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A£®CH3COOH(aq)+NaOH(aq)=== CH3COONa(aq)+H2O(l) H=57.3kJ/mol
B£®KOH(aq)+H2SO4(aq)= K2SO4(aq)+H2O(l) H=57.3kJ/mol
C£®2C8H18(g)+25O2 (g)=16CO2 (g)+18H2O(1) H=11036 kJ/mol
D£®C8H18(l)+ O2 (g)=8CO2 (g)+ 9H2O(g) H=5518 kJ/mol
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A£®2H+(aq) +(aq)+(aq)+2(aq) = BaSO4(s)+2HO(l);H =57.3 kJ/mol
B£®KOH(aq)+HSO4(aq) = KSO4(aq)+HO(l);H=57.3kJ/mol
C£®C8H18(l)+ O(g)=8CO(g)+ 9HO(g);H=5518 kJ/mol
D£®2C8H18(g)+25O(g)=16CO(g)+18HO(1);H=5518 kJ/mol
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25 ¡æ£¬101 k Paʱ£¬Ç¿ËáÓëÇ¿¼îµÄÏ¡ÈÜÒº·¢ÉúÖкͷ´Ó¦µÄÖкÍÈÈΪ57.3 kJ/mol£¬ÐÁÍéµÄȼÉÕÈÈΪ5518 kJ/mol¡£ÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÊéдÕýÈ·µÄÊÇ ( )
A£®2H+(aq)+SO42£(aq)+Ba2£«(aq)+2OH-(aq)=BaSO4(s)+2H2O(1) ¡÷H=57.3 kJ/mol
B£®KOH(aq)+H2 SO4(aq)=K2SO4(aq)+H2O(l) ¡÷H=57.3kJ/mol
C£®C8H18(I)+O2(g)=8CO2(g)+9H2O ¡÷H=5518 kJ/mol
D£®2C8H18(g)+25O2(g)=16CO2(g)+18H2O(1) ¡÷H=5518 kJ/mol
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25¡æ£¬101 k Paʱ£¬Ç¿ËáÓëÇ¿¼îµÄÏ¡ÈÜÒº·¢ÉúÖкͷ´Ó¦µÄÖкÍÈÈΪ57.3 kJ/mol£¬ÐÁÍéµÄȼÉÕÈÈΪ5518 kJ/mol¡£ÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÊéдÕýÈ·µÄÊÇ£¨ £©
A£®2H+(aq) +SO42£(aq)+Ba2+(aq)+2OH£(aq)=BaSO4(s)+2H2O(1)£»¦¤H=£57.3 kJ/mol
B£®KOH(aq)+ H2 SO4(aq)=K2SO4(aq)+H2O(l)£»¦¤H=£57.3kJ/mol
C£®2C8H18(g)+25O2(g)=16CO2(g)+18H2O(1)£»¦¤H=£5518 kJ/mol
D£®C8H18(l)+ 25/2 O2(g)=8CO2(g)+ 9H2O(1)£»¦¤H=£5518 kJ/mol
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25 ¡æ£¬101 k Paʱ£¬Ç¿ËáÓëÇ¿¼îµÄÏ¡ÈÜÒº·¢ÉúÖкͷ´Ó¦µÄÖкÍÈÈΪ57.3 kJ/mol£¬ÐÁÍéµÄȼÉÕÈÈΪ5518 kJ/mol¡£ÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÊéдÕýÈ·µÄÊÇ
A.2H+(aq) +(aq)+(aq)+2OH(aq)=BaSO4(s)+2HO(1);H=57.3 kJ/mol
B.KOH(aq)+H SO4(aq)= KSO4(aq)+HO(I); H=57.3kJ/mol
C.C8H18(I)+ O (g)=8CO (g)+ 9HO; H=5518 kJ/mol
D.2C8H18(g)+25O (g)=16CO (g)+18HO(1); H=5518 kJ/mol
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