Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ij°à¼¶Í¬Ñ§²éÔÄ×ÊÁÏ£¬¶ÔNa2SÓÐÁËÒ»¶¨µÄÈÏʶ£¬²¢Ìá³öÁËÒÔϼ¸¸öÎÊÌ⣬Çë»Ø´ð£º
(1)1000¡æʱ£¬ÔÚÃܱÕÈÝÆ÷ÖмÓÈëÒ»¶¨Á¿µÄNa2SO4¹ÌÌåʹÆä·¢ÉúÒÔÏ·´Ó¦´ïµ½Æ½ºâ£º
Na2SO4(s)£«4H2(g) Na2S(s)£«4H2O(g)¡¡¦¤H>0Èô·´Ó¦ÔÚºãκãÈÝ״̬ϽøÐУ¬»Ø´ðÒÔÏÂÎÊÌ⣺
ÏòÈÝÆ÷Öзֱð¼ÓÈëÒÔÏÂÎïÖÊ£¬Åж϶ÔƽºâÓÐÎÞÓ°Ï죬ÓÐÓ°ÏìµÄÌîд³öƽºâÒƶ¯µÄ·½Ïò¡£
¢Ù¼ÓÈëNa2SO4¡¡¡¡¡¡¡¡¡¡¡£¢Ú¼ÓÈ뽹̿¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
(2)ÏòNa2SµÄŨÈÜÒºÖÐÖðµÎ¼ÓÈëÏ¡ÑÎËᣬֱµ½²»ÔÙÉú³ÉH2SÆøÌåΪֹ£¬ÔòÔڴ˹ý³ÌÖУ¬ÈÜÒºµÄc(HS£)±ä»¯Ç÷ÊÆ¿ÉÄÜÊÇ¡¡¡¡¡¡¡£
a.Öð½¥¼õС b.Öð½¥Ôö´ó
c.ÏÈÖð½¥Ôö´ó£¬¶øºó¼õС d.ÏÈÖð½¥¼õС£¬¶øºóÔö´ó
(3)Na2SÈÜÒºÓëÏÂÁÐÈÜÒº»ìºÏ£¬²»ÄÜ·¢Éú·´Ó¦µÄÊÇ¡¡¡¡¡¡¡¡¡£
¢ÙH2S¡¡¢ÚSO2¡¡¢ÛNa2SO3¡¡¢ÜËáÐÔKMnO4ÈÜÒº¡¡¢ÝCuSO4 ¢ÞÂÈË®
(4)д³öNa2SºÍAlCl3ÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ij°à¼¶Í¬Ñ§²éÔÄ×ÊÁÏ£¬¶ÔNa2SÓÐÁËÒ»¶¨µÄÈÏʶ£¬²¢Ìá³öÁËÒÔϼ¸¸öÎÊÌ⣬Çë»Ø´ð£º
(1)1000¡æʱ£¬ÔÚÃܱÕÈÝÆ÷ÖмÓÈëÒ»¶¨Á¿µÄNa2SO4¹ÌÌåʹÆä·¢ÉúÒÔÏ·´Ó¦´ïµ½Æ½ºâ£º
Na2SO4(s)£«4H2(g) Na2S(s)£«4H2O(g)¡¡¦¤H>0Èô·´Ó¦ÔÚºãκãÈÝ״̬ϽøÐУ¬»Ø´ðÒÔÏÂÎÊÌ⣺
ÏòÈÝÆ÷Öзֱð¼ÓÈëÒÔÏÂÎïÖÊ£¬Åж϶ÔƽºâÓÐÎÞÓ°Ï죬ÓÐÓ°ÏìµÄÌîд³öƽºâÒƶ¯µÄ·½Ïò¡£
¢Ù¼ÓÈëNa2SO4¡¡¡¡¡¡¡¡¡¡¡£¢Ú¼ÓÈ뽹̿¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
(2)ÏòNa2SµÄŨÈÜÒºÖÐÖðµÎ¼ÓÈëÏ¡ÑÎËᣬֱµ½²»ÔÙÉú³ÉH2SÆøÌåΪֹ£¬ÔòÔڴ˹ý³ÌÖУ¬ÈÜÒºµÄc(HS£)±ä»¯Ç÷ÊÆ¿ÉÄÜÊÇ¡¡¡¡¡¡¡£
a.Öð½¥¼õС b.Öð½¥Ôö´ó
c.ÏÈÖð½¥Ôö´ó£¬¶øºó¼õС d.ÏÈÖð½¥¼õС£¬¶øºóÔö´ó
(3)Na2SÈÜÒºÓëÏÂÁÐÈÜÒº»ìºÏ£¬²»ÄÜ·¢Éú·´Ó¦µÄÊÇ¡¡¡¡¡¡¡¡¡£
¢ÙH2S¡¡¢ÚSO2¡¡¢ÛNa2SO3¡¡¢ÜËáÐÔKMnO4ÈÜÒº¡¡¢ÝCuSO4 ¢ÞÂÈË®
(4)д³öNa2SºÍAlCl3ÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011½ìºþÄÏÊ¡³¤É³ÊÐÒ»ÖÐѧ¸ßÈýµÚÁù´ÎÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ
ij°à¼¶Í¬Ñ§²éÔÄ×ÊÁÏ£¬¶ÔNa2SÓÐÁËÒ»¶¨µÄÈÏʶ£¬²¢Ìá³öÁËÒÔϼ¸¸öÎÊÌ⣬Çë»Ø´ð£º
(1)1000¡æʱ£¬ÔÚÃܱÕÈÝÆ÷ÖмÓÈëÒ»¶¨Á¿µÄNa2SO4¹ÌÌåʹÆä·¢ÉúÒÔÏ·´Ó¦´ïµ½Æ½ºâ£º
Na2SO4(s)£«4H2(g) Na2S(s)£«4H2O(g)¡¡¦¤H>0Èô·´Ó¦ÔÚºãκãÈÝ״̬ϽøÐУ¬»Ø´ðÒÔÏÂÎÊÌ⣺
ÏòÈÝÆ÷Öзֱð¼ÓÈëÒÔÏÂÎïÖÊ£¬Åж϶ÔƽºâÓÐÎÞÓ°Ï죬ÓÐÓ°ÏìµÄÌîд³öƽºâÒƶ¯µÄ·½Ïò¡£
¢Ù¼ÓÈëNa2SO4¡¡¡¡¡¡¡¡¡¡¡£¢Ú¼ÓÈ뽹̿¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
(2)ÏòNa2SµÄŨÈÜÒºÖÐÖðµÎ¼ÓÈëÏ¡ÑÎËᣬֱµ½²»ÔÙÉú³ÉH2SÆøÌåΪֹ£¬ÔòÔڴ˹ý³ÌÖУ¬ÈÜÒºµÄc(HS£)±ä»¯Ç÷ÊÆ¿ÉÄÜÊÇ¡¡¡¡¡¡¡£
a.Öð½¥¼õС b.Öð½¥Ôö´ó
c.ÏÈÖð½¥Ôö´ó£¬¶øºó¼õС d.ÏÈÖð½¥¼õС£¬¶øºóÔö´ó
(3)Na2SÈÜÒºÓëÏÂÁÐÈÜÒº»ìºÏ£¬²»ÄÜ·¢Éú·´Ó¦µÄÊÇ¡¡¡¡¡¡¡¡¡£
¢ÙH2S¡¡¢ÚSO2¡¡¢ÛNa2SO3¡¡¢ÜËáÐÔKMnO4ÈÜÒº¡¡¢ÝCuSO4 ¢ÞÂÈË®
(4)д³öNa2SºÍAlCl3ÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄê°²»ÕÊ¡ËÞËÉÏظ´ÐËÖÐѧ¸ß¶þµÚÒ»´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ
1000¡æʱ£¬ÔÚÃܱÕÈÝÆ÷ÖмÓÈëÒ»¶¨Á¿µÄNa2SO4¹ÌÌåʹÆä·¢ÉúÒÔÏ·´Ó¦²¢´ïƽºâ£ºNa2SO4(s)+4H2(g)Na2S(s)+4H2O(g)£¬¡÷H<0£¬ÔÚºãκãÈÝʱ»Ø´ðÒÔÏÂÎÊÌ⣺
(1)ÏòÈÝÆ÷Öзֱð¼ÓÈëÒÔÏÂÎïÖÊ£¬Åж϶ÔƽºâÓÐÎÞÓ°Ï죬ÓÐÓ°ÏìµÄÓ¦Ìîд³öƽºâÒƶ¯µÄ·½Ïò¡£
¢Ù¼ÓÈëNa2SO4_________________¡£¢Ú¼ÓÈ뽹̿________________¡£
(2)Èô³õʱ¼ÓÈëµÄNa2SO4ÊÇ1£®42g£¬Æ½ºâʱÈÝÆ÷ÖйÌÌåÎïÖÊÖÊÁ¿ÊÇ1£®10g£¬Na2SO4µÄת»¯ÂÊÊÇ_______________¡£
(3)Èô½«ÈÝÆ÷ζÈÉý¸ß20¡æ£¬H2ÔÚ»ìºÏÆøÌåÖк¬Á¿±ä»¯ÓÃÏÂͼÖÐ_____ ͼ±íʾ×îºÏÊÊ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ì°²»ÕÊ¡¸ß¶þµÚÒ»´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
1000¡æʱ£¬ÔÚÃܱÕÈÝÆ÷ÖмÓÈëÒ»¶¨Á¿µÄNa2SO4¹ÌÌåʹÆä·¢ÉúÒÔÏ·´Ó¦²¢´ïƽºâ£ºNa2SO4(s)+4H2(g)Na2S(s)+4H2O(g)£¬¡÷H<0£¬ÔÚºãκãÈÝʱ»Ø´ðÒÔÏÂÎÊÌ⣺
(1)ÏòÈÝÆ÷Öзֱð¼ÓÈëÒÔÏÂÎïÖÊ£¬Åж϶ÔƽºâÓÐÎÞÓ°Ï죬ÓÐÓ°ÏìµÄÓ¦Ìîд³öƽºâÒƶ¯µÄ·½Ïò¡£
¢Ù¼ÓÈëNa2SO4_________________¡£¢Ú¼ÓÈ뽹̿________________¡£
(2)Èô³õʱ¼ÓÈëµÄNa2SO4ÊÇ1£®42g£¬Æ½ºâʱÈÝÆ÷ÖйÌÌåÎïÖÊÖÊÁ¿ÊÇ1£®10g£¬Na2SO4µÄת»¯ÂÊÊÇ_______________¡£
(3)Èô½«ÈÝÆ÷ζÈÉý¸ß20¡æ£¬H2ÔÚ»ìºÏÆøÌåÖк¬Á¿±ä»¯ÓÃÏÂͼÖÐ_____ ͼ±íʾ×îºÏÊÊ¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com