Ìú¡¢ÂÁ¡¢Í­µÈ½ðÊô¼°Æ仯ºÏÎïÔÚÈÕ³£Éú»îÓ¦Óù㷺£¬Çë¸ù¾ÝÏÂÁÐʵÑé»Ø´ðÎÊÌ⣺

£¨1£©ÉúÌúÖк¬ÓÐÒ»ÖÖÌú̼»¯ºÏÎïX£¨ Fe3C£©¡£ XÔÚ×ãÁ¿µÄ¿ÕÆøÖиßÎÂìÑÉÕ£¬Éú³ÉÓдÅÐԵĹÌÌåY£¬½«YÈÜÓÚ¹ýÁ¿ÑÎËáµÄÈÜÒºÖк¬ÓеĴóÁ¿ÑôÀë×ÓÊÇ        £»XÓë¹ýÁ¿Å¨ÏõËá·´Ó¦ºóÈÜÒºÖк¬ÓеÄÑεĻ¯Ñ§Ê½       £¬¼ìÑé¸ÃÑÎÈÜÒºÖк¬ÓеÄÑôÀë×ÓµÄÊÔ¼ÁΪ________________

£¨2£©Ä³ÈÜÒºÖÐÓÐMg2+¡¢Fe2+¡¢Al3+¡¢Cu2+µÈËÄÖÖÀë×Ó£¬ÏòÆäÖмÓÈë¹ýÁ¿µÄNaOHÈÜÒººó,¹ýÂË£¬½«ÂËÔü¸ßÎÂ×ÆÉÕ²¢½«×ÆÉÕºóµÄ¹ÌÌåͶÈë¹ýÁ¿µÄÏ¡ÑÎËᣬËùµÃÈÜÒºÓëÔ­ÈÜÒºÏà±È£¬ÈÜÒºÖдóÁ¿¼õÉÙµÄÑôÀë×ÓÊÇ________

A£®Mg2+       B£®Fe2+            C£®Al3+             D£®Cu2+

£¨3£©Ñõ»¯ÌúÊÇÖØÒªµÄ¹¤ÒµÑÕÁÏ£¬Ó÷ÏÌúмÖƱ¸ËüµÄÁ÷³ÌÈçÏ£º

»Ø´ðÏÂÁÐÎÊÌ⣺

¢Ù²Ù×÷¢ñµÄÃû³ÆÊÇ                 £¬²Ù×÷¢òµÄÃû³ÆÊÇ                 £»

²Ù×÷²Ù×÷¢òµÄ·½·¨Îª_____________________________________________________________

_______________________________________________________________________________

¢ÚNa2CO3ÈÜÒº¿ÉÒÔ³ýÓÍÎÛ£¬Ô­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©                             £»

¢ÛÇëÍê³ÉÉú³ÉFeCO3³ÁµíµÄÀë×Ó·½³Ìʽ£ºFe2+ + HCO3£­     FeCO3¡ý+          + H2O

£¨4£©ÓÐЩͬѧÈÏΪÓÃKMnO4ÈÜÒºµÎ¶¨Ò²ÄܽøÐÐÌúÔªËغ¬Á¿µÄ²â¶¨£¨5Fe2++MnO4-+8H+===

5Fe3++Mn2++4H2O£©

¢ÙʵÑéÇ°£¬Ê×ÏÈÒª¾«È·ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄKMnO4ÈÜÒº250mL£¬ÅäÖÆʱÐèÒªµÄÒÇÆ÷³ý

Ììƽ¡¢²£Á§°ô¡¢ÉÕ±­¡¢½ºÍ·µÎ¹ÜÍ⣬»¹Ðè         ¡£

¢Ú¸ÃʵÑéÖеÄKMnO4ÈÜÒºÐèÒªËữ£¬ÓÃÓÚËữµÄËáÊÇ            ¡£

       a£®Ï¡ÏõËá      b£®Ï¡ÑÎËá     c£®Ï¡ÁòËá      d£®Å¨ÏõËá

¢ÛijͬѧÉè¼ÆµÄÏÂÁеζ¨·½Ê½£¬×îºÏÀíµÄÊÇ       £¨¼Ð³Ö²¿·ÖÂÔÈ¥£©£¨Ìî×ÖĸÐòºÅ£©

£¨1£©Fe2+  Fe3+   H+£»Fe£¨NO3£©3    KSCNÈÜÒº

£¨2£©BC  £»

£¨3£©¢Ù ¹ýÂË£¬Ï´µÓ£»ÔÚ©¶·ÖмÓÈëÊÊÁ¿ÕôÁóË®,û¹ý³Áµí, ÈÃÕôÁóË®×ÔÈ»Á÷ÏÂ,Öظ´Êý´Î.

¢Ú CO32£­ + H2O  HCO3£­ + OH£­

¢Û  Fe2+ + 2HCO3- = FeCO3¡ý+ CO2 ¡ü + H2O£»

£¨4£©¢Ù250mLÈÝÁ¿Æ¿   ¢Úb      ¢Ûc

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

Ìú¡¢ÂÁ¡¢Í­µÈ½ðÊô¼°Æ仯ºÏÎïÔÚÈÕ³£Éú»îÖÐÓ¦Óù㷺£¬Çë¸ù¾ÝÏÂÁÐʵÑé»Ø´ðÎÊÌ⣺
£¨1£©ÉúÌúÖк¬ÓÐÒ»ÖÖÌú̼»¯ºÏÎïX£¨Fe3C£©£®XÔÚ×ãÁ¿µÄ¿ÕÆøÖиßÎÂìÑÉÕ£¬Éú³ÉÓдÅÐԵĹÌÌåY£¬½«YÈÜÓÚ¹ýÁ¿ÑÎËáµÄÈÜÒºÖк¬ÓеĴóÁ¿ÑôÀë×ÓÊÇ
Fe2+¡¢Fe3+¡¢H+
Fe2+¡¢Fe3+¡¢H+
£®
£¨2£©Ä³ÈÜÒºÖÐÓÐMg2+¡¢Fe2+¡¢Al3+¡¢Cu2+µÈËÄÖÖÀë×Ó£¬ÏòÆäÖмÓÈë¹ýÁ¿µÄNaOHÈÜÒººó£¬¹ýÂË£¬½«ÂËÔü¸ßÎÂ×ÆÉÕ²¢½«×ÆÉÕºóµÄ¹ÌÌåͶÈëµ½¹ýÁ¿µÄÏ¡ÑÎËáÖУ¬ËùµÃÈÜÒºÓëÔ­ÈÜÒºÏà±È£¬ÈÜÒºÖдóÁ¿¼õÉÙµÄÑôÀë×ÓÊÇ
B¡¢C
B¡¢C
£»
A£®Mg2+¡¡ B£®Fe2+C£®Al3+ D£®Cu2+
£¨3£©Ñõ»¯ÌúÊÇÖØÒª¹¤ÒµÑÕÁÏ£¬Ó÷ÏÌúмÖƱ¸ËüµÄÁ÷³ÌÈçͼ1£º

»Ø´ðÏÂÁÐÎÊÌ⣺
¢Ù²Ù×÷¢ñµÄÃû³ÆÊÇ
¹ýÂË
¹ýÂË
£¬²Ù×÷¢òµÄÃû³ÆÊÇ
Ï´µÓ
Ï´µÓ
£®
¢Úд³öÔÚ¿ÕÆøÖÐìÑÉÕFeCO3µÄ»¯Ñ§·½³Ìʽ
4FeCO3+O2
 ¸ßΠ
.
 
2Fe2O3+4CO2
4FeCO3+O2
 ¸ßΠ
.
 
2Fe2O3+4CO2
£»
£¨4£©ÓÐЩͬѧÈÏΪKMnO4ÈÜÒºµÎ¶¨Ò²ÄܽøÐÐÌúÔªËغ¬Á¿µÄ²â¶¨£¨5Fe2++MnO4-+8H+¨T5Fe3++Mn2++4H2O£©£®
a£®³ÆÈ¡2.850gÂÌ·¯£¨FeSO4?7H2O£©²úÆ·£¬Èܽ⣬ÔÚ250mLÈÝÁ¿Æ¿Öж¨ÈÝ£»
b£®Á¿È¡25.00mL´ý²âÈÜÒºÓÚ׶ÐÎÆ¿ÖУ»
c£®ÓÃÁòËáËữµÄ0.01000mol/LKMnO4ÈÜÒºµÎ¶¨ÖÁÖյ㣬ÏûºÄKMnO4ÈÜÒºÌå»ýµÄƽ¾ùֵΪ20.00mL£®
¢ÙʵÑéÇ°£¬Ê×ÏÈÒª¾«È·ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄKMnO4ÈÜÒº250mL£¬ÅäÖÆʱÐèÒªµÄÒÇÆ÷³ýÌìƽ¡¢²£Á§°ô¡¢ÉÕ±­¡¢½ºÍ·µÎ¹ÜÍ⣬»¹Ðè
250 mLÈÝÁ¿Æ¿
250 mLÈÝÁ¿Æ¿
£®
¢ÚijͬѧÉè¼ÆµÄÏÂÁеζ¨·½Ê½£¨Èçͼ2£©£¬×îºÏÀíµÄÊÇ
b
b
£®£¨¼Ð³Ö²¿·ÖÂÔÈ¥£©£¨Ìî×ÖĸÐòºÅ£©
¢Û¼ÆËãÉÏÊöÑùÆ·ÖÐFeSO4?7H2OµÄÖÊÁ¿·ÖÊýΪ
0.975
0.975
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ìú¡¢ÂÁ¡¢Í­µÈ½ðÊô¼°Æ仯ºÏÎïÔÚÈÕ³£Éú»îÖÐÓ¦Óù㷺£¬Çë¸ù¾ÝÏÂÁÐʵÑé»Ø´ðÎÊÌ⣺
£¨1£©ÉúÌúÖк¬ÓÐÒ»ÖÖÌú̼»¯Ì¨ÎïX£¨FeC£©£®XÔÚ×ãÁ¿µÄ¿ÕÆøÖиßÎÂìÑÉÕ£¬Éú³ÉÓдÅÐԵĹÌÌåY£¬½«YÈÜÓè¹ýÁ¿ÑÎËáºóÈÜÒºÖдóÁ¿´æÔÚµÄÑôÀë×ÓÊÇ
Fe2+¡¢Fe3+¡¢H+
Fe2+¡¢Fe3+¡¢H+
£»YÓë¹ýÁ¿Å¨ÏõËá·´Ó¦ºóÈÜÒºÖк¬ÓеÄÑεĻ¯Ñ§Ê½Îª
Fe£¨NO3£©3
Fe£¨NO3£©3
£®
£¨2£©Ä³ÈÜÒºÖк¬ÓÐMg2+¡¢Fe2+¡¢Al3+¡¢Cu2+µÈÀë×Ó£¬ÏòÆäÖмÓÈë¹ýÁ¿µÄNaOHÈÜÒººó£¬¹ýÂË£¬½«ÂËÔü¸ßÎÂ×ÆÉÕ²¢½«×ÆÉÕºóµÄ¹ÌÌåͶÈëµ½¹ýÁ¿µÄÏ¡ÑÎËáÖУ¬ËùµÃÈÜÒºÓëÔ­ÈÜÒºÏà±È£¬ÈÜÒºÖдóÁ¿¼õÉÙµÄÑôÀë×ÓÊÇ
BC
BC
£»
A£®Mg2+

B£®Fe2+

C£®Al3+

D£®Cu2+
Ñõ»¯ÌúÊÇÖØÒªµÄ¹¤ÒµÑÕÁÏ£¬Ó÷ÏÌúмÖƱ¸ËüµÄÁ÷³ÌÈçÏ£º

»Ø´ðÏÂÁÐÎÊÌ⣺
¢Ù²Ù×÷IµÄÃû³ÆÊÇ
¹ýÂË
¹ýÂË
£»²Ù×÷¢òµÄÃû³ÆÊÇ
Ï´µÓ
Ï´µÓ
£»²Ù×÷¢òµÄ·½·¨Îª
ÔÚ©¶·ÖмÓÈëÊÊÁ¿ÕôÁóË®£¬½þû¹ý³Áµí£¬ÈÃÕôÁóË®×ÔÈ»Á÷Ï£¬Öظ´Êý´Î
ÔÚ©¶·ÖмÓÈëÊÊÁ¿ÕôÁóË®£¬½þû¹ý³Áµí£¬ÈÃÕôÁóË®×ÔÈ»Á÷Ï£¬Öظ´Êý´Î
£®
¢ÚNaC0ÈÜÒº¿ÉÒÔ³ýÓÍÎÛ£¬Ô­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©
CO32-+H2O?HCO3-+OH-
CO32-+H2O?HCO3-+OH-
£®
¢ÛÇëÍê³ÉÉú³ÉFeC0³ÁµíµÄÀë×Ó·½³Ìʽ£º
Fe2++2HCO3-=FeCO3¡ý+CO2¡ü+H2O
Fe2++2HCO3-=FeCO3¡ý+CO2¡ü+H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêËÄ´¨ÃàÑô¸ß¿¼Ô¤²â£¨×ÛºÏÌ⣩»¯Ñ§¾í ÌâÐÍ£ºÊµÑéÌâ

£¨16·Ö£©Ìú¡¢ÂÁ¡¢Í­µÈ½ðÊô¼°Æ仯ºÏÎïÔÚÈÕ³£Éú»îÓ¦Óù㷺£¬Çë¸ù¾ÝÏÂÁÐʵÑé»Ø´ðÎÊÌ⣺
£¨1£©ÉúÌúÖк¬ÓÐÒ»ÖÖÌú̼»¯ºÏÎïX£¨Fe3C£©¡£ XÔÚ×ãÁ¿µÄ¿ÕÆøÖиßÎÂìÑÉÕ£¬Éú³ÉÓдÅÐԵĹÌÌåY£¬½«YÈÜÓÚ¹ýÁ¿ÑÎËáµÄÈÜÒºÖк¬ÓеĴóÁ¿ÑôÀë×ÓÊÇ       £»XÓë¹ýÁ¿Å¨ÏõËá·´Ó¦ºóÈÜÒºÖк¬ÓеÄÑεĻ¯Ñ§Ê½      £¬¼ìÑé¸ÃÑÎÈÜÒºÖк¬ÓеÄÑôÀë×ÓµÄÊÔ¼ÁΪ________________
£¨2£©Ä³ÈÜÒºÖÐÓÐMg2+¡¢Fe2+¡¢Al3+¡¢Cu2+µÈËÄÖÖÀë×Ó£¬ÏòÆäÖмÓÈë¹ýÁ¿µÄNaOHÈÜÒººó,¹ýÂË£¬½«ÂËÔü¸ßÎÂ×ÆÉÕ²¢½«×ÆÉÕºóµÄ¹ÌÌåͶÈë¹ýÁ¿µÄÏ¡ÑÎËᣬËùµÃÈÜÒºÓëÔ­ÈÜÒºÏà±È£¬ÈÜÒºÖдóÁ¿¼õÉÙµÄÑôÀë×ÓÊÇ________
A£®Mg2+       B£®Fe2+           C£®Al3+            D£®Cu2+
£¨3£©Ñõ»¯ÌúÊÇÖØÒªµÄ¹¤ÒµÑÕÁÏ£¬Ó÷ÏÌúмÖƱ¸ËüµÄÁ÷³ÌÈçÏ£º

»Ø´ðÏÂÁÐÎÊÌ⣺
¢Ù²Ù×÷¢ñµÄÃû³ÆÊÇ                £¬²Ù×÷¢òµÄÃû³ÆÊÇ                £»
²Ù×÷²Ù×÷¢òµÄ·½·¨Îª_____________________________________________________________
_______________________________________________________________________________
¢ÚNa2CO3ÈÜÒº¿ÉÒÔ³ýÓÍÎÛ£¬Ô­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©                            £»
¢ÛÇëÍê³ÉÉú³ÉFeCO3³ÁµíµÄÀë×Ó·½³Ìʽ£ºFe2+ + HCO3£­     FeCO3¡ý+          + H2O
£¨4£©ÓÐЩͬѧÈÏΪÓÃKMnO4ÈÜÒºµÎ¶¨Ò²ÄܽøÐÐÌúÔªËغ¬Á¿µÄ²â¶¨£¨5Fe2++MnO4-+8H+===
5Fe3++Mn2++4H2O£©
¢ÙʵÑéÇ°£¬Ê×ÏÈÒª¾«È·ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄKMnO4ÈÜÒº250mL£¬ÅäÖÆʱÐèÒªµÄÒÇÆ÷³ý
Ììƽ¡¢²£Á§°ô¡¢ÉÕ±­¡¢½ºÍ·µÎ¹ÜÍ⣬»¹Ðè        ¡£
¢Ú¸ÃʵÑéÖеÄKMnO4ÈÜÒºÐèÒªËữ£¬ÓÃÓÚËữµÄËáÊÇ           ¡£
a£®Ï¡ÏõËá       b£®Ï¡ÑÎËá       c£®Ï¡ÁòËá       d£®Å¨ÏõËá
¢ÛijͬѧÉè¼ÆµÄÏÂÁеζ¨·½Ê½£¬×îºÏÀíµÄÊÇ      £¨¼Ð³Ö²¿·ÖÂÔÈ¥£©£¨Ìî×ÖĸÐòºÅ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêÁÉÄþÊ¡±¾ÏªÒ»Öи߶þµÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÊµÑéÌâ

(14·Ö)Ìú¡¢ÂÁ¡¢Í­µÈ½ðÊô¼°Æ仯ºÏÎïÔÚÈÕ³£Éú»îÖÐÓ¦Óù㷺£¬Çë¸ù¾ÝÏÂÁÐʵÑé»Ø´ðÎÊÌ⣺
(1)ÉúÌúÖк¬ÓÐÒ»ÖÖÌú̼»¯ºÏÎïX(Fe3C)¡£XÔÚ×ãÁ¿µÄ¿ÕÆøÖиßÎÂìÑÉÕ£¬Éú³ÉÓдÅÐԵĹÌÌåY£¬½«YÈÜÓÚ¹ýÁ¿ÑÎËáµÄÈÜÒºÖк¬ÓеĴóÁ¿ÑôÀë×ÓÊÇ________________________¡£
(2)ijÈÜÒºÖÐÓÐMg2£«¡¢Fe2£«¡¢Al3£«¡¢Cu2£«µÈËÄÖÖÀë×Ó£¬ÏòÆäÖмÓÈë¹ýÁ¿µÄNaOHÈÜÒººó£¬¹ýÂË£¬½«ÂËÔü¸ßÎÂ×ÆÉÕ²¢½«×ÆÉÕºóµÄ¹ÌÌåͶÈëµ½¹ýÁ¿µÄÏ¡ÑÎËáÖУ¬ËùµÃÈÜÒºÓëÔ­ÈÜÒºÏà±È£¬ÈÜÒºÖдóÁ¿¼õÉÙµÄÑôÀë×ÓÊÇ________£»
A£®Mg2£«¡¡¡¡B£®Fe2£«         C£®Al3£«      D£®Cu2£«
(3)Ñõ»¯ÌúÊÇÖØÒª¹¤ÒµÑÕÁÏ£¬Ó÷ÏÌúмÖƱ¸ËüµÄÁ÷³ÌÈçÏ£º

»Ø´ðÏÂÁÐÎÊÌ⣺
¢Ù²Ù×÷¢ñµÄÃû³ÆÊÇ________£¬²Ù×÷¢òµÄÃû³ÆÊÇ________¡£
¢Úд³öÔÚ¿ÕÆøÖÐìÑÉÕFeCO3µÄ»¯Ñ§·½³Ìʽ                     £»
(4)ÓÐЩͬѧÈÏΪKMnO4ÈÜÒºµÎ¶¨Ò²ÄܽøÐÐÌúÔªËغ¬Á¿µÄ²â¶¨(5Fe2£«£«MnO4£­£«8H£«===5Fe3£«£«Mn2£«£«4H2O)¡£
a.³ÆÈ¡2.850gÂÌ·¯£¨FeSO4¡¤7H2O£©²úÆ·£¬Èܽ⣬ÔÚ250mLÈÝÁ¿Æ¿Öж¨ÈÝ£»
b.Á¿È¡25.00mL´ý²âÈÜÒºÓÚ׶ÐÎÆ¿ÖУ»
c.ÓÃÁòËáËữµÄ0.01000mol/LKMnO4ÈÜÒºµÎ¶¨ÖÁÖյ㣬ÏûºÄKMnO4ÈÜÒºÌå»ýµÄƽ¾ùֵΪ20.00mL¡£
¢ÙʵÑéÇ°£¬Ê×ÏÈÒª¾«È·ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄKMnO4ÈÜÒº250 mL£¬ÅäÖÆʱÐèÒªµÄÒÇÆ÷³ýÌìƽ¡¢²£Á§°ô¡¢ÉÕ±­¡¢½ºÍ·µÎ¹ÜÍ⣬»¹Ðè_____________________________________________¡£
¢ÚijͬѧÉè¼ÆµÄÏÂÁеζ¨·½Ê½£¬×îºÏÀíµÄÊÇ________¡£(¼Ð³Ö²¿·ÖÂÔÈ¥)(Ìî×ÖĸÐòºÅ)

¢Û¼ÆËãÉÏÊöÑùÆ·ÖÐFeSO4¡¤7H2OµÄÖÊÁ¿·ÖÊýΪ             ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêºÓÄÏÊ¡ÐÅÑôÊиßÈýÉÏѧÆÚµÚÒ»´Îµ÷Ñп¼ÊÔ»¯Ñ§¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨18·Ö£©Ìú¡¢ÂÁ¡¢Í­µÈ½ðÊô¼°Æ仯ºÏÎïÔÚÈÕ³£Éú»îÖÐÓ¦Óù㷺£¬Çë¸ù¾ÝÏÂÁÐʵÑé»Ø´ðÎÊÌ⣺

£¨1£©ÉúÌúÖк¬ÓÐÒ»ÖÖÌú̼»¯ºÏÎïX£¨Fe­3C£©¡£XÔÚ×ãÁ¿µÄ¿ÕÆøÖиßÎÂìÑÉÕ£¬Éú³ÉÓдÅÐԵĹÌÌåY£¬½«YÈÜÓÚ¹ýÁ¿ÑÎËáµÄÈÜÒºÖк¬ÓеĴóÁ¿ÑôÀë×ÓÊÇ                    £»XÓë¹ýÁ¿Å¨ÏõËá·´Ó¦ºóÈÜÒºÖк¬ÓеÄÑεĻ¯Ñ§Ê½Îª                 ¡£

£¨2£©Ä³ÈÜÒºÖÐÓÐMg2+¡¢Fe2+¡¢A13+¡¢Cu2+µÈËÄÖÖÀë×Ó£¬ÏòÆäÖмÓÈë¹ýÁ¿µÄNaOHÈÜÒººó£¬¹ýÂË£¬½«ÂËÔü¸ßÎÂ×ÆÉÕ²¢½«×ÆÉÕºóµÄ¹ÌÌåͶÈëµ½¹ýÁ¿µÄÏ¡ÑÎËáÖУ¬ËùµÃÈÜÒºÓëÔ­ÈÜÒºÏà±È£¬ÈÜÒºÖдóÁ¿¼õÉÙµÄÑôÀë×ÓÊÇ                 £»

A£®Mg2+                B£®Fe2+                     C£®A13+                     D£®Cu2+

£¨3£©Ñõ»¯ÌúÊÇÖØÒª¹¤ÒµÑÕÁÏ£¬Ó÷ÏÖÈмÖƱ¸ËüµÄÁ÷³ÌÈçÏ£º

»Ø´ðÏÂÁÐÎÊÌ⣺

¢Ù²Ù×÷IµÄÃû³ÆÊÇ            £¬²Ù×÷IIµÄÃû³ÆÊÇ                    £»²Ù×÷IIIµÄ

·½·¨Îª                                  ¡£

¢ÚNa2CO3ÈÜÒº¿ÉÒÔ³ýÓÍÎÛ£¬Ô­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©                £»

¢ÛÇëÍê³ÉÉú³ÉFeCO3³ÁµíµÄÀë×Ó·½³Ìʽ                    ¡£

   £¨4£©ÓÐЩͬѧÈÏΪKMnO4ÈÜÒºµÎ¶¨Ò²ÄܽøÐÐÌúÔªËغ¬Á¿µÄ²â¶¨

£¨5Fe2++MnO-4+8H+====5Fe3++Mn2++4H2O£©

¢ÙʵÑéÇ°£¬Ê×ÏÈÒª¾«È·ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄKMnO4ÈÜÒº250mL£¬ÅäÖÆʱÐèÒªµÄÒÇÆ÷³ýÌìƽ¡¢²£Á§°ô¡¢ÉÕ±­¡¢½ºÍ·µÎ¹ÜÍ⣬»¹Ðè         ¡£

¢Ú¸ÃʵÑéÖеÄKMnO4ÈÜÒºÐèÒªËữ£¬ÓÃÓÚËữµÄËáÊÇ         ¡£

A£®Ï¡ÏõËá     B£®Ï¡ÑÎËá        C£®Ï¡ÁòËá          D£®Å¨ÏõËá

¢ÛijͬѧÉè¼ÆµÄÏÂÁеζ¨·½Ê½£¬×îºÏÀíµÄÊÇ      ¡££¨¼Ð³Ö²¿·ÖÂÔÈ¥£©£¨Ìî×ÖĸÐòºÅ£©

 

[

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸