ijС×éͬѧÓûÑо¿SO2µÄÐÔÖÊ¡£
(1)½«Ïà¹ØµÄº¬ÁòÎïÖÊ·ÖΪÈçϱíËùʾ3×飬µÚ2×éÖÐÎïÖÊXµÄ»¯Ñ§Ê½ÊÇ       ¡£

µÚ1×é
µÚ2×é
µÚ3×é
S(µ¥ÖÊ)
SO2¡¢X¡¢Na2SO3¡¢NaHSO3
SO3¡¢H2SO4¡¢Na2SO4¡¢NaHSO4
(2)ÀûÓÃÏÂͼËùʾµÄ×°ÖÃÑо¿SO2µÄÐÔÖÊ£º
(È۵㣺SO£­76.1¡æ£¬SO3  16.8¡æ£»·Ðµã£ºSO£­10¡æ£¬SO45¡æ)

¢Ù×°ÖâñÄ£Ä⹤ҵÉú²úÖÐSO2´ß»¯Ñõ»¯µÄ·´Ó¦£¬Æ仯ѧ·½³ÌʽÊÇ                 ¡£
¢Ú¼×ͬѧ°´¢ñ¡¢¢ò¡¢¢ó¡¢¢ôµÄ˳ÐòÁ¬½Ó×°Öã¬×°ÖâòµÄ×÷ÓÃÊÇ                    £»×°ÖâóÖÐÈÜÒºÖð½¥ÍÊÉ«£¬Éú³ÉMn2+£¬Í¬Ê±pH½µµÍ£¬Ôò¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                           ¡£
¢ÛÒÒͬѧ°´¢ñ¡¢¢ò¡¢¢ôµÄ˳ÐòÁ¬½Ó×°Öã¬Èô×°ÖâôÖÐÓÐ40 mL 2.5mol/L NaOHÈÜÒº£¬·´Ó¦ºóÔöÖØ4.8 g£¬Ôò×°ÖâôÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                            ¡£

(1)H2SO3  (2)¢Ù2SO2£«O22SO3
¢ÚʹSO3Äý½á³É¹ÌÌåÓëSO2·ÖÀë   5SO2£«2H2O£«2MnO4¡ª£½5SO42¡ª£«2Mn2£«£«4H£«
¢Û3SO2£«4NaOH£½Na2SO3£«2NaHSO3£«H2

½âÎöÊÔÌâ·ÖÎö£º£¨1£©½«Ïà¹ØµÄº¬ÁòÎïÖÊÒÀ¾ÝÁòÔªËØ»¯ºÏ¼Û·Ö×飬ÒÀ¾ÝµÍÈý×å·ÖÀà˳Ðò£¬ÅжÏXΪ+4¼ÛµÄËáΪH2SO3 £»
¹Ê´ð°¸Îª£ºH2SO3 £»
£¨2£©¢Ù¹¤ÒµÉú²úÖÐSO2´ß»¯Ñõ»¯µÄ·´Ó¦ÊǶþÑõ»¯ÁòµÄ´ß»¯Ñõ»¯·´Ó¦£»»¯Ñ§·½³ÌʽΪ£º2SO2+O2 2SO3£»
¹Ê´ð°¸Îª£»2SO2+O22SO3£»
¢Ú×°ÖÃIIµÄ×÷ÓÃÊÇÀäÈ´×°Öã¬ÈýÑõ»¯ÁòµÄ·Ðµã½ÏµÍ£¬Í¨¹ý±ùË®»ìºÏÎʹSO3Äý½á³É¹ÌÌåÓëSO2·ÖÀ룬װÖÃIIIÖиßÃÌËá¼ØÈÜÒº»áºÍ¶þÑõ»¯Áò·´Ó¦Öð½¥ÍÊÉ«£¬Éú³ÉMn2+£¬¶þÑõ»¯Áò±»Ñõ»¯ÎªÁòË᣻
·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º5SO2+2H2O+2MnO4=5SO42-+2Mn2++4H+£»
¹Ê´ð°¸Îª£ºÊ¹SO3Äý½á³É¹ÌÌåÓëSO2·ÖÀ룬5SO2+2H2O+2MnO4=5SO42-+2Mn2++4H+£»
¢ÛÈô×°ÖÃIVÖÐÓÐ40mL 2.5mol?L-1NaOHÈÜÒº£¬·´Ó¦ºóÔöÖØ4.8g£¬ÎüÊÕµÄΪ¶þÑõ»¯ÁòÆøÌ壬ÒÀ¾Ý¶þÑõ»¯ÁòÎïÖʵÄÁ¿ºÍÇâÑõ»¯ÄÆÎïÖʵÄÁ¿½øÐзÖÎöÅжÏÉú³É²úÎÈôn£¨SO2£©£ºn£¨NaOH£©=1£º2·´Ó¦°´ÕÕ·´Ó¦£ºSO2+2NaOH=Na2SO3+H2O£»Èôn£¨SO2£©£ºn£¨NaOH£©=1£º1£¬·´Ó¦°´ÕÕ·´Ó¦SO2+NaOH=NaHSO3£»×°ÖÃIVÖÐÓÐ40mL 2.5mol?L-1NaOHÈÜÒºÖÐn£¨NaOH£©=0.1mol£¬n£¨SO2£©="4.8g¡Â64g/mol" =0.075mol£»n£¨SO2£©£ºn£¨NaOH£©=0.075£º0.1=3£º4£¬ËùÒÔÉú³É²úÎïΪÑÇÁòËáÄƺÍÑÇÁòËáÇâÄÆ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽÒÀ¾Ýֱƽ·¨Ð´³ö£º3SO2+4NaOH¨TNa2SO3+2NaHSO3+H2O£»
¹Ê´ð°¸Îª£º3SO2+4NaOH¨TNa2SO3+2NaHSO3+H2O¡£
¿¼µã£º¶þÑõ»¯ÁòµÄ»¯Ñ§ÐÔÖÊ
µãÆÀ£º±¾Ì⿼²éÁËÎïÖÊ·ÖÀà·½·¨£¬¹æÂÉ×ܽᣬʵÑé¹ý³Ì·ÖÎöÅжϣ¬»¯Ñ§·½³ÌʽºÍÀë×Ó·½³ÌʽµÄÊéд£¬·´Ó¦²úÎïµÄ·ÖÎöÅжϣ¬ÌâÄ¿ÄѶÈÖеȡ£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013-2014ѧÄêºþÄÏÊ¡³¤É³ÊиßÈýµÚÈý´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨1£©Ä³»¯Ñ§ÐËȤС×éµÄͬѧ½øÐÐCl2¡¢NH3µÄÖƱ¸¼°ÐÔÖʼìÑéµÈʵÑéµÄÁ÷³ÌºÍ²¿·Ö×°ÖÃÈçÏ£º

ÇëÀûÓÃA¡¢G×°ÖÃÉè¼ÆÒ»¸ö¼òµ¥µÄʵÑéÑéÖ¤Cl2¡¢Fe3£«¡¢I2µÄÑõ»¯ÐÔÇ¿ÈõΪCl2>Fe3£«>I2(ʵÑéÖв»¶ÏµØСÐÄÕñµ´G×°ÖÃÖеÄÊÔ¹Ü)¡£AÖз´Ó¦ÎïÊÇKMnO4ºÍŨÑÎËᣬÇëд³öAÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º                                          £¬Çëд³öÊÔ¼ÁMΪ            ÈÜÒº£¬Ö¤Ã÷Ñõ»¯ÐÔΪCl2>Fe3£«>I2µÄʵÑéÏÖÏóÊÇ                                                     ¡£

¢ÚÒÑÖª3Cl2£«2NH3=6HCl£«N2£¬µ±DµÄÉÕÆ¿ÖгäÂú»ÆÂÌÉ«ÆøÌåºó£¬¹Ø±Õa¡¢c´ò¿ªb£¬DÖеÄÏÖÏóΪ»ÆÂÌÉ«ÆøÌåÏûʧ£¬²úÉú°×ÑÌ£¬·´Ó¦Ò»¶Îʱ¼äºó£¬¹Ø±Õb´ò¿ªc£¬¹Û²ìµ½µÄÏÖÏóΪ_________________________________________________________________¡£

£¨2£©Ä³·ÏË®Öк¬ÓÐÒ»¶¨Á¿µÄNa+¡¢SO£¬¿ÉÄܺ¬ÓÐCO£¬Ä³Ñо¿Ð¡×éÓû²â¶¨ÆäÖÐSOµÄŨ¶È£¬Éè¼ÆÈçÏÂʵÑé·½°¸£º

¢Ù´ÓÏÂÁÐÊÔ¼ÁÖÐÑ¡ÔñÊÔ¼ÁXΪ_________£¨ÌîÐòºÅ£©£»

A£®0.1 mol/L KMnO4(H2SO4Ëữ)ÈÜÒº        B£®0.5 mol/L NaOHÈÜÒº

C£®ÐÂÖÆÂÈË®                              D£®KIÈÜÒº

¢Ú¼ÓÈëÊÔ¼ÁXÉú³ÉSOµÄÀë×Ó·½³ÌʽΪ_____________________________________£»

¢ÛÖ¤Ã÷¸Ã·ÏË®ÖÐÊÇ·ñº¬ÓÐCOµÄʵÑé·½°¸Îª                                                  ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013-2014ѧÄêºþÄÏÊ¡³¤É³ÊиßÈýµÚÈý´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨1£©Ä³»¯Ñ§ÐËȤС×éµÄͬѧ½øÐÐCl2¡¢NH3µÄÖƱ¸¼°ÐÔÖʼìÑéµÈʵÑéµÄÁ÷³ÌºÍ²¿·Ö×°ÖÃÈçÏ£º

ÇëÀûÓÃA¡¢G×°ÖÃÉè¼ÆÒ»¸ö¼òµ¥µÄʵÑéÑéÖ¤Cl2¡¢Fe3£«¡¢I2µÄÑõ»¯ÐÔÇ¿ÈõΪCl2>Fe3£«>I2(ʵÑéÖв»¶ÏµØСÐÄÕñµ´G×°ÖÃÖеÄÊÔ¹Ü)¡£AÖз´Ó¦ÎïÊÇKMnO4ºÍŨÑÎËᣬÇëд³öAÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º                                          £¬Çëд³öÊÔ¼ÁMΪ            ÈÜÒº£¬Ö¤Ã÷Ñõ»¯ÐÔΪCl2>Fe3£«>I2µÄʵÑéÏÖÏóÊÇ                                                     ¡£

¢ÚÒÑÖª3Cl2£«2NH3=6HCl£«N2£¬µ±DµÄÉÕÆ¿ÖгäÂú»ÆÂÌÉ«ÆøÌåºó£¬¹Ø±Õa¡¢c´ò¿ªb£¬DÖеÄÏÖÏóΪ»ÆÂÌÉ«ÆøÌåÏûʧ£¬²úÉú°×ÑÌ£¬·´Ó¦Ò»¶Îʱ¼äºó£¬¹Ø±Õb´ò¿ªc£¬¹Û²ìµ½µÄÏÖÏóΪ_________________________________________________________________¡£

£¨2£©Ä³·ÏË®Öк¬ÓÐÒ»¶¨Á¿µÄNa+¡¢SO£¬¿ÉÄܺ¬ÓÐCO£¬Ä³Ñо¿Ð¡×éÓû²â¶¨ÆäÖÐSOµÄŨ¶È£¬Éè¼ÆÈçÏÂʵÑé·½°¸£º

¢Ù´ÓÏÂÁÐÊÔ¼ÁÖÐÑ¡ÔñÊÔ¼ÁXΪ_________£¨ÌîÐòºÅ£©£»

A£®0.1 mol/L KMnO4(H2SO4Ëữ)ÈÜÒº        B£®0.5 mol/L NaOHÈÜÒº

C£®ÐÂÖÆÂÈË®                              D£®KIÈÜÒº

¢Ú¼ÓÈëÊÔ¼ÁXÉú³ÉSOµÄÀë×Ó·½³ÌʽΪ_____________________________________£»

¢ÛÖ¤Ã÷¸Ã·ÏË®ÖÐÊÇ·ñº¬ÓÐCOµÄʵÑé·½°¸Îª                                                  ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸