¡¾ÌâÄ¿¡¿Ì¿ºÚÊÇÎíö²ÖеÄÖØÒª¿ÅÁ£ÎïÖ®Ò»£¬Ñо¿·¢ÏÖËü¿ÉÒԻÑõ·Ö×ÓÉú³É»î»¯Ñõ£¬»î»¯Ñõ¿ÉÒÔ¿ìËÙÑõ»¯¶þÑõ»¯Áò¡£»î»¯¹ý³ÌµÄÄÜÁ¿±ä»¯Ä£Äâ¼ÆËã½á¹ûÈçͼËùʾ£¬ÏÂÁÐ˵·¨´íÎóµÄÊÇ

A.Ì¿ºÚ¿ÅÁ£ÊÇ´óÆøÖжþÑõ»¯Áòת»¯ÎªÈýÑõ»¯ÁòµÄ´ß»¯¼Á

B.Ñõ·Ö×ӵĻ°üÀ¨O-O¼üµÄ¶ÏÁÑÓëC-O¼üµÄÉú³É

C.Ë®¿ÉʹÑõ·Ö×ӻ·´Ó¦µÄ»î»¯ÄܽµµÍ0.42 eV

D.ÿ»î»¯Ò»¸öÑõ·Ö×ӷųö0.29 eVµÄÄÜÁ¿

¡¾´ð°¸¡¿C

¡¾½âÎö¡¿

A. »î»¯Ñõ¿ÉÒÔ¿ìËÙÑõ»¯¶þÑõ»¯Áò£¬¶øÌ¿ºÚ¿ÅÁ£¿ÉÒԻÑõ·Ö×Ó£¬Òò´ËÌ¿ºÚ¿ÅÁ£¿ÉÒÔ¿´×÷´óÆøÖжþÑõ»¯Áòת»¯ÎªÈýÑõ»¯ÁòµÄ´ß»¯¼Á£¬AÕýÈ·£»

B£®¸ù¾ÝͼÏó·ÖÎö£¬Ñõ·Ö×ӻ¹ý³ÌO-O¼ü¶ÏÁÑ£¬Éú³ÉC-O¼ü£¬ËùÒÔÑõ·Ö×ӵĻÊÇO-OµÄ¶ÏÁÑÓëC-O¼üµÄÉú³É¹ý³Ì£¬BÕýÈ·£»

C£®»¯ÄÜ·´Ó¦¹ý³ÌÖдæÔڶಽ·´Ó¦µÄ»î»¯ÄÜ£¬Õû¸ö·´Ó¦µÄ»îΪ»î»¯ÄܽϴóÕߣ¬¸ù¾ÝÄÜÁ¿Í¼·ÖÎö£¬Õû¸ö·´Ó¦µÄ»î»¯ÄÜΪ»î»¯ÄܽϴóÕߣ¬ÔòûÓÐË®¼ÓÈëµÄ·´Ó¦»î»¯ÄÜΪE=0.75eV£¬ÓÐË®¼ÓÈëµÄ·´Ó¦µÄ»î»¯ÄÜΪE=0.57eV£¬ËùÒÔË®¿ÉʹÑõ·Ö×ӻ·´Ó¦µÄ»î»¯ÄܽµµÍ0.75 eV-0.57 eV=0.18 eV£¬C´íÎó£»

D£®ÓÉͼ¿ÉÖª£¬·´Ó¦ÎïµÄ×ÜÄÜÁ¿¸ßÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿£¬Òò´Ëÿ»î»¯Ò»¸öÑõ·Ö×ӷųö0.29 eVµÄÄÜÁ¿£¬DÕýÈ·£»

¹ÊºÏÀíÑ¡ÏîÊÇC¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÒÑÖªX¡¢Y¡¢Z¡¢W¡¢RÎåÖÖÔªËؾùλÓÚÖÜÆÚ±íµÄÇ°ËÄÖÜÆÚ£¬ÇÒÔ­×ÓÐòÊýÒÀ´ÎÔö´ó¡£ÔªËØXÊÇÖÜÆÚ±íÖÐÔ­×Ӱ뾶×îСµÄÔªËØ£»YµÄ»ù̬ԭ×ÓÖеç×ÓÕ¼¾ÝÁËÈýÖÖÄÜÁ¿²»Í¬µÄÔ­×Ó¹ìµÀ£¬ÇÒÕâÈýÖÖ¹ìµÀÖеĵç×ÓÊýÏàͬ£»WλÓÚµÚ2ÖÜÆÚ£¬Æä»ù̬ԭ×ӵĺËÍâ³É¶Ôµç×ÓÊýÊÇδ³É¶Ôµç×ÓÊýµÄ3±¶£»R»ù̬ԭ×Ó3d¹ìµÀÉϵĵç×ÓÊýÊÇ4s¹ìµÀÉϵÄ4±¶¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺£¨´ðÌâʱ£¬X¡¢Y¡¢Z¡¢W¡¢RÓÃËù¶ÔÓ¦µÄÔªËØ·ûºÅ±íʾ£©

¢Å»ù̬RÔ­×ÓµÄÍâΧµç×ÓÅŲ¼Ê½Îª______£»Y¡¢Z¡¢WµÄµç¸ºÐÔÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ____¡£

¢ÆÔªËØY¡¢Z¾ùÄÜÓëÔªËØXÐγɺ¬18¸öµç×ÓµÄ΢Á££¬ÕâЩ΢Á£Öзеã×î¸ßµÄÊÇ______£¬Æä·Ðµã×î¸ßµÄÔ­ÒòÊÇ______£»Y2X4ÄÑÈÜÓÚX2WµÄÔ­ÒòÊÇ_____¡£

¢ÇYWµÄ½á¹¹Ê½Îª______(Ðë±ê³öÆäÖеÄÅäλ¼ü)£»ÔÚ»¯Ñ§Ê½Îª£ÛR(ZX3)4(X2W)2£Ý2+µÄÅäÀë×ÓÖÐÓëRÐγÉÅäλ¼üµÄÔ­×ÓÊÇ______¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÎªÁ˲ⶨÒÒ´¼µÄ½á¹¹Ê½£¬ÓÐÈËÉè¼ÆÁËÓÃÎÞË®¾Æ¾«ÓëÄÆ·´Ó¦µÄʵÑé×°ÖúͲⶨÇâÆøÌå»ýµÄ×°ÖýøÐÐʵÑé¡£¿É¹©Ñ¡ÓõÄʵÑéÒÇÆ÷ÈçͼËùʾ¡£

Çë»Ø´ðÒÔÏÂÎÊÌ⣺

(1)²âÁ¿ÇâÆøÌå»ýµÄÕýÈ·×°ÖÃÊÇ________(Ìîд±àºÅ)¡£

(2)×°ÖÃÖÐA²¿·ÖµÄ·ÖҺ©¶·ÓëÕôÁóÉÕÆ¿Ö®¼äÁ¬½ÓµÄµ¼¹ÜËùÆðµÄ×÷ÓÃÊÇ________(Ìîд±àºÅ)¡£

A£®·ÀÖ¹ÎÞË®¾Æ¾«»Ó·¢

B£®±£Ö¤ÊµÑé×°Öò»Â©Æø

C£®Ê¹ÎÞË®¾Æ¾«ÈÝÒ×µÎÏÂ

(3)ʵÑéÇ°Ô¤ÏȽ«Ð¡¿éÄÆÔÚ¶þ¼×±½ÖÐÈÛ»¯³ÉСÄÆÖ飬ÀäÈ´ºóµ¹ÈëÉÕÆ¿ÖУ¬ÆäÄ¿µÄÊÇ

________________________________________________________________________¡£

(4)ÒÑÖªÎÞË®¾Æ¾«µÄÃܶÈΪ0.789 g¡¤cm£­3£¬ÒÆÈ¡2.0 mL¾Æ¾«£¬·´Ó¦ÍêÈ«ºó(ÄƹýÁ¿)£¬ÊÕ¼¯390 mLÆøÌå¡£ÔòÒÒ´¼·Ö×ÓÖÐÄܱ»ÄÆÈ¡´ú³öµÄÇâÔ­×ÓÊýΪ________£¬ÓÉ´Ë¿ÉÈ·¶¨ÒÒ´¼µÄ½á¹¹Ê½Îª________________¶ø²»ÊÇ____________________________________________________¡£

(5)ʵÑéËù²â¶¨µÄ½á¹ûÆ«¸ß£¬¿ÉÄÜÒýÆðµÄÔ­ÒòÊÇ________(Ìîд±àºÅ)¡£

A£®±¾ÊµÑéÔÚÊÒÎÂϽøÐÐ

B£®ÎÞË®¾Æ¾«ÖлìÓÐ΢Á¿¼×´¼

C£®ÎÞË®¾Æ¾«ÓëÄƵķ´Ó¦²»¹»ÍêÈ«

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÒÑÖªCrO42-ºÍCr2O72-ÔÚÈÜÒºÖпÉÏ໥ת»¯¡£ÊÒÎÂÏ£¬³õʼŨ¶ÈΪ1.0 mol¡¤L£­1µÄNa2CrO4ÈÜÒºÖÐc(Cr2O72-)Ëæc(H£«)µÄ±ä»¯ÈçͼËùʾ¡£

(1)ÓÃÀë×Ó·½³Ìʽ±íʾNa2CrO4ÈÜÒºÖеÄת»¯·´Ó¦______¡£

(2)ÓÉͼ¿ÉÖª£¬ÈÜÒºËáÐÔÔö´ó£¬CrO42-µÄƽºâת»¯ÂÊ____(Ìî¡°Ôö´ó¡±¡°¼õС¡±»ò¡°²»±ä¡±)¡£¸ù¾ÝAµãÊý¾Ý£¬¼ÆËã³ö¸Ãת»¯·´Ó¦µÄƽºâ³£ÊýΪ________¡£

(3)Éý¸ßζȣ¬ÈÜÒºÖÐCrO42-µÄƽºâת»¯ÂʼõС£¬Ôò¸Ã·´Ó¦µÄ¦¤H________0(Ìî¡°´óÓÚ¡±¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿°±ÆøÊÇÒ»ÖÖÖØÒªµÄÎïÖÊ£¬¿ÉÓÃÓÚÖÆÈ¡»¯·ÊºÍÏõËáµÈ¡£ÒÑÖªH-H¼ü¡¢N-H¼ü¡¢N¡ÔN¼üµÄ¼üÄÜ·Ö±ðÊÇ436kJ/mol¡¢391kJ/mol¡¢946kJ/mol¡£

(1)д³öºÏ³É°±µÄÈÈ·´Ó¦·½³Ìʽ__________¡£Éú³É1 mol NH3ÐèÒªÎüÊÕ»ò·Å³ö_______ kJµÄÈÈÁ¿¡£

(2)µ±ºÏ³É°±·´Ó¦´ïµ½Æ½ºâºó£¬¸Ä±äijһÍâ½çÌõ¼þ²»¸Ä±äN2¡¢H2ºÍNH3µÄÁ¿£¬·´Ó¦ËÙÂÊÓëʱ¼äµÄ¹ØϵÈçͼËùʾͼÖÐt1ʱÒýÆðƽºâÒƶ¯µÄÌõ¼þ¿ÉÄÜÊÇ_______¡£ÆäÖбíʾƽºâ»ìºÏÎïÖÐNH3µÄº¬Á¿×î¸ßµÄÒ»¶Îʱ¼äÊÇ________¡£

(3)ζÈΪT0Cʱ£¬½«2a molH2ºÍa molN2·ÅÈë0.5LÃܱÕÈÝÆ÷ÖУ¬³ä·Ö·´Ó¦ºó²âµÃN2µÄת»¯ÂÊΪ50%£¬Ôò¸Ã·´Ó¦µÄƽºâ³£ÊýΪ_________¡£

(4)ÒÑÖª373Kʱ£¬¿ÉÄ淴Ӧƽºâ³£ÊýΪK=0.12£¬Èôijʱ¿Ìʱ£¬²âµÃc(N2)=1 mol/L£¬c(H2)=3 mol/L£¬c(NH3)=2 mol/L£¬´Ëʱ¿ÉÄæ·´Ó¦_________¡£

A.ÏòÕý·½Ïò½øÐÐ B.ÏòÄæ·½Ïò½øÐÐ C´¦ÓÚƽºâ״̬

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿¾ÝÔ¤²â£¬µ½2040ÄêÎÒ¹úú̿Ïû·ÑÈÔ½«Õ¼ÄÜÔ´½á¹¹µÄÈý·ÖÖ®Ò»×óÓÒ¡£H2SÔÚ´ß»¯»îÐÔ̼£¨AC£©±íÃæµÄǨÒÆ£¬¶ÔúµÄÇå½àºÍ×ÛºÏÓ¦ÓÃÆðÁ˺ܴóµÄ´Ù½ø×÷Óã¬Æä»úÀíÈçͼËùʾ£¬ÆäÖÐad±íʾÎïÖÖµÄÎü¸½×´Ì¬¡£ÏÂÁÐÓйØÐðÊö´íÎóµÄÊÇ

A.ͼÖÐÒõÓ°²¿·Ö±íʾH2S·Ö×ÓµÄÎü¸½ÓëÀë½â

B.AC±íÃæ×÷ÓõÄζȲ»Í¬£¬H2SµÄÈ¥³ýÂʲ»Í¬

C.H2SÔÚAC±íÃæ×÷ÓÃÉú³ÉµÄ²úÎïÓÐH2O¡¢H2¡¢S¡¢SO2¡¢CS2µÈ

D.ͼÖз´Ó¦¹ý³ÌÖÐÖ»ÓÐH¡ªS¼üµÄ¶ÏÁÑ£¬Ã»ÓÐH¡ªS¼üµÄÐγÉ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Éú²úÒ½Ó÷À»¤¿ÚÕÖµÄÔ­ÁϾ۱ûÏ©ÏËάÊôÓÚÓлú¸ß·Ö×Ó²ÄÁÏ£¬Æäµ¥ÌåΪ±ûÏ©¡£±ûÏ©³ýÁ˺ϳɾ۱ûÏ©Í⣬»¹¹ã·ºÓÃÓÚÖƱ¸1£¬2¡ª¶þÂȱûÍé¡¢±ûÏ©È©¡¢±ûÏ©ËáµÈ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

¢ñ.¹¤ÒµÉÏÓñûÏ©¼Ó³É·¨ÖƱ¸1£¬2¡ª¶þÂȱûÍ飬Ö÷Òª¸±²úÎïΪ3¡ªÂȱûÏ©£¬·´Ó¦Ô­ÀíΪ£º

¢Ù

¢Ú

£¨1£©ÒÑÖªµÄ»î»¯ÄÜ£¨Ä棩Ϊ£¬Ôò¸Ã·´Ó¦µÄ£¨Õý£©»î»¯ÄÜΪ_____¡£

£¨2£©Ò»¶¨Î¶ÈÏ£¬ÏòºãÈÝÃܱÕÈÝÆ÷ÖгäÈëµÈÎïÖʵÄÁ¿µÄºÍ£¬ÔÚ´ß»¯¼Á×÷ÓÃÏ·¢Éú·´Ó¦¢Ù¢Ú£¬ÈÝÆ÷ÄÚÆøÌåµÄѹǿËæʱ¼äµÄ±ä»¯ÈçϱíËùʾ¡£

ʱ¼ä/min

0

60

120

180

240

300

360

ѹǿ/kPa

80

74.2

69.4

65.2

61.6

57.6

57.6

Óõ¥Î»Ê±¼äÄÚÆøÌå·ÖѹµÄ±ä»¯À´±íʾ·´Ó¦ËÙÂÊ£¬¼´£¬Ôò·´Ó¦¢ÙÇ°180minÄÚƽ¾ù·´Ó¦ËÙÂÊ____£¨±£ÁôСÊýµãºó2룩¡£

¢ò.±ûÏ©µÄÖƱ¸·½·¨

·½·¨Ò»£º±ûÍéÎÞÑõÍÑÇâ·¨ÖƱ¸±ûÏ©·´Ó¦ÈçÏ£º

£¨3£©¢ÙijζÈÏ£¬ÔÚ¸ÕÐÔÈÝÆ÷ÖгäÈ룬ÆðʼѹǿΪ10kPa£¬Æ½ºâʱ×ÜѹΪ14kPa£¬µÄƽºâת»¯ÂÊΪ______¡£¸Ã·´Ó¦µÄƽºâ³£Êý______kPa£¨±£ÁôСÊýµãºó2룩¡£

¢Ú×Üѹ·Ö±ðΪ100kPa¡¢10kPaʱ·¢Éú¸Ã·´Ó¦£¬Æ½ºâÌåϵÖк͵ÄÎïÖʵÄÁ¿·ÖÊýËæζȱ仯¹ØϵÈçͼËùʾ£º

10kPaʱ£¬ºÍµÄÎïÖʵÄÁ¿·ÖÊýËæζȱ仯¹ØϵµÄÇúÏß·Ö±ðÊÇ_____¡¢______¡£

·½·¨¶þ£º±ûÍéÑõ»¯ÍÑÇâ·¨ÖƱ¸±ûÏ©»¹Éú³É¡¢µÈ¸±²úÎÖƱ¸±ûÏ©µÄ·´Ó¦ÈçÏ£º

¡£ÔÚ´ß»¯¼Á×÷ÓÃϵÄת»¯Âʺ͵IJúÂÊËæζȱ仯¹ØϵÈçͼËùʾ¡£

£¨4£©¢ÙͼÖеÄת»¯ÂÊËæζÈÉý¸ß¶øÉÏÉýµÄÔ­ÒòÊÇ_________¡£

¢Ú575¡æʱ£¬µÄÑ¡ÔñÐÔΪ___¡££¨µÄÑ¡ÔñÐÔ=£©

¢Û»ùÓÚÉÏÊöÑо¿½á¹û£¬ÄÜÌá¸ßÑ¡ÔñÐԵĴëÊ©ÊÇ______¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿½«Ò»¶¨Á¿µÄX¼ÓÈëijÃܱÕÈÝÆ÷ÖУ¬·¢Éú·´Ó¦£º2X(g) 3Y(g)+Z(g)£¬»ìºÏÆøÌåÖÐXµÄÎïÖʵÄÁ¿·ÖÊýÓëζȹØϵÈçͼËùʾ£ºÏÂÁÐÍƶÏÕýÈ·µÄÊÇ()¡£

A. Éý¸ßζȣ¬¸Ã·´Ó¦Æ½ºâ³£ÊýK¼õС

B. ѹǿ´óСÓÐP3£¾P2£¾P1

C. ƽºâºó¼ÓÈë¸ßЧ´ß»¯¼Áʹƽ¾ùĦ¶ûÖÊÁ¿Ôö´ó

D. ÔÚ¸ÃÌõ¼þÏÂMµãXƽºâת»¯ÂÊΪ9/11

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ä廯¸ÆÊÇÒ»ÖÖÖØÒªµÄä廯Î¿ÉÓÃÓÚÖÆÔì¹âÃôÖ½¡¢Ãð»ð¼Á¡¢ÖÆÀä¼ÁµÈ£¬ÒÔʯ»ÒÈé¡¢Òºäå¼°°±µÈΪԭÁÏÖƱ¸CaBr22H2OµÄʵÑéÁ÷³ÌÈçÏ£º

(1)²½Öè¢ÙÐè¿ØÖÆÔÚ70¡æÒÔÏ£¬Î¶Ȳ»Ò˹ý¸ßµÄÔ­ÒòÊÇ________________¡£

(2)ÏÂÁÐʵÑéÊÒÖÆÈ¡ÉÙÁ¿NH3µÄ·½·¨ÕýÈ·µÄÊÇ_____________£¨Ìî±êºÅ£©¡£

A£® B£® C£® D£®

(3)ÒÑÖªNH3±»Ñõ»¯ÎªN2¡£²½Öè¢ÚÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________________¡£

(4)²½Öè¢Ü¡¢¢ÝµÄÄ¿µÄÒÀ´ÎÊÇ_______________________________¡¢________________________¡£

(5)²½Öè¢Þ³£ÓÃ_________________½øÐÐÍÑÉ«£¬ËüÀûÓÃÁ˸ÃÎïÖʵÄ____________________¡£

(6)²½Öè¢ßµÃµ½²úÆ·µÄ²Ù×÷·½·¨ÊÇ__________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸