ij»ìºÏ¼îÊÇ¢ÙNa2CO3ºÍNaHCO3 »ò¢Ú Na2CO3ºÍ NaOH¡£Óá° ˫ָʾ¼Á·¨¡±¶ÔÑùÆ·µÄ×é·ÖºÍ×ܼîÁ¿ [n (Na2O) ] ½øÐвⶨ¡£ÊµÑé·½°¸£º³ÆÈ¡ 0.2960g ÑùÆ·Åä³É 500mL ÈÜÒº£¬È¡25.00mLÖÃÓÚ250mL ׶ÐÎÆ¿ÖУ¬¼ÓÊÊÁ¿ÕôÁóË®ºÍ¼¸µÎ·Ó̪£¬ÓÃ0.0100 mol•L£­1 µÄÑÎËá±ê×¼ÈÜÒº½«»ìºÏ¼îµÎ¶¨³ÉNaHCO3£¬È»ºóÔÙÓÃäå¼×·ÓĄ̂D¨D¶þ¼×»ù»ÆΪָʾ¼Á½øÐе樣¬½«NaHCO3ÍêÈ«Öк͡£

£¨1£©Ä³Í¬Ñ§Æ½Ðеζ¨ÁËÈý´Î£¬Ã¿´ÎµÎ¶¨´Ó "0" µã¿ªÊ¼¶ÁÊý£¬ÆäÖÐµÚ I ´ÎµÎ¶¨µÄµÚÒ»¸öÖÕµãµÄÒºÃæÈçÏÂͼËùʾ£¬Çë¶Á³öʵÑéÊý¾Ý£¬ÌîÈëÏÂÁбí¸ñÖÐ

ÐòºÅ

µÚÒ»µÎ¶¨ÖÕµãµÄ¶ÁÊý£¨V1/mL£© 

µÚ¶þµÎ¶¨ÖÕµãµÄ¶ÁÊý£¨V2/mL£©

I

£¿

26.85

II

10.02

25.02

III

9.98

24.98

             

            

         

           

       

£¨2£©¸Ã»ìºÏ¼îÑùÆ·µÄ×é³ÉΪ                 £¬ÀíÓÉ                      ¡£

£¨3£©½«»ìºÏ¼îµÎ¶¨³ÉNaHCO3µÄ¹ý³ÌÖУ¬ÎªÁ˽á¹û¸ü¼Ó׼ȷ£¬Ó¦Ê¼ÖÕÖðµÎµÎ¼Ó£¬ÕâÑù²Ù×÷µÄÔ­ÒòÊÇ                                                             ¡£

£¨4£©ÉÏÊö¼îÑùÖÐ×ܼîÁ¿[n (Na2O) ]ÊǶàÉÙ£¿Ð´³ö¼ÆËã¹ý³Ì

                                                                     ¡£

£¨5£©Èç¹û±¾ÊµÑéÖ»²â¶¨ÑùÆ·µÄ×ܼîÁ¿£¬ÊµÑé·½°¸Ó¦¸ÃÔõÑùÉè¼Æ£º                     

                                                                    ¡£

£¨1£©11£®76~11£®78¾ù¿É

£¨2£©Na2CO3 ºÍNaHCO3  ÒòΪµÚÒ»µÎ¶¨ÖÕµãËùÓÃÌå»ýСÓÚµÚ¶þµÎ¶¨ÖÕµãËùÓÃÌå»ý»ò

V1<£¨V2-V1£©»ò¼ÆËã˵Ã÷

£¨3£©ÒÔ·ÀµÎ¶¨¹ý¿ìʹNa2CO3Ö±½ÓÉú³ÉH2CO3 

£¨4£©¼îÑùµÄ×ܼîÁ¿Îª£º

n(Na2O)= [£¨25£®02mL +24£®98 mL£©/2]¡Á10-3L/ mL¡Á0.0100mol/L¡Á1/2¡Á20=0.0025mol

£¨5£©Ö±½ÓÒÔäå¼×·ÓÂÌ-¶þ¼×»ù»Æ»ò¼×»ù³ÈΪָʾ¼ÁµÎ¶¨ÖÁÖÕµã

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøij»ìºÏ¼îÊÇ¢ÙNa2CO3ºÍNaHCO3 »ò¢ÚNa2CO3ºÍ NaOH£®Óá°Ë«Ö¸Ê¾¼Á·¨¡±¶ÔÑùÆ·µÄ×é·ÖºÍ×ܼîÁ¿[n£¨Na2O£©]½øÐвⶨ£®ÊµÑé·½°¸£º³ÆÈ¡ 0.2960g ÑùÆ·Åä³É 500mL ÈÜÒº£¬È¡25.00mLÖÃÓÚ250mL ×¶ÐÎÆ¿ÖУ¬¼ÓÊÊÁ¿Õô¹ÝË®ºÍ¼¸µÎ·Ó̪£¬ÓÃ0.0100mol?L-1 µÄÑÎËá±ê×¼ÈÜÒº½«»ìºÏ¼îµÎ¶¨³ÉNaHCO3£¬È»ºóÔÙÓÃäå¼×·ÓÂÌ--¶þ¼×»ù»ÆΪָʾ¼Á½øÐе樣¬½«NaHCO3ÍêÈ«Öкͣ®
£¨1£©Ä³Í¬Ñ§Æ½Ðеζ¨ÁËÈý´Î£¬Ã¿´ÎµÎ¶¨´Ó¡°0¡°µã¿ªÊ¼¶ÁÊý£¬ÆäÖеڠI ´ÎµÎ¶¨µÄµÚÒ»¸öÖÕµãµÄÒºÃæÈçͼËùʾ£¬Çë¶Á³öʵÑéÊý¾Ý£¬ÌîÈëÏÂÁбí¸ñÖÐ
ÐòºÅ µÚÒ»µÎ¶¨ÖÕµãµÄ¶ÁÊý£¨V1/mL£© µÚ¶þµÎ¶¨ÖÕµãµÄ¶ÁÊý£¨V2/mL£©
I £¿ 26.85
II 10.02 25.02
III 9.98 24.98
£¨2£©¸Ã»ìºÏ¼îÑùÆ·µÄ×é³ÉΪ
 
£¬ÀíÓÉ
 
£®
£¨3£©½«»ìºÏ¼îµÎ¶¨³ÉNaHCO3µÄ¹ý³ÌÖУ¬ÎªÁ˽á¹û¸ü¼Ó׼ȷ£¬Ó¦Ê¼ÖÕÖðµÎµÎ¼Ó£¬ÕâÑù²Ù×÷µÄÔ­ÒòÊÇ
 
£®
£¨4£©ÉÏÊö¼îÑùÖÐ×ܼîÁ¿[n£¨Na2O£©]ÊǶàÉÙ£¿Ð´³ö¼ÆËã¹ý³Ì
 
£®
£¨5£©Èç¹û±¾ÊµÑéÖ»²â¶¨ÑùÆ·µÄ×ܼîÁ¿£¬ÊµÑé·½°¸Ó¦¸ÃÔõÑùÉè¼Æ£º
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ij»ìºÏ¼îÊÇ¢ÙNa2CO3ºÍNaHCO3 »ò¢Ú Na2CO3ºÍ NaOH¡£Óá° ˫ָʾ¼Á·¨¡±¶ÔÑùÆ·µÄ×é·ÖºÍ×ܼîÁ¿ [n (Na2O) ] ½øÐвⶨ¡£ÊµÑé·½°¸£º³ÆÈ¡ 0.2960g ÑùÆ·Åä³É 500mL ÈÜÒº£¬È¡25.00mLÖÃÓÚ250mL ׶ÐÎÆ¿ÖУ¬¼ÓÊÊÁ¿Õô¹ÝË®ºÍ¼¸µÎ·Ó̪£¬ÓÃ0.0100 mol??L£­1 µÄÑÎËá±ê×¼ÈÜÒº½«»ìºÏ¼îµÎ¶¨³ÉNaHCO3£¬È»ºóÔÙÓÃäå¼×·ÓÂÌ¡ª¡ª¶þ¼×»ù»ÆΪָʾ¼Á½øÐе樣¬½«NaHCO3ÍêÈ«Öк͡£

£¨1£©Ä³Í¬Ñ§Æ½Ðеζ¨ÁËÈý´Î£¬Ã¿´ÎµÎ¶¨´Ó "0" µã¿ªÊ¼¶ÁÊý£¬ÆäÖÐµÚ I ´ÎµÎ¶¨µÄµÚÒ»¸öÖÕµãµÄÒºÃæÈçÓÒͼËùʾ£¬Çë¶Á³öʵÑéÊý¾Ý£¬ÌîÈëÏÂÁбí¸ñÖÐ

ÐòºÅ

µÚÒ»µÎ¶¨ÖÕµãµÄ¶ÁÊý£¨V1/mL£©

µÚ¶þµÎ¶¨ÖÕµãµÄ¶ÁÊý£¨V2/mL£©

I

£¿

26.85

II

10.02

25.02

III

9.98

24.98

£¨2£©¸Ã»ìºÏ¼îÑùÆ·µÄ×é³ÉΪ                 £¬ÀíÓÉ                      ¡£

£¨3£©½«»ìºÏ¼îµÎ¶¨³ÉNaHCO3µÄ¹ý³ÌÖУ¬ÎªÁ˽á¹û¸ü¼Ó׼ȷ£¬Ó¦Ê¼ÖÕÖðµÎµÎ¼Ó£¬ÕâÑù²Ù×÷µÄÔ­ÒòÊÇ                                                    ¡£

£¨4£©ÉÏÊö¼îÑùÖÐ×ܼîÁ¿[n (Na2O) ]ÊǶàÉÙ£¿Ð´³ö¼ÆËã¹ý³Ì

                                                                                                                                                                                                 ¡£

£¨5£©Èç¹û±¾ÊµÑéÖ»²â¶¨ÑùÆ·µÄ×ܼîÁ¿£¬ÊµÑé·½°¸Ó¦¸ÃÔõÑùÉè¼Æ£º                                       

                                                                                                ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

 (12 ·Ö )ij»ìºÏ¼îÊÇ¢ÙNa2CO3ºÍNaHCO3 »ò¢Ú Na2CO3ºÍ NaOH¡£Óá° ˫ָʾ¼Á·¨¡±¶ÔÑùÆ·µÄ×é·ÖºÍ×ܼîÁ¿ [n (Na2O)] ½øÐвⶨ¡£ÊµÑé·½°¸£º³ÆÈ¡ 0.2960g ÑùÆ·Åä³É 500mL ÈÜÒº£¬È¡25.00mLÖÃÓÚ250mL׶ÐÎÆ¿ÖУ¬¼ÓÊÊÁ¿Õô¹ÝË®ºÍ¼¸µÎ·Ó̪£¬ÓÃ0.0100 mol•L£­1 µÄÑÎËá±ê×¼ÈÜÒº½«»ìºÏ¼îµÎ¶¨³ÉNaHCO3£¬È»ºóÔÙÓÃäå¼×·ÓÂÌ¡ª¡ª¶þ¼×»ù»ÆΪָʾ¼Á½øÐе樣¬½«NaHCO3ÍêÈ«Öк͡£

£¨1£©Ä³Í¬Ñ§Æ½Ðеζ¨ÁËÈý´Î£¬Ã¿´ÎµÎ¶¨´Ó "0" µã¿ªÊ¼¶ÁÊý£¬ÆäÖÐµÚ I ´ÎµÎ¶¨µÄµÚÒ»¸öÖÕµãµÄÒºÃæÈçÓÒͼËùʾ£¬Çë¶Á³öʵÑéÊý¾Ý£¬ÌîÈëÏÂÁбí¸ñÖÐ

ÐòºÅ

µÚÒ»µÎ¶¨ÖÕµãµÄ¶ÁÊý£¨V1/mL£©

µÚ¶þµÎ¶¨ÖÕµãµÄ¶ÁÊý£¨V2/mL£©

I

£¿

26.85

II

10.02

25.02

III

9.98

24.98

 

£¨2£©¸Ã»ìºÏ¼îÑùÆ·µÄ×é³ÉΪ                £¬Àí

ÓÉ                     ¡£

£¨3£©½«»ìºÏ¼îµÎ¶¨³ÉNaHCO3µÄ¹ý³ÌÖУ¬ÎªÁ˽á¹û¸ü¼Ó׼ȷ£¬Ó¦Ê¼ÖÕÖðµÎµÎ¼Ó£¬ÕâÑù²Ù×÷µÄÔ­ÒòÊÇ                                                   ¡£

£¨4£©ÉÏÊö¼îÑùÖÐ×ܼîÁ¿[n (Na2O) ]ÊǶàÉÙ£¿Ð´³ö¼ÆËã¹ý³Ì

                                                                                 

                                                                          ¡£

£¨5£©Èç¹û±¾ÊµÑéÖ»²â¶¨ÑùÆ·µÄ×ܼîÁ¿£¬ÊµÑé·½°¸Ó¦¸ÃÔõÑùÉè¼Æ£º                         

                                                                          ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º¹óÖÝÊ¡Ç廪ʵÑéѧУ2010½ì¸ßÈýÏÂѧÆÚ3ÔÂÔ¿¼ ÌâÐÍ£ºÌî¿ÕÌâ

 (12 ·Ö )ij»ìºÏ¼îÊÇ¢ÙNa2CO3ºÍNaHCO3 »ò¢Ú Na2CO3ºÍ NaOH¡£Óá° ˫ָʾ¼Á·¨¡±¶ÔÑùÆ·µÄ×é·ÖºÍ×ܼîÁ¿ [n (Na2O) ] ½øÐвⶨ¡£ÊµÑé·½°¸£º³ÆÈ¡ 0.2960g ÑùÆ·Åä³É 500mL ÈÜÒº£¬È¡25.00mLÖÃÓÚ250mL ׶ÐÎÆ¿ÖУ¬¼ÓÊÊÁ¿Õô¹ÝË®ºÍ¼¸µÎ·Ó̪£¬ÓÃ0.0100 mol•L£­1 µÄÑÎËá±ê×¼ÈÜÒº½«»ìºÏ¼îµÎ¶¨³ÉNaHCO3£¬È»ºóÔÙÓÃäå¼×·ÓÂÌ¡ª¡ª¶þ¼×»ù»ÆΪָʾ¼Á½øÐе樣¬½«NaHCO3ÍêÈ«Öк͡£

£¨1£©Ä³Í¬Ñ§Æ½Ðеζ¨ÁËÈý´Î£¬Ã¿´ÎµÎ¶¨´Ó "0" µã¿ªÊ¼¶ÁÊý£¬ÆäÖÐµÚ I ´ÎµÎ¶¨µÄµÚÒ»¸öÖÕµãµÄÒºÃæÈçÓÒͼËùʾ£¬Çë¶Á³öʵÑéÊý¾Ý£¬ÌîÈëÏÂÁбí¸ñÖÐ

ÐòºÅ

µÚÒ»µÎ¶¨ÖÕµãµÄ¶ÁÊý£¨V1/mL£©

µÚ¶þµÎ¶¨ÖÕµãµÄ¶ÁÊý£¨V2/mL£©

I

£¿

26.85

II

10.02

25.02

III

9.98

24.98

 

£¨2£©¸Ã»ìºÏ¼îÑùÆ·µÄ×é³ÉΪ                 £¬Àí

ÓÉ                      ¡£

£¨3£©½«»ìºÏ¼îµÎ¶¨³ÉNaHCO3µÄ¹ý³ÌÖУ¬ÎªÁ˽á¹û¸ü¼Ó׼ȷ£¬Ó¦Ê¼ÖÕÖðµÎµÎ¼Ó£¬ÕâÑù²Ù×÷µÄÔ­ÒòÊÇ                                                    ¡£

£¨4£©ÉÏÊö¼îÑùÖÐ×ܼîÁ¿[n (Na2O) ]ÊǶàÉÙ£¿Ð´³ö¼ÆËã¹ý³Ì

                                                                                 

                                                                           ¡£

£¨5£©Èç¹û±¾ÊµÑéÖ»²â¶¨ÑùÆ·µÄ×ܼîÁ¿£¬ÊµÑé·½°¸Ó¦¸ÃÔõÑùÉè¼Æ£º                          

                                                                           ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸