£¨2012?¹ãÖÝһģ£©Ì¼Ëá¼×ÒÒõ¥£¨CH3OCOOC2H5£©ÊÇÒ»ÖÖÀíÏëµÄ﮵ç³ØÓлúµç½âÒº£¬Éú³É̼Ëá¼×ÒÒõ¥µÄÔ­ÀíΪ£ºC2H5OCOOC2H5£¨g£©+CH3OCOOCH3£¨g£©?2CH3OCOOC2H5£¨g£©¡÷H1
£¨1£©ÆäËûÌõ¼þÏàͬ£¬CH3OCOOCH3µÄƽºâת»¯ÂÊ£¨¦Á£©Óëζȣ¨T£©¡¢·´Ó¦ÎïÅä±È£¨R£©µÄ¹ØϵÈçͼËùʾ£®
¢Ù¡÷H1
£¾
£¾
0£¨Ìî¡°£¼¡±¡¢¡°=¡±»ò¡°£¾¡±£©£®
¢ÚÓÉͼ¿ÉÖª£¬ÎªÁËÌá¸ßCH3OCOOCH3µÄƽºâת»¯ÂÊ£¬³ýÁËÉýΣ¬ÁíÒ»´ëÊ©ÊÇ
Ôö´ó·´Ó¦ÎïÖÐC2H5OCOOC2H5µÄŨ¶È£¨»ò±ÈÀý£©
Ôö´ó·´Ó¦ÎïÖÐC2H5OCOOC2H5µÄŨ¶È£¨»ò±ÈÀý£©
£®
¢ÛÔÚÃܱÕÈÝÆ÷ÖУ¬½«1mol C2H5OCOOC2H5ºÍ1mol CH3OCOOCH3»ìºÏ¼ÓÈȵ½650K£¬ÀûÓÃͼÖеÄÊý¾Ý£¬Çó´ËζÈϸ÷´Ó¦µÄƽºâ³£ÊýK=
9
9
£®
£¨2£©ÒÑÖªÉÏÊö·´Ó¦ÐèÒª´ß»¯¼Á£¬ÇëÔÚ´ðÌ⿨µÄ×ø±êͼÖУ¬»­³öÓд߻¯¼ÁÓëÎÞ´ß»¯¼ÁÁ½ÖÖÇé¿öÏ·´Ó¦¹ý³ÌÖÐÌåϵÄÜÁ¿±ä»¯Ê¾Òâͼ£¬²¢½øÐбØÒª±ê×¢£®
£¨3£©ÒÑÖªCH3OCOOCH3£¨g£©+C2H5OH£¨g£©?CH3OCOOC2H5£¨g£©+CH3OH£¨g£©¡÷H2
CH3OCOOC2H5£¨g£©+C2H5OH£¨g£©?C2H5OCOOC2H5£¨g£©+CH3OH£¨g£©¡÷H3
¡÷H1=
¡÷H2£¬-¡÷H3
¡÷H2£¬-¡÷H3
£¨Óá÷H2ºÍ¡÷H3±íʾ£©
·ÖÎö£º£¨1£©¢ÙÓÉͼ¿ÉÖª£¬Î¶ÈÔ½´ó£¬CH3OCOOCH3µÄƽºâת»¯ÂÊÔ½´ó£»
¢ÚÓÉͼ¿ÉÖª£¬Î¶ÈÔ½´ó£¬RÔ½´ó£¬CH3OCOOCH3µÄƽºâת»¯ÂÊÔ½´ó£»
¢ÛÓÉͼ¿ÉÖª£¬R=1£¬650K£¬CH3OCOOCH3µÄƽºâת»¯ÂÊΪ60%£¬Ôò
     C2H5OCOOC2H5£¨g£©+CH3OCOOCH3£¨g£©?2CH3OCOOC2H5£¨g£©
¿ªÊ¼   
1
V
               
1
V
                 0
ƽºâ   
0.4
V
           
0.4
V
                
1.2
V

KΪƽºâʱÉú³ÉÎïŨ¶ÈÃÝÖ®»ýÓë·´Ó¦ÎïŨ¶ÈÃÝÖ®»ýµÄ±È£»
£¨2£©´ß»¯¼Á²»Ó°Ïì·´Ó¦ÈÈ£¬µ«´ß»¯¼Á½µµÍ·´Ó¦ËùÐèµÄ»î»¯ÄÜ£¬ÒÔ´ËÀ´Í¼»­£»
£¨3£©ÒÑÖª¢ÚCH3OCOOCH3£¨g£©+C2H5OH£¨g£©?CH3OCOOC2H5£¨g£©+CH3OH£¨g£©¡÷H2£¬
¢ÛCH3OCOOC2H5£¨g£©+C2H5OH£¨g£©?C2H5OCOOC2H5£¨g£©+CH3OH£¨g£©¡÷H3£¬
¸ù¾Ý¸Ç˹¶¨ÂÉ¿ÉÖª£¬¢Ú-¢Û¿ÉµÃC2H5OCOOC2H5£¨g£©+CH3OCOOCH3£¨g£©?2CH3OCOOC2H5£¨g£©£®
½â´ð£º½â£º£¨1£©¢ÙÓÉͼ¿ÉÖª£¬Î¶ÈÔ½´ó£¬CH3OCOOCH3µÄƽºâת»¯ÂÊÔ½´ó£¬Ôò¸Ã·´Ó¦µÄÕý·´Ó¦ÎªÎüÈÈ·´Ó¦£¬ËùÒÔ¡÷H£¾0£¬¹Ê´ð°¸Îª£º£¾£»
¢ÚÓÉͼ¿ÉÖª£¬Î¶ÈÔ½´ó£¬RÔ½´ó£¬CH3OCOOCH3µÄƽºâת»¯ÂÊÔ½´ó£¬Ôò³ýÉýÎÂÍ⣬»¹¿ÉÔö´ó·´Ó¦ÎïÖÐC2H5OCOOC2H5µÄŨ¶È£¨»ò±ÈÀý£©£¬¹Ê´ð°¸Îª£ºÔö´ó·´Ó¦ÎïÖÐC2H5OCOOC2H5µÄŨ¶È£¨»ò±ÈÀý£©£»
¢ÛÓÉͼ¿ÉÖª£¬R=1£¬650K£¬CH3OCOOCH3µÄƽºâת»¯ÂÊΪ60%£¬ÉèÈÝÆ÷µÄÌå»ýΪVL£¬Ôò
     C2H5OCOOC2H5£¨g£©+CH3OCOOCH3£¨g£©?2CH3OCOOC2H5£¨g£©
¿ªÊ¼   
1
V
               
1
V
                 0
ƽºâ   
0.4
V
           
0.4
V
                
1.2
V

K=
(
1.2
V
)
2
0.4
V
¡Á
0.4
V
=9£¬¹Ê´ð°¸Îª£º9£»
£¨2£©´ß»¯¼Á²»Ó°Ïì·´Ó¦ÈÈ£¬µ«´ß»¯¼Á½µµÍ·´Ó¦ËùÐèµÄ»î»¯ÄÜ£¬ÈçͼËùʾ´ß»¯¼Á¶Ô·´Ó¦µÄÓ°ÏìΪ£¬
¹Ê´ð°¸Îª£º£»
£¨3£©ÒÑÖª¢ÚCH3OCOOCH3£¨g£©+C2H5OH£¨g£©?CH3OCOOC2H5£¨g£©+CH3OH£¨g£©¡÷H2£¬
¢ÛCH3OCOOC2H5£¨g£©+C2H5OH£¨g£©?C2H5OCOOC2H5£¨g£©+CH3OH£¨g£©¡÷H3£¬
¸ù¾Ý¸Ç˹¶¨ÂÉ¿ÉÖª£¬¢Ú-¢Û¿ÉµÃC2H5OCOOC2H5£¨g£©+CH3OCOOCH3£¨g£©?2CH3OCOOC2H5£¨g£©£¬Ôò¡÷H1=¡÷H2£¬-¡÷H3£¬
¹Ê´ð°¸Îª£º¡÷H2£¬-¡÷H3£®
µãÆÀ£º±¾Ì⿼²é»¯Ñ§Æ½ºâµÄÓ°ÏìÒòËؼ°»¯Ñ§Æ½ºâµÄ¼ÆË㣬·´Ó¦ÈȵļÆË㣬עÒâѧÉúÄÜÁ¦µÄ¿¼²é£¬Ã÷ȷͼÏóµÄ·ÖÎöÊǽâ´ðµÄ¹Ø¼ü£¬×¢Òâ´ß»¯¼Á²»Äܸı䷴ӦÈÈ£¬ÌâÄ¿ÄѶÈÖеȣ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?¹ãÖÝһģ£©ÄÜÔÚË®ÈÜÒºÖдóÁ¿¹²´æµÄÒ»×éÀë×ÓÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?¹ãÖÝһģ£©ÉènAΪ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÊýÖµ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨Ïà¶ÔÔ­×ÓÖÊÁ¿£ºC 12   O 16£©£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?¹ãÖÝһģ£©¶ÔÓÚ0.1mol?L-1 NH4ClÈÜÒº£¬ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?¹ãÖÝһģ£©Ä³Ð¡×éΪÑо¿µç»¯Ñ§Ô­Àí£¬Éè¼ÆÈçͼװÖã¬ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?¹ãÖÝһģ£©¶ÌÖÜÆÚÔªËؼס¢ÒÒ¡¢±û¡¢¶¡µÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£¬¼×λÓÚµÚVA×壬ÒÒÔ­×ӵĺËÍâµç×ÓÊý±È¼×Ô­×Ó¶à1£¬ÒÒÓ붡ͬ×壬±ûÔ­×Ó×îÍâ²ãµç×ÓÊýÓëµç×Ó²ãÊýÏàµÈ£¬Ôò£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸