´óÆøÖеIJ¿·ÖÔ´ÓÚO3¶Ôº£Ë®ÖÐI£­µÄÑõ»¯¡£½«O3³ÖÐøͨÈëNaIÈÜÒºÖнøÐÐÄ£ÄâÑо¿¡£

(1)O3½«I£­Ñõ»¯³ÉI2µÄ¹ý³ÌÓÉ3²½·´Ó¦×é³É£º

¢ÙI£­(aq)£«O3(g)===IO£­(aq)£«O2(g)¡¡¦¤H1£»

¢ÚIO£­(aq)£«H£«(aq) HOI(aq)¡¡¦¤H2£»

¢ÛHOI(aq)£«I£­(aq)£«H£«(aq) I2(aq)£«H2O(l)¡¡¦¤H3¡£

×Ü·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________________________________________________£¬Æä·´Ó¦ÈȦ¤H£½________¡£

(2)ÔÚÈÜÒºÖдæÔÚ»¯Ñ§Æ½ºâ£ºI2(aq)£«I£­(aq) I(aq)£¬Æäƽºâ³£Êý±í´ïʽΪ______________¡£

(3)Ϊ̽¾¿Fe2£«¶ÔO3Ñõ»¯I£­·´Ó¦µÄÓ°Ïì(·´Ó¦ÌåϵÈçͼ0)£¬Ä³Ñо¿Ð¡×é²â¶¨Á½×éʵÑéÖÐIŨ¶ÈºÍÌåϵpH£¬½á¹û¼ûͼ1ºÍÏÂ±í¡£

񅧏

·´Ó¦Îï

·´Ó¦Ç°pH

·´Ó¦ºópH

µÚ1×é

O3£«I£­

5.2

11.0

µÚ2×é

O3£«I£­£«Fe2£«

5.2

4.1

¢ÙµÚ1×éʵÑéÖУ¬µ¼Ö·´Ó¦ºópHÉý¸ßµÄÔ­ÒòÊÇ__________________________________

________________________________________________________________________¡£

¢ÚͼÖеÄAΪ________¡£ÓÉFe3£«Éú³ÉAµÄ¹ý³ÌÄÜÏÔÖøÌá¸ßI£­µÄת»¯ÂÊ£¬Ô­ÒòÊÇ

________________________________________________________________________

________________________________________________________________________¡£

¢ÛµÚ2×éʵÑé½øÐÐ18 sºó£¬IŨ¶ÈϽµ¡£µ¼ÖÂϽµµÄÖ±½ÓÔ­ÒòÓÐ(Ë«Ñ¡)________¡£

A£®c(H£«)¼õС¡¡¡¡¡¡¡¡B£®c(I£­)¼õС

C£®I2(g)²»¶ÏÉú³É  D£®c(Fe3£«)Ôö¼Ó

(4)¾Ýͼ1£¬¼ÆËã3¡«18 sÄÚµÚ2×éʵÑéÖÐÉú³ÉIµÄƽ¾ù·´Ó¦ËÙÂÊ(д³ö¼ÆËã¹ý³Ì£¬½á¹û±£ÁôÁ½Î»ÓÐЧÊý×Ö)¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ϱíÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬ÆäÖÐÒѱê³öÁË¢Ù-¢á¾ÅÖÖÔªËØ¡£

ÖÜÆÚ

 

1

2

¢Ù

¢Ú

3

¢Û

¢Ü

¢Ý

¢Þ

¢ß

4

¢à

¢á

ÇëÓÃÕâ¾ÅÖÖÔªËػشðÏÂÁÐÎÊÌ⣺

£¨1£©ÊôÓÚ¹ý¶ÉÔªËصÄÊÇ      £¨ÓñíÖÐÊý×Ö±íʾ£©¡£

£¨2£©½ðÊôÐÔ×îÇ¿µÄÔªËØÊÇ       £¨ÌîÔªËØ·ûºÅ£©¡£

£¨3£©ÔªËØ¢ÝÐγɵÄÄÜʹƷºìÈÜÒºÍÊÉ«µÄÑõ»¯ÎïÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                               ¡£

£¨4£©Ð´³öÔªËØ¢ÛºÍÔªËØ¢ÞÐγɵĻ¯ºÏÎïµÄµç×Óʽ            ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔÚË®ÈÜÒºÖÐÄÜ´óÁ¿¹²´æ£¬ÇÒ¼ÓÈë¹ýÁ¿Ï¡ÁòËáʱ£¬ÓÐÆøÌåÉú³ÉµÄÊÇ£¨   £©

A£®Na+¡¢Ag+¡¢CO32¡ª¡¢Cl¡ª           B£®K+¡¢Ba2+¡¢SO42¡ª¡¢Cl¡ª

C£®Na+¡¢K+¡¢CO32¡ª¡¢Cl¡ª            D£®H+¡¢K+¡¢Cl¡ª¡¢HCO3¡ª

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


(1)½«4 mol AÆøÌåºÍ2 mol BÆøÌåÔÚ2 LµÄÈÝÆ÷ÖлìºÏ£¬²¢ÔÚÒ»¶¨Ìõ¼þÏ·¢ÉúÈçÏ·´Ó¦£º2A(g)£«B(g) 2C(g)£¬Èô¾­2 sºó²âµÃCµÄŨ¶ÈΪ0.6 mol·L£­1£¬ÏÖÓÐÏÂÁм¸ÖÖ˵·¨£º

¢ÙÓÃÎïÖÊA±íʾ·´Ó¦µÄƽ¾ùËÙÂÊΪ0.3 mol·L£­1·s£­1

¢ÚÓÃÎïÖÊB±íʾ·´Ó¦µÄƽ¾ùËÙÂÊΪ0.6mol·L£­1·s£­1

¢Û2 sʱÎïÖÊAµÄת»¯ÂÊΪ70%

¢Ü2 sʱÎïÖÊBµÄŨ¶ÈΪ0.7 mol·L£­1

ÆäÖÐÕýÈ·µÄÊÇ                                (¡¡¡¡)

A£®¢Ù¢Û      B£®¢Ù¢Ü      C£®¢Ú¢Û    D£®¢Û¢Ü

(2)Èô¢Ù¢ÚÖÐÓÃA¡¢B±íʾ·´Ó¦µÄƽ¾ùËÙÂÊ·Ö±ðΪ0.3 mol·L£­1·s£­1¡¢0.6 mol·L£­1·s£­1£¬ÄÄÖÖÎïÖʱíʾµÄ»¯Ñ§·´Ó¦ËÙÂʸü¿ì£¿

(3)ÈôÎïÖÊAµÄת»¯Âʾ­¹ý¼ÆËãΪ30%£¬ÄÇô£¬ÎïÖÊBµÄת»¯ÂÊΪ¶àÉÙ£¿ÄãÄÜѸËٵóö´ð°¸Âð

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔËÓÃÏà¹Ø»¯Ñ§ÖªÊ¶½øÐÐÅжϣ¬ÏÂÁнáÂÛ´íÎóµÄÊÇ(¡¡¡¡)

A£®Ä³ÎüÈÈ·´Ó¦ÄÜ×Ô·¢½øÐУ¬Òò´Ë¸Ã·´Ó¦ÊÇìØÔö·´Ó¦

B£®NH4FË®ÈÜÒºÖк¬ÓÐHF£¬Òò´ËNH4FÈÜÒº²»ÄÜ´æ·ÅÓÚ²£Á§ÊÔ¼ÁÆ¿ÖÐ

C£®¿Éȼ±ùÖ÷ÒªÊǼ×ÍéÓëË®ÔÚµÍθßѹÏÂÐγɵÄË®ºÏÎᄃÌ壬Òò´Ë¿É´æÔÚÓÚº£µ×

D£®Ôö´ó·´Ó¦ÎïŨ¶È¿É¼Ó¿ì·´Ó¦ËÙÂÊ£¬Òò´ËÓÃŨÁòËáÓëÌú·´Ó¦ÄÜÔö´óÉú³ÉH2µÄËÙÂÊ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ʹ·´Ó¦4NH3(g)£«3O2(g)===2N2(g)£«6H2O(g)ÔÚ2 LµÄÃܱÕÈÝÆ÷ÖнøÐУ¬°ë·ÖÖÓºóN2µÄÎïÖʵÄÁ¿Ôö¼ÓÁË0.6 mol¡£´Ë·´Ó¦µÄƽ¾ùËÙÂÊv(X)Ϊ                          (¡¡¡¡)

A£®v(NH3)£½0.02 mol·L£­1·s£­1

B£®v(O2)£½0.01 mol·L£­1·s£­1

C£®v(N2)£½0.02 mol·L£­1·s£­1

D£®v(H2O)£½0.02 mol·L£­1·s£­1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


¼ÓÈë0.1 molµÄMnO2·ÛÄ©ÓÚ50 mL¹ýÑõ»¯ÇâµÄÈÜÒºÖÐ(ÃܶÈΪ1.1 g·mL£­1)£¬ÔÚ±ê×¼×´¿öÏ·ųöÆøÌåµÄÌå»ýºÍʱ¼äµÄ¹ØϵÈçÏÂͼËùʾ£¬»Ø´ðÏÂÁÐÎÊÌ⣺

(1)A¡¢B¡¢C¡¢DËĵ㻯ѧ·´Ó¦ËÙÂÊ¿ìÂýµÄ˳ÐòΪ

________________________________________________________________________¡£

(2)½âÊÍ·´Ó¦ËÙÂʱ仯µÄÔ­Òò

________________________________________________________________________¡£

(3)¼ÆËã¹ýÑõ»¯ÇâµÄ³õʼÎïÖʵÄÁ¿Å¨¶È

________________________________________________________________________¡£

(4)Çó·´Ó¦½øÐе½2·ÖÖÓʱ¹ýÑõ»¯ÇâµÄÖÊÁ¿·ÖÊý¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


Äܹ»Ê¹·´Ó¦Cu+2H2O====Cu(OH)2+H2¡ü·¢ÉúµÄÊÇ(   )

A£®ÓÃͭƬ×÷Òõ¡¢Ñô¼«£¬µç½âÂÈ»¯Í­ÈÜÒº

B£®ÓÃͭƬ×÷Òõ¡¢Ñô¼«£¬µç½âÁòËá¼ØÈÜÒº

C£®Í­Ð¿ºÏ½ðÔÚ³±Êª¿ÕÆøÖз¢Éúµç»¯Ñ§¸¯Ê´

D£®Í­Æ¬×÷Ô­µç³ØµÄ¸º¼«£¬Ì¼°ô×÷Ô­µç³ØµÄÕý¼«£¬ÂÈ»¯ÄÆ×÷µç½âÖÊÈÜÒº

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁйØÓÚÄƺÍÄƵĻ¯ºÏÎïµÄÐðÊö²»ÕýÈ·µÄÊÇ(     )

A. ÈÈÎȶ¨ÐÔ£ºNa2CO3>NaHCO3

B£®Na2OÓëNa2O2¶¼ÄܺÍË®·´Ó¦Éú³É¼î£¬ËüÃǶ¼ÊǼîÐÔÑõ»¯Îï

C£®Ì¼ËáÇâÄÆ¿ÉÓÃÓÚÖÎÁÆθËá¹ý¶à

D£®Na2O2ÖÐÒõ¡¢ÑôÀë×ӵĸöÊý±ÈΪ1¡Ã 2

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸