£¨10·Ö£©Í¼ÖÐA¡«X·Ö±ð´ú±íÒ»ÖÖ·´Ó¦Îï»òÉú³ÉÎÆäÖÐF¡¢G¡¢XΪµ¥ÖÊ£¬¶ÌÖÜÆÚÔªËØXÔ­ÓèµÄºËµçºÉÊýÊÇÆä×îÍâ²ãºÍ×îÄÚ²ãµç×ÓÊýÖ®ºÍµÄ3±¶¡£ÒÑÖªAÊÜÈÈ·Ö½âµÃµ½µÈÎïÖʵÄÁ¿µÄB¡¢C¡¢DÈýÖÖÆø̬ÎïÖÊ£¬DÆøÌåÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶É«£¬ÆäËüΪ»¯ºÏÎͼÖв¿·ÖÉú³ÉÎïδÁгö¡£

Çë»Ø´ð£º
£¨1£©BµÄµç×Óʽ      £¬Ð´³öFµÄÒ»ÖÖͬËØÒìÐÎÌå____£¬   
£¨2£©Ð´³ö·´Ó¦BÓëX·´Ó¦µÄ»¯Ñ§·½³Ìʽ__                 __        ¡£
£¨3£©Ð´³öAÓë×ãÁ¿KÈÜÒº¼ÓÈÈʱ·´Ó¦µÄÀë×Ó·½³Ìʽ___              _¡£
£¨4£©ÔÚÒ»¶¨Ìõ¼þÏ£¬2 LµÄHÆøÌåÓë0.5 LµÄGÆøÌåÏà»ìºÏ£¬Èô¸Ã»ìºÏÆøÌå±»NaOHÈÜҺǡºÃÍêÈ«ÎüÊÕ£¬Ö»Éú³ÉÒ»ÖÖÑΡ£Çëд³ö¸Ã·´Ó¦¹ý³ÌÖÐ×ܵĻ¯Ñ§·´Ó¦·½³Ìʽ£º        ¡£
£¨5£©ÔÚFÓëJµÄ·´Ó¦Öе±×ªÒÆÁË1.5 molµç×Óʱ£¬²úÉú±ê×¼×´¿öϵÄIÆøÌåµÄÌå»ýΪ_______L¡£
£¨10·Ö£©
£¨1£©£¨1·Ö£©£»½ð¸Õʯ£¨C60¡¢Ê¯Ä«µÈ£©£¨1·Ö£©£»
£¨2£©  £¨2·Ö£©
£¨3£©£¨2·Ö£©
£¨4£©4NO+O2+4NaOH = 4NaNO2+2 H2O£¨2·Ö£©
£¨5£©33£®6 £¨2·Ö£©
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

ϱíÊÇÖÐѧ»¯Ñ§½Ì¿ÆÊéÖÐÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬³ý±ê³öµÄÔªËØÍ⣬±íÖеÄÿ¸ö±àºÅ±íʾһÖÖÔªËØ£¬Çë¸ù¾ÝÒªÇó»Ø´ðÎÊÌâ¡£

IA
 
0
1
¢Ù
II A
 
III A
IV A
V A
VI A
VIIA
 
2
 
 
 
¢Ú
¢Û
 
 
Ne
3
¢Ü
¢Ý
Al
 
 
S
¢Þ
 
(1)¢Þ±íʾµÄÔªËØÊÇ           £»
(2)¢ÚµÄÔ­×ӽṹʾÒâͼÊÇ             £»
(3)Óɢٺ͢ÛÁ½ÖÖÔªËØ×é³ÉµÄ»¯ºÏÎïµÄ»¯Ñ§Ê½ÊÇ           £»
(4)¢ÜºÍ¢ÝÁ½ÖÖÔªËصĽðÊôÐÔÇ¿Èõ˳ÐòÊÇ¢Ü      ¢Ý£¨Ìî¡°<¡±»ò¡°>¡±£©¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨10·Ö£©Ï±íÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬»Ø´ðÏÂÁÐÓйØÎÊÌ⣺

¢ÅÔÚÕâЩԪËØÖУ¬Ä³ÔªËصÄÑõ»¯Îï¼È¿É×÷Ư°×¼ÁÓÖÊÇ¿ÕÆøÖÊÁ¿µÄ¼à²â¶ÔÏ󣬸ÃÔªËØÊÇ             £¨ÌîдÐòºÅ£©¡£
¢ÆÔÚÕâЩԪËصÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïÖУ¬ËáÐÔ×îÇ¿µÄÊÇ              £¨Ìѧʽ£©£¬³ÊÁ½ÐÔµÄÇâÑõ»¯ÎïÊÇ           £¨Ìѧʽ£©£»Ð´³öÁ½Õß·´Ó¦µÄÀë×Ó·½³Ìʽ                              ¡£
¢ÇÇëд³ö¹¤ÒµÉÏ¢ÙµÄÇ⻯Îï·¢Éú´ß»¯Ñõ»¯µÄ»¯Ñ§·½³Ìʽ_________________     ¡£
¢ÈÔÚ¢ÛÓë¢ÜÖУ¬»¯Ñ§ÐÔÖʽϻîÆõÄÊÇ         £¨ÌîÔªËØ·ûºÅ£©£¬Ö¤Ã÷¸Ã½áÂ۵Ļ¯Ñ§ÊµÑéÊÇ                                               ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÍƶÏÌâ

(10·Ö) A¡¢B¡¢C¡¢D¡¢EÎåÖÖ¶ÌÖÜÆÚÔªËØ£¬Ô­×ÓÐòÊýÒÀ´ÎÔö´ó£¬A¡¢EͬÖ÷×壬AÔªËصÄÔ­×Ӱ뾶×îС£¬BÔªËØÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇÄÚ²ãµç×ÓÊýµÄ2±¶£¬CÔªËØÔ­×ӵĵç×Ó²ãÊýΪn£¬×îÍâ²ãµç×ÓÊýΪ2n+l£¬A¡¢B¡¢C¡¢EÿÖÖÔªËض¼ÄÜÓëDÔªËØ×é³ÉÁ½ÖÖ»òÁ½ÖÖÒÔÉϵij£¼û»¯ºÏÎï¡£ »Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ð´³öÏÂÁи÷ÔªËØ·ûºÅ£ºC___________    E____________
£¨2£©AºÍCÐγɵÄ×î¼òµ¥»¯ºÏÎïµÄµç×ÓʽΪ           £¬AºÍD°´Ô­×ÓÊý1:1ÐγɵĻ¯ºÏÎïµÄ½á¹¹Ê½Îª           ¡£
£¨3£©ÒÑÖª£º BA3DA(g)+A2D(g)=BD2(g)+3A2(g)   ¡÷H= +49£®0kJ£¯mol
BA3DA(g)+3£¯2D2(g)=BD2(g)+2A2(g) ¡÷H = Ò»192£®9kJ£¯mol
ÊÔд³ö£ºÆø̬BA3DAÍêȫȼÉÕÉú³ÉÆø̬A2DµÄÈÈ»¯Ñ§·½³Ìʽ(ÓÃÍƳöµÄÔªËØ·ûºÅд£¬ÏÂͬ)
                                                              ¡£
ÀûÓøÃȼÉÕ·´Ó¦Éè¼Æ³ÉµÄȼÁϵç³ØÕýÖ𲽵õ½Íƹ㣬Çëд³ö¸ÃȼÁϵç³Ø¸º¼«µç¼«·´Ó¦Ê½(µç½âÖÊÈÜҺΪKOH)£º                                           ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÒÑÖªÔªËØRÓÐijÖÖͬλËصÄÂÈ»¯ÎïRClX£¬¸ÃÂÈ»¯ÎïÖÐR΢Á£ºËÄÚÖÐ×ÓÊýΪY£¬ºËÍâµç×ÓÊýΪZ£¬¸ÃͬλËصķûºÅΪ   (    )
A£®B£®C£®D£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨10·Ö£©ÒÑÖªAΪËáʽÑΣ¬BΪij¶þ¼ÛÖ÷×å½ðÊôÔªËصĻ¯ºÏÎ³£Î³£Ñ¹ÏÂC¡¢D¡¢F¡¢G¡¢I¾ù³ÊÆø̬¡£µÈÎïÖʵÄÁ¿A¡¢BÓëÉÙÁ¿µÄË®³ä·Ö»ìºÏÄÜÇ¡ºÃÍêÈ«·´Ó¦¡£Í¼Öз´Ó¦Ìõ¼þ£¨³ý¸ßÎÂÍ⣩¾ùÒÑÂÔÈ¥¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ð´³öBµÄµç×Óʽ        £¬
£¨2£©Ð´³öAÓëB·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                                                      ¡£
£¨3£©Èç¶ÔÆøÌåG½øÐмÓѹ²Ù×÷£¬²úÉúµÄÏÖÏóÊÇ                                                     ¡£
£¨4£©Ð´³öÏÂÁз´Ó¦µÄÀë×Ó·½³Ìʽ£º
¢ÙÔÚAÈÜÒºÖмÓÈëM                                                                                    ¡£
¢ÚÏòAÈÜÒºÖмÓÈë¹ýÁ¿NaOHÈÜÒº£¬²¢¼ÓÈÈ                                                  ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

´Óij΢Á£µÄÔ­×ӽṹʾÒâͼ·´Ó³³ö£¨   £©
A£®ÖÊ×ÓÊýºÍÖÐ×ÓÊý
B£®ÖÐ×ÓÊýºÍµç×ÓÊý
C£®ºËµçºÉÊýºÍºËÍâµç×Ó²ãÅŲ¼µÄµç×ÓÊý
D£®ÖÊÁ¿ÊýºÍºËÍâµç×Ó²ãÅŲ¼µÄµç×ÓÊý

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨10·Ö£©Ï±íΪԪËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬Çë²ÎÕÕÔªËآ١«¢àÔÚ±íÖеÄλÖã¬Óû¯Ñ§ÓÃÓï»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©¢Û¡¢¢Ü¡¢¢ÝµÄÔ­×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ____________________¡£
£¨2£©¢Ú¡¢¢ß¡¢¢àµÄ×î¸ß¼Ûº¬ÑõËáµÄËáÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ________________¡£
£¨3£©¢Ù¡¢¢Ú¡¢¢Ü¡¢¢ÝËÄÖÖÔªËØ¿ÉÐγÉÖÐѧ³£¼ûµÄ»¯ºÏÎïM£¬Ð´³öMÖдæÔڵĻ¯Ñ§¼üÀàÐÍ_______£»¼ÓÈÈM¹ÌÌå¿ÉÉú³ÉÒ»ÖÖËáÐÔÑõ»¯Îд³ö´ËÑõ»¯ÎïµÄµç×Óʽ______________________¡£
£¨4£©ÓɱíÖТ٢ÜÁ½ÖÖÔªËصÄÔ­×Ó°´1¡Ã1×é³ÉµÄ³£¼ûҺ̬»¯ºÏÎïµÄÏ¡ÈÜÒºÒ×±»´ß»¯·Ö½â£¬¿ÉʹÓõĴ߻¯¼ÁΪ(ÌîÐòºÅ)________¡£
a£®MnO2  b£®Na2SO3  c£®FeCl3  d£®KMnO4

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨8·Ö£©A¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖÎïÖʵÄÏ໥ת»¯¹ØϵÈçÓÒͼËùʾ¡£Í¼Öз´Ó¦Ìõ¼þ¾ùδ±ê³ö£¬²¿·Ö²úÎ°üÀ¨Ë®£©ÒÑÂÔÈ¥£¬·´Ó¦¢ÙÊÇÖû»·´Ó¦¡£

£¨1£©ÈôB¡¢C¡¢F¶¼ÊÇÆø̬µ¥ÖÊ£¬ÇÒBΪ»ÆÂÌÉ«Óж¾ÆøÌå¡£¢ÛºÍ¢ÜÁ½¸ö·´Ó¦Öж¼ÓÐË®Éú³É£¬·´Ó¦¢ÚÐèÒª·Åµç²ÅÄÜ·¢Éú¡£A¡¢D¾ùΪ¼«Ò×ÈÜÓÚË®µÄÆø̬Ç⻯ÎÇÒÏàÓöÓа×ÑÌÉú³É¡£ÔòA·Ö×ÓµÄÁ¢Ìå¹¹ÐÍΪ                   £¬·´Ó¦¢ÛµÄ»¯Ñ§·½³ÌʽΪ                                                    ¡£
£¨2£©ÈôA¡¢DΪ¶ÌÖÜÆÚÔªËصĵ¥ÖÊ£¬ÇÒËùº¬ÔªËصÄÔ­×ÓÐòÊýAÊÇDµÄ2±¶£¬Ëùº¬ÔªËصÄÔ­×Ó×îÍâ²ãµç×ÓÊýDÊÇAµÄ2±¶¡£FÊÇÒ»ÖÖº¬ÑõËᣬ¢ÛºÍ¢ÜÁ½¸ö·´Ó¦Öж¼Óкì×ØÉ«ÆøÌåÉú³É¡£ÔòEµÄ»¯Ñ§Ê½Îª
          £¬·´Ó¦¢ÜµÄ»¯Ñ§·½³ÌʽΪ                                             ¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸