ÒÑÖªÒÒȲÓë±½ÕôÆûÍêȫȼÉÕµÄÈÈ»¯Ñ§·½³ÌʽÈçÏÂËùʾ£º
¢ÙC2H2£¨g£©+5/2O2£¨g£©¡ú2CO2£¨g£©+H2O£¨1£© ¡÷H=£­1300KJ/mol
¢ÚC6H6£¨g£©+15/2O2£¨g£©¡ú6CO2£¨g£©+3H2O£¨1£©¡÷H=£­3295Kj/mol
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ                          £¨   £©
A£®1mol C2H2£¨g£©ÍêȫȼÉÕÉú³ÉÆø̬ˮʱ·ÅÈÈ´óÓÚ1300kJ
B£®1mol C6H6£¨1£©ÍêȫȼÉÕÉú³ÉҺ̬ˮʱ·ÅÈÈ´óÓÚ3295kJ
C£®ÏàͬÌõ¼þÏ£¬µÈÖÊÁ¿µÄC2H2£¨g£©ÓëC6H6£¨g£©ÍêȫȼÉÕ£¬C6H6£¨g£©·ÅÈȸü¶à
D£®C2H2£¨g£©Èý¾ÛÉú³ÉC6H6£¨g£©µÄ¹ý³ÌÊôÓÚ·ÅÈÈ·´Ó¦
D

ÊÔÌâ·ÖÎö£ºA¡¢ÓÉÆø̬ˮ±äΪҺ̬ˮ»á·Å³öÈÈÁ¿£¬¹Ê1mol C2H2£¨g£©ÍêȫȼÉÕÉú³ÉÆø̬ˮʱ·ÅÈÈСÓÚ1300kJ£¬¹Ê´í£»
B¡¢C6H6£¨1£©±äΪC6H6£¨g£©ÒªÎüÊÕÈÈÁ¿£¬¹Ê1mol C6H6£¨1£©ÍêȫȼÉÕÉú³ÉҺ̬ˮʱ·ÅÈÈСÓÚ3295kJ£¬¹Ê´í£»
C¡¢¼ÙÉèÖÊÁ¿¶¼Îªmg£¬ÔòC2H2£¨g£©ÓëC6H6£¨g£©ÎïÖʵÄÁ¿·Ö±ðΪ(m/26)mol¡¢(m/78)mol£¬·Ö±ð´øÈë¸÷×ÔµÄÈÈ»¯Ñ§·½³ÌʽÖУ¬·Å³öµÄÈÈÁ¿·Ö±ðΪ50 KJ/mol¡¢42 KJ/mol£¬¹ÊC2H2£¨g£©·ÅÈȸü¶à£¬¹Ê´í¡£
¹ÊÑ¡D¡£
µãÆÀ£º±¾Ì⿼²éµÄÊÇÈÈ»¯Ñ§·½³ÌʽµÄÓ¦Óã¬ÌâÄ¿ÄѶȲ»´ó£¬Ö÷Òª¿¼²éѧÉú¶Ô»ù´¡ÖªÊ¶µÄÕÆÎճ̶ȡ£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£º¼ÆËãÌâ

¹¤ÒµºÏ³É°±µÄ·´Ó¦Îª£ºN2(g)+3H2(g) 2NH3(g)    ¡÷H<0¡£Ä³ÊµÑ齫3.0 mol N2(g)ºÍ4. 0 mol H2(g)³äÈëÈÝ»ýΪ10LµÄÃܱÕÈÝÆ÷ÖУ¬ÔÚζÈT1Ï·´Ó¦¡£²âµÃH2µÄÎïÖʵÄÁ¿Ë淴Ӧʱ¼äµÄ±ä»¯ÈçÏÂͼËùʾ¡£

£¨1£©·´Ó¦¿ªÊ¼3minÄÚ£¬H2µÄƽ¾ù·´Ó¦ËÙÂÊΪ                         ¡£
£¨2£©¼ÆËã¸ÃÌõ¼þϺϳɰ±·´Ó¦µÄ»¯Ñ§Æ½ºâ³£Êý£¨Ð´³ö¼ÆËã¹ý³Ì£¬½á¹û±£Áô2λÓÐЧÊý×Ö£©¡£
£¨3£©½ö¸Ä±äζÈΪT2 ( T2СÓÚTI£©ÔÙ½øÐÐʵÑ飬ÇëÔÚ´ðÌ⿨¿òͼÖл­³öH2µÄÎïÖʵÄÁ¿Ëæ
·´Ó¦Ê±¼ä±ä»¯µÄÔ¤ÆÚ½á¹ûʾÒâͼ¡£
£¨4£©ÔÚÒÔúΪÖ÷ÒªÔ­Áϵĺϳɰ±¹¤ÒµÖУ¬Ô­ÁÏÆøÇâÆø³£ÓÃÏÂÊö·½·¨»ñµÃ£º

д³öÉÏÊöCOÓëH2O(g)·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º                     ¡£
£¨5£©ºÏ³É°±¹¤ÒµÖУ¬Ô­ÁÏÆø(N2¡¢H2»ìÓÐÉÙÁ¿CO¡¢NH3£©ÔÚ½øÈëºÏ³ÉËþ֮ǰ£¬Óô×Ëá¶þ°±ºÏÍ­£¨I£©ÈÜÒºÀ´ÎüÊÕCOÆ䷴ӦΪ£ºCH3COO[Cu(NH3)2]+CO+NH3CH3COO[Cu(NH3)3]?CO  ¡÷H<0¡£Ð´³öÌá¸ßCOÎüÊÕÂʵÄÆäÖÐÒ»Ïî´ëÊ©£º               ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÔÚ1200¡æʱ£¬ÌìÈ»ÆøÍÑÁò¹¤ÒÕÖлᷢÉúÏÂÁз´Ó¦
¢ÙH2S(g)+ O2(g)=SO2(g)+H2O(g)         ¡÷H1
¢Ú2H2S(g)+SO2(g)= S2(g)+2H2O(g)      ¡÷H2
¢ÛH2S(g)+ O2(g)=S(g)+H2O(g)             ¡÷H3
¢Ü2S(g) =S2(g)                            ¡÷H4
Ôò¡÷H4µÄÕýÈ·±í´ïʽΪ£¨ £©
A£®¡÷H4=2/3£¨¡÷H1+¡÷H2-3¡÷H3£©
B£®¡÷H4=2/3£¨3¡÷H3-¡÷H1-¡÷H2£©
C£®¡÷H4=3/2£¨¡÷H1+¡÷H2-3¡÷H3£©
D£®¡÷H4=3/2£¨¡÷H1-¡÷H2-3¡÷H3£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÒÑÖª£ºH2(g)£«F2(g)===2HF(g)¡¡¦¤H£½£­270 kJ¡¤mol£­1£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
A£®2 L·ú»¯ÇâÆøÌå·Ö½â³É1 LÇâÆøºÍ1 L·úÆøÎüÊÕ270 kJÈÈÁ¿
B£®1 molÇâÆøÓë1 mol·úÆø·´Ó¦Éú³É2 molҺ̬·ú»¯Çâ·Å³öÈÈÁ¿Ð¡ÓÚ270 kJ
C£®ÔÚÏàͬÌõ¼þÏ£¬1 molÇâÆøÓë1 mol·úÆøµÄÄÜÁ¿×ܺʹóÓÚ2 mol·ú»¯ÇâÆøÌåµÄÄÜÁ¿
D£®1¸öÇâÆø·Ö×ÓÓë1¸ö·úÆø·Ö×Ó·´Ó¦Éú³É2¸ö·ú»¯ÇâÆøÌå·Ö×ӷųö270 kJµÄÈÈÁ¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÕýÈ·µÄÊÇ£¨µÄ¾ø¶ÔÖµ¾ùÕýÈ·£©
A£®C2H5OH£¨l£©+3O2£¨g£©==2CO2£¨g£©+3H2O£¨g£©£»¡÷H=¡ª1367.0 kJ/mol£¨È¼ÉÕÈÈ£©
B£®NaOH£¨aq£©+HCl£¨aq£©==NaCl£¨aq£©+H2O£¨l£©£»¡÷H=+57.3kJ/mol£¨ÖкÍÈÈ£©
C£®S£¨s£©+O2£¨g£©===SO2£¨g£©£»¡÷H=¡ª269.8kJ/mol£¨·´Ó¦ÈÈ£©
D£®2NO2==O2+2NO£»¡÷H=+116.2kJ/mol£¨·´Ó¦ÈÈ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÓÒͼÊÇijÌõ¼þÏÂÓë·´Ó¦¹ý³ÌÖÐÄÜÁ¿±ä»¯µÄÇúÏßͼ¡£¸ù¾ÝͼÏñÅжÏÏÂÁÐÐðÊöÖÐÕýÈ·µÄÊÇ
A£®¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£ºN2(g)+3H2(g)2NH3(g)¦¤H=+92kJ/mol
B£®ÇúÏßÊǼÓÈë´ß»¯¼ÁʱµÄÄÜÁ¿±ä»¯ÇúÏß
C£®¼ÓÈë´ß»¯¼Á£¬¸Ã»¯Ñ§·´Ó¦µÄ·´Ó¦ÈÈÊýÖµ»á¼õС
D£®·´Ó¦2NH3(g) N2(g)+3H2(g) ¦¤H=+92kJ/mol

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÒÑÖªH¡ªH¼ü¼üÄÜ(¶ÏÁÑʱÎüÊÕ»òÉú³ÉʱÊͷŵÄÄÜÁ¿)Ϊ436 kJ¡¤mol£­1£¬N¡ªH¼ü¼üÄÜΪ391 kJ¡¤mol£­1£¬¸ù¾ÝÈÈ»¯Ñ§·½³Ìʽ£ºN2(g)£«3H2(g)===2NH3(g)¡¡¦¤H£½£­92.4 kJ¡¤mol£­1¡£ÔòN¡ÔN¼üµÄ¼üÄÜÊÇ
A£®431 kJ¡¤mol£­1B£®945.6 kJ¡¤mol£­1
C£®649 kJ¡¤mol£­1D£®896 kJ¡¤mol£­1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

HCNÎÞÉ«ÓÐÐÓÈÊÆøζµÄÓж¾ÆøÌ壬ÔçÆڹ㷺ÓÃÓÚ´¬²Õ¡¢²Ö¿âµÄÑÌѬÃðÊó¡£
ÒÑÖª£ºHCN( aq)ÓëNaOH(aq)·´Ó¦µÄìʱ䦤H£½£­12.1 kJ¡¤mol£­1; HCl(aq)ÓëNaOH(aq)·´Ó¦µÄìʱ䦤H£½£­55.6 kJ¡¤mol£­1¡£ÔòHCNÔÚË®ÈÜÒºÖеçÀëµÄìʱ䦤HµÈÓÚ
A£®£­67.7 kJ¡¤mol£­1B£®£­43.5 kJ¡¤mol£­1
C£®£«43.5 kJ¡¤mol£­1D£®£«67.7 kJ¡¤mol£­1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

(18·Ö)ÔÚÈÝ»ý²»Í¬µÄ¶à¸öÃܱÕÈÝÆ÷ÄÚ£¬·Ö±ð³äÈëͬÁ¿µÄN2ºÍH2£¬ÔÚ²»Í¬Î¶ÈÏ£¬Í¬Ê±·¢Éú·´Ó¦N2+3H22NH3£¬²¢·Ö±ðÔÚtÃëʱ²â¶¨ÆäÖÐNH3µÄÌå»ý·ÖÊý£¬»æͼÈçÓÒ£º

(1)A£¬B£¬C£¬D£¬EÎåµãÖУ¬ÉÐδ´ïµ½»¯Ñ§Æ½ºâ״̬µÄµãÊÇ                  ¡£
(2) ÏòÒ»ºãÈÝÈÝÆ÷ÖмÓÈë1 mol N2 ºÍ3 mol H2£¬T3ʱ£¬²âµÃÌåϵѹǿΪԭÀ´µÄ7/8£¬²¢·Å³ö23.1 kJµÄÈÈÁ¿£¬Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ              ¡£
(3)µ±ÉÏÊö·´Ó¦´¦ÓÚƽºâ״̬ʱ£¬ÔÚÌå»ý²»±äµÄÌõ¼þÏ£¬ÏÂÁдëÊ©ÖÐÓÐÀûÓÚÌá¸ßNH3²úÂʵÄÓР         £¨Ìî×Öĸ£©
A£®Éý¸ßζÈB£®½µµÍζÈC£®Ôö´óѹǿD£®¼õСѹǿ
E£®¼ÓÈë´ß»¯¼Á   F£®ÎüÊÕNH3    G£®Í¨ÈëN2
(4)AC¶ÎµÄÇúÏߺÍCE¶ÎÇúÏ߱仯Ç÷ÊÆÏà·´£¬ÊÔ´Ó·´Ó¦ËÙÂʺÍƽºâ½Ç¶È˵Ã÷ÀíÓÉ¡£
                                                                 ¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸