(1)Ϊ²úÉú¹âÁÁµÄÒø¾µ£¬ÊÔ¹ÜÓ¦ÏÈÓÃ___________ÈÜÒºÖó·Ð£¬µ¹µôÖó·ÐÒººóÔÙÓÃÇåË®½«ÊԹܳåÏ´¸É¾»¡£
(2)ÅäÖÆÒø°±ÈÜҺʱÏòÊ¢ÓÐ___________ÈÜÒºµÄÊÔ¹ÜÖÐÖðµÎµÎ¼Ó___________ÈÜÒº±ßµÎ±ßÕñµ´Ö±µ½___________Ϊֹ¡£Óйػ¯Ñ§·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º
¢Ù____________________________________________________________¡£
¢Ú____________________________________________________________¡£
(3)¼ÓÈÈʱӦÓÃ_____________¼ÓÈÈ£¬²úÉúÒø¾µµÄ»¯Ñ§·½³ÌʽÊÇ_________________________¡£
(4)ʵÑéÊÒÅäÖÆÒø°±ÈÜҺʱÈôÏòAgNO3ÈÜÒºÖмÓÈ백ˮÐγÉÒø°±ÈÜҺʱ£¬Ó¦·ÀÖ¹¼ÓÈ백ˮ¹ýÁ¿£¬·ñÔòÈÝÒ×Éú³ÉÈÝÒ×±¬Õ¨µÄ___________£¬ÊÔ¼Á±¾ÉíҲʧȥÁéÃôÐÔ¡£ÅäÖƺõÄÒø°±ÈÜÒº²»¿É¾ÃÖ㬷ñÔò»áÉú³É___________´ÓÈÜÒºÖÐÎö³öÕâÖÖ³Áµí£¬ÄÄÅÂÊÇÓò£Á§°ô¹Î²ÁÒ²»á·Ö½â·¢ÉúÃÍÁҵı¬Õ¨¡£
(1)NaOH
(2)AgNO3 °±Ë® ×î³õÏÈÉú³ÉµÄ³ÁµíÇ¡ºÃÈܽâ
(3)ˮԡ CH3CHO+2[Ag(NH3)2]OHCH3COONH4+3NH3+2Ag¡ý+H2O
(4)Ag3N Ag2NH
½âÎö£ºÓûʹÒø¾µ·´Ó¦ÊµÑé³É¹¦±ØÐëÓÃNaOHÈÜÒºÖó·ÐÊԹܳýÈ¥ÓÍÎÛ£¬ÒÔÃâÎö³öµÄÒøÄÑÒÔ¸½×ÅÔÚÊÔ¹ÜÄÚ±ÚÉÏ¡£ÔÚÅäÖÆÒø°±ÈÜҺʱһ¶¨Òª×¢ÒâÔÚAgNO3ÈÜÒºÖмÓÈë1µÎNaOHÈÜÒººóÁ¢¼´²úÉúºÖÉ«³Áµí£¬ËæºóÖðµÎµÎÈëÏ¡°±Ë®±ßµÎ±ßÕñµ´Ö±ÖÁ³Áµí¸Õ¸ÕÏûʧΪֹ£¬¾ÍµÃµ½ÎÞÉ«µÄÒø°±ÈÜÒº¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
(1)ÅäÖÆÒø°±ÈÜҺʱÏòÊ¢ÓÐ_________ÈÜÒºµÄÊÔ¹ÜÖÐÖðµÎµÎ¼Ó_________ÈÜÒº£¬±ßµÎ±ßÕñµ´Ö±µ½_________Ϊֹ¡£Óйط´Ó¦µÄÀë×Ó·½³ÌʽΪ£º¢Ù_______________£¬¢Ú_______________¡£
(2)¼ÓÈÈʱӦÓÃ_________¼ÓÈÈ£¬·¢ÉúÒø¾µ·´Ó¦µÄÀë×Ó·½³ÌʽΪ_____________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêÉÂÎ÷Ê¡³¤°²Ò»Öи߶þÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ
ʵÑéÊÒ×öÒÒÈ©ºÍÒø°±ÈÜÒº·´Ó¦µÄʵÑéʱ£º
£¨1£©ÎªÁ˵õ½¹âÁÁµÄÒø¾µ£¬ÊÔ¹ÜÓ¦ÏÈÓà ÈÜÒºÖó·Ð£¬µ¹µôÖó·ÐÒºÌåºóÔÙÓÃÕôÁóË®½«ÊԹܳåÏ´¸É¾»¡£
£¨2£©ÅäÖÆÒø°±ÈÜҺʱÏòÊ¢ÓÐ ÈÜÒºµÄÊÔ¹ÜÖÐÖðµÎµÎ¼Ó ÈÜÒº£¬±ßµÎ±ßÕñµ´£¬Ö±µ½ Ϊֹ¡£Óйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º¢Ù £»¢Ú ¡£
£¨3£©¼ÓÈÈʱӦÓà ¼ÓÈÈ¡£²úÉúÒø¾µ·´Ó¦µÄ»¯Ñ§·½³Ìʽ ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ìÉÂÎ÷Ê¡¸ß¶þÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
ʵÑéÊÒ×öÒÒÈ©ºÍÒø°±ÈÜÒº·´Ó¦µÄʵÑéʱ£º
£¨1£©ÎªÁ˵õ½¹âÁÁµÄÒø¾µ£¬ÊÔ¹ÜÓ¦ÏÈÓà ÈÜÒºÖó·Ð£¬µ¹µôÖó·ÐÒºÌåºóÔÙÓÃÕôÁóË®½«ÊԹܳåÏ´¸É¾»¡£
£¨2£©ÅäÖÆÒø°±ÈÜҺʱÏòÊ¢ÓÐ ÈÜÒºµÄÊÔ¹ÜÖÐÖðµÎµÎ¼Ó ÈÜÒº£¬±ßµÎ±ßÕñµ´£¬Ö±µ½ Ϊֹ¡£Óйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º¢Ù £»¢Ú ¡£
£¨3£©¼ÓÈÈʱӦÓà ¼ÓÈÈ¡£²úÉúÒø¾µ·´Ó¦µÄ»¯Ñ§·½³Ìʽ ¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com