ25%µÄÏ¡ÁòËáÌṩH^£«£¬ÈÜÒºÖеÄNO₃^£­¿É¼ÌÐøÑõ»¯Í­
£¨2£©NO₃^£­¡¢H^£«¡¢Cu¾ùΪ0£®04mol£¬½áºÏÏÂÃæµÄÀë×Ó·½³Ìʽ£º
3Cu   +   8H^£«  +  2NO₃^£­ =3Cu^2£« + 2NO¡ü + 4H₂O
0.015mol   0.04mol   0.01mol   0.015mol
ÈÜÒºÖÐCu^2£«µÄÎïÖʵÄÁ¿Å¨¶ÈΪ0.15mol¡¤L^-1
(3)ÉèºÏ½ðÖÐͭΪx mol£¬ÒøΪ y mol
ÓɺϽðÖÊÁ¿¿ÉÖª£º64x+108y=14  Óɵç×ÓÊغã¿ÉµÃ£º2x+y=4¡Á11.2/22.4
x=0.05mol  y=0.1mol
ËùÒÔͭΪ3£®2g