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A£®CH3COOH(aq)+NaOH(aq)=== CH3COONa(aq)+H2O(l) H=57.3kJ/mol

B£®KOH(aq)+H2SO4(aq)= K2SO4(aq)+H2O(l)      H=57.3kJ/mol

C£®2C8H18(g)+25O2 (g)=16CO2 (g)+18H2O(1)    H=11036 kJ/mol

D£®C8H18(l)+  O2 (g)=8CO2 (g)+ 9H2O(g)     H=5518 kJ/mol

 

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A£®2H+(aq) +(aq)+(aq)+2(aq) = BaSO4(s)+2HO(l);H =57.3 kJ/mol

B£®KOH(aq)+HSO4(aq) = KSO4(aq)+HO(l);H=57.3kJ/mol

C£®C8H18(l)+ O(g)=8CO(g)+ 9HO(g);H=5518 kJ/mol

D£®2C8H18(g)+25O(g)=16CO(g)+18HO(1);H=5518 kJ/mol

 

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A£®2H+(aq)+SO42£­(aq)+Ba2£«(aq)+2OH-(aq)=BaSO4(s)+2H2O(1)  ¡÷H=57.3 kJ/mol

B£®KOH(aq)+H2 SO4(aq)=K2SO4(aq)+H2O(l)  ¡÷H=57.3kJ/mol

C£®C8H18(I)+O2(g)=8CO2(g)+9H2 ¡÷H=5518 kJ/mol

D£®2C8H18(g)+25O2(g)=16CO2(g)+18H2O(1)  ¡÷H=5518 kJ/mol

 

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A£®2H+(aq) +SO42£­(aq)+Ba2+(aq)+2OH£­(aq)=BaSO4(s)+2H2O(1)£»¦¤H=£­57.3 kJ/mol

B£®KOH(aq)+ H2 SO4(aq)=K2SO4(aq)+H2O(l)£»¦¤H=£­57.3kJ/mol

C£®2C8H18(g)+25O2(g)=16CO2(g)+18H2O(1)£»¦¤H=£­5518 kJ/mol

D£®C8H18(l)+ 25/2 O2(g)=8CO2(g)+ 9H2O(1)£»¦¤H=£­5518 kJ/mol

 

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A.2H+(aq) +(aq)+(aq)+2OH(aq)=BaSO4(s)+2HO(1);H=57.3 kJ/mol

B.KOH(aq)+H SO4(aq)= KSO4(aq)+HO(I); H=57.3kJ/mol

C.C8H18(I)+  O (g)=8CO (g)+ 9HO; H=5518 kJ/mol

D.2C8H18(g)+25O (g)=16CO (g)+18HO(1); H=5518 kJ/mol

 

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