ÔÚ101 kPaºÍ25¡æʱ£¬Óз´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ
H2(g) + 1/2O2(g) =H2O(g)   ¡÷H=-241.8 kJ/mol
H2(g) + 1/2O2(g) =H2O(1)   ¡÷H=-285.8 kJ/mol
ÏÂÁÐ˵·¨ÖдíÎóµÄÊÇ£º
[     ]
A£®H2ȼÉÕÉú³É1mol H2O(g)ʱ£¬·Å³ö241.8kJµÄÈÈÁ¿
B£®H2µÄȼÉÕÈÈΪ285.8kJ
C£®O2Ç°ÃæµÄ1/2±íʾ²Î¼Ó·´Ó¦µÄO2µÄÎïÖʵÄÁ¿
D£®1molҺ̬ˮ±ä³ÉË®ÕôÆøʱÎüÊÕ44kJµÄÈÈÁ¿
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º¼ªÁÖÊ¡³¤´ºÊÐʮһ¸ß2011£­2012ѧÄê¸ßÒ»ÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔÌâ ÌâÐÍ£º013

ÔÚ101 kPaºÍ25¡æʱ£¬Óйط´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÈçÏ£º

C(s)£«1/2O2(g)£½CO(g)¡¡¦¤H1£½£­110.5 kJ¡¤mol£­1

H2(g)£«1/2O2(g)£½H2O(g)¡¡¦¤H2£½£­241.7 kJ¡¤mol£­1

H2(g)£«1/2O2(g)£½H2O(l)¡¡¦¤H3£½£­285.8 kJ¡¤mol£­1

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

[¡¡¡¡]

A£®

C(s)£«H2O(g)£½CO(g)£«H2(g)¡¡¦¤H£½£­131.2 kJ¡¤mol£­1

B£®

H2ȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽΪ£º2H2(g)£«O2(g)£½2H2O(l)¡¡¦¤H£½£­571.6 kJ¡¤mol£­1

C£®

2H2O(g)£½2H2(g)£«O2(g)¡¡¦¤H£½£­483.4 kJ¡¤mol£­1

D£®

H2O(g)£½H2O(l)¡¡¦¤H£½£­44.1 kJ¡¤mol£­1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2007-2008ѧÄ꺣Ä϶«·½Ìú·ÖÐѧ¸ßÈýµÚһѧÆÚ»¯Ñ§ÆÚÄ©¿¼ÊÔ ÌâÐÍ£º013

ÔÚ101 kPaºÍ25¡æʱ£¬Óз´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£ºH2(g)£«1/2O2(g)£½H2O(g)£»¦¤H£½£­241.8 kJ/mol£¬H2(g)£«1/2O2(g)£½H2O(1)£»¦¤H£½£­285.8 kJ/mol£®ÏÂÁÐ˵·¨ÖдíÎóµÄÊÇ£º

[¡¡¡¡]

A£®

H2ȼÉÕÉú³É1 mol¡¡H2O(g)ʱ£¬·Å³ö241.8 kJµÄÈÈÁ¿

B£®

H2µÄȼÉÕÈÈΪ285.8 kJ

C£®

O2Ç°ÃæµÄ1/2±íʾ²Î¼Ó·´Ó¦µÄO2µÄÎïÖʵÄÁ¿

D£®

1 molҺ̬ˮ±ä³ÉË®ÕôÆøʱÎüÊÕ44 kJµÄÈÈÁ¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ì¼ªÁÖ³¤´ºÊÐʮһ¸ß¸ßÒ»ÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÔÚ101 kPaºÍ25 ¡æ ʱ£¬Óйط´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÈçÏ£º

C(s)+1/2O2(g) =CO(g)    ¦¤H1£½£­110.5 kJ¡¤mol-1

H2(g)+ 1/2O2(g)=H2O(g)   ¦¤H2£½£­241.7 kJ¡¤mol-1

H2(g)+ 1/2O2(g)=H2O(l)   ¦¤H3£½£­285.8 kJ¡¤mol-1

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨    £©

A£®C(s)+H2O(g)=CO(g)+H2(g)  ¦¤H£½£­131.2 kJ¡¤mol-1

B£®H2ȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽΪ£º2H2(g)+O2(g)=2H2O (l)  ¦¤H£½£­571.6 kJ¡¤mol-1

C£®2H2O(g)=2H2(g)+O2 (g)  ¦¤H£½£­483.4 kJ¡¤mol-1

D£®H2O(g)=H2O(l)  ¦¤H£½£­44.1 kJ¡¤mol-1

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010Ä꼪ÁÖÊ¡¸ß¶þÉÏѧÆÚµÚÒ»´ÎÔ¿¼£¨»¯Ñ§£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÔÚ101 kPaºÍ25 ¡æʱ£¬Óйط´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÈçÏ£º

C(s)+1/2O2(g) =CO(g)    ¦¤H1£½£­110.5 kJ¡¤mol-1

H2(g)+ 1/2O2(g)=H2O(g)  ¦¤H2£½£­241.7 kJ¡¤mol-1

H2(g)+ 1/2O2(g)=H2O(l)   ¦¤H3£½£­285.8 kJ¡¤mol-1

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A£®C(s)+H2O(g)=CO(g)+H2(g)  ¦¤H£½£­131.2 kJ¡¤mol-1

B£®H2ȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽΪ£º2H2(g)+O2(g)=2H2O(l)  ¦¤H£½£­571.6 kJ¡¤mol-1

C£®2H2O(g)=2H2(g)+O2(g)  ¦¤H£½£­483.4 kJ¡¤mol-1

D£®H2O(g)=H2O(l)  ¦¤H£½£­44.1 kJ¡¤mol-1

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÆÚÖÐÌâ ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÔÚ101 kPaºÍ25 ¡æʱ£¬Óйط´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÈçÏ£º
C(s)+1/2O2(g) =CO(g)    ¦¤H1£½£­110.5 kJ¡¤mol-1
H2(g)+ 1/2O2(g)=H2O(g)   ¦¤H2£½£­241.7 kJ¡¤mol-1
H2(g)+ 1/2O2(g)=H2O(l)   ¦¤H3£½£­285.8 kJ¡¤mol-1
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
[     ]
A£®C(s)+H2O(g)=CO(g)+H2(g)  ¦¤H£½£­131.2 kJ¡¤mol-1
B£®H2ȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽΪ£º2H2(g)+O2(g)=2H2O (l)  ¦¤H£½£­571.6 kJ¡¤mol-1
C£®2H2O(g)=2H2(g)+O(g)  ¦¤H£½£­483.4 kJ¡¤mol-1
D£®H2O(g)=H2O(l)  ¦¤H£½£­44.1 kJ¡¤mol-1

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸