(ÿ¿Õ2·Ö£¬¹²10·Ö)A¡¢B¡¢C¡¢D¡¢E¶¼ÊǶÌÖÜÆÚÔªËØ£¬Ô­×ÓÐòÊýÒÀ´ÎÔö´ó£¬ÎåÖÖÔªËغ˵çºÉ×ÜÊýΪ42£¬B¡¢CͬÖÜÆÚ£¬A¡¢DͬÖ÷×å¡£A¡¢BÄÜÐγÉÁ½ÖÖҺ̬»¯ºÏÎï¼×ºÍÒÒ£¬Ô­×Ó¸öÊý±È·Ö±ðΪ2¡Ã1ºÍ1¡Ã1¡£¸ù¾ÝÒÔÉÏÐÅÏ¢»Ø´ðÏÂÁÐÎÊÌ⣺
¢Å¼×¡¢ÒÒÁ½·Ö×ÓÖк¬ÓзǼ«ÐÔ¹²¼Û¼üµÄÎïÖʵĵç×ÓʽÊÇ                        £¬CÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ                        ¡£
¢ÆCºÍDµÄÀë×ÓÖУ¬°ë¾¶½ÏСµÄÊÇ                £¨ÌîÀë×Ó·ûºÅ£©¡£
¢Ç½«DµÄµ¥ÖÊͶÈë¼×ÖУ¬´ýDÏûʧºóÔÙÏòÉÏÊöÈÜÒºÖмÓÈëEµÄµ¥ÖÊ£¬´Ëʱ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ______________________________________________________¡£
¢ÈC¡¢D¡¢E¿É×é³ÉÀë×Ó»¯ºÏÎïDxEC6£¬Æ侧°û£¨¾§°ûÊÇÔÚ¾§ÌåÖоßÓдú±íÐÔµÄ×îСÖظ´µ¥Ôª£©½á¹¹ÈçÏÂͼËùʾ£¬ÑôÀë×ÓD£«£¨Óáð±íʾ£©Î»ÓÚÕý·½ÌåµÄÀâµÄÖеãºÍÕý·½ÌåÄÚ²¿£»ÒõÀë×ÓEC6x£­£¨Óáñ±íʾ£©Î»ÓÚ¸ÃÕý·½ÌåµÄ¶¥µãºÍÃæÐÄ¡£¸Ã»¯ºÏÎïµÄ»¯Ñ§Ê½ÊÇ               ¡£

¢Å       µÚ¶þÖÜÆÚ¡¢µÚ¢÷A×å        ¢Æ Na+
¢Ç 2Al£«2NaOH£«2H2O£½2NaAlO2£«3H2¡ü         ¢È Na3AlF6

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨Ã¿¿Õ2·Ö£¬¹²10·Ö£©ÎïÖÊFÊǺϳɶàÖÖÊÖÐÔÒ©ÎïºÍÉúÎï»îÐÔÎïÖʵÄÖØÒªÖмäÌ壬ÆäºÏ³É·ÏßÈçÏ£º

£¨1£©·´Ó¦¢ÙµÄÀàÐÍΪ            £¬·´Ó¦¢ÜµÄÀàÐÍΪ          ¡£

£¨2£©ÎïÖÊA¾ÛºÏ¿ÉµÃ¾Û±ûȲËá¼×õ¥£¬Æä½á¹¹¼òʽΪ            ¡£

£¨3£©ÎïÖÊCµÄË×ÃûΪÈâ¹ðÈ©£¬Ð´³öÆäͬʱÂú×ãÏÂÁÐÌõ¼þµÄÒ»ÖÖͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ                                                   ¡£

¢ÙÄÜÓëÂÈ»¯ÌúÈÜÒºÏÔ×ÏÉ«£»¢Ú±½»·ÉÏÓÐÁ½¸öÈ¡´ú»ù£»¢Û·Ö×ӵĺ˴Ź²ÕñÇâÆ×ÓÐ4¸ö·å¡£

£¨4£©Èô²¿·ÖC±»Ñõ»¯ÎªÈâ¹ðËᣬ·´Ó¦¢Ú½«²úÉú¸±²úÎ·Ö×ÓʽΪC14H15NO3£©£¬Ð´³öÆä½á¹¹¼òʽ                                                                        ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêÖØÇìÊÐÑî¼ÒƺÖÐѧ¸ßÒ»ÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨Ã¿¿Õ2·Ö£¬¹²10·Ö£©ÒÀ¾ÝÊÂʵ£¬Ìî¿Õ£º
£¨1£©ÒÑ֪ijÌõ¼þÏ¿ɷ¢ÉúÈçÏ·´Ó¦CH3£­CH3¡úCH2£½CH2£«H2£¬Óйػ¯Ñ§¼üµÄ¼üÄÜÈçÏ£º

»¯Ñ§¼ü
C£­H
C£½C
C£­C
H£­H
¼üÄÜ£¨kJ/mol£©
414.4
615.3
347.4
435.3
Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÓұߵĦ¤H£½                     £»
£¨2£©ÇâÑõȼÁϵç³ØÒÑÓÃÓÚº½Ìì·É»ú¡£ÒÔ30%KOHÈÜҺΪµç½âÖʵÄÕâÖÖµç³ØÔÚʹÓÃʱµÄµç¼«·´Ó¦Ê½£ºÕý¼«£º                       £»¸º¼«£º                       
£¨3£©Ä³ºËËØAZXµÄÂÈ»¯ÎïXCl2 1.11 gÅä³ÉÈÜÒººó£¬ÐèÓÃ1mol¡¤L-1µÄÏõËáÒøÈÜÒº20 ml²ÅÄÜ°ÑÂÈÀë×ÓÍêÈ«³ÁµíÏÂÀ´¡£ÔòXµÄÖÊÁ¿ÊýΪ         £»
(4) ½«¼×ÍéºÍÑõÆøµÄ»ìºÏÆøÌå³äÈ뺬ÓÐ23.4 g Na2O2µÄÃܱÕÈÝÆ÷ÖУ¬±£³ÖÈÝÆ÷ÖÐζÈΪ150 ¡æ£¬Óõç»ð»¨Òýȼ³ä·Ö·´Ó¦ºó£¬Ñ¹Ç¿Îª0 Pa£¬Èô½«²ÐÁôÎïÈÜÓÚË®£¬ÎÞÆøÌåÒݳö¡£´Ë¹ý³ÌµÄ×Ü·´Ó¦·½³ÌʽΪ                                          ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêÔÆÄÏÊ¡ÓñϪһÖи߶þÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨Ã¿¿Õ2·Ö£¬¹²10·Ö£©Ê³Æ·°²È«¹Øϵ¹ú¼ÆÃñÉú£¬Ó°ÏìʳƷ°²È«µÄÒòËغܶࡣ
(1)¾ÛÆ«¶þÂÈÒÒÏ©()¾ßÓг¬Ç¿×è¸ôÐÔÄÜ£¬¿É×÷Ϊ±£ÏÊʳƷµÄ°ü×°²ÄÁÏ¡£ËüÊÇÓÉ________(д½á¹¹¼òʽ)·¢Éú¼Ó¾Û·´Ó¦Éú³ÉµÄ¡£
(2)ÁÓÖÊÖ²ÎïÓÍÖеÄÑÇÓÍËá[CH3(CH2)4¡ªCH===CH¡ªCH2¡ªCH===CH¡ª(CH2)7COOH]º¬Á¿ºÜµÍ¡£ÏÂÁйØÓÚÑÇÓÍËáµÄ˵·¨ÖУ¬ÕýÈ·µÄÊÇ________¡£

A£®·Ö×ÓʽΪC18H34O2
B£®Ò»¶¨Ìõ¼þÏÂÄÜÓëÒÒËá·¢Éúõ¥»¯·´Ó¦
C£®ÄܺÍNaOHÈÜÒº·´Ó¦
D£®ÄÜʹËáÐÔKMnO4ÈÜÒºÍÊÉ«
(3)¼Ù¾ÆÖм״¼(CH3OH)º¬Á¿³¬±ê£¬Çëд³öNaºÍ¼×´¼·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º____________________¡£
(4)ÁÓÖÊÄÌ·ÛÖе°°×Öʺ¬Á¿ºÜµÍ¡£µ°°×ÖÊË®½âµÄ×îÖÕ²úÎïÊÇ__________________¡£
(5)ÔÚµí·ÛÖмÓÈëµõ°×¿éÖƵõķÛË¿Óж¾¡£µí·Û×îÖÕµÄË®½â²úÎïÊÇÆÏÌÑÌÇ¡£ÇëÉè¼ÆʵÑéÖ¤Ã÷µí·ÛÒѾ­È«²¿Ë®½â£¬Ð´³ö²Ù×÷¡¢ÏÖÏóºÍ½áÂÛ£º_________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ìÔÆÄÏÊ¡¸ß¶þÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨Ã¿¿Õ2·Ö£¬¹²10·Ö£©Ê³Æ·°²È«¹Øϵ¹ú¼ÆÃñÉú£¬Ó°ÏìʳƷ°²È«µÄÒòËغܶࡣ

(1)¾ÛÆ«¶þÂÈÒÒÏ©()¾ßÓг¬Ç¿×è¸ôÐÔÄÜ£¬¿É×÷Ϊ±£ÏÊʳƷµÄ°ü×°²ÄÁÏ¡£ËüÊÇÓÉ________(д½á¹¹¼òʽ)·¢Éú¼Ó¾Û·´Ó¦Éú³ÉµÄ¡£

(2)ÁÓÖÊÖ²ÎïÓÍÖеÄÑÇÓÍËá[CH3(CH2)4¡ªCH===CH¡ªCH2¡ªCH===CH¡ª(CH2)7COOH]º¬Á¿ºÜµÍ¡£ÏÂÁйØÓÚÑÇÓÍËáµÄ˵·¨ÖУ¬ÕýÈ·µÄÊÇ________¡£

A£®·Ö×ÓʽΪC18H34O2

B£®Ò»¶¨Ìõ¼þÏÂÄÜÓëÒÒËá·¢Éúõ¥»¯·´Ó¦

C£®ÄܺÍNaOHÈÜÒº·´Ó¦

D£®ÄÜʹËáÐÔKMnO4ÈÜÒºÍÊÉ«

(3)¼Ù¾ÆÖм״¼(CH3OH)º¬Á¿³¬±ê£¬Çëд³öNaºÍ¼×´¼·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º____________________¡£

(4)ÁÓÖÊÄÌ·ÛÖе°°×Öʺ¬Á¿ºÜµÍ¡£µ°°×ÖÊË®½âµÄ×îÖÕ²úÎïÊÇ__________________¡£

(5)ÔÚµí·ÛÖмÓÈëµõ°×¿éÖƵõķÛË¿Óж¾¡£µí·Û×îÖÕµÄË®½â²úÎïÊÇÆÏÌÑÌÇ¡£ÇëÉè¼ÆʵÑéÖ¤Ã÷µí·ÛÒѾ­È«²¿Ë®½â£¬Ð´³ö²Ù×÷¡¢ÏÖÏóºÍ½áÂÛ£º_________________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ìɽ¶«¹ÚÏØÎäѵ¸ßÖи߶þÏÂѧÆÚµÚÈý´Î¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨Ã¿¿Õ2·Ö£¬¹²10·Ö£©

ijÌþA 0.2 mol ÔÚÑõÆøÖÐÍêȫȼÉÕºó£¬Éú³ÉCO2ºÍH2O¸÷1.2 mol¡£ÊԻشð£º

£¨1£©ÌþAµÄ·Ö×ÓʽΪ_____________¡£

£¨2£©ÈôÈ¡Ò»¶¨Á¿µÄÌþAÍêȫȼÉÕºó£¬Éú³ÉCO2ºÍH2O¸÷3 mol£¬ÔòÓÐ________gÌþA²Î¼ÓÁË·´Ó¦£¬È¼ÉÕʱÏûºÄ±ê×¼×´¿öϵÄÑõÆø___________L¡£

£¨3£©ÈôÌþA²»ÄÜʹäåË®ÍÊÉ«£¬µ«ÔÚÒ»¶¨Ìõ¼þÏÂÄÜÓëÂÈÆø·¢ÉúÈ¡´ú·´Ó¦£¬ÆäÒ»ÂÈÈ¡´úÎïÖ»ÓÐÒ»ÖÖ£¬ÔòÌþAµÄ½á¹¹¼òʽΪ__________________¡£

£¨4£©ÈôÌþAÄÜʹäåË®ÍÊÉ«£¬ÔÚ´ß»¯¼Á×÷ÓÃÏ£¬ÓëH2¼Ó³É£¬Æä¼Ó³É²úÎï¾­²â¶¨·Ö×ÓÖк¬ÓÐ4¸ö¼×»ù£¬ÌþA¿ÉÄÜÓеĽṹ¼òʽΪ______________£¨Ð´³öÒ»ÖÖ¼´¿É£©

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸