Question

2£®ÔÚÒ»¶¨Î¶ÈÏ£¬Ìå»ýΪ4LµÄÃܱÕÈÝÆ÷ÖУ¬NO₂ºÍN₂O₄Ö®¼ä·¢Éú·´Ó¦£º2NO₂£¨g£©£¨ºì×ØÉ«£©?N₂O₄£¨g£©£¨ÎÞÉ«£©£¬ÈçͼËùʾ£®
£¨1£©ÇúÏßX£¨Ìî¡°X¡±»ò¡°Y¡±£©±íʾN₂O₄µÄÎïÖʵÄÁ¿Ëæʱ¼äµÄ±ä»¯ÇúÏߣ®
£¨2£©ÈôÉý¸ßζȣ¬Ôòv£¨Õý£©¼Ó¿ì£¬v£¨Ä棩¼Ó¿ì£®£¨Ìî¡°¼Ó¿ì¡±»ò¡°¼õÂý¡±£©£®
£¨3£©ÈôÉÏÊö·´Ó¦Ôڼס¢ÒÒÁ½¸öÏàͬÈÝÆ÷ÄÚͬʱ½øÐУ¬·Ö±ð²âµÃ¼×ÖÐv£¨NO₂£©=
9mol/£¨L•min£©£¬ÒÒÖÐv£¨N₂O₄£©=1mol/£¨L•s£©£¬ÔòÒÒÖз´Ó¦¸ü¿ì£®
£¨4£©ÔÚ0µ½1minÖÐÄÚÓÃX±íʾ¸Ã·´Ó¦µÄËÙÂÊÊÇ0.075 mol/£¨L£®min£©£¬¸Ã·´Ó¦´ïÏÞ¶Èʱ£¬YµÄת»¯ÂÊ60%£¬·´Ó¦¿ªÊ¼Ê±Óë·´Ó¦´ïƽºâ״̬ʱµÄѹǿ֮±ÈΪ14£º11£®

Answer 1

·ÖÎö £¨1£©¸ù¾ÝÎïÖʵÄÁ¿µÄ±ä»¯Á¿Ö®±ÈµÈÓÚ¼ÆÁ¿ÊýÖ®±È·ÖÎö£»
£¨2£©¸ù¾ÝζȶԷ´Ó¦ËÙÂʵÄÓ°Ïì·ÖÎö£»
£¨3£©¸ù¾Ý·´Ó¦ËÙÂÊÖ®±ÈµÈÓÚ»¯Ñ§¼ÆÁ¿ÊýÖ®±È±È½Ï£»
£¨4£©¸ù¾Ýv=$\frac{¡÷c}{¡÷t}$¼ÆËã·´Ó¦ËÙÂÊ£¬½áºÏͼÏó¼ÆËãÏà¹ØÎïÀíÁ¿£®

½â´ð ½â£º£¨1£©ÓÉ·½³ÌʽN₂O₄£¨g£©?2NO₂ £¨g£©£¬¿ÉÖª·´Ó¦ÖÐN₂O₄ µÄÎïÖʵÄÁ¿±ä»¯½ÏС£¬ÔòX±íʾN₂O₄µÄÎïÖʵÄÁ¿Ëæʱ¼äµÄ±ä»¯ÇúÏߣ¬¹Ê´ð°¸Îª£ºX£»
£¨2£©Î¶ÈÉý¸ß£¬ÕýÄæ·´Ó¦ËÙÂʶ¼Ôö´ó£¬¹Ê´ð°¸Îª£º¼Ó¿ì£»¼Ó¿ì£»
£¨3£©¼×ÖÐv£¨NO₂£©=9mol/£¨L•min£©£¬ÒÒÖÐv £¨N₂O₄£©=1mol•L^-1•s^-1£¬v£¨NO₂£©=2v£¨N₂O₄£©=2mol•L^-1•s^-1=120mol/£¨L•min£©£¬ÔòÒÒ·´Ó¦½Ï¿ì£¬
¹Ê´ð°¸Îª£ºÒÒ£»
£¨4£©v£¨X£©=$\frac{\frac{0.7mol-0.4mol}{4L}}{1min}$=0.075mol•£¨L•min£©^-1£¬
¸Ã·´Ó¦´ï×î´óÏÞ¶Èʱ£¬YµÄת»¯ÂÊΪ£º$\frac{1mol-0.4mol}{1mol}$=60%£¬
¿ªÊ¼Ê±£ºn£¨X£©+n£¨Y£©=0.4mol+1mol=1.4mol£¬
ƽºâʱ£ºn£¨X£©+n£¨Y£©=0.7mol+0.4mol=1.1mol£¬
ÔÚÏàͬÌõ¼þÏ£¬ÆøÌåµÄѹǿ֮±ÈµÈÓÚÎïÖʵÄÁ¿Ö®±È£¬
Ôò·´Ó¦¿ªÊ¼Ê±Óë·´Ó¦´ïƽºâ״̬ʱµÄѹǿ֮±ÈΪ1.4mol£º1.1mol=14£º11£¬
¹Ê´ð°¸Îª£º0.075 mol/£¨L£®min£©£»60%£»14£º11£®

µãÆÀ ±¾Ì⿼²é½ÏΪ×ۺϣ¬ÌâÄ¿ÄѶÈÖеȣ¬×¢Òâ°ÑÎÕ»¯Ñ§·´Ó¦ËÙÂÊÒÔ¼°»¯Ñ§Æ½ºâµÄ»ù±¾ÖªÊ¶¼´¿É½â´ð¸ÃÌ⣮