ÈçͼËùʾ£¬Í¨µç5 minºó£¬µç¼«5µÄÖÊÁ¿Ôö¼ÓÁË2.16 g£¬»Ø´ð£º

(1)µçÔ´£ºaÊÇ________¼«£¬C³ØÊÇ________³Ø¡£

A³ØÑô¼«µç¼«·´Ó¦Ê½Îª__________________£¬Òõ¼«µç¼«·´Ó¦Ê½Îª__________________¡£C³ØÑô¼«µç¼«·´Ó¦Ê½__________________£¬Òõ¼«µç¼«·´Ó¦Ê½Îª_____________________¡£

(2)Èç¹ûB²ÛÖй²ÊÕ¼¯µ½224 mLÆøÌå(±ê×¼×´¿ö)£¬ÇÒÈÜÒºÌå»ýΪ200 mL(Éèµç½â¹ý³ÌÖÐÈÜ

ÒºÌå»ý²»±ä)£¬ÔòͨµçÇ°ÈÜÒºÖÐCu2£«µÄÎïÖʵÄÁ¿Å¨¶ÈΪ____________________________¡£

(3)Èç¹ûA³ØÈÜÒºÒ²ÊÇ200 mL(µç½â¹ý³ÌÖÐÈÜÒºÌå»ý²»±ä)£¬Ôòͨµçºó£¬ÈÜÒºµÄpHΪ

________¡£


´ð°¸¡¡(1)¸º¡¡µç½â¡¡2Cl£­£­2e£­===Cl2¡ü

2H£«£«2e£­===H2¡ü

Cu£­2e£­===Cu2£«¡¡2Ag£«£«2e£­===2Ag

(2)0.025 mol¡¤L£­1¡¡(3)13


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


 ³ýÈ¥ÒÒÍéÖлìÓеÄÉÙÁ¿ÒÒÏ©£¬ÕýÈ·µÄ´¦Àí·½·¨ÊÇ
A.½«ÆøÌåͨÈëË®                        B.½«ÆøÌåͨÈë³ÎÇåʯ»ÒË®

C.½«ÆøÌåͨÈëäåË®                      D.½«ÆøÌåͨÈëÇâÆø½øÐйâÕÕ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ijЩ·Ï¾ÉËÜÁϿɲÉÓÃÏÂÁз½·¨´¦Àí£¬½«·ÏËÜÁϸô¾ø¿ÕÆø¼ÓÇ¿ÈÈ£¬Ê¹Æä±ä³ÉÓÐÓõÄÎïÖÊ£¬ÊµÑé×°ÖÃÈçÏÂͼ¡£

¼ÓÈȾ۱ûÏ©·ÏËÜÁϵõ½µÄ²úÎïÈçÏÂ±í£º

²úÎï

ÇâÆø

¼×Íé

ÒÒÏ©

±ûÏ©

±½

¼×±½

̼

ÖÊÁ¿·ÖÊý(%)

12

24

12

16

20

10

6

(1)ÊÔ¹ÜAÖвÐÓàÎïÓжàÖÖÓÃ;£¬ÈçÏÂÁÐת»¯¾Í¿ÉÖÆÈ¡¸ß¾ÛÎï¾ÛÒÒȲ¡£

AÖвÐÁôÎï

д³ö·´Ó¦¢Ú¡¢¢ÛµÄ»¯Ñ§·½³ÌʽÊÇ___________________ _______________________£¬__________________________________¡£

(2)ÊÔ¹ÜBÊÕ¼¯µ½µÄ²úÆ·ÖУ¬ÄÜʹ¸ßÃÌËá¼ØËáÐÔÈÜÒºÍÊÉ«µÄÎïÖÊÊÇ________(ÌîÃû³Æ)£¬¸ÃÎïÖÊÓëÏõËáÖÆÈ¡Ò»ÖÖµ­»ÆÉ«¾§Ìå¡¢ÁÒÐÔÕ¨Ò©µÄ»¯Ñ§·½³ÌʽΪ________________________________ ________________________________________________________________________________________________________________£»

¸ÃÎïÖʵÄÒ»ÂÈ´úÎïÓÐ________ÖÖ¡£

(3)׶ÐÎÆ¿CÖй۲쵽µÄÏÖÏóÊÇ______________________¡£¾­äåË®³ä·ÖÎüÊÕ£¬Ê£ÓàÆøÌå¾­¸ÉÔïºóµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿Îª________¡£

(4)д³öCÖÐÒݳöµÄÆøÌåÔÚ¹¤ÒµÉϵÄÁ½ÖÖÓÃ;____________¡¢________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


д³öÏÂÁи÷ÌþµÄÃû³Æ£¨²ÉÓÃϵͳÃüÃû·¨£©

£¨1£©(CH3)2CH(CH2)2CH(C2H5)(CH2)2CH£¨2£©  

                                                                          

 

£¨3£©         £¨4£©                     £¨4£©

                                                                          

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔÚÏÂͼװÖÃÖУ¬Í¨µçºó¿É¹Û²ìµ½Cu¼«Èܽ⣬ÔòÏÂÁÐ˵·¨Öв»ÕýÈ·µÄÊÇ(¡¡¡¡)

A£®Ö±Á÷µçÔ´ÖУ¬AÊÇÕý¼«                B£®Á½³ØÄÚCuSO4ÈÜҺŨ¶È¾ù²»¸Ä±ä

C£®Á½Ìú¼«ÉÏ×î³õÎö³öÎïÏàͬ              D£®P³ØÄÚÈÜÒºµÄÖÊÁ¿Öð½¥¼õС

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


¶ÔÓÚ·´Ó¦2SO2(g)£«O2(g)2SO3(g)£¬ÄÜÔö´óÕý·´Ó¦ËÙÂʵĴëÊ©ÊÇ(¡¡¡¡)

A£®Í¨Èë´óÁ¿O2                     B£®Ôö´óÈÝÆ÷ÈÝ»ý

C£®ÒÆÈ¥²¿·ÖSO3                    D£®½µµÍÌåϵζÈ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁÐ˵·¨´íÎóµÄÊÇ(¡¡¡¡)

A£®¹²¼Û¼ü¾ßÓз½ÏòÐÔ

B£®¹²¼Û¼ü¾ßÓб¥ºÍÐÔ

C£®¹²¼Û¼üµÄʵÖÊÊÇÔ­×Ó¹ìµÀµÄÏ໥Öصþ

D£®¹²¼Û¼üÊÇͨ¹ýµç×ÓµÃʧ¶øÐγɵĻ¯Ñ§¼ü

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


¡¡¶ÔÓڴﵽƽºâ״̬µÄ¿ÉÄæ·´Ó¦N2+3H22NH3,ÏÂÁÐÓйØÐðÊöÕýÈ·µÄÊÇ()

A. ·´Ó¦ÎïºÍÉú³ÉÎïŨ¶È²»ÔÙ·¢Éú±ä»¯

B. ·´Ó¦ÎïºÍÉú³ÉÎïµÄŨ¶ÈÏàµÈ

C. Ìõ¼þ¸Ä±ä,ƽºâ״̬²»·¢Éú¸Ä±ä

D. Õý·´Ó¦ºÍÄæ·´Ó¦²»ÔÙ½øÐÐ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ij¶þÔªËá(»¯Ñ§Ê½ÓÃH2A±íʾ)ÔÚË®ÈÜÒºÖеĵçÀë·½³ÌʽÊÇH2A===H£«£«HA£­£»HA£­

H£«£«A2£­¡£

»Ø´ðÏÂÁÐÎÊÌ⣺

(1)Na2AÈÜÒºÏÔ________(Ìî¡°ËáÐÔ¡±¡¢¡°ÖÐÐÔ¡±»ò¡°¼îÐÔ¡±)£¬ÀíÓÉÊÇ(ÓÃÀë×Ó·½³Ìʽ±íʾ)________________________________________________________________________¡£

(2)Èô0.1 mol¡¤L£­1 NaHAÈÜÒºµÄpH£½2£¬Ôò0.1 mol¡¤L£­1 H2AÈÜÒºÖÐÇâÀë×ÓµÄÎïÖʵÄÁ¿Å¨¶È¿ÉÄÜ__________0.11 mol¡¤L£­1(Ìî¡°£¾¡±¡¢¡°£½¡±»ò¡°£¼¡±)£¬ÀíÓÉÊÇ

________________________________________________________________________

__________________¡£

(3)0.1 mol¡¤L£­1 NaHAµÄÈÜÒºÖи÷ÖÖÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ

________________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸