£¨10·Ö£©ÊµÑéÊҺϳÉÒÒËáÒÒõ¥È磨ÓÒͼËùʾ£©£¬µÃµ½º¬ÓÐÒÒ´¼¡¢ÒÒËáºÍË®µÄÒÒËáÒÒõ¥´Ö²úÆ·¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺£¨ÒÑÖª£ºÒÒ´¼¡¢ÒÒËá¡¢ÒÒËáÒÒõ¥µÄ·ÐµãÒÀ´ÎÊÇ
£¨78.5¡æ¡¢118¡æ¡¢77.1¡æ£©
      
£¨1£©ÔÚ×ó²àÊÔ¹ÜÖгýÁ˼ÓÈëÒÒ´¼ºÍÒÒËáÍ⣬»¹Ó¦¼ÓÈëµÄÊÔ¼ÁÊÇ           
¸ÃÊÔ¼ÁµÄ×÷ÓÃÊÇ£º¢Ù_____ _ __              ¢Ú_____________    ¡£
£¨2£©·´Ó¦½áÊøºó½«ÓÒ²àµÄÊÔ¹ÜÈ¡Ï£¬Õñµ´¡¢¾²Ö㬹۲쵽µÄÏÖÏóÊÇ
¡£
£¨3£©ÏÖÄâ·ÖÀ뺬ÒÒËá¡¢ÒÒ´¼ºÍË®µÄÒÒËáÒÒõ¥´Ö²úÆ·£¬ÏÂͼÊÇ·ÖÀë²Ù×÷Á÷³Ì£¬
ÇëÔÚͼÖÐÔ²À¨ºÅÄÚÌîÈëÊʵ±µÄÊÔ¼Á£¬ÔÚ·½À¨ºÅÄÚÌîÈëÊʵ±µÄ·ÖÀë·½·¨¡£
ÊÔ¼ÁaÊÇ__________£¬bÊÇ_______________£»
·ÖÀë·½·¨¢ÙÊÇ__________£¬¢ÚÊÇ______________£¬¢ÛÊÇ_______________¡£
д³öC ¡ú D ·´Ó¦µÄ»¯Ñ§·½³Ìʽ
  
£¨1£©Å¨ÁòËá  ´ß»¯¼Á   ÎüË®¼Á
£¨2£©ÒºÃæÉÏÓÐ͸Ã÷µÄ²»ÈÜÓÚË®µÄÓÍ×´ÒºÌå²úÉú£¬²¢¿ÉÒÔÎŵ½Ïãζ
£¨3£©±¥ºÍ̼ËáÄÆÈÜÒº  Å¨ÁòËá  ·ÖÒº  ÕôÁó   ÕôÁó
2CH3COONa + H2SO4 = Na2SO4 + 2CH3COOH
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

³ýÈ¥ÒÒËáÒÒõ¥ÖÐÉÙÁ¿ÒÒËáµÄ·½·¨ÕýÈ·µÄÊÇ£¨   £©
A£®ÕôÁóB£®¼ÓÒÒ´¼ºó¼ÓÈÈ
C£®¹ýÁ¿±¥ºÍ̼ËáÄÆÈÜҺϴµÓºó·ÖÒºD£®¹ýÁ¿ÇâÑõ»¯ÄÆÈÜҺϴµÓºó·ÖÒº

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

£¨16·Ö£©AÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤Ô­ÁÏ£¬ËüµÄ²úÁ¿¿ÉÒÔºâÁ¿Ò»¸ö¹ú¼ÒʯÓÍ»¯¹¤Ë®Æ½µÄ¸ßµÍ¡£A¡¢B¡¢C¡¢DÔÚÒ»¶¨Ìõ¼þÏ´æÔÚÈçÏÂת»¯¹Øϵ£¨²¿·Ö·´Ó¦Ìõ¼þ¡¢²úÎﱻʡÂÔ£©¡£
 
£¨1£©¹¤ÒµÉÏ£¬ÓÉʯÓÍ»ñµÃʯÀ¯Ó͵ķ½·¨ÊÇ_________£¬ÓÉʯÀ¯ÓÍ»ñµÃAÊÇ________±ä»¯¡£
£¨2£©Ð´³öA¡úBµÄ·´Ó¦·½³Ìʽ£º                                  
¸Ã·´Ó¦µÄÀàÐÍÊÇ____________________
д³ö·´Ó¦B£«C¡úDµÄ»¯Ñ§·½³Ìʽ£º____________________________     
¸Ã·´Ó¦µÄÀàÐÍÊÇ                    ¡£
£¨3£©Ê¹1molAÓëÂÈÆø·¢ÉúÍêÈ«¼Ó³É·´Ó¦£¬È»ºóʹ¸Ã¼Ó³É·´Ó¦µÄ²úÎïÓëÂÈÆøÔÚ¹âÕÕµÄÌõ¼þÏ·¢ÉúÍêÈ«È¡´ú·´Ó¦£¬ÔòÁ½¸ö¹ý³ÌÖÐÏûºÄµÄÂÈÆøµÄ×ܵÄÎïÖʵÄÁ¿ÊÇ           mol 
£¨4£©ÊµÑéÊÒÖƱ¸DµÄʵÑé×°ÖÃͼÈçͼËùʾ£ºÊÕ¼¯²úÎïµÄÊÔ¹ÜÖÐÊ¢·ÅµÄÒºÌåΪ                 £»¸ÃÈÜÒºµÄ×÷ÓÃÓУº

¢Ù³ýµô²úÎïÖеĠ           ºÍ               ÔÓÖÊ£»
¢Ú                                          
£¨5£©ÔÚÖƱ¸ÒÒËáÒÒõ¥¹ý³ÌÖУ¬ÍùÍù¼ÓÈëµÄÒÒËáºÍÒÒ´¼µÄÁ¿Òª±ÈÀíÂÛ¼ÆËãÁ¿¶àµÃ¶à£¬Çë½âÎöÆäÖпÉÄÜ´æÔÚµÄÔ­Òò£º
¢Ù                                                        
¢Ú                                                       

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

£¨13·Ö£©ÈçͼËùʾ£¬ÖÐѧ»¯Ñ§ÊµÑéÊÒ²ÉÓøÃ×°ÖÃÓÃÓÚÖƱ¸ÒÒËáÒÒõ¥¡£

¢Åд³öÖƱ¸ÒÒËáÒÒõ¥µÄ»¯Ñ§·½³Ìʽ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ø¡¡¡¡¡¡¡¡    ¡¡¡¡¡¡¡¡¡¡¡£
¢ÆŨÁòËáÔÚʵÑéÖеÄ×÷ÓÃÊÇ¡¡  ¡ø ¡¡¡¢¡¡  ¡ø ¡¡¡£
¢Ç¼ÓÈÈÒ»¶Îʱ¼äºó£¬ÔÚÊÔ¹ÜB±¥ºÍ̼ËáÄÆÈÜÒºµÄÒºÃæÉÏ·½ÓÐÒ» ²ãÓͲ㣬ÔÚÓÍ¡¢Ë®½»½ç´¦¹Û²ìµ½ÓÐÆøÅݲúÉú£¬ÆøÅݵÄÖ÷Òª³É·ÖÊÇ¡¡  ¡ø¡¡¡¡¡£
¢ÈÍ£Ö¹¼ÓÈÈ£¬È¡ÏÂÊÔ¹ÜB £¬ÐáÎŹÜÄÚÒºÌåÆø棬Îŵ½¸ü¶àµÄÊǴ̼¤ÐÔÆø棬ÕâÊÇÒòΪÎïÖʵĻӷ¢µÈÒòËص¼Ö²úÆ·»ìÓÐÔÓÖÊ£¬Èç¡¡¡¡¡ø¡¡¡¡ºÍ¡¡¡¡¡ø¡¡¡¡µÈ£¬Îª½øÒ»²½ÑéÖ¤²úÎïÖÐijЩÔÓÖÊ´æÔÚ£¬ÔÚ±£³ÖÊÔ¹ÜBÏà¶ÔÎȶ¨Çé¿öÏ£¬ÑØÊÔ¹ÜÄÚ±ÚµÎÈë×ÏɫʯÈïÊÔÒº£¬¾²ÖÃƬ¿Ì»áÔÚÊÔ¹ÜÄÚÓͲãÏ·½Ã÷ÏÔ¿´µ½ÒºÌå³ÊÏÖÈýÖÖÑÕÉ«£¬ÓÉÉ϶øÏ·ֱðΪºìÉ«¡¢×ÏÉ«¡¢À¶É«£¬ÆäÔ­Òò¿ÉÄÜÊÇ¡¡¡¡¡¡     ¡ø¡¡       ¡¡   ¡¡¡¡£¬¹Ê²úÆ·Ðè½øÐÐÌá´¿¡£
¢ÉÒÑÖªÒÒ´¼ÄܺÍÂÈ»¯¸Æ½áºÏ¡£½«ËùµÃ²úÆ·ÒÀ´ÎÓñ¥ºÍ̼ËáÄÆÈÜÒº¡¢±¥ºÍʳÑÎË®¡¢±¥ºÍÂÈ»¯¸ÆÈÜҺϴµÓÓͲ㣬·Ö±ð·ÖÒº¡£Óñ¥ºÍʳÑÎˮϴµÓÈ¥³ýÓͲãÖпÉÄܺ¬ÓеĠ  ¡ø¡¡¡¡ÔÓÖÊ£¬¼õÉÙÒÒËáÒÒõ¥µÄÈܽ⣬²¢·ÀÖ¹¶ÔÏÂÃæ²Ù×÷²úÉú²»ÀûÓ°Ïì¡£
¢ÊÔÚÉÏÊö²Ù×÷ºó£¬ÔÚËùµÃÓÍ×´ÒºÌåÖмÓÈëÎÞË®ÁòËáÄƳä·ÖÕñµ´£¬Çãµ¹³öÓÍ×´ÒºÌ壬ÔÙ½øÐС¡ ¡ø ¡¡(ÌîÌá´¿µÄ²Ù×÷·½·¨)£¬ÊÕ¼¯74¡«78¡æµÄÁó·Ö¼´¿É»ñµÃ½Ï´¿¾»µÄÒÒËáÒÒõ¥¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

¡°¶Ô°±»ù±½¼×Ëᶡõ¥¡±ÊÇ·Àɹ˪ÖÐÄÜÎüÊÕ×ÏÍâÏߵķÀɹ¼Á¡£ÏÂÁйØÓÚ¡°¶Ô°±»ù±½¼×Ëᶡõ¥¡±µÄ˵·¨ÕýÈ·µÄÊÇ£¨   £©
A£®´ÓÓлúÎï·ÖÀà¿´£¬Ëü¿ÉÊôÓÚ¡°°±»ùËáÀࡱ¡°õ¥Àࡱ¡°·¼ÏãÌþÀࡱ
B£®ËüÄÜÓëÑÎËá·´Ó¦£¬Ò²ÄÜÓë¿ÁÐÔÄÆÈÜÒº·´Ó¦
C£®¼×Ëᶡõ¥»ù£¨¡ªCOOC4H9£©ÓÐ3ÖÖ²»Í¬½á¹¹
D£®ËüµÄ·Ö×ÓʽC11H11NO2

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

£¨10·Ö£©Ä³»¯Ñ§Ð¡×é²ÉÓÃÀàËÆÖÆÒÒËáÒÒõ¥µÄ×°Öã¨Èçͼ£©£¬ÒÔ»·¼º´¼ÖƱ¸»·¼ºÏ©
 
£¨1£©ÖƱ¸´ÖÆ·
½«12.5mL»·¼º´¼¼ÓÈëÊÔ¹ÜAÖУ¬ÔÙ¼ÓÈëlmLŨÁòËᣬҡÔȺó·ÅÈëËé´ÉƬ£¬¿ØÖÆˮԡζÈÔÚ85oC×óÓÒ£¬»ºÂý¼ÓÈÈÖÁ·´Ó¦ÍêÈ«£¬ÔÚÊÔ¹ÜCÄڵõ½»·¼ºÏ©´ÖÆ·¡£

¢ÙÉÏÃæµÄÖƱ¸×°ÖÃÖУ¬»¹È±ÉٵIJ£Á§ÒÇÆ÷ÊÇ             £¬µ¼¹ÜB³ýÁ˵¼ÆøÍ⻹¾ßÓеÄ×÷ÓÃÊÇ            ¡£
¢ÚÊÔ¹ÜCÖÃÓÚ±ùˮԡÖеÄÄ¿µÄÊÇ                            ¡£
£¨2)ÖƱ¸¾«Æ·£¨ÓÃÏÂͼ£©
¢Ù»·¼ºÏ©´ÖÆ·Öк¬Óл·¼º´¼ºÍÉÙÁ¿ËáÐÔÔÓÖʵȡ£¼ÓÈë±¥ºÍʳÑÎË®£¬Õñµ´¡¢¾²Öᢷֲ㣬»·¼ºÏ©ÔÚ       ²ã(ÌîÉÏ»òÏÂ)£¬·ÖÒººóÓà          (ÌîÈë±àºÅ)Ï´µÓ¡£
a£®KMnO4ÈÜÒº      b£®Ï¡H2SO       c£®Na2CO3ÈÜÒº
¢ÚÔÙ½«»·¼ºÏ©°´ÏÂͼװÖÃÕôÁó£¬ÀäÈ´Ë®´Ó          ¿Ú£¨ÌîÉÏ»òÏ£©½øÈë¡£ÕôÁóʱҪ¼ÓÈëÉúʯ»Ò£¬Ä¿µÄÊÇ                 ¡£

¢ÛÊÕ¼¯²úƷʱ£¬¿ØÖƵÄζÈÓ¦ÔÚ         ×óÓÒ£¬ÊµÑéÖƵõĻ·¼ºÏ©¾«Æ·ÖÊÁ¿µÍÓÚÀíÂÛ²úÁ¿£¬¿ÉÄܵÄÔ­ÒòÊÇ£¨    £©
a£®ÕôÁóʱ´Ó70¡æ¿ªÊ¼ÊÕ¼¯²úÆ·
b£®»·¼º´¼Êµ¼ÊÓÃÁ¿¶àÁË
c£®ÖƱ¸´ÖƷʱ»·¼º´¼»Ó·¢Ëæ²úÆ·Ò»ÆðÕô³ö
£¨3£©ÒÔÏÂÇø·Ö»·¼ºÏ©¾«Æ·ºÍ´ÖÆ·µÄ·½·¨£¬ºÏÀíµÄÊÇ             ¡£
a£®ÓÃËáÐÔ¸ßÃÌËá¼ØÈÜÒº     b£®ÓÃäåË®      c£®²â¶¨·Ðµã

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁйØÓÚ°¢Ë¾Æ¥ÁÖ£¨£©µÄ˵·¨´íÎóµÄÊÇ
A£®°¢Ë¾Æ¥ÁÖÊôÓÚôÈËáÀàÓлúÎïB£®°¢Ë¾Æ¥ÁÖÓнâÈÈÕòÍ´µÄ×÷ÓÃ
C£®·þÓð¢Ë¾Æ¥ÁÖ¿ÉÄܳöÏÖ²»Á¼·´Ó¦
D£®°¢Ë¾Æ¥ÁÖ²»ÄÜË®½â

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÈôÒÒËáÓëÒÒËáÒÒõ¥µÄ»ìºÏÎïÖÐÇâÔªËصÄÖÊÁ¿·ÖÊýÊÇ£¬Ôò»ìºÏÎïÖÐÑõÔªËصÄÖÊÁ¿·ÖÊýÊÇ£¨  £©
A£®B£®C£®D£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

³ýÈ¥ÏÂÁÐÎïÖÊÖÐËùº¬ÉÙÁ¿ÔÓÖÊ£¨À¨ºÅÄÚΪÔÓÖÊ£©£¬ËùÑ¡ÓõÄÊÔ¼ÁºÍ·ÖÀë·½·¨ÄܴﵽʵÑéÄ¿µÄµÄÊÇ
 
»ìºÏÎï
ÊÔ¼Á
·ÖÀë·½·¨
A
±½£¨±½·Ó£©[
äåË®
·ÖÒº
B
ÒÒ´¼£¨Ë®£©
ÄÆ
ÕôÁó
C
äå±½£¨ä壩
ÇâÑõ»¯ÄÆÈÜÒº
·ÖÒº
D
ÒÒËáÒÒõ¥£¨ÒÒËᣩ[]
±¥ºÍ̼ËáÄÆÈÜÒº
¹ýÂË

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸