ÒÑÖª25¡æʱ£¬µçÀë³£ÊýKa(HF)=3.6¡Á10-4 £¬ÈܶȻý³£ÊýKsp(CaF2) =1. 46¡Á10 -10¡£ÏÖÏò1L 0.2mol¡¤L-1 HFÈÜÒºÖмÓÈë1L0.2mol¡¤L-1 CaCl2ÈÜÒº£¬ÔòÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ
[     ]
A£®25¡æʱ£¬0.1mol¡¤L-1HFÈÜÒºÖÐpH=1
B£®Ksp(CaF2)ËæζȺÍŨ¶ÈµÄ±ä»¯¶ø±ä»¯
C£®¸ÃÌåϵÖÐÓÐCaF2³Áµí²úÉú
D£®¸ÃÌåϵÖУ¬
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?Ôæׯ¶þÄ££©ÎïÖÊÔÚË®ÈÜÒºÖеÄÐÐΪÊÇÖÐѧ»¯Ñ§µÄÖØÒªÄÚÈÝ£®ÒÑÖªÏÂÁÐÎïÖʵĵçÀë³£ÊýÖµ£¨25¡æ£©£º
HClO£ºKa=3¡Á10-8£¬HCN£ºKa=4.9¡Á10-10
H2CO3£ºKa1=4.3¡Á10-7£¬Ka2=5.6¡Á10-11
£¨1£©84Ïû¶¾ÒºÖÐͨÈëÉÙÁ¿µÄCO2£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
NaClO+CO2+H2O¨THClO+NaHCO3
NaClO+CO2+H2O¨THClO+NaHCO3
£®
£¨2£©25¡æʱ£¬µÈÎïÖʵÄÁ¿Å¨¶ÈµÄ¢ÙNaClOÈÜÒº£»¢ÚNa2CO3ÈÜÒº£»¢ÛNaCNÈÜÒº£¬ÈýÈÜÒºµÄpHÓÉ´óµ½Ð¡µÄ˳ÐòΪ
¢Ú£¾¢Û£¾¢Ù
¢Ú£¾¢Û£¾¢Ù
£¨ÌîÐòºÅ£©£®
£¨3£©µÈÎïÖʵÄÁ¿NaClOºÍNaHCO3µÄ»ìºÏÒºÖУ¬¸÷΢Á£Å¨¶ÈµÄ¹ØϵΪ£º[Na+]=
[Na+]=[ClO-]+[HClO]+[HCO3-]+[HCO32-]
[Na+]=[ClO-]+[HClO]+[HCO3-]+[HCO32-]
+[H2CO3]
£¨4£©ÊµÑéÊÒ¿ÉÓÃÈçͼËùʾװÖÃÖƱ¸84Ïû¶¾Òº£¬ÔòaΪ
¸º
¸º
¼«£¬ÖƱ¸¹ý³ÌÖÐ×ܵÄÀë×Ó·´Ó¦·½³ÌʽΪ
Cl-+H2O
 µç½â 
.
 
ClO-+H2¡ü
Cl-+H2O
 µç½â 
.
 
ClO-+H2¡ü
£®
£¨5£©25¡æʱx mol?L-1CH3COOHÈÜÒºÓë0.01mol?L-1 NaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ÈÜÒºÏÔÖÐÐÔ£¬Ôò[CH3COO-]
=
=
[Na+]£¨Ñ¡Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£¬Óú¬xµÄ´úÊýʽ±íʾCH3COOHµÄµçÀëƽºâ³£ÊýKa=
10-9
x-10-2
10-9
x-10-2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄ긣½¨Ê¡ÕÄÖÝÊÐܼ³ÇÖÐѧ¸ß¶þÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

°´ÒªÇó»Ø´ð£º
£¨1£©Ð´³öµçÀë·½³Ìʽ£º
NaHCO3_______________________________________________________________________
H2S__________________________________________________________________________
£¨2£©Ð´³öË®½âµÄÀë×Ó·½³Ìʽ£º
Na2CO3________________________________________________________________________
£¨3£©ÓÃpHÊÔÖ½²â¶¨0.1 mol¡¤L£­1µÄ´¿¼îÈÜÒºµÄpH£¬ÆäÕýÈ·µÄ²Ù×÷ÊÇ
__________________________________________________________________________________¡£
£¨4£©ÂÈ»¯ÂÁË®ÈÜÒº³Ê       ÐÔ£¨ÌîËáÐÔ¡¢ÖÐÐÔ¡¢¼îÐÔ£©£¬Ô­ÒòÊÇ£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£º_____________________            _______________________________________________ ______ ¡£°ÑFeCl3ÈÜÒºÕô¸É£¬×ÆÉÕ£¬×îºóµÃµ½µÄÖ÷Òª¹ÌÌå²úÎïÊÇ                    ¡£
£¨5£©ÊµÑéÊÒÔÚÅäÖÆAgNO3µÄÈÜҺʱ£¬³£½«AgNO3¹ÌÌåÏÈÈÜÓÚ½ÏŨµÄÏõËáÖУ¬È»ºóÔÙÓÃÕôÁóˮϡÊ͵½ËùÐèµÄŨ¶È£¬ÒÔ            £¨Ìî¡°´Ù½ø¡±¡¢¡°ÒÖÖÆ¡±£©Ag+Ë®½â¡£
£¨6£©ÔÚ25¡æÏ£¬½«a mol¡¤L£­1µÄ°±Ë®Óë0.01 mol¡¤L£­1µÄÑÎËáµÈÌå»ý»ìºÏ£¬³ä·Ö·´Ó¦ºóÈÜÒº³ÊÖÐÐÔ£¬Ôò·´Ó¦ºóÈÜÒº´æÔÚµÄÀë×ÓÓР                               £¬ÆäŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ
                                  £¬°±Ë®µÄŨ¶Èa      0.01 mol¡¤L£­1£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©¡£
£¨7£©ÔÚ25¡æÏ£¬ÏòŨ¶È¾ùΪ0.20 mol¡¤L£­1µÄMgCl2ºÍCuCl2»ìºÏÈÜÒºÖÐÖðµÎ¼ÓÈ백ˮ£¬ÏÈÉú³É        ³Áµí£¨Ìѧʽ£©£¬Éú³É¸Ã³ÁµíµÄÀë×Ó·½³ÌʽΪ                           £»µ±²âµÃÈÜÒºpH=11ʱ£¬Ôò´ËζÈϲÐÁôÔÚÈÜÒºÖеÄc(Mg2+)£ºc(Cu2+)=            £¨ÒÑÖª25¡æʱKsp[Mg(OH)2]=1.8¡Á10£­11£¬Ksp[Cu(OH)2]=2.0¡Á10£­20£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ì¸£½¨Ê¡ÕÄÖÝÊи߶þÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

°´ÒªÇó»Ø´ð£º

£¨1£©Ð´³öµçÀë·½³Ìʽ£º

NaHCO3_______________________________________________________________________

H2S__________________________________________________________________________

£¨2£©Ð´³öË®½âµÄÀë×Ó·½³Ìʽ£º

Na2CO3________________________________________________________________________

£¨3£©ÓÃpHÊÔÖ½²â¶¨0.1 mol¡¤L£­1µÄ´¿¼îÈÜÒºµÄpH£¬ÆäÕýÈ·µÄ²Ù×÷ÊÇ

__________________________________________________________________________________¡£

£¨4£©ÂÈ»¯ÂÁË®ÈÜÒº³Ê       ÐÔ£¨ÌîËáÐÔ¡¢ÖÐÐÔ¡¢¼îÐÔ£©£¬Ô­ÒòÊÇ£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£º_____________________            _______________________________________________ ______ ¡£°ÑFeCl3ÈÜÒºÕô¸É£¬×ÆÉÕ£¬×îºóµÃµ½µÄÖ÷Òª¹ÌÌå²úÎïÊÇ                    ¡£

£¨5£©ÊµÑéÊÒÔÚÅäÖÆAgNO3µÄÈÜҺʱ£¬³£½«AgNO3¹ÌÌåÏÈÈÜÓÚ½ÏŨµÄÏõËáÖУ¬È»ºóÔÙÓÃÕôÁóˮϡÊ͵½ËùÐèµÄŨ¶È£¬ÒÔ            £¨Ìî¡°´Ù½ø¡±¡¢¡°ÒÖÖÆ¡±£©Ag+Ë®½â¡£

£¨6£©ÔÚ25¡æÏ£¬½«a mol¡¤L£­1µÄ°±Ë®Óë0.01 mol¡¤L£­1µÄÑÎËáµÈÌå»ý»ìºÏ£¬³ä·Ö·´Ó¦ºóÈÜÒº³ÊÖÐÐÔ£¬Ôò·´Ó¦ºóÈÜÒº´æÔÚµÄÀë×ÓÓР                               £¬ÆäŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ

                                  £¬°±Ë®µÄŨ¶Èa      0.01 mol¡¤L£­1£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©¡£

£¨7£©ÔÚ25¡æÏ£¬ÏòŨ¶È¾ùΪ0.20 mol¡¤L£­1µÄMgCl2ºÍCuCl2»ìºÏÈÜÒºÖÐÖðµÎ¼ÓÈ백ˮ£¬ÏÈÉú³É        ³Áµí£¨Ìѧʽ£©£¬Éú³É¸Ã³ÁµíµÄÀë×Ó·½³ÌʽΪ                           £»µ±²âµÃÈÜÒºpH=11ʱ£¬Ôò´ËζÈϲÐÁôÔÚÈÜÒºÖеÄc(Mg2+)£ºc(Cu2+)=            £¨ÒÑÖª25¡æʱKsp[Mg(OH)2]=1.8¡Á10£­11£¬Ksp[Cu(OH)2]=2.0¡Á10£­20£©

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÔæׯ¶þÄ£ ÌâÐÍ£ºÎÊ´ðÌâ

ÎïÖÊÔÚË®ÈÜÒºÖеÄÐÐΪÊÇÖÐѧ»¯Ñ§µÄÖØÒªÄÚÈÝ£®ÒÑÖªÏÂÁÐÎïÖʵĵçÀë³£ÊýÖµ£¨25¡æ£©£º
HClO£ºKa=3¡Á10-8£¬HCN£ºKa=4.9¡Á10-10
H2CO3£ºKa1=4.3¡Á10-7£¬Ka2=5.6¡Á10-11
£¨1£©84Ïû¶¾ÒºÖÐͨÈëÉÙÁ¿µÄCO2£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£®
£¨2£©25¡æʱ£¬µÈÎïÖʵÄÁ¿Å¨¶ÈµÄ¢ÙNaClOÈÜÒº£»¢ÚNa2CO3ÈÜÒº£»¢ÛNaCNÈÜÒº£¬ÈýÈÜÒºµÄpHÓÉ´óµ½Ð¡µÄ˳ÐòΪ______£¨ÌîÐòºÅ£©£®
£¨3£©µÈÎïÖʵÄÁ¿NaClOºÍNaHCO3µÄ»ìºÏÒºÖУ¬¸÷΢Á£Å¨¶ÈµÄ¹ØϵΪ£º[Na+]=______+[H2CO3]
£¨4£©ÊµÑéÊÒ¿ÉÓÃÈçͼËùʾװÖÃÖƱ¸84Ïû¶¾Òº£¬ÔòaΪ______¼«£¬ÖƱ¸¹ý³ÌÖÐ×ܵÄÀë×Ó·´Ó¦·½³ÌʽΪ______£®
£¨5£©25¡æʱx mol?L-1CH3COOHÈÜÒºÓë0.01mol?L-1 NaOHÈÜÒºµÈÌå»ý»ìºÏ£¬ÈÜÒºÏÔÖÐÐÔ£¬Ôò[CH3COO-]______[Na+]£¨Ñ¡Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£¬Óú¬xµÄ´úÊýʽ±íʾCH3COOHµÄµçÀëƽºâ³£ÊýKa=______£®
¾«Ó¢¼Ò½ÌÍø

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012Äêɽ¶«Ê¡ÔæׯÊи߿¼»¯Ñ§¶þÄ£ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

ÎïÖÊÔÚË®ÈÜÒºÖеÄÐÐΪÊÇÖÐѧ»¯Ñ§µÄÖØÒªÄÚÈÝ£®ÒÑÖªÏÂÁÐÎïÖʵĵçÀë³£ÊýÖµ£¨25¡æ£©£º
HClO£ºKa=3×10-8£¬HCN£ºKa=4.9×10-10
H2CO3£ºKa1=4.3×10-7£¬Ka2=5.6×10-11
£¨1£©84Ïû¶¾ÒºÖÐͨÈëÉÙÁ¿µÄCO2£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£®
£¨2£©25¡æʱ£¬µÈÎïÖʵÄÁ¿Å¨¶ÈµÄ¢ÙNaClOÈÜÒº£»¢ÚNa2CO3ÈÜÒº£»¢ÛNaCNÈÜÒº£¬ÈýÈÜÒºµÄpHÓÉ´óµ½Ð¡µÄ˳ÐòΪ______£¨ÌîÐòºÅ£©£®
£¨3£©µÈÎïÖʵÄÁ¿NaClOºÍNaHCO3µÄ»ìºÏÒºÖУ¬¸÷΢Á£Å¨¶ÈµÄ¹ØϵΪ£º[Na+]=______+[H2CO3]
£¨4£©ÊµÑéÊÒ¿ÉÓÃÈçͼËùʾװÖÃÖƱ¸84Ïû¶¾Òº£¬ÔòaΪ______¼«£¬ÖƱ¸¹ý³ÌÖÐ×ܵÄÀë×Ó·´Ó¦·½³ÌʽΪ______ ClO-+H2¡ü

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸