ÔÚÈý¸ö2 LºãÈݵÄÈÝÆ÷ÖУ¬·Ö±ð·¢Éú·´Ó¦A(g)£«3B(g)2C(g)£¬5 minºó¸÷ÈÝÆ÷·´Ó¦´ïƽºâ״̬£¬ÆäÖм×ÈÝÆ÷ÖÐAµÄÎïÖʵÄÁ¿Îª0.4 mol£®

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A£®

ÒÒÖÐ5 minÄÚCµÄ·´Ó¦ËÙÂÊΪ0.12 mol/(L¡¤min)

B£®

´ïµ½Æ½ºâʱ£¬±ûÖÐAµÄŨ¶ÈÊǼ×ÖеÄ2±¶

C£®

±ûÖз´Ó¦µÄƽºâ³£Êý´óÓÚ¼×Öз´Ó¦µÄƽºâ³£Êý

D£®

´ïµ½Æ½ºâʱ£¬¼×ÒÒÁ½ÈÝÆ÷ÖÐCµÄÎïÖʵÄÁ¿°Ù·Öº¬Á¿ÏàµÈ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÔÚÈý¸ö2LºãÈݵÄÈÝÆ÷ÖУ¬·Ö±ð·¢Éú·´Ó¦A£¨g£©+3B£¨g£©?2C£¨g£© 5minºó¸÷ÈÝÆ÷·´Ó¦´ïƽºâ״̬£¬ÆäÖм×ÈÝÆ÷ÖÐAµÄÎïÖʵÄÁ¿Îª0.4mol£®
  ·´Ó¦Ç°¸÷ÎïÖʵÄÎïÖʵÄÁ¿/mol
A B C
¼× 1 3 0
ÒÒ 0 0 2
±û 1.5 4.5 1
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A¡¢ÒÒÖÐ5minÄÚCµÄ·´Ó¦ËÙÂÊΪ0.12mol/£¨L?min£©
B¡¢´ïµ½Æ½ºâʱ£¬¼×ÒÒÁ½ÈÝÆ÷ÖÐCµÄÎïÖʵÄÁ¿°Ù·Öº¬Á¿ÏàµÈ
C¡¢´ïµ½Æ½ºâʱ£¬±ûÖÐAµÄŨ¶ÈÊǼ×ÖеÄ2±¶
D¡¢±ûÖз´Ó¦µÄƽºâ³£Êý´óÓÚ¼×Öз´Ó¦µÄƽºâ³£Êý

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê½­ËÕÊ¡ÉϸԸ߼¶ÖÐѧ¸ß¶þÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨16·Ö£©ÒÔúΪԭÁÏ£¬¾­¹ý»¯Ñ§¼Ó¹¤Ê¹Ãº×ª»¯ÎªÆøÌå¡¢ÒºÌå¡¢¹ÌÌåȼÁÏÒÔ¼°¸÷ÖÖ»¯¹¤²úÆ·µÄ¹¤Òµ½Ðú»¯¹¤¡£
£¨1£©½«Ë®ÕôÆøͨ¹ýºìÈȵÄ̼¼´¿É²úÉúˮúÆø¡£·´Ó¦Îª£º
C(s)£«H2O(g) CO(g)£«H2(g)  ¦¤H=£«131.3 kJ?mol-1£¬
¢Ù¸Ã·´Ó¦ÔÚ³£ÎÂÏ   ×Ô·¢½øÐУ¨Ìî¡°ÄÜ¡±Óë¡°²»ÄÜ¡±£©£»
¢ÚºãΣ¬ÔÚÈÝ»ý¿É±äµÄÃܱÕÈÝÆ÷ÖУ¬½øÐÐÈçÉÏ¿ÉÄæ·´Ó¦¡£Ò»¶Îʱ¼äºó£¬ÏÂÁÐÎïÀíÁ¿²»·¢Éú±ä»¯Ê±£¬ÄܱíÃ÷¸Ã·´Ó¦ÒѴﵽƽºâ״̬µÄÓР  
¢ñ»ìºÏÆøÌåµÄÃܶȣ»              ¢òÈÝÆ÷ÄÚÆøÌåµÄѹǿ£»
¢ó»ìºÏÆøÌåµÄ×ÜÎïÖʵÄÁ¿£»       ¢ôCOÎïÖʵÄÁ¿Å¨¶È
A£®Ö»ÓТô    B£®Ö»ÓТñºÍ¢ô  C£®Ö»ÓТòºÍ¢ó  D£®¢ñ¡¢¢óºÍ¢ô    
£¨2£©Ë®ÃºÆøÔÙ½øÒ»²½·´Ó¦¿ÉÖÆÈ¡ÇâÆø¡£·´Ó¦ÎªH2O(g)+CO(g) H2(g)+CO2(g)£¬Ä³Î¶Èϸ÷´Ó¦µÄƽºâ³£ÊýK= 4/9¡£¸ÃζÈÏÂÔڼס¢ÒÒ¡¢±ûÈý¸öºãÈÝÃܱÕÈÝÆ÷ÖУ¬Ö»Í¶ÈëH2(g)ºÍCO2(g)£¬ÆäÆðʼŨ¶ÈÈçϱíËùʾ¡£ÏÂÁÐÅжϲ»ÕýÈ·µÄÊÇ   ¡£

ÆðʼŨ¶È
¼×
ÒÒ
±û
c(H2)/mol/L
0.010
0.020
0.020
c(CO2)/mol/L
0.010
0.010
0.020
 
A£®·´Ó¦¿ªÊ¼Ê±£¬±ûÖеķ´Ó¦ËÙÂÊ×î¿ì£¬¼×Öеķ´Ó¦ËÙÂÊ×îÂý
B£®Æ½ºâʱ£¬¼×ÖкͱûÖУÈ2µÄת»¯ÂʾùÊÇ60£¥
C£®Æ½ºâʱ£¬±ûÖУã(CO2)ÊǼ×ÖеÄ2±¶£¬ÊÇ0.012mol/L
D£®Æ½ºâʱ£¬ÒÒÖÐCO2µÄת»¯ÂÊ´óÓÚ60%
£¨3£©Ä¿Ç°¹¤ÒµÉÏÓÐÒ»ÖÖ·½·¨ÊÇÓÃCO2À´Éú²ú¼×´¼¡£Ò»¶¨Ìõ¼þÏ·¢Éú·´Ó¦£ºCO2(g)£«3H2(g)CH3OH(g)£«H2O(g) £¬ÓÒͼ±íʾ¸Ã·´Ó¦½øÐйý³ÌÖÐÄÜÁ¿(µ¥Î»ÎªkJ?mol¡ª1)µÄ±ä»¯¡£ÔÚÌå»ýΪ1 LµÄºãÈÝÃܱÕÈÝÆ÷ÖУ¬³äÈë1mol CO2ºÍ3mol H2·´Ó¦

¢ÙÏÂÁдëÊ©ÖÐÄÜʹc (CH3OH)Ôö´óµÄÊÇ   ¡£
A£®Éý¸ßζȠ    
B£®³äÈëHe(g)£¬Ê¹ÌåϵѹǿÔö´ó
C£®½«H2O(g)´ÓÌåϵÖзÖÀë³öÀ´   
D£®ÔÙ³äÈë1mol CO2ºÍ3mol H2
¢ÚÔÚζÈT1ʱ£¬µ±·´Ó¦´ïµ½Æ½ºâʱ£¬²âµÃn(H2) =" 2.4" mol£»ÆäËüÌõ¼þ²»±ä£¬ÔÚζÈT2ʱ£¬µ±·´Ó¦´ïµ½Æ½ºâʱ£¬²âµÃn(CO2) =" 0.82" mol£¬ÔòT2    T1¡££¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°£½¡±£©£¬
£¨4£©ÔÚÒ»¶¨Ìõ¼þÏ¿Æѧ¼Ò´ÓÑ̵ÀÆøÖзÖÀë³öCO2ÓëÌ«ÑôÄܵç³Øµç½âË®²úÉúµÄH2ºÏ³É¼×´¼¡£CH3OH¡¢H2µÄȼÉÕÈÈ·Ö±ðΪ£º¡÷H£½£­725.5kJ/mol¡¢¡÷H£½£­285.8kJ/mol¡£
¢Ùд³ö¹¤ÒµÉÏÒÔCO2¡¢H2ºÏ³ÉCH3OHºÍҺ̬ˮµÄÈÈ»¯Ñ§·½³Ìʽ£º   £»
¢Ú¸Ãת»¯µÄ»ý¼«ÒâÒåÊÇ   £»
¢ÛÓÐÈËÌá³ö£¬¿ÉÒÔÉè¼Æ·´Ó¦CO2£½C£«O2£¨¡÷H£¾0¡¢¡÷S£¼0£©À´Ïû³ýCO2¶Ô»·¾³µÄÓ°Ïì¡£ÇëÄãÅжÏÊÇ·ñ¿ÉÐв¢Ëµ³öÀíÓÉ£º   

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêºþ±±¾£ÃŸ߶þÉÏѧÆÚÆÚÄ©½ÌѧÖÊÁ¿¼ì²â»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

¹¤ÒµÉÏͨ³£ÔÚºãÈÝÃܱÕÈÝÆ÷ÖвÉÓÃCO(g)ºÍH2 (g)·´Ó¦´ß»¯ºÏ³É¼×´¼CH3OH(g)£º
£¨1£©ÒÑÖª£º¢Ù 2CO(g) + O2 (g) = 2CO2 (g) ¦¤H =" -566.0" kJ¡¤mol-1
¢Ú 2H2(g) + O2 (g) ="2" H2O (g) ¦¤H =" -398.0" kJ¡¤mol-1
¢Û2CH3OH(g) +3O2 (g) =2CO2 (g) +4 H2O(g) ¦¤H =" -1104.0" kJ¡¤mol-1
ÔòCO(g)ÓëH2(g)ºÏ³ÉCH3OH(g)µÄÈÈ»¯Ñ§·½³ÌʽÊÇ_______________¡£
£¨2£©¾ÝÑо¿£¬·´Ó¦¹ý³ÌÖÐÆð´ß»¯×÷ÓõÄΪCuO£¬·´Ó¦ÌåϵÖк¬ÉÙÁ¿CO2ÓÐÀûÓÚά³Ö´ß»¯¼ÁCuOµÄÁ¿²»±ä£¬Ô­ÒòÊÇ£º_______________________________ (Óû¯Ñ§·½³Ìʽ±íʾ)¡£
£¨3£©ÅжϷ´Ó¦´ïµ½Æ½ºâ״̬µÄÒÀ¾ÝÊÇ£¨Ìî×ÖĸÐòºÅ£¬ÏÂͬ£©__________¡£
A. »ìºÏÆøÌåµÄÃܶȲ»±ä
B. »ìºÏÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»±ä
C. CH3OH(g)¡¢CO(g)¡¢H2(g)µÄŨ¶È¶¼²»ÔÙ·¢Éú±ä»¯
D.Éú³ÉCH3OH(g)µÄËÙÂÊÓëÏûºÄCO(g)µÄËÙÂÊÏàµÈ
£¨4£©Ï±íËùÁÐÊý¾ÝÊÇ·´Ó¦ÔÚ²»Í¬Î¶ÈϵĻ¯Ñ§Æ½ºâ³£Êý£¨K£©¡£

ζÈ
250¡æ
300¡æ
350¡æ
K
2.041
0.250
0.012
ijζÈÏ£¬½«2molCO(g)ºÍ6mol H2(g)³äÈë2LµÄÃܱÕÈÝÆ÷ÖУ¬³ä·Ö·´Ó¦ºó£¬´ïµ½Æ½ºâʱ²âµÃc(CO)=0.5mol/L£¬ÔòCO(g)µÄת»¯ÂÊΪ________£¬´ËʱµÄζÈΪ__________¡£
£¨5£©ÒªÌá¸ßCO(g)µÄת»¯ÂÊ£¬¿ÉÒÔ²ÉÈ¡µÄ´ëÊ©ÊÇ__________¡£
A. Éý¸ßζȠ        B. ¼ÓÈë´ß»¯¼Á         C. Ôö¼ÓCO(g)µÄŨ¶È
D. ¼ÓÈëH2(g)¼Óѹ    E. ·ÖÀë³ö¼×´¼         F.¼ÓÈë¶èÐÔÆøÌå¼Óѹ
£¨6£©Ò»¶¨Ìõ¼þÏ£¬ÔÚÈÝ»ýÏàͬµÄÈý¸öÃܱÕÈÝÆ÷ÖУ¬°´²»Í¬·½Ê½Í¶Èë·´Ó¦Î±£³ÖºãΡ¢ºãÈÝ£¬²âµÃ·´Ó¦´ïµ½Æ½ºâʱµÄÓйØÊý¾ÝÈçÏ£º
ÈÝÆ÷
¼×
ÒÒ
±û
·´Ó¦ÎïͶÈëÁ¿
1molCO  2molH2
1molCH3OH
2molCH3OH
ƽºâÊý¾Ý
CH3OHµÄŨ¶È£¨mol/L£©
c 1
c 2
c 3
·´Ó¦µÄÄÜÁ¿±ä»¯µÄ¾ø¶ÔÖµ(kJ)
a
b
c
Ìåϵѹǿ£¨Pa£©
P1
P2
P3
·´Ó¦Îïת»¯ÂÊ
¦Á1
¦Á2
¦Á3
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ__________¡£
A. 2c1>c3             B.  a+b=129         C.  2p2<p3          D. ¦Á1+¦Á3<1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê½­ËÕÊ¡¸ßÈýÏÂѧÆÚÖÊÁ¿¼ì²â£¨Èý£©»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÔÚÈý¸ö2LºãÈݵÄÈÝÆ÷ÖУ¬·Ö±ð·¢Éú·´Ó¦A(g)+3B(g)2C(g)£¬5minºó¸÷ÈÝÆ÷·´Ó¦´ïƽºâ״̬,ÆäÖм×ÈÝÆ÷ÖÐAµÄÎïÖʵÄÁ¿Îª0.4mol¡£

 

·´Ó¦Ç°¸÷ÎïÖʵÄÎïÖʵÄÁ¿/mol

A

B

C

¼×

1

3

0

ÒÒ

0

0

2

±û

1.5

4.5

1

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨     £©

A£®ÒÒÖÐ5minÄÚCµÄ·´Ó¦ËÙÂÊΪ0.12mol/(L¡¤min)

B£®´ïµ½Æ½ºâʱ£¬±ûÖÐAµÄŨ¶ÈÊǼ×ÖеÄ2±¶

C£®±ûÖз´Ó¦µÄƽºâ³£Êý´óÓÚ¼×Öз´Ó¦µÄƽºâ³£Êý

D£® ´ïµ½Æ½ºâʱ£¬¼×ÒÒÁ½ÈÝÆ÷ÖÐCµÄÎïÖʵÄÁ¿°Ù·Öº¬Á¿ÏàµÈ

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸