ʵÑéÊÒÖÐÒªÖÆÈ¡½Ï´¿¾»µÄFe(OH)2³Áµí(²»±Ø´ÓË®ÈÜÒºÖÐÂ˳ö)£®ÏÖÓÐÏÂÁÐʵÑéÓÃÆ·£ºÊԹܡ¢½ºÍ·µÎ¹Ü¡¢100 ml ÉÕ±­¡¢²£Á§°ô¡¢Ìú¼Ų̈(´øÌúȦ)¡¢Ê¯ÃÞÍø¡¢¾Æ¾«µÆ¡¢½Ç³×¡¢ÆÕͨ©¶·¼°ÂËÖ½¡¢Ï¸Ìú·Û¡¢ÇâÑõ»¯ÄÆ(·ÖÎö´¿)¡¢¾ÃÖõ·¯¡¢¾ÃÖÃÕôÁóË®¡¢±½¡¢ËÄÂÈ»¯Ì¼¡¢ÎÞË®ÒÒ´¼¡¢Ï¡ÁòËᣮÇëÑ¡ÓúÏÀíµÄÒÇÆ÷ºÍÊÔ¼Á²¢²ÉÓñØÒªµÄ²Ù×÷·½·¨Íê³ÉʵÑé²½Öè(²»×¼½«½ºÍ·µÎ¹ÜÉìÈë·´Ó¦Æ÷ÖÐ)£®

(1)

ÅäÖÆÈÜÒº(ÎÞÑϸñµÄŨ¶È¼°Á¿µÄÏÞÖÆ£¬ÓйØÒÇÆ÷×é×°¿ÉÊ¡ÂÔ)£®

¢ÙÅäÖÆNaOHÈÜÒº£ºÑ¡È¡ÊÊÁ¿NaOH¹ÌÌåÓڽྻµÄÉÕ±­ÖУ¬¼ÓÈëÊÊÁ¿Öó·Ð¹ýµÄÕôÁóË®£¬½Á°èÖƵÃNaOHÈÜÒº±¸Óã®

¢ÚÅäÖÆ´¿FeSO4ÈÜÒº£º_____________________________

¢ÛÖƽϴ¿¾»µÄFe(OH)2³Áµí£º________________________

(2)

ÅäÖÆNaOHÈÜÒº¼°FeSO4ÈÜÒºËùÓõÄÕôÁóË®£¬Ó¦ÏȼÓÈÈÖó·Ð²¢ÀäÈ´ºóÔÙʹÓã¬ÆäÄ¿µÄÊÇ

_______________________________________

´ð°¸£º
½âÎö£º

(1)

¡¡¡¡¢ÙÓýdz×È¡ÊÊÁ¿ÂÌ·¯ÓڽྻµÄСÉÕ±­ÖУ¬È»ºó¼ÓÈëÊÊÁ¿Öó·Ð¹ýµÄÕôÁóË®ºÍÉÙÁ¿Ï¡H2SO4£¬Í¬Ê±¼ÓÈë×ãÁ¿Ìú·Û£¬Óò£Á§°ô³ä·Ö½Á°è£¬¹ýÂ˺ó½«ÂËҺתÒÆÓÚϸ¿ÚÊÔ¼ÁÆ¿Öб¸Óã®

¡¡¡¡¢ÚÈ¡ÊÊÁ¿ÐÂÅäÖƵÄFeSO4ÈÜÒºÓÚÊÔ¹ÜÖУ¬È»ºó¼ÓÈë1 ml ±½(±½ÔÚÉϲã)£¬ÔÙ½«ÎüÓÐNa0HÈÜÒºµÄ½ºÍ·µÎ¹ÜÐü´¹ÓÚÊÔ¹ÜÉÏ·½£¬ÖðµÎµÎÈëNaOHÈÜÒº£¬ÔÚ±½²ãÏÂÓа×É«µÄFe(OH)2³ÁµíÉú³É£®

(2)

³ýÈ¥ÈÜÔÚÕôÁóË®ÖеÄÉÙÁ¿O2£¬±ÜÃâÒòÑõÆøÑõ»¯¶øʹÖƵõÄFe(OH)2²»´¿


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

ÎÒ¹ú²ñ´ïľÅèµØÓµÓзḻµÄÑοó×ÊÔ´£¬ÒºÌå¿ó´²ÒԼؿóΪÖ÷£¬°éÉú×Åþ¡¢äåµÈ¶àÖÖ¿ó²ú£®¹¤ÒµÉÏÈ¡Ñκþ¿à±µÄŨËõÒº£¨¸»º¬K+¡¢Mg2+¡¢Br-¡¢SO42-¡¢Cl-µÈ£©£¬À´ÖÆÈ¡½Ï´¿¾»µÄÂÈ»¯¼Ø¾§Ìå¼°Òºä壨Br2£©£¬¹¤ÒµÁ÷³ÌÈçͼ1£º
¾«Ó¢¼Ò½ÌÍø
Çë¸ù¾ÝÒÔÉÏÁ÷³Ì£¬»Ø´ðÏà¹ØÎÊÌ⣺
£¨1£©²Ù×÷¢ÙÐèÒªµÄ²£Á§ÒÇÆ÷ÓÐ
 
£®
£¨2£©²ÎÕÕͼ2Èܽâ¶ÈÇúÏߣ¬ÓÐÈËÈÏΪ¹ÌÌåBÊÇÂÈ»¯¼Ø£¬ÓÐÈË˵ÊÇÂÈ»¯Ã¾£¬Çë˵³öÄãµÄ¹ÛµãºÍÖ§³ÅÄã¹ÛµãµÄÀíÓÉ£º
 
£®
£¨3£©Í¬Ñ§¼×Ä£·ÂʵÑéÊÒÖдÖÑÎÌá´¿µÄ²Ù×÷£¬¶ÔÉÏÊö²Ù×÷¢ÚºóÎÞÉ«ÒºÌåÉè¼ÆÁ˳ýÔÓÌᴿʵÑé·½°¸£¬Ò²¿ÉÖƵýϴ¿¾»µÄÂÈ»¯¼Ø¾§Ì壮Æä·½°¸Á÷³ÌÈçÏ£º
¾«Ó¢¼Ò½ÌÍø
ÓйØ×ÊÁÏ£º
»¯Ñ§Ê½ Ca£¨OH£©2 CaSO4 BaCO3 BaSO4 MgCO3 Mg£¨OH£©2
Ksp 1.0¡Á10Ò»4 7.1¡Á10Ò»5 8.1¡Á10Ò»9 1.08¡Á10Ò»10 3.5¡Á10Ò»5 1.6¡Á10Ò»11
£¨i£©¸Ã·½°¸ÖеÄÎÞÉ«ÈÜÒº¾ÍÊDzÙ×÷¢ÚºóÎÞÉ«ÒºÌ壬»ìºÏÒºAµÄÖ÷Òª³É·ÖÊÇ
 
£®£¨Ìѧʽ£©ÓÐÈËÈÏΪÓÃÒ»ÖÖÊÔ¼Á
 
£¨Ìѧʽ£©¾Í¿ÉÒÔÆðµ½»ìºÏÒºAµÄ×÷Óã¬ÄãµÄ¹ÛµãÊÇ
 
£®
£¨ii£©ÓÐͬѧÌá³ö´Ó¾­¼ÃÉÏ¿¼ÂÇ¿ÉÒÔÓÃʯ»ÒÈé´úÌæÊÔ¼ÁA½øÐÐʵÑ飬¾­ÌÖÂÛ£¬ÆäËûͬѧһÖÂÈÏΪ¸ÃÌáÒé²»¿ÉÐУ¬ËûÃǵÄÀíÓÉÊÇ
 
£®
£¨¢££©ÊµÑé¹ý³ÌÖУ¬ÈôҪȷ±£Mg2+ÍêÈ«³ý¾¡£¬Óù㷺pHÊÔÖ½²â¶¨ÈÜÒºµÄpHÓ¦¡Ý
 
£®£¨ÈôÀë×ÓŨ¶ÈСÓÚ10-5mol?L-1¿ÉÊÓ×÷Òѱ»ÍêÈ«³ý¾¡£©£®
£¨¢¤£©¶ÔÈÜÒºB¼ÓÈȲ¢²»¶ÏµÎ¼Ó1 mol?LÒ»1µÄÑÎËáÈÜÒº£¬Í¬Ê±ÓÃpHÊÔÖ½¼ì²âÈÜÒº£¬Ö±ÖÁpH=5ʱֹͣ¼ÓÑÎËᣬµÃµ½ÈÜÒºC£®ÓÉÈÜÒºCµÃµ½¹ÌÌåCµÄ²Ù×÷Ãû³ÆÊÇ
 
£®
£¨v£©¹¤ÒµÁ÷³ÌÖÐÒ²¿ÉÒÔ»ñµÃÂÈ»¯Ã¾µÄÈÜÒº£¬´ÓÖпÉÒÔÌáÈ¡½ðÊô²ÄÁÏþ£®·½·¨ÊÇ£º¼ÓÈÈÕô·¢ÂÈ»¯Ã¾µÄÈÜÒºµÃµ½MgCl2?6H2O£¬ÔÚ
 
ÖмÓÈÈʹÆäʧȥ½á¾§Ë®µÃµ½MgCl2£¬µç½â¾Í¿ÉÒԵõ½½ðÊôþ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÎïÀí½ÌÑÐÊÒ ÌâÐÍ£º058

ʵÑéÊÒÖÐÒªÖÆÈ¡½Ï´¿¾»µÄFe£¨OH£©2³Áµí£¨²»±Ø´ÓË®ÈÜÒºÖÐÂ˳ö£©¡£ÏÖÓÐÏÂÁÐʵÑéÓÃÆ·£º15¡Á150ÊԹܡ¢½ºÍ·µÎ¹Ü¡¢100mLÉÕ±­¡¢²£Á§°ô¡¢Ìú¼Ų̈£¨´øÌúȦ£©¡¢Ê¯ÃÞÍø¡¢¾Æ¾«µÆ¡¢½Ç³×¡¢ÆÕͨ©¶·¼°ÂËÖ½¡¢Ï¸Ìú·Û¡¢ÇâÑõ»¯ÄÆ(·ÖÎö´¿)¡¢¾ÃÖÃÂÌ·¯¡¢¾ÃÖõÄÕôÁóË®¡¢±½¡¢ËÄÂÈ»¯Ì¼¡¢ÎÞË®ÒÒ´¼¡¢Ï¡ÁòËá¡£ÇëÑ¡ÓúÏÀíµÄÒÇÆ÷ºÍÊÔ¼Á²¢²ÉÈ¡±ØÒªµÄ²Ù×÷·½·¨Íê³ÉʵÑé²½Ö裨²»×¼½«½ºÍ·µÎ¹ÜÉìÈë·´Ó¦Æ÷ÖУ©£º

£¨1£©ÅäÖÆÈÜÒº£¨ÎÞÑϸñµÄŨ¶È¼°Á¿µÄÏÞÖÆ£¬ÓйØÒÇÆ÷×é×°¿ÉÊ¡ÂÔ£©£º

ÏÈÈ¡ÊÊÁ¿NaOH¹ÌÌåÓڽྻµÄÉÕ±­ÖУ¬¼ÓÈëÊÊÁ¿Öó·Ð¹ýµÄÕôÁóË®£¬½Á°èÖƵÃNaOHÈÜÒº±¸Óá£

¢ÙÅäÖÆ´¿FeSO4ÈÜÒº£º________¡£

¢ÚÖƽϴ¿¾»µÄFe£¨OH£©2³Áµí£º________¡£

£¨2£©ÅäÖÆNaOHÈÜÒº¼°FeSO4ÈÜÒºËùÐèÓõÄÕôÁóË®£¬Ó¦ÏȼÓÈÈÖó·Ð²¢ÀäÈ´ºóÔÙʹÓã¬ÆäÄ¿µÄÊÇ________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º058

ʵÑéÊÒÖÐÒªÖÆÈ¡½Ï´¿¾»µÄFe£¨OH£©2³Áµí£¨²»±Ø´ÓË®ÈÜÒºÖÐÂ˳ö£©¡£ÏÖÓÐÏÂÁÐʵÑéÓÃÆ·£º15¡Á150ÊԹܡ¢½ºÍ·µÎ¹Ü¡¢100mLÉÕ±­¡¢²£Á§°ô¡¢Ìú¼Ų̈£¨´øÌúȦ£©¡¢Ê¯ÃÞÍø¡¢¾Æ¾«µÆ¡¢½Ç³×¡¢ÆÕͨ©¶·¼°ÂËÖ½¡¢Ï¸Ìú·Û¡¢ÇâÑõ»¯ÄÆ(·ÖÎö´¿)¡¢¾ÃÖÃÂÌ·¯¡¢¾ÃÖõÄÕôÁóË®¡¢±½¡¢ËÄÂÈ»¯Ì¼¡¢ÎÞË®ÒÒ´¼¡¢Ï¡ÁòËá¡£ÇëÑ¡ÓúÏÀíµÄÒÇÆ÷ºÍÊÔ¼Á²¢²ÉÈ¡±ØÒªµÄ²Ù×÷·½·¨Íê³ÉʵÑé²½Ö裨²»×¼½«½ºÍ·µÎ¹ÜÉìÈë·´Ó¦Æ÷ÖУ©£º

£¨1£©ÅäÖÆÈÜÒº£¨ÎÞÑϸñµÄŨ¶È¼°Á¿µÄÏÞÖÆ£¬ÓйØÒÇÆ÷×é×°¿ÉÊ¡ÂÔ£©£º

ÏÈÈ¡ÊÊÁ¿NaOH¹ÌÌåÓڽྻµÄÉÕ±­ÖУ¬¼ÓÈëÊÊÁ¿Öó·Ð¹ýµÄÕôÁóË®£¬½Á°èÖƵÃNaOHÈÜÒº±¸Óá£

¢ÙÅäÖÆ´¿FeSO4ÈÜÒº£º________¡£

¢ÚÖƽϴ¿¾»µÄFe£¨OH£©2³Áµí£º________¡£

£¨2£©ÅäÖÆNaOHÈÜÒº¼°FeSO4ÈÜÒºËùÐèÓõÄÕôÁóË®£¬Ó¦ÏȼÓÈÈÖó·Ð²¢ÀäÈ´ºóÔÙʹÓã¬ÆäÄ¿µÄÊÇ________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º»Æ¸ÔÖصã×÷Òµ¡¡¸ßÈý»¯Ñ§£¨Ï£© ÌâÐÍ£º058

ʵÑéÊÒÖÐÒªÖÆÈ¡½Ï´¿¾»µÄFe(OH)2³Áµí(²»±Ø´ÓË®ÈÜÒºÖÐÂ˳ö)£®ÏÖÓÐÏÂÁÐʵÑéÓÃÆ·£ºÊԹܡ¢½ºÍ·µÎ¹Ü¡¢100 ml ÉÕ±­¡¢²£Á§°ô¡¢Ìú¼Ų̈(´øÌúȦ)¡¢Ê¯ÃÞÍø¡¢¾Æ¾«µÆ¡¢½Ç³×¡¢ÆÕͨ©¶·¼°ÂËÖ½¡¢Ï¸Ìú·Û¡¢ÇâÑõ»¯ÄÆ(·ÖÎö´¿)¡¢¾ÃÖõ·¯¡¢¾ÃÖÃÕôÁóË®¡¢±½¡¢ËÄÂÈ»¯Ì¼¡¢ÎÞË®ÒÒ´¼¡¢Ï¡ÁòËᣮÇëÑ¡ÓúÏÀíµÄÒÇÆ÷ºÍÊÔ¼Á²¢²ÉÓñØÒªµÄ²Ù×÷·½·¨Íê³ÉʵÑé²½Öè(²»×¼½«½ºÍ·µÎ¹ÜÉìÈë·´Ó¦Æ÷ÖÐ)£®

(1)

ÅäÖÆÈÜÒº(ÎÞÑϸñµÄŨ¶È¼°Á¿µÄÏÞÖÆ£¬ÓйØÒÇÆ÷×é×°¿ÉÊ¡ÂÔ)£®

¢ÙÅäÖÆNaOHÈÜÒº£ºÑ¡È¡ÊÊÁ¿NaOH¹ÌÌåÓڽྻµÄÉÕ±­ÖУ¬¼ÓÈëÊÊÁ¿Öó·Ð¹ýµÄÕôÁóË®£¬½Á°èÖƵÃNaOHÈÜÒº±¸Óã®

¢ÚÅäÖÆ´¿FeSO4ÈÜÒº£º_____________________________

¢ÛÖƽϴ¿¾»µÄFe(OH)2³Áµí£º________________________

(2)

ÅäÖÆNaOHÈÜÒº¼°FeSO4ÈÜÒºËùÓõÄÕôÁóË®£¬Ó¦ÏȼÓÈÈÖó·Ð²¢ÀäÈ´ºóÔÙʹÓã¬ÆäÄ¿µÄÊÇ

_______________________________________

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸