¸ù¾ÝÈÈ»¯Ñ§·½³Ìʽ£ºS(s) + O2(g)= SO2(g)£»¡÷H=akJ¡¤mol£­1(a=-297.2),·ÖÎöÏÂÁÐ˵·¨Öв»ÕýÈ·µÄÊÇ
A£®S(s)ÔÚO2(g)ÖÐȼÉյķ´Ó¦ÊÇ·ÅÈÈ·´Ó¦
B£®S(g) + O2(g)= SO2(g)£»¡÷H=bkJ¡¤mol£­1,Ôòa<b
C£®1mol SO2(g)Ëù¾ßÓеÄÄÜÁ¿µÍÓÚ1mol S(s)Óë1mol O2(g)Ëù¾ßÓеÄÄÜÁ¿Ö®ºÍ
D£®16¿Ë¹ÌÌåÁòÔÚ¿ÕÆøÖгä·ÖȼÉÕ£¬¿É·Å³ö148.6kJµÄÈÈÁ¿
B
ÁòȼÉÕÊÇ·ÅÈÈ·´Ó¦£¬ËµÃ÷·´Ó¦ÎïµÄ×ÜÄÜÁ¿¸ßÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿£¬ËùÒÔA¡¢CÕýÈ·¡£¸ù¾ÝÈÈ»¯Ñ§·½³Ìʽ¿ÉÖª¼ÆË㣬ѡÏîDÕýÈ·¡£ÓÉÓÚÆø̬ÁòµÄÄÜÁ¿¸ßÓÚ¹Ì̬ÁòµÄÄÜÁ¿£¬ËùÒÔÆø̬ÁòȼÉշųöµÄÈÈÁ¿¶àÓà¹Ì̬ÁòȼÉշųöµÄÄÜÁ¿£¬µ«·ÅÈÈÔ½¶à£¬¡÷HԽС£¬ËùÒÔa´óÓÚb£¬Ñ¡ÏîB²»ÕýÈ·£¬´ð°¸Ñ¡B¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÒÑ֪ǿËáÓëÇ¿¼îÔÚÏ¡ÈÜÒºÖз´Ó¦µÄÖкÍÈȿɱíʾΪ£º
H+(aq)+OH-(aq)=H2O(l)£»¦¤H=-57.3kJ¡¤mol-1¶ÔÓÚÏÂÁз´Ó¦£º
CH3COOH(aq)+NaOH(aq)=CH3COONa(aq)+H2O(l)£»¦¤H= -Q1kJ¡¤mol-1
1/2H2SO4(Ũ)+NaOH(aq)=1/2Na2SON4(aq)+H2O(l)£»¦¤H= -Q2kJ¡¤mol-1
HNO3(aq)+NaOH(aq)=NaNO3(aq)+H2O(l)£»¦¤H= -Q3kJ¡¤mol-1ÉÏÊö·´Ó¦¾ùÔÚÈÜÒºÖнøÐУ¬ÔòÏÂÁÐQ1¡¢Q2¡¢Q3µÄ¹ØϵÕýÈ·µÄÊÇ  (    )
A£®Q1=Q2=Q3B£®Q2£¾Q1£¾Q3C£®Q2£¾Q3£¾Q1D£®Q2=Q3£¾Q1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

¸ù¾ÝÈÈ»¯Ñ§·½³Ìʽ(ÔÚ101kPaʱ)£ºS(s)+02(g)==SO2(g)£»¡÷H=-297.23kJ£¯mol£¬·ÖÎöÏÂÁÐ˵·¨Öв»ÕýÈ·µÄÊÇ
A£®1mol SÍêȫȼÉÕʱ·Å³öµÄÈÈÁ¿Îª297£®23kJ
B£®S(g)+O2(g)=SO2(g)·Å³öµÄÈÈÁ¿´óÓÚ297.23kJ
C£®S(g)+O2(g)=SO2(g)·Å³öµÄÈÈÁ¿Ð¡ÓÚ297.23KJ
D£®ÐγÉ1mol SO2µÄ»¯Ñ§¼üËùÊͷŵÄ×ÜÄÜÁ¿´óÓÚ¶ÏÁÑlmol S(s)ºÍ1mol O2(g)µÄ»¯Ñ§¼üËùÎüÊÕµÄ×ÜÄÜÁ¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨5·Ö£©£¨1£©ÒÑÖª1 g±ûÍéÍêȫȼÉÕÉú³ÉÆø̬ˮ£¬·Å³öµÄÈÈÁ¿ÊÇ47 kJ£¬ÓÖÖª£º
H2O£¨l£©== H2O£¨g£© ¦¤H£½+ 44 kJ¡¤mol£­1£¬Ôò±íʾ±ûÍéȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽΪ             
                                                 
(2)ÏÂͼÖÐÄܽÏ׼ȷµØ·´Ó³±ûÍéȼÉÕʱÄÜÁ¿±ä»¯µÄÇúÏßÊÇ________¡£

(3)ÒÑÖªÔÚ298KʱÏÂÁз´Ó¦µÄ·´Ó¦ÈÈΪ£º
¢ÙCH3COOH£¨l£© + 2O2£¨g£©£½2CO2£¨g£©+2H2O £¨l£©¡÷H1£½£­870.3KJ/mol
¢ÚC£¨s£©+O2£¨g£©£½CO2£¨g£©¡÷H2£½£­393.5KJ/mol
¢ÛH2£¨g£©+1/2O2£¨g£©£½H2O £¨l£© ¡÷H3£½£­285.8KJ/mol
Ôò·´Ó¦£º2C£¨s£© +2H2£¨g£© +O2£¨g£©£½CH3COOH£¨l£©µÄ·´Ó¦ÈÈ
¡÷H=         KJ/mol

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨8·Ö£©£¨1£©ÒÑÖªH2£¨g£©È¼ÉÕÈÈΪ-285£®8kJ¡¤mol-1ÓÃÌ«ÑôÄÜ·Ö½â10molË®ÏûºÄµÄÄÜÁ¿ÊÇ_____________kJ£»
£¨2£©ÒÑÖª0.4 molҺ̬ëÂ(N2 H4)Óë×ãÁ¿H2O2·´Ó¦£¬Éú³ÉµªÆøºÍË®ÕôÆø£¬·Å³ö256.65 kJµÄÈÈÁ¿¡£Ð´³ö¸Ã¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ__________________________________________________¡£
ÓÖÒÑÖª H2O£¨l£©=== H2O£¨g£©¦¤H£½£«44kJ¡¤mol£­1Ôò16gҺ̬ëÂÓë×ãÁ¿H2O2·´Ó¦£¬Éú³ÉµªÆøºÍҺ̬ˮ·Å³öµÄÈÈÁ¿ÊÇ_____________ kJ¡£
ÉÏÊö·´Ó¦Ó¦ÓÃÓÚ»ð¼ýÍƽø¼Á£¬³ýÊÍ·Å´óÁ¿µÄÈȺͿìËÙ²úÉú´óÁ¿ÆøÌåÍ⣬»¹ÓÐÒ»¸öºÜÍ»³öµÄÓŵãÊÇ____________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£º¼ÆËãÌâ

£¨ÌáÇ°½ø¶È£©
£¨1£©ÒÑÖªH2O£¨1£©=H2O£¨g£©£»¡÷H=+44KJ/mol¡£ÔÚ25¡æ¡¢101 kPaÏ£¬1g¼×´¼È¼ÉÕÉú³ÉCO2ºÍÆø̬ˮʱ·ÅÈÈ19.93kJ£¬Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽӦΪ______¡£
£¨2£©ÒÑÖªH2µÄȼÉÕÈÈ¡÷H=£­285.8kJ¡¤mol£­1£¬COµÄȼÉÕÈÈ¡÷H=£­282.8 kJ¡¤mol£­1¡£ÏÖÓÐCO¡¢H2¡¢CO2×é³ÉµÄ»ìºÏÆøÌå67.2L£¨±ê×¼×´¿ö£©£¬¾­³ä·ÖȼÉÕºó·Å³öµÄ×ÜÈÈÁ¿Îª710.0 kJ£¬²¢Éú³É18gҺ̬ˮ£¬ÇóȼÉÕÇ°»ìºÏÆøÌåÖÐCOµÄÌå»ý·ÖÊý¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÔÚʵÑéÊÒÖУ¬ÓÃ4molSO2Óë2molO2½øÐÐÏÂÁз´Ó¦£º2SO2(g)+O2(g)2SO3(g) ¡÷H=-196.64kJ/mol£¬µ±·Å³ö314.624kJÈÈÁ¿Ê±£¬SO2µÄת»¯ÂÊΪ£¨  £©
A£®40%B£®50%C£®80%D£®90%

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÒÑÖªÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£º
£¨1£©CH3COOH(l)+2O2(g) == 2CO2(g)£«2H2O(l)  ¦¤H1£½£­870.3 kJ¡¤mol-1
£¨2£©C(s)+ O2(g) == CO2(g) ¡÷H2£½-393.5 kJ?mol-1
£¨3£©H2(g) +O2(g) == H2O(l) ¡÷H3£½-285.8kJ¡¤mol-1
Ôò·´Ó¦2 C(s)+2H2(g) +O2(g) == CH3COOH(l)µÄ¡÷HΪ£¨   £©
A£®-488.3 kJ¡¤mol-1B£®-244.15 kJ¡¤mol-1C£®+488.3 kJ¡¤mol-1D£®+244.15 kJ¡¤mol-1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨7·Ö£©»¯Ñ§¼üµÄ¼üÄÜÊÇÖ¸Æø̬ԭ×Ó¼äÐγÉ1mol»¯Ñ§¼üʱÊͷŵÄÄÜÁ¿¡£È磺H(g)£«I(g)¡úH£­I(g)£«297KJ ¼´H£­I¼üµÄ¼üÄÜΪ297kJ/mol£¬Ò²¿ÉÒÔÀí½âΪÆÆ»µ1mol H£­I¼üÐèÒªÎüÊÕ297KJµÄÈÈÁ¿¡£»¯Ñ§·´Ó¦µÄ·¢Éú¿ÉÒÔ¿´³É¾É»¯Ñ§¼üµÄÆÆ»µºÍл¯Ñ§¼üµÄÐγɡ£Ï±íÊÇһЩ¼üÄÜÊý¾Ý¡££¨µ¥Î»£ºkJ/mol£©
 
¼üÄÜ
 
¼üÄÜ
 
¼üÄÜ
H£­H
436
Cl£­Cl
243
H£­Cl
432
S£½S
255
H£­S
339
C£­F
427
C£­Cl
330
C£­I
218
H£­F
565
C£­O
347
H£­O
464
Si¡ªSi
176
Si¡ªO
460
O=O
497
 
 
 
ÔĶÁÉÏÊöÐÅÏ¢£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¸ù¾Ý±íÖÐÊý¾ÝÅжÏCCl4µÄÎȶ¨ÐÔ         £¨Ìî¡°´óÓÚ¡±»ò¡°Ð¡ÓÚ¡±£©CF4µÄÎȶ¨ÐÔ¡£ÊÔÔ¤²âC£­Br¼üµÄ¼üÄÜ·¶Î§_________<  C£­Br¼üÄÜ <__________
£¨2£©ÓÐÈËÈÏΪ£ºH£­O¼üµÄ¼üÄÜ´óÓÚH£­S¼üµÄ¼üÄÜ£¬ËùÒÔH2OµÄÈ۷еã¸ßÓÚH2SµÄÈ۷е㡣ÄãÊÇ·ñÔÞͬÕâÖֹ۵㣿Èç²»ÔÞͬ£¬Çë˵³öÄãµÄ½âÊÍ¡£                                      
                                                                                    
£¨3£©ÒÑÖªH2O(l)£½H2O(g)   ¦¤H£½+44kJ/mol,Çëд³ö±íʾÇâÆøȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ£º
                                                    

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸