ÓÐÒ»¹ÌÌå»ìºÏÎ¿ÉÄÜÓÉ̼ËáÄÆ¡¢ÁòËáÄÆ¡¢ÁòËáÍ­¡¢ÂÈ»¯¸Æ¡¢ÂÈ»¯ÄƵÈÎïÖÊ×é³É¡£Îª¼ø±ðËüÃÇ£¬×öÁËÈçÏÂʵÑ飺

(1)½«¹ÌÌå»ìºÏÎïÈÜÓÚË®£¬½Á°èºóµÃÎÞÉ«ÈÜÒº£»

(2)ÔÚ´ËÈÜÒºÖеÎÈëÂÈ»¯±µÈÜÒºÓа×É«³ÁµíÉú³É£»

(3)¹ýÂË£¬È»ºóÔÚ´Ë°×É«³ÁµíÖмÓÈë×ãÁ¿Ï¡ÏõËᣬ³Áµí×îºóÈ«²¿Ïûʧ¡£

ÓÉ´ËÍƶϣ¬¹ÌÌå»ìºÏÎïÖп϶¨ÓÐ________£»¿Ï¶¨Ã»ÓÐ__________________________£»¿ÉÄÜ»áÓÐ__________¡£Èç¹ûÒª½øÒ»²½È·¶¨¿ÉÄÜÓеÄÎïÖÊÊÇ·ñ´æÔÚ£¬¿É²ÉÓõļìÑé·½·¨ÊÇ________________________________________________________________________

________________________________________________________________________¡£


(1)̼ËáÄÆ¡¡ÁòËáÄÆ¡¢ÁòËáÍ­¡¢ÂÈ»¯¸Æ¡¡ÂÈ»¯ÄÆ¡¡¼ÓÈëÏõËáËữµÄAgNO3ÈÜÒº£¬ÈôÓа×É«³ÁµíÉú³É£¬Ôòº¬ÓÐNaCl£¬·ñÔò²»º¬

½âÎö¡¡ÓÉÒÑÖªÌõ¼þ(1)ÍƳö¿Ï¶¨²»º¬À¶É«Cu2£«£¬Na2CO3ºÍCaCl2Ö»º¬ÆäÖÐÒ»ÖÖ£»ÓÉÌõ¼þ(2)ÍƳöNa2CO3ºÍNa2SO4ÖÁÉÙº¬ÓÐÒ»ÖÖ£»ÓÉÌõ¼þ(3)ÍƳöÖ»º¬Na2CO3¶øÎÞNa2SO4£¬½áºÏ(1)µÄ½áÂۿɵÃÎÞCaCl2¡£

ÈôҪȷ¶¨ÊÇ·ñº¬ÓÐNaCl£¬Ó¦¼ìÑéCl£­µÄ´æÔÚ£¬È¡ÉÙÁ¿Ô­ÈÜÒºÓÚÊÔ¹ÜÖУ¬¼ÓÈëÏõËáËữµÄAgNO3ÈÜÒº£¬ÈôÓа×É«³ÁµíÉú³É£¬Ôòº¬ÓÐNaCl£¬·ñÔò²»º¬¡£


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁйØÓÚÓлú»¯ºÏÎïµÄ½á¹¹¡¢ÐÔÖʵÄÐðÊöÕýÈ·µÄÊÇ(¡¡¡¡)

A£®±½¡¢ÓÍÖ¬¾ùÄÜʹËáÐÔKMnO4ÈÜÒºÍÊÉ«

B£®¼×ÍéºÍCl2µÄ·´Ó¦ÓëÒÒÏ©ºÍBr2µÄ·´Ó¦ÊôÓÚͬһÀàÐ͵ķ´Ó¦

C£®ÕáÌÇ¡¢ÂóÑ¿ÌǵķÖ×Óʽ¾ùΪC12H22O11£¬¶þÕß»¥ÎªÍ¬·ÖÒì¹¹Ìå

D£®ÒÒ´¼¡¢ÒÒËá¾ùÄÜÓëNaOHÈÜÒº·´Ó¦£¬ÒòΪ·Ö×ÓÖоùº¬ÓйÙÄÜÍÅ¡°¡ªOH¡±

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


Na¡¢Al¡¢Fe¡¢Cu¡¢Cl¡¢Si¡¢N¡¢SÊÇÖÐѧ»¯Ñ§ÖÐÖØÒªµÄÔªËØ£¬ÇëÍê³ÉÏÂÁÐÏà¹ØÔªËؼ°Æ仯ºÏÎïµÄÎÊÌ⣺

£¨1£©Ð´³ö¹¤Òµ¹ÌµªºÏ³É°±µÄ»¯Ñ§·½³Ìʽ____________________________________£»

£¨2£©½«Na2Fe5Si8O22(OH)2 д³öÑõ»¯ÎïµÄÐÎʽΪ_________________________________£»                

£¨3£©ÇâÁòËáΪÈõËᣬ½«H2SÆøÌåͨÈëµ½FeCl3ÈÜÒºÖÐÈÜÒº³öÏÖµ­»ÆÉ«µÄ³Áµí£¬Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ____________________________£»

£¨4£©Ð´³öÓÃAlÓëMnO2¸ßÎÂÏ·´Ó¦ÖÆMnµÄ»¯Ñ§·½³Ìʽ__________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


¶ÌÖÜÆÚ½ðÊôÔªËؼס«¶¡ÔÚÔªËØÖÜÆÚ±íÖеÄÏà¶ÔλÖÃÈçÓÒ±íËùʾ£º

ÏÂÁÐÅжÏÕýÈ·µÄÊÇ(     )

A¡¢Ô­×Ӱ뾶£º±û>¶¡>ÒÒ             

B¡¢µ¥ÖʵĻ¹Ô­ÐÔ£º¶¡>±û>¼×

C¡¢¼×¡¢ÒÒ¡¢±ûµÄÑõ»¯Îï¾ùΪ¹²¼Û»¯ºÏÎï  

D¡¢ÒÒ¡¢±û¡¢¶¡µÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÄÜÏ໥·´Ó¦

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔÚÒ»Ö§25 mLµÄËáʽµÎ¶¨¹ÜÖÐÊ¢Èë0.1 mol·L£­1 HClÈÜÒº£¬ÆäÒºÃæÇ¡ºÃÔÚ5 mLµÄ¿Ì¶È´¦£¬Èô°ÑµÎ¶¨¹ÜÖеÄÈÜҺȫ²¿·ÅÈëÉÕ±­ÖУ¬È»ºóÒÔ0.1 mol·L£­1 NaOHÈÜÒº½øÐÐÖкͣ¬ÔòËùÐèNaOHÈÜÒºµÄÌå»ý(¡¡¡¡)

A£®´óÓÚ20 mL        B£®Ð¡ÓÚ20 mL       C£®µÈÓÚ20 mL       D£®µÈÓÚ5 mL

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔÚÏÂͼװÖÃÖУ¬Í¨µçºó¿É¹Û²ìµ½Cu¼«Èܽ⣬ÔòÏÂÁÐ˵·¨Öв»ÕýÈ·µÄÊÇ(¡¡¡¡)

A£®Ö±Á÷µçÔ´ÖУ¬AÊÇÕý¼«

B£®Á½³ØÄÚCuSO4ÈÜҺŨ¶È¾ù²»¸Ä±ä

C£®Á½Ìú¼«ÉÏ×î³õÎö³öÎïÏàͬ

D£®P³ØÄÚÈÜÒºµÄÖÊÁ¿Öð½¥¼õС

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔÚA¡¢B¡¢CÈý¸öÉÕ±­ÖзֱðÊ¢ÓÐÏàͬŨ¶ÈµÄÏ¡ÁòËᣬÈçͼËùʾ£º

(1)AÖз´Ó¦µÄÀë×Ó·½³ÌʽΪ_____________________________________________¡£

(2)BÖÐSn¼«µÄµç¼«·´Ó¦Ê½Îª__________________________________________£¬

Sn¼«¸½½üÈÜÒºµÄpH________(Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±»ò¡°²»±ä¡±)¡£

(3)CÖб»¸¯Ê´µÄ½ðÊôÊÇ________£¬×Ü·´Ó¦µÄÀë×Ó·½³ÌʽΪ________________________________£¬±È½ÏA¡¢B¡¢CÖÐÌú±»¸¯Ê´µÄËÙÂÊ£¬ÓÉ¿ìµ½ÂýµÄ˳ÐòÊÇ________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÒÑÖªH2(g)¡¢C2H4(g)ºÍC2H5OH(l)µÄȼÉÕÈÈ·Ö±ðÊÇ£­285.8 kJ·mol£­1¡¢£­1 411.0 kJ·mol£­1ºÍ£­1 366.8 kJ·mol£­1£¬ÔòÓÉC2H4(g)ºÍH2O(l)·´Ó¦Éú³ÉC2H5OH(l)µÄ¦¤HΪ¡¡¡¡

A£®£­44.2 kJ·mol£­1¡¡¡¡¡¡¡¡¡¡¡¡B£®£«44.2 kJ·mol£­1

C£®£­330 kJ·mol£­1            D£®£«330 kJ·mol£­1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


½«amolСËÕ´òºÍbmol¹ýÑõ»¯ÄÆÖÃÓÚijÌå»ý¿É±äµÄÃܱÕÈÝÆ÷Öгä·Ö¼ÓÈÈ£¬·´Ó¦ºó²âµÃÈÝÆ÷ÄÚµÄÑõÆøΪ1mol£¬ÏÂÁÐ˵·¨Ò»¶¨ÕýÈ·µÄÊÇ

A£®b=2                        B£®ÈÝÆ÷ÖÐÒ»¶¨Ã»ÓвÐÓàµÄCO2ºÍË®ÕôÆø

C£®a:b¡Ý1                       D£®·´Ó¦ÖÐתÒƵĵç×ÓÊýÒ»¶¨Îª2NA

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸