ÏÖÓÐ0.1 mol¡¤L-1µÄAlCl3ÈÜÒººÍ0.1 mol¡¤L-1µÄNaOHÈÜÒº£¬½øÐÐÏÂÃæµÄʵÑé¡£

(1)ÔÚÊÔ¹ÜÖÐÊ¢ÓÐÉÏÊöAlCl3ÈÜÒº10 mL£¬ÏòÆäÖÐÖð½¥µÎÈëÉÏÊöµÄNaOHÈÜÒº¡£

¢Ù¼ÓÈë10 mL NaOHÈÜҺʱµÄÏÖÏóÊÇ___________£»¼ÓÈë30 mL NaOHÈÜҺʱµÄÏÖÏóÊÇ___________£»¼ÓÈë35 mL NaOHÈÜҺʱµÄÏÖÏóÊÇ___________¡£

¢ÚÉú³É³ÁµíÖÊÁ¿×î¶àʱ£¬ÐèNaOHÈÜÒº___________mL¡£

(2)ÏòÊ¢ÓÐ10 mL NaOHÈÜÒºµÄÊÔ¹ÜÖеÎÈëAlCl3ÈÜÒº£¬Í¬Ê±²»Í£Ò¡¶¯ÊԹܣ¬³öÏÖµÄÏÖÏóÊÇ___________£¬ÖÁ¼ÓÈë___________mL AlCl3ÈÜҺʱ¿ªÊ¼³öÏÖ³Áµí£¬ÖÁ¼ÓÈë___________mL AlCl3ÈÜҺʹ³Áµí´ï×î´óÖµ¡£Ð´³öÉÏÊö¹ý³ÌµÄÀë×Ó·½³Ìʽ_______________________________¡£

½âÎö£ºÏòAlCl3ÈÜÒºÖð½¥¼ÓÈëNaOHÈÜÒºµÄÏÖÏóÊÇÖð½¥Éú³É°×É«½º×´³Áµí£¬ÖÁNaOHÈÜÒº¹ýÁ¿Ê±£¬³ÁµíÖð½¥Èܽ⡣ÓÉÀë×Ó·½³ÌʽAl3++3OH-Al(OH)3¡ýµÄÁ¿µÄ¹Øϵ¿ÉÖª£¬µ±¼ÓÈë30 mL NaOHÓÚ10 mLͬŨ¶ÈAlCl3ÈÜÒºÖÐÎö³ö³ÁµíÁ¿´ï×î´óÖµ£¬ÓÖÓÉAl(OH)3+OH- +2H2OÀë×Ó·½³Ìʽ¿ÉÖª£¬ÔÙ¼Ó10 mL´ËNaOHÈÜÒº£¬³ÁµíÍêÈ«Èܽ⣬¼´ÓÃÈ¥×ÜÁ¿40 mLµÄNaOH£¬ÔòAl3+Íêȫת»¯Îª¡£·ûºÏ×ÜÀë×Ó·½³ÌʽAl3++4OH-+2H2O¡£Òò´ËÔÚ¼Ó35 mL NaOHʱ£¬³Áµí½öÈÜÈ¥Ò»°ë¡£

    ÏòNaOHÈÜÒºÖв»¶Ï¼ÓÈëAlCl3ÈÜҺʱ£¬¿ªÊ¼¿´²»³ö³Áµí¡²Al3++3OH-Al(OH)3¡ý¡³£¬Òò´Ëʱ¼îÒº¹ýÁ¿£¬Al(OH)3Á¢¿ÌÈÜÓÚÖÜΧ¼îÒºÖжø³ÉNaAlO2¡£ÓÉAl3++4OH-+2H2O¿ÉÖª£¬ÓÃ0.1 mol¡¤L-1µÄAlCl3ÈÜÒº´ïµ½0.1 mol¡¤L-1 NaOHÈÜÒºÌå»ýµÄ1/4ʱ£¬Ô­NaOHµÄOH-ºÄ¾¡¡£ÈÜÒºÖÐAl3+ȫתΪ¡£ËùÒÔ(2)ÖÐÓÃ10/4 mL(2.5 mL)AlCl3ʱ£¬OH-ÔÚ¼îÖÐÒÑÏûºÄÍê¡£´ËºóÔÙ¼ÓAlCl3£¬Ôò½øÐÐÏÂÃæ·´Ó¦£º6H2O+Al3++34Al(OH)3¡ý

    ¿ÉÖªAlCl3ÈÜÒº¸Õ³¬¹ý2.5 mL¾ÍÓгÁµíÉú³É¡£ÖÁ·ûºÏÔ­Àë×Ó·½³ÌʽAl3++3OH- Al(OH)3¡ýʱ£¬³Áµí×î¶à£¬¼´10/3 mL AlCl3¼ÓÈëºó£¬³Áµí´ï×î´óÖµ¡£

´ð°¸£º(1)¢ÙÖð½¥Éú³É°×É«½º×´³Á×´  ³ÁµíÁ¿´ïµ½×î´óÖµ  ³Áµí½öÈÜÈ¥Ò»°ë  ¢Ú20

(2)¿ªÊ¼¿´²»³öÓгÁµí  2.5  10/3

Al3++3OH-Al(OH)3¡ý

Al3++4OH-+2H2O

6H2O+Al3++34Al(OH)3¡ý


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÖÓÐ0.1 mol¡¤L-1µÄAlCl3ÈÜÒººÍ0.1 mol¡¤L-1µÄÇâÑõ»¯ÄÆÈÜÒº£¬½øÐÐÏÂÃæµÄʵÑé¡£?

£¨1£©ÔÚÊÔ¹ÜÖÐÊ¢ÓÐÉÏÊöAlCl3ÈÜÒº10 mL£¬ÏòÆäÖÐÖð½¥µÎÈëÉÏÊöµÄNaOHÈÜÒº¡£?

¢Ù¼ÓÈë10 mL NaOHÈÜҺʱµÄÏÖÏóÊÇ__________________£¬¼ÓÈë30 mL NaOHÈÜҺʱµÄÏÖÏóÊÇ___________________£¬¼ÓÈë35 mL NaOHÈÜҺʱµÄÏÖÏóÊÇ____________¡£?

¢ÚÉú³É³ÁµíÖÊÁ¿×î¶àʱ£¬ÐèNaOHÈÜÒº_________mL¡£?

£¨2£©ÏòÊ¢ÓÐ10 mL NaOHÈÜÒºµÄÊÔ¹ÜÖеÎÈëAlCl3ÈÜÒº£¬Í¬Ê±²»Í£Ò¡¶¯ÊԹܣ¬³öÏÖµÄÏÖÏóÊÇ__________________£¬ÖÁ¼ÓÈë¶àÉÙºÁÉýAlCl3ÈÜҺʱ¿ªÊ¼³öÏÖ³Áµí£¿_______________£¬ÖÁ¼ÓÈë¶àÉÙºÁÉýAlCl3ÈÜҺʱ³ÁµíÁ¿×î¶à£¿____________¡£?

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(1)ÏÖÓÐ0.1 mol¡¤L-1µÄ´¿¼îÈÜÒº£¬ÊÔÓÃpHÊÔÖ½²â¶¨ÈÜÒºµÄpH£¬ÆäÕýÈ·µÄ²Ù×÷ÊÇ___________________£»´¿¼îÈÜÒº³Ê¼îÐÔµÄÔ­ÒòÊÇ_________________(ÓÃÀë×Ó·½³Ìʽ±íʾ)¡£

(2)Ϊ̽¾¿´¿¼îÈÜÒº³Ê¼îÐÔÊÇÓÉÒýÆðµÄ£¬ÇëÄãÉè¼Æ¡ª¸ö¼òµ¥µÄʵÑé·½°¸£º___________¡£

(3)Ϊ֤Ã÷ÑεÄË®½âÊÇÎüÈÈ·´Ó¦£¬ËÄλѧÉú·Ö±ðÉè¼ÆÈçÏ·½°¸£¬ÆäÖÐÕýÈ·µÄÊÇ£¨    £©

A.¼×ѧÉú£ºÔÚ´×ËáÄÆÈÜÒºÖеÎÈë2µÎ·Ó̪£¬¼ÓÈȺóºìÉ«¼ÓÉ˵Ã÷ÑÎÀàË®½âÊÇÎüÈÈ·´Ó¦

B.ÒÒѧÉú£ºÔÚÑÎËáÖмÓÈ백ˮ£¬»ìºÏҺζÈÉÏÉý£¬ËµÃ÷ÑÎÀàË®½âÊÇÎüÈÈ·´Ó¦

C.±ûѧÉú£º½«ÏõËá茶§ÌåÈÜÓÚË®£¬Ë®ÎÂϽµ£¬ËµÃ÷ÑÎÀàË®½âÊÇÎüÈÈ·´Ó¦

D.¶¡Ñ§Éú£ºÔÚ°±Ë®ÖмÓÈëÂÈ»¯ï§¹ÌÌ壬ÈÜÒºµÄpH±äС£¬ËµÃ÷ÑÎÀàË®½âÊÇÎüÈÈ·´Ó¦

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

10·Ö£©£¨1£©ÏÖÓÐ0.1 mol¡¤L-1µÄ´¿¼îÈÜÒº£¬ÊÔÓÃpHÊÔÖ½²â¶¨ÈÜÒºµÄpH,ÕýÈ·µÄ²Ù×÷ÊÇ __________¡£´¿¼îÈÜÒº³Ê¼îÐÔµÄÔ­Òò£¨ÓÃÀë×Ó·½³Ìʽ±íʽ£©ÊÇ__________£¬ÄãÈÏΪ¸ÃÈÜÒºpHµÄ·¶Î§Ò»¶¨½éÓÚ__________Ö®¼ä¡£

£¨2£©ÎªÌ½¾¿´¿¼îÈÜÒº³Ê¼îÐÔÊÇÓÉÒýÆðµÄ£¬ÇëÉè¼ÆÒ»¸ö¼òµ¥µÄʵÑé·½°¸¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêɽ¶«Ê¡Ý·ÏØʵÑé¸ßÖи߶þ12ÔÂÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

(8·Ö)(1)ÏÖÓÐ0.1 mol¡¤L£­1µÄ´¿¼îÈÜÒº£¬ÊÔÓÃpHÊÔÖ½²â¶¨ÈÜÒºµÄpH£¬ÆäÕýÈ·µÄ²Ù×÷ÊÇ________________________________________________________________________
________________________________________________________________________________________________________________________________________________£»
´¿¼îÈÜÒº³Ê¼îÐÔµÄÔ­ÒòÊÇ(ÓÃÀë×Ó·½³Ìʽ±íʾ)__________________________________ ______________________________________¡£
(2)Ϊ̽¾¿´¿¼îÈÜÒº³Ê¼îÐÔÊÇÓÉCO32£­ÒýÆðµÄ£¬ÇëÄãÉè¼ÆÒ»¸ö¼òµ¥µÄʵÑé·½°¸£º________ ________________________________________¡£
(3)Ϊ֤Ã÷ÑεÄË®½âÊÇÎüÈÈ·´Ó¦£¬ËÄλѧÉú·Ö±ðÉè¼ÆÁËÈçÏ·½°¸£¬ÆäÖÐÕýÈ·µÄÊÇ________¡£

A£®¼×ѧÉú£ºÔÚ´×ËáÄÆÈÜÒºÖеÎÈë2µÎ·Ó̪£¬¼ÓÈȺóºìÉ«¼ÓÉ˵Ã÷ÑÎÀàË®½âÊÇÎüÈÈ·´Ó¦
B£®ÒÒѧÉú£ºÔÚÑÎËáÖмÓÈ백ˮ£¬»ìºÏҺζÈÉÏÉý£¬ËµÃ÷ÑÎÀàË®½âÊÇÎüÈÈ·´Ó¦
C£®±ûѧÉú£º½«ÏõËá茶§ÌåÈÜÓÚË®£¬Ë®ÎÂϽµ£¬ËµÃ÷ÑÎÀàË®½âÊÇÎüÈÈ·´Ó¦
D£®¶¡Ñ§Éú£ºÔÚ°±Ë®ÖмÓÈëÂÈ»¯ï§¹ÌÌ壬ÈÜÒºµÄpH±äС£¬ËµÃ÷ÑÎÀàË®½âÊÇÎüÈÈ·´Ó¦

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012Ä곿ưæ¸ßÖл¯Ñ§Ñ¡ÐÞ6 4ÄðÖÆÃ×¾ÆÁ·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ijϡNaOHÈÜÒºµÄŨ¶È´óÔ¼ÔÚ0.07¡«0.08 mol¡¤L£­1Ö®¼ä£¬ÊµÑéÊÒÏÖÓТÙ0.1 mol¡¤L£­1¡¢¢Ú1.0 mol¡¤L£­1¡¢¢Û5.0 mol¡¤L£­1µÄÈýÖÖ±ê×¼ÑÎËáÈÜÒº£¬ÈôҪͨ¹ýÖк͵ζ¨·¨È·¶¨NaOHµÄ׼ȷŨ¶È£¬ÔòӦѡÓõıê×¼ÑÎËáÈÜÒºÊÇ(¡¡¡¡)

A£®¢Ù                                   B£®¢Ú

C£®¢Û                                   D£®¢Ù¢Ú¢Û¾ù¿É

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸