£¨10·Ö£©ÏÂͼÊÇ×ö¹ý°±ÆøÈÜÓÚË®µÄÅçȪʵÑé×°Öã¬ÊµÑéÍê³ÉºóÉÕÆ¿ÀïµÄ¿Õ¼ä±»·ÖΪÁ½¸ö²¿·Ö£ºAºÍB£¬Çë¸ù¾ÝʵÑéÄÚÈÝ°´ÒªÇóÌî¿Õ£º

£¨1£©AÖеÄÖ÷Òª³É·ÖÊÇ              £»

£¨2£©BÖÐÈÜÒº¼´Îª°±Ë®£¬°Ñ·Ó̪µÎÈ백ˮÖУ¬ÈÜÒºÏÔ       É«£¬ÊÇÒòΪ                           £¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£»

£¨3£©ÊÔ¼ÁµÄµÎ¼Ó˳Ðò²»Í¬£¬ÓÐʱ»á²úÉú²»Í¬µÄÏÖÏó¡£

¢Ù°Ñ°±Ë®µÎÈëAl2(SO4)3ÈÜÒºÖУ¬¢Ú°ÑAl2(SO4)3ÈÜÒºµÎÈ백ˮÖУ¬  ¢Ù¡¢¢ÚµÄʵÑéÏÖÏóÊÇ·ñÏàͬ             (Ìî¡°Ïàͬ¡±»ò¡°²»Í¬¡±)£¬Ð´³ö·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ                                         £»

·´Ó¦¢ÚµÄÀë×Ó·½³Ìʽ                                                        £»

£¨4£©°Ñ°±Ë®µÎ¼Óµ½FeSO4ÈÜÒºÖеÄÏÖÏóΪ                                       

                                                                         ¡£

 

¡¾´ð°¸¡¿

£¨7·Ö£©£¨1£©¿ÕÆø»òN2¡¢O2£»£¨2£©ºìÉ«£¬ NH3¡¤H2ONH4+ + OH-[

£¨3£©¢Ù Al2(SO4)3+6NH3¡¤H2O + 6H2O£½2Al(OH)3¡ý+3(NH4)2SO4

¢Ú Al3++3NH3¡¤H2O £½Al(OH)3¡ý+3NH4+

£¨4£©ÏÈÉú³É°×É«³Áµí£¬Èúó±ä³É»ÒÂÌÉ«£¬×îºó±ä³ÉºìºÖÉ«¡£

¡¾½âÎö¡¿

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨10·Ö£©ÏÂͼÊÇ×ö¹ý°±ÆøÈÜÓÚË®µÄÅçȪʵÑé×°Öã¬ÊµÑéÍê³ÉºóÉÕÆ¿ÀïµÄ¿Õ¼ä±»·ÖΪÁ½¸ö²¿·Ö£ºAºÍB£¬Çë¸ù¾ÝʵÑéÄÚÈÝ°´ÒªÇóÌî¿Õ£º

£¨1£©AÖеÄÖ÷Òª³É·ÖÊÇ             £»

£¨2£©BÖÐÈÜÒº¼´Îª°±Ë®£¬°Ñ·Ó̪µÎÈ백ˮÖУ¬ÈÜÒºÏÔ      É«£¬ÊÇÒòΪ                          £¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£»

£¨3£©ÊÔ¼ÁµÄµÎ¼Ó˳Ðò²»Í¬£¬ÓÐʱ»á²úÉú²»Í¬µÄÏÖÏó¡£

¢Ù°Ñ°±Ë®µÎÈëAl2(SO4)3ÈÜÒºÖУ¬¢Ú°ÑAl2(SO4)3ÈÜÒºµÎÈ백ˮÖУ¬  ¢Ù¡¢¢ÚµÄʵÑéÏÖÏóÊÇ·ñÏàͬ            (Ìî¡°Ïàͬ¡±»ò¡°²»Í¬¡±)£¬Ð´³ö·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ                                        £»

·´Ó¦¢ÚµÄÀë×Ó·½³Ìʽ                                                       £»

£¨4£©°Ñ°±Ë®µÎ¼Óµ½FeSO4ÈÜÒºÖеÄÏÖÏóΪ                                       

                                                                        ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010¡ª2011ѧÄêºþ±±Ê¡É³ÊÐÖÐѧ¸ßÒ»ÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

£¨10·Ö£©ÏÂͼÊÇ×ö¹ý°±ÆøÈÜÓÚË®µÄÅçȪʵÑé×°Öã¬ÊµÑéÍê³ÉºóÉÕÆ¿ÀïµÄ¿Õ¼ä±»·ÖΪÁ½¸ö²¿·Ö£ºAºÍB£¬Çë¸ù¾ÝʵÑéÄÚÈÝ°´ÒªÇóÌî¿Õ£º

£¨1£©AÖеÄÖ÷Òª³É·ÖÊÇ             £»
£¨2£©BÖÐÈÜÒº¼´Îª°±Ë®£¬°Ñ·Ó̪µÎÈ백ˮÖУ¬ÈÜÒºÏÔ      É«£¬ÊÇÒòΪ                          £¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£»
£¨3£©ÊÔ¼ÁµÄµÎ¼Ó˳Ðò²»Í¬£¬ÓÐʱ»á²úÉú²»Í¬µÄÏÖÏó¡£
¢Ù°Ñ°±Ë®µÎÈëAl2(SO4)3ÈÜÒºÖУ¬¢Ú°ÑAl2(SO4)3ÈÜÒºµÎÈ백ˮÖУ¬ ¢Ù¡¢¢ÚµÄʵÑéÏÖÏóÊÇ·ñÏàͬ            (Ìî¡°Ïàͬ¡±»ò¡°²»Í¬¡±)£¬Ð´³ö·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ                                        £»
·´Ó¦¢ÚµÄÀë×Ó·½³Ìʽ                                                       £»
£¨4£©°Ñ°±Ë®µÎ¼Óµ½FeSO4ÈÜÒºÖеÄÏÖÏóΪ                                       
                                                                        ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂͼÊÇ×ö¹ý°±ÆøÈÜÓÚË®µÄÅçȪʵÑé×°Öã¬ÊµÑéÍê³ÉºóÉÕÆ¿ÀïµÄ¿Õ¼ä±»·ÖΪÁ½¸ö²¿·Ö£ºAºÍB£¬Çë¸ù¾ÝʵÑéÄÚÈÝ°´ÒªÇóÌî¿Õ£º

£¨1£©AÖеÄÖ÷Òª³É·ÖÊÇ              £»

£¨2£©BÖÐÈÜÒº¼´Îª°±Ë®£¬°Ñ·Ó̪µÎÈ백ˮÖУ¬ÈÜÒºÏÔ       É«£¬ÊÇÒòΪ                           £¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£»

£¨3£©ÊÔ¼ÁµÄµÎ¼Ó˳Ðò²»Í¬£¬ÓÐʱ»á²úÉú²»Í¬µÄÏÖÏó¡£

¢Ù°Ñ°±Ë®µÎÈëAl2(SO4)3ÈÜÒºÖУ¬¢Ú°ÑAl2(SO4)3ÈÜÒºµÎÈ백ˮÖУ¬  ¢Ù¡¢¢ÚµÄʵÑéÏÖÏóÊÇ·ñÏàͬ             (Ìî¡°Ïàͬ¡±»ò¡°²»Í¬¡±)£¬Ð´³ö·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ                                         £»

·´Ó¦¢ÚµÄÀë×Ó·½³Ìʽ                                                        £»

£¨4£©°Ñ°±Ë®µÎ¼Óµ½FeSO4ÈÜÒºÖеÄÏÖÏóΪ                                       

                                                                         ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂͼÊÇ×ö¹ý°±ÆøÈÜÓÚË®µÄÅçȪʵÑé×°Öã¬ÊµÑéÍê³ÉºóÉÕÆ¿ÀïµÄ¿Õ¼ä±»·ÖΪÁ½¸ö²¿·Ö£ºAºÍB£¬Çë¸ù¾ÝʵÑéÄÚÈÝ°´ÒªÇóÌî¿Õ£º

£¨1£©AÖеÄÖ÷Òª³É·ÖÊÇ              £»

£¨2£©BÖÐÈÜÒº¼´Îª°±Ë®£¬°Ñ·Ó̪µÎÈ백ˮÖУ¬ÈÜÒºÏÔ       É«£¬ÊÇÒòΪ                           £¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£»

£¨3£©ÊÔ¼ÁµÄµÎ¼Ó˳Ðò²»Í¬£¬ÓÐʱ»á²úÉú²»Í¬µÄÏÖÏó¡£

¢Ù°Ñ°±Ë®µÎÈëAl2(SO4)3ÈÜÒºÖУ¬¢Ú°ÑAl2(SO4)3ÈÜÒºµÎÈ백ˮÖУ¬  ¢Ù¡¢¢ÚµÄʵÑéÏÖÏóÊÇ·ñÏàͬ             (Ìî¡°Ïàͬ¡±»ò¡°²»Í¬¡±)£¬Ð´³ö·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ                                         £»

·´Ó¦¢ÚµÄÀë×Ó·½³Ìʽ                                                        £»

£¨4£©°Ñ°±Ë®µÎ¼Óµ½FeSO4ÈÜÒºÖеÄÏÖÏóΪ                                       

                                                                         ¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸