ÓÐһƿ³ÎÇåÈÜÒº£¬ÆäÖпÉÄܺ¬ÓÐNH¡¢K£«¡¢Na£«¡¢Mg2£«¡¢Ba2£«¡¢Al3£«¡¢Fe3£«¡¢Cl£¡¢I£¡¢NO¡¢CO¡¢SOÖеļ¸ÖÖ¡£È¡¸ÃÈÜÒº½øÐÐÒÔÏÂʵÑé¡£
(1)Ìîд±íÖпհףº
ʵÑé²½Öè | ¿Ï¶¨²»´æÔÚµÄÀë×Ó |
¢ÙÓÃpHÊÔÖ½¼ìÑ飬ÈÜÒº³ÊÇ¿ËáÐÔ | |
¢ÚÈ¡³ö²¿·ÖÈÜÒº£¬¼ÓÈëÉÙÁ¿CCl4¼°ÊýµÎÐÂÖƵÄÂÈË®£¬¾Õñµ´¡¢¾²ÖúóCCl4²ã³Ê×ϺìÉ« | |
¢ÛÁíÈ¡²¿·ÖÈÜÒº£¬ÏòÆäÖмÓÈëNaOHÈÜÒº£¬Ê¹ÈÜÒº´ÓËáÐÔÖð½¥±äΪ¼îÐÔ£¬Ôڵμӹý³ÌÖм°µÎ¼ÓÍê±Ïºó£¬¾ùÎÞ³Áµí²úÉú | |
¢ÜÈ¡¢ÛÖеIJ¿·Ö¼îÐÔÈÜÒº¼ÓÈÈ£¬ÓÐÆøÌå·Å³ö£¬¸ÃÆøÌåÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶ | |
¢ÝÁíÈ¡¢ÛÖеIJ¿·Ö¼îÐÔÈÜÒº£¬ÏòÆäÖмÓÈëNa2CO3ÈÜÒº£¬Óа×É«³Áµí²úÉú |
(2)¸ù¾ÝÒÔÉÏÊÂʵ£¬¸ÃÈÜÒºÖп϶¨´æÔÚµÄÀë×ÓÊÇ________¡£
(3)д³öʵÑé¢Ú¡¢¢Ü¡¢¢ÝÖз´Ó¦µÄÀë×Ó·½³Ìʽ£º
ʵÑé¢Ú________________________________________________________________________£»
ʵÑé¢Ü________________________________________________________________________£»
ʵÑé¢Ý________________________________________________________________________¡£
´ð°¸¡¡(1)¢ÙCO¡¡¢ÚFe3£«¡¢NO¡¡¢ÛMg2£«¡¢Al3£«
¢ÜÎÞ¡¡¢ÝSO
(2)I£¡¢NH¡¢Ba2£«
(3)Cl2£«2I£===2Cl££«I2
NH£«OH£NH3¡ü£«H2O
Ba2£«£«CO===BaCO3¡ý
½âÎö¡¡¢ÙÈÜÒº³ÊÇ¿ËáÐԿ϶¨ÓÐH£«£¬¹Ê¿Ï¶¨²»º¬ÓÐCO£»¢Ú¼ÓÈëÉÙÁ¿CCl4¼°ÊýµÎÐÂÖÆÂÈË®£¬¾Õñµ´¡¢¾²ÖúóCCl4²ã³Ê×ϺìÉ«£¬Ò»¶¨º¬ÓÐI££¬¹Ê¿Ï¶¨²»º¬ÓÐFe3£«¡¢NO£»¢ÛÔÚµÎÈëNaOHÈÜÒº¹ý³ÌÖм°µÎ¼ÓÍê±Ïºó£¬¾ùÎÞ³Áµí²úÉú£¬¹Ê¿Ï¶¨²»º¬ÓÐMg2£«¡¢Al3£«£»¢Ü½«¢ÛÖеIJ¿·Ö¼îÐÔÈÜÒº¼ÓÈÈ£¬ÓÐÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶µÄÆøÌå·Å³ö£¬¹Ê¿Ï¶¨º¬ÓÐNH£»¢ÝÏò¢ÛÖеIJ¿·Ö¼îÐÔÈÜÒºÖмÓ̼ËáÄÆÈÜÒº£¬Óа×É«³Áµí²úÉú£¬¿Ï¶¨º¬ÓÐBa2£«£¬Ôò¿Ï¶¨²»º¬ÓÐSO¡£×ÛÉÏËùÊö£¬ÔÈÜÒºÖп϶¨´æÔÚµÄÀë×ÓÊÇBa2£«¡¢I£¡¢NH£»¿Ï¶¨²»´æÔÚµÄÀë×ÓÊÇCO¡¢Fe3£«¡¢NO¡¢Mg2£«¡¢Al3£«¡¢SO£»²»ÄÜÈ·¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÊÇK£«¡¢Na£«¡¢Cl£¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÏÂÁи÷×éÊý¾ÝÖУ¬Ç°Õ߸պÃÊǺóÕßÁ½±¶µÄÊÇ (¡¡¡¡ )
A£®2 molË®µÄĦ¶ûÖÊÁ¿ºÍ1 molË®µÄĦ¶ûÖÊÁ¿
B£®200 mL 1 mol/LÂÈ»¯¸ÆÈÜÒºÖÐc(Cl£)ºÍ100 mL 2 mol/LÂÈ»¯¼ØÈÜÒºÖÐc(Cl£)
C£®64 g¶þÑõ»¯ÁòÖÐÑõÔ×ÓÊýºÍ±ê×¼×´¿öÏÂ22.4 LÒ»Ñõ»¯Ì¼ÖÐÑõÔ×ÓÊý
D£®20%NaOHÈÜÒºÖÐNaOHµÄÎïÖʵÄÁ¿Å¨¶ÈºÍ10%NaOHÈÜÒºÖÐNaOHµÄÎïÖʵÄÁ¿Å¨¶È
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
Íê³ÉÏÂÁÐÀë×Ó·½³Ìʽ£º
(1)ÄÆÓëË®·´Ó¦£º_______________________________________________________________¡£
(2)ÂÈÆøͨÈëË®ÖУº_____________________________________________________________¡£
(3)ÏòÇâÑõ»¯ÄÆÈÜÒºÖÐͨÈëÉÙÁ¿CO2£º
________________________________________________________________________¡£
(4)̼Ëá¸ÆÖеÎÈë´×ËáÈÜÒº£º
________________________________________________________________________¡£
(5)ÂÁƬͶÈëÇâÑõ»¯ÄÆÈÜÒº£º
________________________________________________________________________¡£
(6)ÂÈ»¯ÂÁÈÜÒºÖмÓ×ãÁ¿Ì¼ËáÇâÄÆÈÜÒº£º
________________________________________________________________________¡£
(7)FeCl3ÈÜÒºÓëCu·´Ó¦£º
________________________________________________________________________¡£
(8)ËáÐÔÁòËáÑÇÌúÈÜÒºÖмÓÈë¹ýÑõ»¯ÇâÈÜÒº£º
________________________________________________________________________¡£
(9)ʵÑéÊÒÓÃMnO2ÓëŨÑÎËáÖÆÈ¡Cl2£º
________________________________________________________________________¡£
(10)NO2ÈÜÓÚË®£º_____________________________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÏÂÁз´Ó¦µÄÀë×Ó·½³ÌʽÊéдÕýÈ·µÄÊÇ(Ë«Ñ¡)(¡¡¡¡)
A£®ÏòAl2(SO4)3ÈÜÒºÖмÓÈë¹ýÁ¿°±Ë®£ºAl3£«£«3NH3·H2O===Al(OH)3¡ý£«3NH
B£®½«Fe(OH)2ÈÜÓÚ¹ýÁ¿µÄÏ¡ÏõË᣺Fe(OH)2£«2H£«===Fe2£«£«2H2O
C£®ÓÃNaClOÈÜÒºÎüÊÕ¹ýÁ¿µÄSO2£ºClO££«SO2£«H2O===SO£«Cl££«2H£«
D£®Fe(OH)3ÈÜÓÚÇâµâË᣺Fe(OH)3£«3H£«===Fe3£«£«3H2O
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
Îíö²ÑÏÖØÓ°ÏìÈËÃǵÄÉú»îÓ뽡¿µ¡£Ä³µØÇøµÄÎíö²ÖпÉÄܺ¬ÓÐÈçÏ¿ÉÈÜÐÔÎÞ»úÀë×Ó£ºNa£«¡¢NH¡¢Mg2£«¡¢Al3£«¡¢SO¡¢NO¡¢Cl£ ¡£Ä³Í¬Ñ§ÊÕ¼¯Á˸õØÇøµÄÎíö²£¬¾±ØÒªµÄÔ¤´¦ÀíºóµÃÊÔÑùÈÜÒº£¬Éè¼Æ²¢Íê³ÉÁËÈçÏÂʵÑ飺
ÒÑÖª£º3NO£« 8Al£«5OH££«2H2O3NH3¡ü£«8AlO
¸ù¾ÝÒÔÉϵÄʵÑé²Ù×÷ÓëÏÖÏ󣬸ÃͬѧµÃ³öµÄ½áÂÛ²»ÕýÈ·µÄÊÇ(¡¡¡¡)
A£®ÊÔÑùÖп϶¨´æÔÚNH¡¢Mg2£«¡¢SOºÍNO
B£®ÊÔÑùÖÐÒ»¶¨²»º¬Al3£«
C£®ÊÔÑùÖпÉÄÜ´æÔÚNa£«¡¢Cl£
D£®¸ÃÎíö²ÖпÉÄÜ´æÔÚNaNO3 ¡¢NH4ClºÍMgSO4
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÏÂÁÐ˵·¨ÖУ¬ÕýÈ·µÄÊÇ(¡¡¡¡)
A£®ÔÚ»¯Ñ§·´Ó¦¹ý³ÌÖУ¬·¢ÉúÎïÖʱ仯µÄͬʱ²»Ò»¶¨·¢ÉúÄÜÁ¿±ä»¯
B£®ÆÆ»µ·´Ó¦²úÎïÈ«²¿»¯Ñ§¼üËùÐèÒªµÄÄÜÁ¿´óÓÚÆÆ»µ·´Ó¦ÎïÈ«²¿»¯Ñ§¼üËùÐèÒªµÄÄÜÁ¿Ê±£¬·´Ó¦ÎªÎüÈÈ·´Ó¦
C£®·´Ó¦²úÎïµÄ×ÜìÊ´óÓÚ·´Ó¦ÎïµÄ×ÜìÊʱ£¬·´Ó¦ÎüÈÈ£¬¦¤H>0
D£®¦¤HµÄ´óСÓëÈÈ»¯Ñ§·½³ÌʽµÄ¼ÆÁ¿ÏµÊýÎÞ¹Ø
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÒÑÖª£º
(1)H2(g)£«O2(g)===H2O(g) ¦¤H1£½a kJ·mol£1
(2)2H2(g)£«O2(g)===2H2O(g) ¦¤H2£½b kJ·mol£1
(3)H2(g)£«O2(g)===H2O(l) ¦¤H3£½c kJ·mol£1
(4)2H2(g)£«O2(g)===2H2O(l) ¦¤H4£½d kJ·mol£1
ÏÂÁйØϵʽÖÐÕýÈ·µÄÊÇ(¡¡¡¡)
A£®a<c<0 B£®b>d>0 C£®2a£½b<0 D£®2c£½d>0
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
½«1 mol±ù´×Ëá¼ÓÈëµ½Ò»¶¨Á¿µÄÕôÁóË®ÖÐ×îÖյõ½1 LÈÜÒº¡£ÏÂÁи÷ÏîÖУ¬±íÕ÷ÒÑ´ïµ½µçÀëƽºâ״̬µÄÊÇ(¡¡¡¡)
A£®´×ËáµÄŨ¶È´ïµ½1 mol¡¤L£1
B£®[H£«]µÄŨ¶È´ïµ½0.5 mol¡¤L£1
C£®[CH3COOH]¡¢[CH3COO£]¡¢[H£«]¾ùΪ0.5 mol¡¤L£1
D£®´×Ëá·Ö×ÓµçÀë³ÉÀë×ÓµÄËÙÂʺÍÀë×ÓÖØнáºÏ³É·Ö×ÓµÄËÙÂÊÏàµÈ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÏÂÁи÷ÈÜÒºÖУ¬Á£×ÓµÄÎïÖʵÄÁ¿Å¨¶È¹ØϵÕýÈ·µÄÊÇ( )
A£®0.1 mol¡¤L£1µÄCH3COONaÈÜÒºÖУºc(CH3COO£)>c(Na£«)>c(H£«)>c(OH£)
B£®0.1 mol¡¤L£1µÄNa2CO3ÈÜÒºÖУºc(OH£)£½c(HCO)+c(H£«)+c(H2CO3)
C£®0.1 mol¡¤L£1µÄNH4ClÈÜÒºÖУºC(Cl£)>C(NH)>c(OH£)>c(H£«)
D£®c(NH)ÏàµÈµÄ(NH4)2SO4ÈÜÒº¡¢NH4HSO4ÈÜÒº¡¢(NH4)2CO3ÈÜÒº¡¢NH4ClÈÜÒº£º
c< c<c(NH4HSO4)<c(NH4Cl)
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com