ÏÂÁлìºÏÈÜÒºÖУ¬¸÷Àë×ÓŨ¶ÈµÄ´óС˳ÐòµÄ±íʾÖУ¬ÕýÈ·µÄÊÇ ( )
A£®10 mL 0.10 mol¡¤L-1°±Ë®Óë10 mL 0.10 mol¡¤L-1ÑÎËá»ìºÏ c£¨Cl-£©> c£¨NH4+£©> c£¨OH -£© > c£¨H+£© |
B£®10 mL 0.10 mol¡¤L-1 NH4ClÈÜÒºÓë5 mL 0.20 mol¡¤L-1 NaOHÈÜÒº»ìºÏ c£¨Na+£© = c£¨Cl-]£©> c£¨OH -£©> c£¨H+£© |
C£®10 mL 0.10 mol¡¤L-1 CH3COOHÈÜÒºÓë5 mL 0.20 mol¡¤L-1 NaOHÈÜÒº»ìºÏ c£¨Na+£©= c£¨CH3COO-£© > c£¨OH -£© > c£¨H+£© |
D£®10 mL 0.50 mol¡¤L-1 CH3COONaÈÜÒºÓë6 mL 1.0 mol¡¤L-1ÑÎËá»ìºÏ |
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
c(OH-) | c(NH3?H2O) |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013-2014ѧÄêºÓÄÏÊ¡ÔÃûУ¸ßÈýÉÏѧÆÚÆÚÁª¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
¢ñ£®Ä³ÈÜÒºÖнöº¬Ï±íÀëÓèÖеÄ5ÖÖÀë×Ó£¨²»¿¼ÂÇË®µÄµçÀë¼°Àë×ÓµÄË®½â£©£¬ÇÒ¸÷Àë×ÓµÄÎïÖʵÄÁ¿¾ùÏàµÈ¶¼Îª0£®0lmol¡£
¢ÙÈôÏòÔÈÜÒºÖмÓÈëKSCNÈÜÒº£¬ÎÞÃ÷ÏԱ仯¡£
¢ÚÈôÏòÔÈÜÒºÖмÓÈë¹ýÁ¿µÄÑÎËá,ÓÐÆøÌåÉú³É£®ÈÜÒºÖÐÒõÀë×ÓÖÖÀ಻±ä¡£
¢ÛÈôÏòÔÈÜÒºÖмÓÈëBaCl2ÈÜÒº£¬Óа×É«³ÁµíÉú³É¡£
ÊԻشðÏÂÁÐÎÊÌâ
£¨1£©ÈôÏÈÏòÔÈÜÒºÖÐÏȼÓÈë¹ýÁ¿µÄÑÎËᣬÔÙ¼ÓÈëKSCNÈÜÒº£¬ÏÖÏóÊÇ__________________¡£¸Ã¹ý³ÌÖÐÉæ¼°µÄÀë×Ó·½³ÌʽÓÐ________________¡¢__________________¡£
£¨2£©ÏòÔÈÜÒºÖмÓÈë×ãÁ¿µÄNaOHÈÜÒº£¬³ä·Ö·´Ó¦ºó£¬¹ýÂË¡¢Ï´µÓ¡¢×ÆÉÕ£¬×îÖÕËùµÃ¹ÌÌåΪ____________________£¨Ð´»¯Ñ§Ê½£©¡£
£¨3£©ÏòÔÈÜÒºÖмÓÈë×ãÁ¿ÑÎËáºó£¬ÓÃÅÅË®·¨ÊÕ¼¯Ëù²úÉúµÄÆøÌ岢ʹÆøÌåÇ¡ºÃ³äÂúÈÝÆ÷£¬½«ÈÝÆ÷µ¹ÖÃÓÚË®²ÛÖУ¬ÔÙÏòÈÝÆ÷ÖÐͨÈë___________mLO2£¨ÆøÌåÌå»ý¾ùÖ¸±ê×¼×´¿ö£©£¬ÄÜʹÈÜÒº³äÂú¸ÃÈÝÆ÷¡£
¢ò£®amolCu2SºÍbmol FeSͶÈëµ½v L c mol£¯LµÄÏ¡ÏõËáÖУ»³ä·Ö·´Ó¦£¬Éú³ÉNOÆøÌ壬ËùµÃ³ÎÇåÈÜÒº¿ÉÒÔ¿´×÷Cu£¨NO3£©2¡¢Fe£¨NO3£©3ºÍH2SO4µÄ»ìºÏÈÜÒº£¬Ôò·´Ó¦ÖÐδ±»»¹ÔµÄÏõËáµÄÎïÖʵÄÁ¿Îª ___________mol£¨ÓÃͬʱº¬ÓÐa¡¢b¡¢v¡¢cµÄ±í´ïʽ±íʾ£©¡£
¢ó£®ÒÑÖªCH4£¨g£©£«2O2£¨g£©CO2£¨g£©£«2H2O£¨l£© ¡÷H1£½a kJ£¯molÓû¼ÆËã·´Ó¦CH4£¨g£©£«4NO£¨g£©2N2£¨g£©£«CO2£¨g£©£«2H2O£¨l£©µÄìʱä¡÷H2£¬Ôò»¹ÐèÒª²éÕÒij·´Ó¦µÄìʱä¡÷H3£¬µ±·´Ó¦Öи÷ÎïÖÊ»¯Ñ§¼ÆÁ¿ÊýÖ®±ÈΪ×î¼òÕûÊý±Èʱ¡÷H3£½b kJ£¯mol£¬Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ______________________________________¡£
¾Ý´Ë¼ÆËã³ö¡÷H2£½_____________kJ£¯mol£¨Óú¬aºÍbµÄʽ×Ó±íʾ£©¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2015½ì°²»ÕÊ¡¸ßÒ»µÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ
£¨¹²18·Ö£©Ä³´ÎʵÑéÐèÓÃ0.4 mol¡¤L£1 NaOHÈÜÒº480 mL¡£ÅäÖÆ·½·¨ÈçÏ£º
£¨1£©ÅäÖƸÃÈÜҺӦѡÓÃ_____________mLÈÝÁ¿Æ¿£»
£¨2£©ÓÃÍÐÅÌÌìƽ׼ȷ³ÆÁ¿__________ g ¹ÌÌåNaOH£»
£¨3£©½«³ÆÁ¿ºÃµÄNaOH¹ÌÌå·ÅÔÚ500 mL´óÉÕ±ÖУ¬µ¹ÈëÔ¼300 mLÕôÁóË®£¬Óò£Á§°ô½Á°è£¬Ê¹¹ÌÌåÈ«²¿Èܽ⣬´ý___________ºó£¬½«ÉÕ±ÖеÄÈÜҺעÈëÈÝÁ¿Æ¿ÖУ»
£¨4£©ÓÃÉÙÁ¿ÕôÁóˮϴµÓÉÕ± ´Î£¬Ï´µÓºóµÄÈÜҺҲתÒƵ½ÈÝÁ¿Æ¿ÖУ¬ÇáÇá»Î¶¯ÈÝÁ¿Æ¿£¬Ê¹ÈÜÒº»ìºÏ¾ùÔÈ£»
£¨5£©ÏòÈÝÁ¿Æ¿ÖмÓÈëÕôÁóË®£¬µ½ÒºÃæÀë¿Ì¶ÈÏß_______________ ʱ£¬¸ÄÓÃ___________¼ÓÕôÁóË®ÖÁÒºÃæ×îµÍµãÓë¿Ì¶ÈÏßÏàÇС£¸ÇºÃÆ¿Èû£¬ÉÏϵߵ¹Ò¡ÔÈ¡£
£¨6£©ÈôÔÚÅäÖƹý³ÌÖгöÏÖÏÂÁÐÇé¿ö£¬½«Ê¹ËùÅäÖƵÄNaOHÈÜÒºµÄŨ¶ÈÆ«¸ßµÄÊÇ_________£¬Æ«µÍµÄÊÇ_________£¬¶ÔʵÑé½á¹ûûÓÐÓ°ÏìµÄÊÇ_________£¨Ìî¸÷Ñ¡ÏîµÄÐòºÅ£©¡£
A£®ËùÓõÄNaOHÖлìÓÐÉÙÁ¿NaCl
B£®ÓÃÍÐÅÌÌìƽ³ÆÁ¿Ò»¶¨ÖÊÁ¿¹ÌÌåNaOHʱ£¬íÀÂëÉÏÓÐÓÍÎÛ
C£®ÅäÖÆÈÜÒºËùÓõÄÈÝÁ¿Æ¿Ï´¾»ºóûÓкæ¸É
D£®¹ÌÌåNaOHÔÚÉÕ±ÖÐÈܽâºó£¬Á¢¼´½«ÈÜҺתÒƵ½ÈÝÁ¿Æ¿ÄÚ²¢½Ó׎øÐкóÐø²Ù×÷
E£®×ªÒÆÈÜÒººó£¬Î´Ï´µÓÉÕ±ºÍ²£Á§°ô¾ÍÖ±½Ó¶¨ÈÝ
F£®×îºóÈ·¶¨NaOHÈÜÒºÌå»ý£¨¶¨ÈÝ£©Ê±£¬¸©ÊÓ¹Û²ìÒºÃæÓëÈÝÁ¿Æ¿¿Ì¶ÈÏß
G£®¶¨ÈÝÒ¡ÔȺó¾²Ö¹£¬·¢ÏÖÒºÃæµÍÓڿ̶ÈÏߣ¬ÔÙ¼ÓÕôÁóË®ÖÁ¿Ì¶ÈÏß¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
³£ÎÂÏÂÓÐŨ¶È¾ùΪ0.1mol¡¤L-1µÄËÄÖÖÈÜÒº£º¢Ù̼ËáÄÆÈÜÒº£»¢Ú̼ËáÇâÄÆÈÜÒº£»¢ÛÑÎË᣻¢Ü°±Ë®¡£Çë¸ù¾ÝÌâÄ¿ÒªÇó»Ø´ðÏÂÁÐÎÊÌâ¡£
(1) ÉÏÊöÈÜÒºÖУ¬¼ÈÄÜÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦£¬ÓÖÄÜÓëÁòËáÈÜÒº·´Ó¦µÄÊÇ__________¡£
(2) È¡ÊÊÁ¿ÈÜÒº¢Ü£¬¼ÓÈëÉÙÁ¿ÂÈ»¯ï§¹ÌÌ壬´ËʱÈÜÒºÖÐ µÄÖµ_____(Ìî¡°Ôö´ó¡± »ò¡°¼õС¡±»ò¡°²»±ä¡±)¡£
(3) ½«µÈÌå»ýµÄ¢ÛºÍ¢ÜµÄÈÜÒº»ìºÏºó£¬ËùµÃÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£º__________¡£ ËùµÃÈÜÒºµÄpH£¼7£¬ÓÃÀë×Ó·½³Ìʽ±íʾÆäÔÒò________________£»»ìºÏºóµÄÈÜÒºÖÐÓÉË®µç Àë
³öµÄc(OH-)____0.1 mol/L NaOHÈÜÒºÖÐÓÉË®µçÀë³öµÄc(OH-) £¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©¡£
(4) È¡10mLÈÜÒº¢Û£¬¼ÓˮϡÊ͵½500mL£¬Ôò¸ÃÈÜÒºÖÐÓÉË®µçÀë³öc(H+)£½________________¡£
(5) ÈôÏò°±Ë®ÖмÓÈëpH=1µÄÁòËᣬÇÒ°±Ë®ÓëÁòËáµÄÌå»ý±ÈΪ1:1£¬ÔòËùµÃÈÜÒºÖи÷Àë×ÓÎïÖʵÄÁ¿Å¨¶ÈÓÉ´óµ½Ð¡µÄ¹ØϵÊÇ__________¡£
(6) ÓÐÏàͬζÈÏÂÏàͬŨ¶ÈµÄËÄÖÖÑÎÈÜÒº£ºA£®NH4HCO3£»B£®CH3COONH4£»C£®(NH4)2SO4£» D£®NH4Cl£¬ °´pHÓÉ´óµ½Ð¡µÄ˳ÐòÅÅÁÐ_______ _(ÌîÐòºÅ)
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêÁÉÄþÊ¡ÉòÑô¶þÖи߶þ£¨ÉÏ£©ÆÚÖл¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com