ʵÑéÌâ

º£´øÖк¬ÓзḻµÄµâ£®ÎªÁË´Óº£´øÖÐÌáÈ¡µâ£¬Ä³Ñо¿ÐÔѧϰС×éÉè¼Æ²¢½øÐÐÁËÒÔÏÂʵÑ飺

ÇëÌîдÏÂÁпհףº

(1)

²½Öè¢Ù×ÆÉÕº£´øʱ£¬³ýÐèÒªÈý½Å¼ÜÍ⣬»¹ÐèÒªÓõ½µÄʵÑéÒÇÆ÷ÊÇ________(´ÓÏÂÁÐÒÇÆ÷ÖÐÑ¡³öËùÐèµÄÒÇÆ÷£¬ÓñêºÅ×ÖĸÌîдÔÚ¿Õ°×´¦)£®

A¡¢ÉÕ±­¡¡B¡¢ÛáÛö¡¡C¡¢±íÃæÃó¡¡D¡¢ÄàÈý½Ç¡¡E¡¢¾Æ¾«µÆ¡¡F¡¢¸ÉÔïÆ÷

(2)

²½Öè¢ÛµÄʵÑé²Ù×÷Ãû³ÆÊÇ________£»²½Öè¢ÞµÄÄ¿µÄÊÇ´Óº¬µâ±½ÈÜÒºÖзÖÀë³öµ¥ÖʵâºÍ»ØÊÕ±½£¬¸Ã²½ÖèµÄʵÑé²Ù×÷Ãû³ÆÊÇ________£®

(3)

²½Öè¢Ü·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ________£®

(4)

²½Öè¢ÝÖУ¬Ä³Ñ§ÉúÑ¡ÔñÓñ½À´ÌáÈ¡µâµÄÀíÓÉÊÇ________£®

(5)

ÇëÉè¼ÆÒ»ÖÖ¼ìÑéÌáÈ¡µâºóµÄË®ÈÜÒºÖÐÊÇ·ñ»¹º¬Óе¥ÖʵâµÄ¼òµ¥·½·¨£º________£®

´ð°¸£º1£®BDE;
½âÎö£º

(2)

¹ýÂË,ÕôÁó

(3)

2I£­£«MnO2£«4H+=Mn2+£«I2£«2H2O

(4)

±½ÓëË®»¥²»ÏàÈÜ£»µâÔÚ±½ÖеÄÈܽâ¶È±ÈÔÚË®Öдó

(5)

È¡ÉÙÁ¿ÌáÈ¡µâºóµÄË®ÈÜÒºÓÚÊÔ¹ÜÖУ¬¼ÓÈ뼸µÎµí·ÛÊÔÒº£»¹Û²ìÊÇ·ñ³öÏÖÀ¶É«(Èç¹û±äÀ¶£¬ËµÃ÷»¹Óе¥Öʵâ)


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

º£´øÖк¬ÓзḻµÄµâ£®ÎªÁË´Óº£´øÖÐÌáÈ¡µâ£¬Ä³Ñо¿ÐÔѧϰС×éÉè¼Æ²¢½øÐÐÁËÒÔÏÂʵÑ飺

ÇëÌîдÏÂÁпհףº
£¨1£©²½Öè¢Ù×ÆÉÕº£´øʱ£¬³ýÐèÒªÈý½Å¼ÜÍ⣬»¹ÐèÒªÓõ½µÄʵÑéÒÇÆ÷ÊÇ
BDE
BDE
 £¨´ÓÏÂÁÐÒÇÆ÷ÖÐÑ¡³öËùÐèµÄÒÇÆ÷£¬ÓñêºÅ×ÖĸÌîдÔÚ¿Õ°×´¦£©£®
A£®ÉÕ±­  B£®ÛáÛö    C£®±íÃæÃó    D£®ÄàÈý½Ç   E£®¾Æ¾«µÆ     F£®¸ÉÔïÆ÷
£¨2£©²½Öè¢ÛµÄʵÑé²Ù×÷Ãû³ÆÊÇ
¹ýÂË
¹ýÂË
£»²½Öè¢ÞµÄÄ¿µÄÊÇ´Óº¬µâ±½ÈÜÒºÖзÖÀë³öµ¥ÖʵâºÍ»ØÊÕ±½£¬¸Ã²½ÖèµÄʵÑé²Ù×÷Ãû³ÆÊÇ
ÕôÁó
ÕôÁó
£®
£¨3£©²½Öè¢Ü·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ
2I-+MnO2+4H+=Mn2++I2+2H2O
2I-+MnO2+4H+=Mn2++I2+2H2O
£®
£¨4£©²½Öè¢ÝÖУ¬Ä³Ñ§ÉúÑ¡ÔñÓñ½À´ÌáÈ¡µâµÄÀíÓÉÊÇ
±½ÓëË®»¥²»ÏàÈÜ£»µâÔÚ±½ÖеÄÈܽâ¶È±ÈÔÚË®Öдó
±½ÓëË®»¥²»ÏàÈÜ£»µâÔÚ±½ÖеÄÈܽâ¶È±ÈÔÚË®Öдó
£®
£¨5£©ÇëÉè¼ÆÒ»ÖÖ¼ìÑéÌáÈ¡µâºóµÄË®ÈÜÒºÖÐÊÇ·ñ»¹º¬Óе¥ÖʵâµÄ¼òµ¥·½·¨£º
È¡ÉÙÁ¿ÌáÈ¡µâºóµÄË®ÈÜÒºÓÚÊÔ¹ÜÖУ¬¼ÓÈ뼸µÎµí·ÛÊÔÒº£»¹Û²ìÊÇ·ñ³öÏÖÀ¶É«£¨Èç¹û±äÀ¶£¬ËµÃ÷»¹Óе¥Öʵ⣩
È¡ÉÙÁ¿ÌáÈ¡µâºóµÄË®ÈÜÒºÓÚÊÔ¹ÜÖУ¬¼ÓÈ뼸µÎµí·ÛÊÔÒº£»¹Û²ìÊÇ·ñ³öÏÖÀ¶É«£¨Èç¹û±äÀ¶£¬ËµÃ÷»¹Óе¥Öʵ⣩
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

º£´øÖк¬ÓзḻµÄµâ£®ÎªÁË´Óº£´øÖÐÌáÈ¡µâ£¬Ä³Ñо¿ÐÔѧϰС×éÉè¼Æ²¢½øÐÐÁËÒÔÏÂʵÑ飺

£¨1£©²½Öè¢ÙµÄʵÑé²Ù×÷Ãû³ÆÊÇ
¹ýÂË
¹ýÂË
£»
£¨2£©ÏÖÓÐÉÕ±­¡¢²£Á§°ô¡¢¼¯ÆøÆ¿¡¢¾Æ¾«µÆ¡¢µ¼¹Ü¡¢Ô²µ×ÉÕÆ¿¡¢Ê¯ÃÞÍøÒÔ¼°±ØÒªµÄ¼Ð³ÖÒÇÆ÷¡¢ÎïÆ·£®Íê³É¸ÃʵÑéÉÐȱÉٵIJ£Á§ÒÇÆ÷ÊÇ
©¶·¡¢·ÖҺ©¶·
©¶·¡¢·ÖҺ©¶·
£»
£¨3£©²½Öè¢ÛÖÐÄÜÑ¡ÓÃCCl4´ÓµâË®ÖÐÝÍÈ¡µâµÄÔ­ÒòÊÇ
AE
AE

A¡¢CCl4ÓëË®²»»¥ÈÜ                 B¡¢CCl4¿ÉÓëI2·¢ÉúÈ¡´ú·´Ó¦
C¡¢CCl4µÄÃܶȱÈË®´ó               D¡¢CCl4²»Ò×ȼÉÕ£¬¿É×÷Ãð»ð¼Á
E¡¢µâÔÚCCl4ÖеÄÈܽâ¶È±ÈÔÚË®ÖдóºÜ¶à
£¨4£©²½Öè¢ÚÖз´Ó¦µÄÀë×Ó·½³ÌʽÊÇ
Cl2+2I-¨TI2+2Cl-
Cl2+2I-¨TI2+2Cl-
£»
£¨5£©ÇëÉè¼ÆÒ»ÖÖ¼òµ¥µÄʵÑé·½·¨£¬¼ìÑéÌáÈ¡µâºóµÄË®ÈÜÒºÖÐÊÇ·ñ»¹º¬Óе¥Öʵ⣺
È¡´ý²âÒºÓÚÊÔ¹ÜÖУ¬µÎÈ뼸µÎµí·ÛÈÜÒº£®Èç¹ûÈÜÒº±äÀ¶£¬ËµÃ÷º¬Óе⣻Èç¹ûÈÜÒº²»±äÀ¶£¬Ôò²»º¬µâ
È¡´ý²âÒºÓÚÊÔ¹ÜÖУ¬µÎÈ뼸µÎµí·ÛÈÜÒº£®Èç¹ûÈÜÒº±äÀ¶£¬ËµÃ÷º¬Óе⣻Èç¹ûÈÜÒº²»±äÀ¶£¬Ôò²»º¬µâ
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

º£´øÖк¬ÓзḻµÄµâ£¬ÎªÁË´Óº£´øÖÐÌáÈ¡µâ£¬Ä³Ñо¿ÐÔѧϰС×éÉè¼Æ²¢½øÐÐÁËÒÔÏÂʵÑ飺
£¨1£©²½Öè¢ÜÖÐÐèÓõ½1mol/LµÄÏ¡ÁòËá100mL£¬ÈôÓÃ98%£¬ÃܶÈΪ1.84g/cm3µÄŨÁòËáÀ´ÅäÖÆ£¬ÔòÓ¦ÓÃÁ¿Í²Á¿È¡Å¨ÁòËáµÄÌå»ýÊÇ
5.4mL
5.4mL
£®
£¨2£©²½Öè¢ÛµÄʵÑé²Ù×÷Ãû³ÆÊÇ
¹ýÂË
¹ýÂË
£»²½Öè¢ÞµÄÄ¿µÄÊÇ´Óº¬µâ±½ÈÜÒºÖзÖÀë³öµ¥ÖʵâºÍ»ØÊÕ±½£¬¸Ã²½ÖèµÄʵÑé²Ù×÷Ãû³ÆÊÇ
ÕôÁó
ÕôÁó
£®
£¨3£©²½Öè¢ÝÖÐÑ¡ÔñÓñ½¶ø²»Óþƾ«À´ÌáÈ¡µâµÄÀíÓÉÊÇ
¾Æ¾«ÈÜÓÚË®¶ø±½²»ÈÜÓÚË®
¾Æ¾«ÈÜÓÚË®¶ø±½²»ÈÜÓÚË®
£®
£¨4£©²éÔÄ×ÊÁÏ£º¸ÃС×éͬѧ֪µÀº£´øÖеĵâÔªËØÖ÷ÒªÒÔÓлúµâ»¯ÎïµÄÐÎʽ´æÔÚ£¬Èô¸ÃС×éʵÑéʱ³ÆµÃº£´øµÄÖÊÁ¿Îªag£¬ÌáÈ¡µâµÄ¹ý³ÌÖеâËðʧÁËm%£¬×îºóµÃµ½µ¥ÖʵâµÄÖÊÁ¿Îªbg£¬¸ÃС×éͬѧ²âµÃµÄº£´øÖеâµÄº¬Á¿Îª£¨Óú¬a¡¢b¡¢mµÄʽ×Ó±íʾ£©
b
a(1-m)
%
»ò
100b
a(1-m%)
%
b
a(1-m)
%
»ò
100b
a(1-m%)
%
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

º£´øÖк¬ÓзḻµÄµâ£®ÎªÁË´Óº£´øÖÐÌáÈ¡µâ£¬Ä³Ñо¿ÐÔѧϰС×éÉè¼Æ²¢½øÐÐÁËÒÔÏÂʵÑ飺
¾«Ó¢¼Ò½ÌÍø
£¨1£©²½Öè¢Ù×ÆÉÕº£´øʱ£¬Ê¢×°º£´øµÄʵÑéÒÇÆ÷ÊÇ
 
£®
A£®ÉÕ±­  B£®ÛáÛö    C£®ÊԹܠ  D£®ÉÕÆ¿   E£®Õô·¢Ãó
£¨2£©²½Öè¢ÛµÄʵÑé²Ù×÷Ãû³ÆÊÇ
 
£» ²½Öè¢ÞµÄÄ¿µÄÊÇ´Óº¬µâ±½ÈÜÒºÖзÖÀë³öµ¥ÖʵâºÍ»ØÊÕ±½£¬¸Ã²½ÖèµÄʵÑé²Ù×÷Ãû³ÆÊÇ
 
£®
£¨3£©²½Öè¢ÜµÄÄ¿µÄÊÇ£º
 
£®
£¨4£©²½Öè¢ÝÖУ¬Ñ¡ÔñÓñ½À´ÌáÈ¡µâµÄÀíÓÉÓÐÁ½Ìõ£®¾Æ¾«Ö»·ûºÏÆäÖеÄÒ»Ìõ£¬²»ÄÜÑ¡ÔñÓþƾ«À´ÌáÈ¡µâµÄÀíÓÉÊÇ£º
 
£®
£¨5£©ÇëÉè¼ÆÒ»¸ö¼òµ¥ÊµÑ飬¼ìÑéÌáÈ¡µâºóµÄË®ÈÜÒºÖÐÊÇ·ñ»¹º¬Óе¥Öʵâ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸