(10¡ä)ΪÁË̽¾¿Ôµç³ØµÄµç¼«Ãû³Æ²»½öÓëµç¼«²ÄÁÏÓйػ¹Óëµç½âÖÊÈÜÒºÓйأ¬Ä³Ñ§Éú×öÁËÈçϵÄʵÑé
±àºÅ | µç¼«²ÄÁÏ | µç½âÖÊÈÜÒº | µç×ÓÁ÷Ïò |
¢Ù | Mg¨DAl | HNO3(Ũ) | Mg¡úAl |
¢Ú | Mg¨DAl | HCl(aq) | Mg¡úAl |
¢Û | Mg¨DAl | NaOH(aq) | Al¡úMg |
¢Ü | Al¨DCu | HNO3(Ũ) | Cu¡úAl |
¸ù¾ÝÒÔÉϱí¸ñÄÚÈݻشð£º
(1)( 4¡ä)ʵÑé1ÖÐMg×÷___________(ÌîÕý¼«»ò¸º¼«)£¬·¢Éú__________(Ñõ»¯·´Ó¦»ò»¹Ô·´Ó¦)
ʵÑé3ÖÐMg×÷___________£¬·¢Éú__________(ͬÉÏ)
(2) ( 6¡ä)ʵÑé2ÖÐMgµç¼«·´Ó¦Ê½Îª__________________¡£
Alµç¼«Éϵĵ缫·´Ó¦Ê½Îª_________________________£¬
×ܵĵç³Ø·´Ó¦ÊÇ_______________________________¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â
ζȣ¨¡æ£© | 10 | 20 | 30 | 50 | 70 | 80 | 100 |
pH | 8.3 | 8.4 | 8.5 | 8.9 | 9.4 | 9.6 | 10.1 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêÉϺ£ÊлÆÆÖÇø¸ßÈýÉÏѧÆÚÆÚÄ©½ÌѧÖÊÁ¿µ÷Ñл¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ
ijѧÉúÔÚ0.1mol/LNaHCO3ÈÜÒºÖеμӷÓ̪ÈÜÒº1µÎ£¬Õû¸öÈÜÒº¼¸ºõûÓÐʲô±ä»¯£¬µ«ÈÜÒº¼ÓÈȺó£¬ÏÔÃ÷ÏÔµºìÉ«£¬¼ÓÈȽϳ¤Ê±¼äºóÀäÈ´£¬ºìÉ«²»ÍÊÈ¥¡£
¸ÃѧÉúΪÁËÁ˽â¸Ã¹ý³ÌµÄÔÒò£¬½øÐÐÁËÏÂÁÐ̽¾¿¹ý³Ì£º
¡¾ÊµÑé̽¾¿¡¿
ʵÑé1: ¼ÓÈÈ0.1mol/LNaHCO3ÈÜÒº£¬²âµÃÈÜÒºpH±ä»¯Èçϱí
ζȣ¨¡æ£© |
10 |
20 |
30 |
50 |
70 |
80 |
100 |
pH |
8.3 |
8.4 |
8.5 |
8.9 |
9.4 |
9.6 |
10.1 |
ʵÑé2£º10¡æʱ£¬ÔÚÉÕ±ÖмÓÈë0.1mol/LNaHCO3ÈÜÒº200mL£¬²âµÃ¸ÃÈÜÒºpH=8.3£¬¼ÓÈȵ½100¡æ£¬²âµÃpH=10.2£¬»Ö¸´µ½10¡æ£¬pH=9.8¡£
ʵÑé3£º¼ÓÈÈ0.1mol/LNaHCO3ÈÜÒº£¬½«²úÉúµÄÆøÌåͨÈë³ÎÇåʯ»ÒË®£¬ÈÜÒº±ä»ë×Ç¡£
ʵÑé4£º
¢ÙÅäÖÆ0.1mol/LNaHCO3ÈÜÒººÍ0.1mol/LNa2CO3ÈÜÒº¸÷200mL£¬10¡æʱ£¬·Ö±ð²âµÃNaHCO3ÈÜÒºpH=8.3£¬Na2CO3ÈÜÒºpH=11.5¡£
¢Ú¼ÓÈÈÕô·¢0.1mol/L NaHCO3ÈÜÒº200mL£¬ÖÁÈÜÒºÌå»ý100mL£¬Í£Ö¹¼ÓÈÈ£¬¼ÓË®ÖÁ200mL£¬ÀäÈ´ÖÁÔζȣ¬²âµÃÈÜÒºpH=9.8¡£
¢Û½«0.1mol/L NaHCO3ÈÜÒº200mL³¨¿Ú·ÅÖÃÈýÌ죬ÔÙ¼ÓË®ÖÁ200mL£¬²âµÃÈÜÒºpH=10.1¡£
Çë¸ù¾ÝÉÏÊöʵÑé»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÓÃÀë×Ó·½³Ìʽ±íʾ0.1mol/LNaHCO3ÈÜÒºÖдæÔÚµÄƽºâ£¨³ýË®µçÀëƽºâÍ⣩___________
________________¡¢_______________________________¡£ÕâÁ½¸öƽºâÒÔ_______________
ΪÖ÷£¬ÀíÓÉÊÇ_______________________________.
£¨1£©ÊµÑé3µÃµ½µÄ½áÂÛÊÇ__________________________________________________¡£
£¨1£©½áºÏʵÑé2¡¢3·ÖÎö£¬¼ÓÈÈ0.1mol/LNaHCO3ÈÜÒº£¬pHÔö´óµÄÔÒò¿ÉÄÜÊÇ_____________
__________¡¢______________________¡¢________________________________¡£
£¨1£©ÊµÑé4¢ÙµÃµ½µÄ½áÂÛÊÇ_______________________________________________¡£
£¨1£©ÊµÑé4¢Ú¡°¼ÓË®ÖÁ200mL¡±µÄÄ¿µÄÊÇ____________________________________________¡£
ʵÑé4¢Û¿ÉÒԵõ½µÄ½áÂÛÊÇ_______________________________________¡£
£¨1£©ÒªÈ·¶¨NaHCO3ÈÜÒº¼ÓÈȺópHÔö´óµÄÖ÷ÒªÔÒò»¹ÐèÒª½â¾öµÄÎÊÌâÊÇ________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÍ¬²½Ìâ ÌâÐÍ£ºÊµÑéÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
£¨17·Ö£©Ä³Ð£»¯Ñ§ÐËȤС×éΪÁË̽¾¿Ôµç³Ø¹¤×÷ÔÀí£¬½øÐÐÈçÏÂϵÁÐʵÑ飺
ʵÑéÒ» ʵÑé¶þ
ʵÑéÈý ʵÑéËÄ
½á¹û£º
£¨1£©ÊµÑéÒ»ÖÐÍƬ¡¢Ð¿Æ¬±íÃæ¾ùÓкìÉ«ÎïÖÊÎö³ö£¬µçÁ÷¼ÆÖ¸Õëƫת£¬µ«½Ï¶Ìʱ¼äÄÚµçÁ÷¼´Ã÷ÏÔ¼õС¡£ÊµÑé½áÊøʱ²âµÃпƬ¼õÉÙÁË3.94g£¬ÍƬÔöÖØÁË3.84g£¬Ôò¸ÃÔµç³ØµÄ¹¤×÷ЧÂÊÊÇ£¨Ö¸²Î¼ÓÔµç³Ø·´Ó¦µÄпռ·´Ó¦×ÜÁ¿µÄ°Ù·ÖÂÊ£©£º ¡£
£¨2£©ÊµÑé¶þÖиս«Í¡¢Ð¿Æ¬²åÈëÈÜÒºÖÐʱµçÁ÷¼ÆÖ¸ÕëÓÐƫת£¬µ«Á¢¼´¾Í¹éÁãÁË¡£ÎªÊ²Ã´Ð¿µÄµç×Ó²»ÄܳÖÐøͨ¹ýµ¼ÏßÁ÷Ïòͼ«¸øCu2+£¿ ¡£
£¨3£©ÊµÑéÈýÖÐÑÎÇÅÖÐK+Á÷Ïò ÈÜÒº£¨ÌîZnSO4»òCuSO4£©£¬Èç¹ûZnµÄÏûºÄËÙÂÊΪ1¡Á10-3mol/s£¬ÔòK+µÄǨÒÆËÙÂÊΪ mol/s¡£
£¨4£©ÊµÑéËÄÖеçÁ÷¼ÆÖ¸ÕëÓÐƫת£¬Ð´³öͼ«µÄµç¼«·´Ó¦Ê½£º
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com