A£® | c£¨Na+£©£¾c£¨HA-£©£¾c£¨OH-£©£¾c£¨H2A£©£¾c£¨H+£©£¾c£¨A2-£© | B£® | c£¨Na+£©£¾c£¨HA-£©£¾c£¨H+£©£¾c£¨A2-£©£¾c£¨H2A£©£¾c£¨OH-£© | ||
C£® | c£¨Na+£©£¾c£¨H+£©£¾c£¨HA-£©£¾c£¨A2-£©£¾c£¨OH-£©£¾c£¨H2A£© | D£® | c£¨Na+£©£¾c£¨OH-£©£¾c£¨HA-£©£¾c£¨H2A£©£¾c£¨H+£©£¾c£¨A2-£© |
·ÖÎö µ±V£¨NaOH£©=20mLʱ£¬n£¨H2A£©=n£¨NaOH£©=0.2mol/L¡Á0.02L=0.004mol£¬¶þÕßÇ¡ºÃ·´Ó¦Éú³ÉNaHA£¬¸ù¾Ýͼ֪£¬ÈÜÒºÖÐc£¨HA-£©£¾c£¨A2-£©£¾c£¨H2A£©£¬ËµÃ÷H2AÊǶþÔªÈõËᣬc£¨A2-£©£¾c£¨H2A£©ËµÃ÷HA-µÄµçÀë³Ì¶È´óÓÚË®½â³Ì¶È£¬ÔòÈÜÒº³ÊËáÐÔ£¬ËùÒÔ´æÔÚc£¨H+£©£¾c£¨OH-£©£¬HA-µÄµçÀëºÍË®½â³Ì¶È¶¼½ÏС£¬¾Ý´Ë·ÖÎö½â´ð£®
½â´ð ½â£ºµ±V£¨NaOH£©=20mLʱ£¬n£¨H2A£©=n£¨NaOH£©=0.2mol/L¡Á0.02L=0.004mol£¬¶þÕßÇ¡ºÃ·´Ó¦Éú³ÉNaHA£¬¸ù¾Ýͼ֪£¬ÈÜÒºÖÐc£¨HA-£©£¾c£¨A2-£©£¾c£¨H2A£©£¬ËµÃ÷H2AÊǶþÔªÈõËᣬc£¨A2-£©£¾c£¨H2A£©ËµÃ÷HA-µÄµçÀë³Ì¶È´óÓÚË®½â³Ì¶È£¬ÔòÈÜÒº³ÊËáÐÔ£¬ËùÒÔ´æÔÚc£¨H+£©£¾c£¨OH-£©£¬HA-µÄµçÀëºÍË®½â³Ì¶È¶¼½ÏС£¬ÄÆÀë×Ó²»Ë®½â£¬ËùÒÔc£¨Na+£©£¾c£¨HA-£©£¬Ë®»¹·¢ÉúµçÀ룬ֻÓÐHA-µçÀëÉú³ÉA2-£¬ËùÒÔc£¨H+£©£¾c£¨A2-£©£¬Ö»ÓÐHA-Ë®½âÉú³ÉH2A£¬ÈÜÒº³ÊËáÐÔ£¬ÇâÑõ¸ùÀë×ÓŨ¶È×îС£¬ËùÒÔÀë×ÓŨ¶È´óС˳ÐòÊÇc£¨Na+£©£¾c£¨HA-£©£¾c£¨H+£©£¾c£¨A2-£©£¾c£¨H2A£©£¾c£¨OH-£©£¬
¹ÊÑ¡B£®
µãÆÀ ±¾ÌâÒÔËá¼î»ìºÏÈÜÒº¶¨ÐÔÅжÏΪÔØÌ忼²éÀë×ÓŨ¶È´óС±È½Ï£¬²àÖØ¿¼²éѧÉú·ÖÎöÅжÏÄÜÁ¦£¬Ã÷È·»ìºÏÈÜÒºÖеÄÈÜÖʼ°ÆäÐÔÖÊÊǽⱾÌâ¹Ø¼ü£¬½áºÏͼÖи÷Àë×ÓŨ¶È´óС˳Ðò·ÖÎö½â´ð£¬ÌâÄ¿ÄѶÈÖеȣ®
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ÔªËØYµÄ×î¸ßÕý»¯ºÏ¼ÛΪ+6 | B£® | ¼òµ¥Àë×Ӱ뾶µÄ´óС˳Ðò£ºX£¾Y£¾Z | ||
C£® | ¼òµ¥Æø̬Ç⻯ÎïµÄÎȶ¨ÐÔ£ºX£¾Y | D£® | ÔªËØXºÍYÄÜÐγÉÀë×Ó»¯ºÏÎï |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ¢Ù¢Ú | B£® | ¢Ú¢Ü¢Ý | C£® | ¢Û¢Ý | D£® | ¢Ù¢Û¢Ü |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | b-m-n | B£® | b+m-n | C£® | b-m+n | D£® | b+m+n |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ·Ö×ÓÖмüÄÜÔ½´ó£¬¼ü³¤Ô½³¤£¬Ôò·Ö×ÓÔ½Îȶ¨ | |
B£® | P4ºÍCH4¶¼ÊÇÕýËÄÃæÌåÐͽṹµÄ·Ö×Ó£¬ÇÒ¼ü½Ç¶¼Îª109¡ã28¨@ | |
C£® | ÔÚ»¯Ñ§·´Ó¦ÖУ¬Ä³ÔªËØÓÉ»¯ºÏ̬±äΪÓÎÀë̬£¬Ôò¸ÃÔªËØÒ»¶¨±»»¹Ô | |
D£® | µç×Ó²ã½á¹¹ÏàͬµÄ¼òµ¥Àë×Ó£¬Æä°ë¾¶ËæºËµçºÉÊýÔö´ó¶ø¼õС |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ÌìÈ»ÓÍÖ¬º¬õ¥»ùÊôÓÚõ¥ÀàÎïÖÊ | B£® | ʯÓÍÁÑ»¯ºÍÁѽⶼ¿ÉÖƵÃÏ©Ìþ | ||
C£® | ·ÓÈ©Ê÷Ö¬ÊÇ·ÓÓëÈ©µÄËõ¾Û²úÎï | D£® | ÂóÑ¿ÌǺÍÕáÌǵÄË®½â²úÎïÏàͬ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
A£® | ³äµçʱµçÔ´µÄÕý¼«Ó¦Óëµç³ØµÄX¼«ÏàÁ¬ | |
B£® | ·Åµçʱ¸º¼«µç¼«·´Ó¦Ê½Îª£ºXH6+6e-¨TX+6H+ | |
C£® | ³äµçʱÑô¼«µç¼«·´Ó¦Ê½Îª£º6Ni£¨OH£©2+6OH-¨T6NiOOH+6H2O+6e- | |
D£® | ¸Ãµç³Ø·Åµç·´Ó¦1 mol XH6ʱ£¬ÈôÓÃÓÚµç½âË®£¬ÀíÂÛÉϿɵõ½16gÑõÆø |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ½ðÊôÄÆÔÚ¿ÕÆøÖÐȼÉյĻðÑæ³Ê»ÆÉ«£¬ÊÇÒòΪÉú³ÉµÄNa2O2Ϊµ»ÆÉ«¹ÌÌå | |
B£® | ÌúË¿ÔÚCl2ÖÐȼÉÕÓкì×ØÉ«µÄÑÌ£¬ÊÇÒòΪÉú³ÉµÄFeCl3Ϊºì×ØÉ«¹ÌÌå | |
C£® | ¹ýÁ¿µÄÌú¼ÓÈëÏ¡HNO3£¬³ä·Ö·´Ó¦ºó£¬µÎÈëKSCNÈÜÒº£¬ÈÜÒº³ÊºìÉ«£¬ËµÃ÷Ï¡HNO3½«FeÑõ»¯ÎªFe3+ | |
D£® | È¡ÉÙÁ¿ÈÜÒºX£¬ÏòÆäÖмÓÈëÊÊÁ¿ÐÂÖƵÄÂÈË®£¬ÔÙ¼Ó¼¸µÎKSCNÈÜÒº£¬ÈÜÒº±äºì£¬ËµÃ÷XÈÜÒºÖÐÒ»¶¨º¬ÓÐFe2+ |
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com