(12·Ö)Ë«ÑõË®¡¢¹ýÁòËá¼ØÊǹ¤ÒµÉϳ£ÓõÄÑõ»¯¼Á¡¢Ïû¶¾¼Á¡£¹¤ÒµÉÏÒÔ²¬ÎªÑô¼«£¬Ç¦»òʯīΪÒõ¼«£¬µç½âNH4HSO4ÈÜÒºµÃ¹ýÁòËá李¾(NH4)2S2O8¡¿ÈÜÒº£¬Æ乤ÒÕÁ÷³ÌΪ£º

£¨1£©½«µç½âºóµÄÈÜÒºËÍÍùË®½âÆ÷ÖÐÔÚ¼õѹÌõ¼þÏÂË®½â¡¢ÕôÁó¡¢Å¨Ëõ·ÖÀ룬¾«ÁóµÃ¹ýÑõ»¯ÇâµÄË®ÈÜÒº£¬Ê£ÓàÈÜÒºÔÙÑ­»·Ê¹Óá£
¢Ùд³öµç½âNH4HSO4ÈÜÒºµÄ»¯Ñ§·½³Ìʽ             
¢Úд³öË®½âÆ÷ÖÐ(NH4)2S2O8ÈÜÒºµÄË®½â·½³Ìʽ              ¡£
¢Û²¬¼Û¸ñ°º¹ó£¬ÊÔ·ÖÎöµç²ÛÑô¼«Óò¬²»ÓÃǦµÄÔ­Òò            ¡£
¢ÜÊÔ·ÖÎöË®½âÆ÷ÖÐʹÓüõѹˮ½â¡¢ÕôÁóµÄÔ­Òò              ¡£
£¨2£©ÔÚµç½âºóµÄ¹ýÁòËáï§ÈÜÒºÖмÓÈëÁòËáÇâ¼Ø£¬Îö³ö¹ýÁòËá¼Ø¹ÌÌ壬¹ýÁòËá¼Ø¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬³£±»»¹Ô­ÎªÁòËá¼Ø£¬80¡æÒÔÉÏÒ×·¢Éú·Ö½â¡£
¢Ù½«0.40 mol¹ýÁòËá¼ØÓë0.20 molÁòËáÅäÖƳÉ1 LÈÜÒº£¬ÔÚ80 ¡æÌõ¼þϼÓÈȲ¢ÔÚtʱ¿ÌÏòÈÜÒºÖеμÓÈëÉÙÁ¿FeCl3ÈÜÒº£¬²â¶¨ÈÜÒºÖи÷³É·ÖµÄŨ¶ÈÈçÓÒͼËùʾ£¨H+Ũ¶Èδ»­³ö£©¡£Í¼ÖÐÎïÖÊXµÄ»¯Ñ§Ê½Îª         ¡£

¢ÚÒÑÖªÁòËáÃÌ£¨MnSO4£©ºÍ¹ýÁòËá¼Ø£¨K2S2O7£©Á½ÖÖÑÎÈÜÒºÔÚÒøÀë×Ó´ß»¯Ï¿ɷ¢Éú·´Ó¦£¬µÃµ½×ϺìÉ«ÈÜÒº¡£´Ë·´Ó¦µÄÀë×Ó·´Ó¦·½³Ìʽ                .
£¨1£©¢Ù2NH4HSO4(NH4)2S2O8£«H2£¨2·Ö£©
¢Ú(NH4)2S2O8£«2H2O = 2NH4HSO4+H2O2£¨2·Ö
¢ÛǦ»áÔÚÑô¼«Ê§µç×ÓÉú³ÉÑôÀë×Ó½øÈëÈÜÒº£¬ÇÒÔÚÑô¼«Éú³ÉµÄS2O82-»áÑõ»¯Ç¦£¨2·Ö£©
¢Ü¼õѹˮ½â¡¢ÕôÁóÊÇΪÁ˼õÉÙË«ÑõË®µÄ·Ö½âËðʧ¡££¨2·Ö£©
£¨2£©¢ÙH2O2  £¨2·Ö£©
¢Ú2Mn2£«£«5S2O82£­£«8H2 2MnO4£­£«10SO42£­£«16H£«£¨2·Ö£©

ÊÔÌâ·ÖÎö£º£¨1£©µç½âºÍË®½âµÄ·´Ó¦Ê½¾ù¿É¸ù¾ÝÌâÖÐËù¸ø·´Ó¦ÎïºÍÉú³ÉÎïÊéд£¬¿ÉµÃ¢Ù2NH4HSO4(NH4)2S2O8£«H2£¬¢Ú(NH4)2S2O8£«2H2O = 2NH4HSO4+H2O2¡£¢ÛʹÓò¬µÄÔ­ÒòÊÇ£¬Ç¦»áÔÚÑô¼«Ê§µç×ÓÉú³ÉÑôÀë×Ó½øÈëÈÜÒº£¬ÇÒÔÚÑô¼«Éú³ÉµÄS2O82-»áÑõ»¯Ç¦¡£¢Ü¼õѹˮ½â¡¢ÕôÁóÊÇΪÁ˼õÉÙË«ÑõË®µÄ·Ö½âËðʧ¡££¨2£©¢Ù¸Õ¿ªÊ¼£¬S2O82£­·¢Éú·´Ó¦£¬²úÉúH2O2 £¬¶øH2O2 Ò׷ֽ⣬µÎÈëÉÙÁ¿FeCl3ÈÜÒº£¬¼´ÊǵÎÈëÁË´ß»¯¼Á£¬¼Ó¿ìÁËH2O2 µÄ·Ö½â£¬¹ÊÔÚtʱº¬Á¿Ñ¸ËÙ½µµÍ¡£¹ÊÎïÖÊX¾ÍÊÇH2O2 ¡£¢ÚµÃµ½×ϺìÉ«ÈÜÒº£¬¼´ÓиßÃÌËá¸ùÉú³É£¬¹Ê·´Ó¦Àë×ÓʽΪ2Mn2£«£«5S2O82£­£«8H2 2MnO4£­£«10SO42£­£«16H£«
µãÆÀ£º±¾ÌâÊôÓÚ³£¹æ¹¤ÒÕÁ÷³ÌÌ⣬ÐèÒªÀûÓû¯Ñ§·´Ó¦Ô­Àí¶ÔÉú²ú¹¤ÒÕ½øÐзÖÎö£¬ÆäÖÐÉæ¼°µÄ»¯Ñ§Ô­Àí¶¼Êdz£¼û»¯Ñ§ÎïÖʵÄÐÔÖÊ£¬½ÓÏÂÀ´µÄСÌâ»áÉæ¼°²»Í¬µÄ֪ʶµãÀ´½â´ð£¬ÒªÀûÓõ½ÎïÖʵÄÌØÊ⻯ѧÐÔÖÊ£¬Ñ§ÉúÓ¦µ±¶ÔÕⲿ·Ö֪ʶÊìÁ·ÕÆÎÕ£¬×îºóµÄͼÏñÌ⣬»¹Êǽ«Í¼ÏñÐÅϢת»¯Îª»¯Ñ§µÄÎÄ×ÖÐÅÏ¢À´Àí½â¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

Ò»ÖÖº¬ÂÁ¡¢ï®¡¢îܵĵç×Ó·ÏÁÏÖУ¬ÂÁÒÔÂÁ²­µÄÐÎʽ´æÔÚ£¬îÜÒÔCo3O4µÄÐÎʽ´æÔÚ£¨Îü¸½ÔÚÂÁ²­µÄµ¥Ãæ»òË«Ã棩£¬ï®»ìÔÓÓÚÆäÖС£´Ó¸Ã·ÏÁÏÖлØÊÕCo3O4µÄ¹¤ÒÕÁ÷³ÌÈçÏ£º

£¨1£©ÈÜÒºAµÄÈÜÖʵÄÖ÷Òª³É·ÖΪ   ¡££¨Ìѧʽ£©
£¨2£©îÜÔüÖмÓÈëÏ¡H2SO4Ëữºó£¬ÔÙ¼ÓÈëNa2S2O3ÈÜÒº¿ÉÒÔ½þ³öîÜÀë×Ó£¬Ôò½þ³öîÜÀë×ÓµÄÀë×Ó·½³ÌʽΪ£¨²úÎïÖÐÖ»ÓÐÒ»ÖÖËá¸ù£©   ¡£
£¨3£©ÔÚʵÑéÊÒÄ£Ä⹤ҵÉú²úʱ£¬Ò²¿ÉÓÃÑÎËá½þ³öîÜÀë×Ó£¬µ«Êµ¼Ê¹¤ÒµÉú²úÖв»ÓÃÑÎËᣬÇë´Ó·´Ó¦Ô­Àí·ÖÎö²»ÓÃÑÎËá½þ³öîÜÀë×ÓµÄÖ÷ÒªÔ­Òò£º   ¡£
£¨4£©¼ÓÈëNaFµÄ·´Ó¦Îª£ºLi£«£«F£­LiF¡ý£¬¸Ã·´Ó¦µÄƽºâ³£Êý±í´ïʽΪK=   ¡£
£¨5£©¼ÓÈë30%Na2CO3ÈÜÒºµÄ×÷ÓÃÊÇ   ¡£
£¨6£©ÔÚ¿ÕÆøÖжÍÉÕCoCO3Éú³ÉCo3O4µÄ»¯Ñ§·½³ÌʽÊÇ   ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

2008Äê°ÂÔËÆڼ䣬ÖйúÌá³öÁË¡°ÂÌÉ«°ÂÔË¡±µÄ¿ÚºÅ£¬ÏÂÁдëÊ©¿ÉÒÔÌá¸ßȼÁÏȼÉÕЧÂʵÄÊÇ£¨    £©
(1)Ìá¸ßȼÁϵÄ×Å»ðµã (2)½µµÍȼÁϵÄ×Å»ðµã  (3)½«¹ÌÌåȼÁÏ·ÛËé
(4)½«ÒºÌåȼÁÏÎí»¯  (5)½«ÃºÆø»¯´¦Àí       (6)ͨÈëÊʵ±¹ýÁ¿¿ÕÆø
A£®(1)(3)(4)(5)B£®(2)(3)(5)(6)C£®(3)(4)(5)(6)D£®(1)(2)(3)(4)

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
A£®¶þÑõ»¯¹è¿ÉÒÔÓÃÀ´ÖÆÔì¹âµ¼ÏËάB£®¹¤ÒÕʦÀûÓÃÑÎËá¿ÌʴʯӢÖÆ×÷ÒÕÊõÆ·
C£®Ë®¾§ÏîÁ´ºÍ²Í×ÀÉϵĴÉÅ̶¼ÊǹèËáÑÎÖÆÆ·D£®´Ö¹èÖƱ¸µ¥¾§¹è²»Éæ¼°Ñõ»¯»¹Ô­·´Ó¦

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÈËÀཫÔÚδÀ´¼¸Ê®ÄêÄÚÖð½¥ÓÉ¡°Ì¼ËØȼÁÏÎÄÃ÷ʱ´ú¡±¹ý¶ÉÖÁ¡°Ì«ÑôÄÜÎÄÃ÷ʱ´ú¡±(°üÀ¨·çÄÜ¡¢ÉúÎïÖÊÄܵÈÌ«ÑôÄܵÄת»»ÐÎ̬)¡£ÆäÖС°µÍ̼¾­¼Ã¡±ÊǺËÐÄ£¬ÏÂÁÐ˵·¨²»·ûºÏÕâÒ»Ö÷ÌâµÄÊÇ(   )
A£®¼õÉÙÒ»´ÎÐÔÓÃÆ·µÄʹÓÃ
B£®ÀûÓÃÌ«ÑôÄÜÕôÁóº£Ë®½øÐк£Ë®µÄµ­»¯
C£®±Ü¿ª¹«¹²½»Í¨µÄÓµ¼·£¬³«µ¼×ԼݳöÐÐ
D£®º£Ë®ºÍµ­Ë®½»»ã´¦°²×°°ë͸Ĥ£¬ÀûÓÃË®Öеç½âÖÊŨ¶ÈµÄ²îÒì½øÐз¢µç

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨12·Ö£©º£Ë®ÊÇÈ¡Ö®²»¾¡ÓÃÖ®²»½ßµÄ»¯Ñ§×ÊÔ´,´Óº£Ë®ÖпÉÌáÈ¡¶àÖÖ»¯¹¤Ô­ÁÏ,ÏÂͼÊÇij»¯¹¤³§¶Ôº£Ë®×ÊÔ´×ÛºÏÀûÓõÄʾÒâͼ¡£

£¨1£©Çëд³öµç½âʳÑÎË®µÄ»¯Ñ§·½³Ìʽ                                        
£¨2£©Ä¸ÒºÖк¬ÓÐK+¡¢Na+ ¡¢Mg2+µÈÑôÀë×Ó£¬´ÓͼÖпɿ´³ö¶ÔĸҺ½øÐÐһϵÁеļӹ¤¿ÉÖƵýðÊôþ¡£
¢Ùʯ»ÒÈéÊÇÉúʯ»ÒÓëË®×÷ÓÃÐγɵĻ¯ºÏÎ´Ó³ä·ÖÀûÓõ±µØº£Ñó»¯Ñ§×ÊÔ´£¬Ìá¸ßÉú²úÓë¾­¼ÃЧÒæµÄ½Ç¶È¿¼ÂÇ£¬Éú²úÉúʯ»ÒµÄÖ÷ÒªÔ­ÁÏÊÇ               
¢Úµç½âÈÛÈÚÂÈ»¯Ã¾µÄ»¯Ñ§·½³ÌʽÊÇ                                            
¢Ûµç½âÎÞË®ÂÈ»¯Ã¾ËùµÃµÄþÕôÆøÔÚÌض¨µÄ»·¾³ÀïÀäÈ´ºó¿ÉµÃ¹Ì̬µÄ½ðÊôþ£¬ÏÂÁÐÎïÖÊÖпÉÒÔÓÃ×÷þÕôÆøµÄÀäÈ´¼ÁµÄÊÇ£¨Ìîд´úºÅ£©                 
A£® H2               B£® CO2         C£®¿ÕÆø         D£® Ar
£¨3£©Ôڸû¯¹¤³§ÖУ¬º£Ë®ÌáÈ¡ÂÈ»¯ÄƺóµÄĸҺ¾­¹ýÌáÈ¡ÂÈ»¯Ã¾ºóÓÖÐγÉÁËеÄĸҺ£¬ÏòÐÂĸҺÖмÓÈëÂÈÆø£¬ÓÖÖÆÈ¡ÁËÖØÒªµÄ»¯¹¤Ô­ÁÏäåµ¥ÖÊ
¢ÙÉú³Éäåµ¥ÖʵĻ¯Ñ§·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                                £¬ÆäÖÐÑõ»¯¼ÁÊÇ        
¹¤ÒµÉú²úÖн«äåµ¥ÖÊ´Ó»ìºÏÎïÖзÖÀë³öÀ´Ó¦²ÉÓà            £¨ÌîʵÑé·½·¨£©
¢ÚÒÔÏÂÊǶÔÉú²úäåµ¥ÖÊËùÓõÄÂÈÆøÑ°ÕÒ»õÔ´µÄÉèÏ룬ÆäÖкÏÀíµÄÊÇ          £¨Ìîд´úºÅ£©
A£®´ÓÍâµØ¹ºÂò                 B£®ÔÚµ±µØн¨Éú²ú³§
C£®´Ó±¾³§Éú²úÉռѭ»·        D£®´Ó±¾³§Éú²úþµ¥ÖÊ´¦Ñ­»·

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁнðÊôµÄÒ±Á¶ÖУ¬Í¨³£ÊÇÓüÓÈÈ·Ö½âµÄ·½·¨À´Íê³ÉµÄÊÇ
A£®NaB£®MgC£®AgD£®Fe

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

¶Ôº£Ë®½øÐпª·¢ÀûÓõIJ¿·ÖÁ÷³ÌÈçÏÂͼËùʾ¡£ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ
A£®¿ÉÓÃBaCl2ÈÜÒº³ýÈ¥´ÖÑÎÖеÄSO42-
B£®´Ó¿à±ÖÐÌáÈ¡Br2µÄ·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º2Br- + Cl2 ="=" 2Cl- + Br2
C£®ÊÔ¼Á1¿ÉÒÔÑ¡ÓÃʯ»ÒÈé
D£®¹¤ÒµÉÏ£¬µç½âÈÛÈÚMg(OH)2Ò±Á¶½ðÊôþ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨¹²12·Ö£©¡¡¡¡¹¤ÒµÉÏÒÔï®»Ôʯ£¨Li2O¡¤Al2O3¡¤4SiO2£¬º¬ÉÙÁ¿Ca¡¢MgÔªËØ£©ÎªÔ­ÁÏÉú²ú̼Ëáﮡ£Æ䲿·Ö¹¤ÒÕÁ÷³ÌÈçÏ£º

¡¡¡¡ÒÑÖª£º¢Ù Li2O¡¤Al2O3¡¤4SiO2H2SO4£¨Å¨£©Li2SO4Al2O3¡¤4SiO2¡¤H2O¡ý
¡¡¡¡¢Ú ijЩÎïÖʵÄÈܽâ¶È(S)ÈçϱíËùʾ£º
T/¡æ
20
40
60
80
(Li2CO3)/g
1.33
1.17
1.01
0.85
(Li2SO4)/g
34.2
32.8
31.9
30.7
¡¡¡¡¢Û ´ÓÂËÔü1ÖзÖÀë³öAl2O3µÄ²¿·ÖÁ÷³ÌÈçÏÂͼËùʾ£º

£¨1£©¡¢ÇëÒÀ´Îд³öÔÚÀ¨ºÅÄÚ¼ÓÈëÊÔ¼ÁµÄ»¯Ñ§Ê½¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¢¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
£¨2£©¡¢ÇëÒÀ´Îд³ö·½¿òÖÐËùµÃµ½ÎïÖʵĻ¯Ñ§Ê½¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¢¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
£¨3£©¡¢²½Öè¢ñÖз´Ó¦µÄÀë×Ó·½³ÌʽÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
£¨4£©¡¢ÒÑÖªÂËÔü2µÄÖ÷Òª³É·ÖÓÐMg(OH)2ºÍCaCO3¡£ÏòÂËÒº1ÖмÓÈëʯ»ÒÈéµÄ×÷ÓÃÊÇ£¨ÔËÓû¯Ñ§Æ½ºâÔ­Àí¼òÊö£©¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
£¨5£©¡¢ÏòÂËÒº2ÖмÓÈë±¥ºÍNa2CO3ÈÜÒº£¬¹ýÂ˺ó£¬Óá°ÈÈˮϴµÓ¡±µÄÔ­ÒòÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡
¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
£¨6£©¡¢Ñõ»¯ÂÁÔÚ¹¤ÒµÉÏÓÃ×÷¸ßÎÂÄÍ»ð²ÄÁÏ£¬ÖÆÄÍ»ðש¡¢ÛáÛö¡¢´ÉÆ÷¡¢ÈËÔ챦ʯµÈ£¬Í¬Ê±Ñõ»¯ÂÁÒ²ÊÇÁ¶ÂÁµÄÔ­ÁÏ¡£Ð´³öÓÃÑõ»¯ÂÁÁ¶ÂÁµÄ»¯Ñ§·½³Ìʽ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸