£¨1£©AgNO3µÄË®ÈÜÒº³Ê
Ëá
Ëá
£¨Ìî¡°Ëᡱ¡¢¡°ÖС±¡¢¡°¼î¡±£©ÐÔ£¬³£ÎÂʱµÄpH
£¼
£¼
7£¨Ìî¡°£¾¡±¡¢¡°=¡±¡¢¡°£¼¡±£©£¬Ô­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£º
Ag++H2O?AgOH+H+
Ag++H2O?AgOH+H+
£»ÊµÑéÊÒÔÚÅäÖÆAgNO3µÄÈÜҺʱ£¬³£½«AgNO3¹ÌÌåÏÈÈÜÓÚ½ÏŨµÄÏõËáÖУ¬È»ºóÔÙÓÃÕôÁóˮϡÊ͵½ËùÐèµÄŨ¶È£¬ÒÔ
ÒÖÖÆ
ÒÖÖÆ
£¨Ìî¡°´Ù½ø¡±¡¢¡°ÒÖÖÆ¡±£©ÆäË®½â£®
£¨2£©°ÑFeCl3ÈÜÒºÕô¸É£¬×ÆÉÕ£¬×îºóµÃµ½µÄÖ÷Òª¹ÌÌå²úÎïÊÇ
Fe2O3£»
Fe2O3£»
£®
£¨3£©ÔÚÅäÖÆÁò»¯ÄÆÈÜҺʱ£¬ÎªÁË·ÀÖ¹·¢ÉúË®½â£¬¿ÉÒÔ¼ÓÈëÉÙÁ¿µÄ
NaOH
NaOH
£®
·ÖÎö£º£¨1£©AgNO3ΪǿËáÈõ¼îÑΣ¬Ag+Àë×ÓË®½âʹÈÜÒº³ÊËáÐÔ£¬´ÓÓ°ÏìƽºâÒƶ¯µÄ½Ç¶È½â´ð£»
£¨2£©FeCl3ÈÜÒºÔÚ¼ÓÈÈʱ´Ù½øFe3+µÄË®½â£¬Ë®½âºóÉú³ÉFe£¨OH£©3£¬¼ÓÈÈ·Ö½âÉú³ÉFe2O3£»
£¨3£©Áò»¯ÄÆË®½â³Ê¼îÐÔ£¬´ÓÓ°ÏìÑÎÀàË®½âƽºâÒƶ¯µÄÒòËØ·ÖÎö£®
½â´ð£º½â£º£¨1£©AgNO3ΪǿËáÈõ¼îÑΣ¬Ag+Àë×ÓË®½âʹÈÜÒº³ÊËáÐÔ£¬Ë®½â·½³ÌʽΪAg++H2O AgOH+H+£¬ÔÚÅäÖÆAgNO3µÄÈÜҺʱ£¬³£½«AgNO3¹ÌÌåÏÈÈÜÓÚ½ÏŨµÄÏõËáÖУ¬·ÀÖ¹Ag+Àë×ÓË®½âʹÈÜÒºÈÜÒº»ë×Ç£¬
¹Ê´ð°¸Îª£ºË᣻£¼£»Ag++H2O AgOH+H+£»ÒÖÖÆ£»
£¨2£©FeCl3ΪǿËáÈõ¼îÑΣ¬Ë®½âÉú³ÉFe£¨OH£©3ºÍÑÎËᣬÑÎËáÒ×»Ó·¢£¬FeCl3ÈÜÒºÔÚ¼ÓÈÈʱ´Ù½øFe3+µÄË®½â£¬Ë®½âºóÉú³ÉFe£¨OH£©3£¬¼ÓÈÈ·Ö½âÉú³ÉFe2O3£¬¹Ê´ð°¸Îª£ºFe2O3£»
£¨3£©Áò»¯ÄÆË®½â³Ê¼îÐÔ£¬ÔÚÈÜÒºÖдæÔÚS2-+H2O?HS-+OH-£¬¼ÓÈÈÉÙÁ¿NaOH£¬ÈÜÒºÖÐOH-Ũ¶ÈÔö´ó£¬¿ÉÒÖÖÆË®½â£¬¹Ê´ð°¸Îª£ºNaOH£®
µãÆÀ£º±¾Ì⿼²éÑÎÀàË®½âµÄÓ¦Óã¬ÌâÄ¿ÄѶÈÖеȣ¬×¢ÒâÑÎÀàË®½âµÄÔ­ÀíÒÔ¼°Ó°ÏìÒòËØ£¬Îª¸ÃÌâµÄÖ÷Òª¿¼²é¶ÔÏó£¬Ñ§Ï°ÖÐ×¢Òâ°ÑÎÕ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

°´ÒªÇóÍê³ÉÏÂÁи÷Ì⣮
£¨1£©AgNO3µÄË®ÈÜÒº³Ê
Ëá
Ëá
£¨Ìî¡°Ëᡱ¡¢¡°ÖС±¡¢¡°¼î¡±£©ÐÔ£¬Ô­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£º
ÒøÀë×ÓË®½âÉú³ÉÇâÑõ»¯ÒøºÍÇâÀë×Ó
ÒøÀë×ÓË®½âÉú³ÉÇâÑõ»¯ÒøºÍÇâÀë×Ó

Ag++H2O?AgOH+H+
Ag++H2O?AgOH+H+
£»ÊµÑéÊÒÔÚÅäÖÆAgNO3µÄÈÜҺʱ£¬³£½«AgNO3¹ÌÌåÏÈÈÜÓÚ½ÏŨµÄÏõËáÖУ¬È»ºóÔÙÓÃÕôÁóˮϡÊ͵½ËùÐèµÄŨ¶È£¬ÆäÖмÓÈëÏõËáÄ¿µÄÊÇ
ÒÖÖÆÏõËáÒøË®½â
ÒÖÖÆÏõËáÒøË®½â
£®
£¨2£©°ÑFeCl3ÈÜÒºÕô¸É£¬×ÆÉÕ£¬×îºóµÃµ½µÄÖ÷Òª¹ÌÌå²úÎïÊÇ
Fe2O3
Fe2O3
£®
£¨3£©25¡æʱ£¬½«pH=9µÄNaOHÈÜÒºÓëpH=4µÄH2SO4ÈÜÒº»ìºÏ£¬ÈôËùµÃ»ìºÏÈÜÒºµÄpH=7£¬ÔòNaOHÈÜÒºÓëH2SO4ÈÜÒºµÄÌå»ý±ÈΪ
10£º1
10£º1
£®
£¨4£©Ä³Î¶ÈÏ£¨Kw=10-13£©£¬SnCl2ÈÜÒºÖÐÓÉË®µçÀëµÄc£¨H+£©=10-4mol?L-1£¬Ôò¸ÃÈÜÒºµÄpHΪ
4
4
£®
£¨5£©ÒÑÖª£º2H2S£¨g£©+O2£¨g£©=2S£¨s£©+2H2O£¨l£©¡÷H=-akJ/mol£»2H2S£¨g£©+3O2£¨g£©=2SO2£¨g£©+2H2O£¨l£©¡÷H=-bkJ/mol
ÔòH2SÓëSO2ÆøÌå»ìºÏÉú³É¹ÌÌåÁòºÍҺ̬ˮµÄÈÈ»¯Ñ§·½³ÌʽΪ
2H2S£¨g£©+SO2£¨g£©=3S£¨s£©+2H2O£¨l£©¡÷H=+£¨b-3a£©/2 kJ/mol
2H2S£¨g£©+SO2£¨g£©=3S£¨s£©+2H2O£¨l£©¡÷H=+£¨b-3a£©/2 kJ/mol
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©AgNO3µÄË®ÈÜÒº³Ê
Ëá
Ëá
£¨Ìî¡°Ëᡱ¡¢¡°ÖС±¡¢¡°¼î¡±£©ÐÔ£¬ÊµÑéÊÒÔÚÅäÖÆAgNO3µÄÈÜҺʱ£¬³£½«AgNO3¹ÌÌåÏÈ
ÈÜÓÚ½ÏŨµÄÏõËáÖÐ
ÈÜÓÚ½ÏŨµÄÏõËáÖÐ
£¬È»ºóÔÙ
ÓÃÕôÁóˮϡÊ͵½ËùÐèµÄŨ¶È
ÓÃÕôÁóˮϡÊ͵½ËùÐèµÄŨ¶È
£¬ÒÔÒÖÖÆÆäË®½â£®
£¨2£©ÂÈ»¯ÂÁË®ÈÜÒº³Ê
Ëá
Ëá
ÐÔ£¬Ô­ÒòÊÇ£º
Al3++3H2O?Al£¨OH£©3+3H+
Al3++3H2O?Al£¨OH£©3+3H+
£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£®°ÑAlCl3ÈÜÒºÕô¸É£¬×ÆÉÕ£¬×îºóµÃµ½µÄÖ÷Òª¹ÌÌå²úÎïÊÇ
Al2O3
Al2O3
£®
£¨3£©Áò»¯ÄÆÈÜÓÚˮʱ·¢ÉúË®½â£¬ÆäË®½âµÄÀë×Ó·½³ÌʽΪ
S2-+H2O?HS-+OH-¡¢HS-+H2O?H2S+OH-
S2-+H2O?HS-+OH-¡¢HS-+H2O?H2S+OH-
£¬ÔÚÅäÖÆÁò»¯ÄÆÈÜҺʱ¿ÉÒÔ¼ÓÈëÉÙÁ¿µÄ
ÇâÑõ»¯ÄÆ
ÇâÑõ»¯ÄÆ
ÒÔÒÖÖÆÆäË®½â£®
£¨4£©ÔÚ25¡æÏ£¬ÏòŨ¶È¾ùΪ0.1mol?L-1µÄMgCL2ºÍCuCl2»ìºÏÈÜÒºÖÐÖðµÎ¼ÓÈ백ˮ£¬ÏÈÉú³É
Cu£¨OH£©2
Cu£¨OH£©2
³Áµí£¨Ìѧʽ£©£¬Éú³É¸Ã³ÁµíµÄÀë×Ó·½³ÌʽΪ
Cu2++2OH-=Cu£¨OH£©2¡ý
Cu2++2OH-=Cu£¨OH£©2¡ý
£®ÒÑÖª25¡æʱKsp[Mg£¨OH£©2]=1.8¡Á10-11£¬KsP[Cu£¨OH£©2]=2.2¡Á10-20£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄê½­ËÕÊ¡ËÞǨÊÐãôºéÏغéÏèÖÐѧ¸ß¶þÏÂѧÆÚÆÚÖп¼»¯Ñ§¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨1£©AgNO3µÄË®ÈÜÒº³Ê      £¨Ìî¡°Ëᡱ¡¢¡°ÖС±¡¢¡°¼î¡±£©ÐÔ£¬³£ÎÂʱµÄpH        7£¨Ìî¡°>¡±¡¢¡°=¡±¡¢¡°<¡±£©£¬ÊµÑéÊÒÔÚÅäÖÆAgNO3µÄÈÜҺʱ£¬³£½«AgNO3¹ÌÌåÏÈÈÜÓÚ½ÏŨµÄÏõËáÖУ¬È»ºóÔÙÓÃÕôÁóˮϡÊ͵½ËùÐèµÄŨ¶È£¬ÒÔ        £¨Ìî¡°´Ù½ø¡±¡¢¡°ÒÖÖÆ¡±£©ÆäË®½â¡£
£¨2£©´×ËáÄÆË®ÈÜÒºPH    7 £¬£¨Ìî¡°>¡±¡¢¡°=¡±¡¢¡°<¡±£©Ô­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£º______¡£°ÑAlCl3ÈÜÒºÕô¸É£¬×ÆÉÕ£¬×îºóµÃµ½µÄÖ÷Òª¹ÌÌå²úÎïÊÇ        ¡£
£¨3£©ÂÈ»¯ï§ÈÜÒºÖеμÓÊÊÁ¿°±Ë®£¬ÖÁÈÜÒº³ÊÖÐÐÔ£¬Ôòc(Cl-)   c(NH4£«)£¨Ìî¡°>¡±¡¢¡°=¡±¡¢¡°<¡±£©¡££¨4£©ÔÚ25¡æÏ£¬Ä³Å¨¶ÈNa2CO3ÈÜÒºÖÐÓÉË®µçÀë³öÀ´c(OH-)=1¡Á10-6 mol/L£¬Ôò´ËÈÜÒºµÄPHֵΪ                        

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ì½­ËÕÊ¡ËÞǨÊи߶þÏÂѧÆÚÆÚÖп¼»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨1£©AgNO3µÄË®ÈÜÒº³Ê      £¨Ìî¡°Ëᡱ¡¢¡°ÖС±¡¢¡°¼î¡±£©ÐÔ£¬³£ÎÂʱµÄpH        7£¨Ìî¡°>¡±¡¢¡°=¡±¡¢¡°<¡±£©£¬ÊµÑéÊÒÔÚÅäÖÆAgNO3µÄÈÜҺʱ£¬³£½«AgNO3¹ÌÌåÏÈÈÜÓÚ½ÏŨµÄÏõËáÖУ¬È»ºóÔÙÓÃÕôÁóˮϡÊ͵½ËùÐèµÄŨ¶È£¬ÒÔ        £¨Ìî¡°´Ù½ø¡±¡¢¡°ÒÖÖÆ¡±£©ÆäË®½â¡£

£¨2£©´×ËáÄÆË®ÈÜÒºPH    7 £¬£¨Ìî¡°>¡±¡¢¡°=¡±¡¢¡°<¡±£©Ô­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£º______¡£°ÑAlCl3ÈÜÒºÕô¸É£¬×ÆÉÕ£¬×îºóµÃµ½µÄÖ÷Òª¹ÌÌå²úÎïÊÇ        ¡£

£¨3£©ÂÈ»¯ï§ÈÜÒºÖеμÓÊÊÁ¿°±Ë®£¬ÖÁÈÜÒº³ÊÖÐÐÔ£¬Ôòc(Cl-)   c(NH4£«)£¨Ìî¡°>¡±¡¢¡°=¡±¡¢¡°<¡±£©¡££¨4£©ÔÚ25¡æÏ£¬Ä³Å¨¶ÈNa2CO3ÈÜÒºÖÐÓÉË®µçÀë³öÀ´c(OH-)=1¡Á10-6 mol/L£¬Ôò´ËÈÜÒºµÄPHֵΪ                        

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêËÄ´¨Ê¡³É¶¼ÊÐÇàÑòÇøʯÊÒÖÐѧ¸ß¶þ£¨Ï£©ÆÚÖл¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

°´ÒªÇóÍê³ÉÏÂÁи÷Ì⣮
£¨1£©AgNO3µÄË®ÈÜÒº³Ê______£¨Ìî¡°Ëᡱ¡¢¡°ÖС±¡¢¡°¼î¡±£©ÐÔ£¬Ô­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£º______
______£»ÊµÑéÊÒÔÚÅäÖÆAgNO3µÄÈÜҺʱ£¬³£½«AgNO3¹ÌÌåÏÈÈÜÓÚ½ÏŨµÄÏõËáÖУ¬È»ºóÔÙÓÃÕôÁóˮϡÊ͵½ËùÐèµÄŨ¶È£¬ÆäÖмÓÈëÏõËáÄ¿µÄÊÇ______£®
£¨2£©°ÑFeCl3ÈÜÒºÕô¸É£¬×ÆÉÕ£¬×îºóµÃµ½µÄÖ÷Òª¹ÌÌå²úÎïÊÇ______£®
£¨3£©25¡æʱ£¬½«pH=9µÄNaOHÈÜÒºÓëpH=4µÄH2SO4ÈÜÒº»ìºÏ£¬ÈôËùµÃ»ìºÏÈÜÒºµÄpH=7£¬ÔòNaOHÈÜÒºÓëH2SO4ÈÜÒºµÄÌå»ý±ÈΪ______£®
£¨4£©Ä³Î¶ÈÏ£¨Kw=10-13£©£¬SnCl2ÈÜÒºÖÐÓÉË®µçÀëµÄc£¨H+£©=10-4mol?L-1£¬Ôò¸ÃÈÜÒºµÄpHΪ______£®
£¨5£©ÒÑÖª£º2H2S£¨g£©+O2£¨g£©=2S£¨s£©+2H2O£¨l£©¡÷H=-akJ/mol£»2H2S£¨g£©+3O2£¨g£©=2SO2£¨g£©+2H2O£¨l£©¡÷H=-bkJ/mol
ÔòH2SÓëSO2ÆøÌå»ìºÏÉú³É¹ÌÌåÁòºÍҺ̬ˮµÄÈÈ»¯Ñ§·½³ÌʽΪ______£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸