£¨14·Ö£©Ä³ÎÞÉ«ÈÜÒºX£¬ÓÉK+¡¢Ba2+¡¢Al3+¡¢Fe3+¡¢AlO-2¡¢CO2-3¡¢SO2-4ÖеÄÈô¸ÉÖÖÀë×Ó×é³É£¬È¡¸ÃÈÜÒº½øÐÐÈçÏÂʵÑ飺

£¨1£©ÆøÌåAÊÇ            £¨Ìѧʽ£¬ÏÂͬ£©£¬ÆøÌåBÊÇ         

£¨2£©Ð´³ö²½Öè¢ÙÖвúÉúÆøÌåµÄÀë×Ó·½³Ìʽ____           

£¨3£©·Ö±ðд³öÐγɰ×É«³Áµí¼×¡¢Éú³ÉÆøÌåBµÄ·´Ó¦µÄÀë×Ó·½³Ìʽ              ¡£

£¨4£©Í¨¹ýÉÏÊöʵÑ飬¿ÉÈ·¶¨XÈÜÒºÖÐÒ»¶¨´æÔÚµÄÀë×ÓÊÇ                  ¡£

ÉÐδȷ¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÊÇ              £¬ÇëÉè¼ÆÒ»¸ö¼òµ¥µÄºóÐøʵÑéÀ´È·¶¨¸ÃÀë×ÓÊÇ·ñ´æÔÚ£¬ÄúÉè¼ÆµÄʵÑéÊÇ                      ¡£

 

¡¾´ð°¸¡¿

³ý£¨1£©Ã¿¿Õ1·ÖÍ⣬ÆäÓàÿ¿Õ2·Ö¡£

   £¨1£©CO2   NH3£¨¸÷1·Ö£©

   £¨2£©¢ÙCO32-+2H+=CO2¡ü+H2O£¨2·Ö£©

   £¨3£©·Ö±ðд³öÐγɰ×É«³Áµí¼×¡¢Éú³ÉÆøÌåBµÄ·´Ó¦µÄÀë×Ó·½³Ìʽ£¨¸÷2·Ö£©

          Al3++3HCO3-=Al(OH)3¡ý+3CO2¡ü   ;   OH-+NH4+=NH3¡ü+H2O   .

   £¨4£©XÈÜÒºÖÐÒ»¶¨´æÔÚK+¡¢AlO2-¡¢CO32-£¬ÉÐδȷ¶¨SO42-£¬ÄúÉè¼ÆµÄʵÑéÊÇ°´¼ìÑéÁòËá¸ùµÄ·½°¸×ÃÇé¸ø·Ö£¨È¡Ñù¡¢Ìí¼ÓÊÔ¼Á¡¢ÏÖÏóÃèÊö¡¢½áÂÛ£©¡££¨Ã¿¿Õ2·Ö£©

¡¾½âÎö¡¿

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijÎÞÉ«ÈÜÒºX£¬ÓÉK+¡¢NH+4¡¢Ba2+¡¢Al3+¡¢Fe3+¡¢CO2-3¡¢SO2-4ÖеÄÈô¸ÉÖÖÀë×Ó×é³É£¬È¡¸ÃÈÜÒº½øÐÐÈçͼʵÑ飺
£¨1£©°×É«³Áµí¼×ÊÇ
ÁòËá±µ
ÁòËá±µ
£»
£¨2£©ÊÔд³öʵÑé¹ý³ÌÖÐÉú³ÉÆøÌåA¡¢BµÄÀë×Ó·½³Ìʽ
CO32-+2H+=H2O+CO2¡ü
CO32-+2H+=H2O+CO2¡ü
¡¢
NH+4+OH-=NH3¡ü+H2O
NH+4+OH-=NH3¡ü+H2O
£»
£¨3£©Í¨¹ýÉÏÊöʵÑ飬¿ÉÈ·¶¨XÈÜÒºÖÐÒ»¶¨´æÔÚµÄÀë×ÓÊÇ
CO32-¡¢SO2-4
CO32-¡¢SO2-4
£¬ÉÐδȷ¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÊÇ
K+
K+
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨14·Ö£©Ä³ÎÞÉ«ÈÜÒºX£¬ÓÉK+¡¢Ba2+¡¢Al3+¡¢Fe3+¡¢AlO-2¡¢CO2-3¡¢SO2-4ÖеÄÈô¸ÉÖÖÀë×Ó×é³É£¬È¡¸ÃÈÜÒº½øÐÐÈçÏÂʵÑ飺

£¨1£©ÆøÌåAÊÇ           £¨Ìѧʽ£¬ÏÂͬ£©£¬ÆøÌåBÊÇ         

£¨2£©Ð´³ö²½Öè¢ÙÖвúÉúÆøÌåµÄÀë×Ó·½³Ìʽ____           

£¨3£©·Ö±ðд³öÐγɰ×É«³Áµí¼×¡¢Éú³ÉÆøÌåBµÄ·´Ó¦µÄÀë×Ó·½³Ìʽ             ¡£

£¨4£©Í¨¹ýÉÏÊöʵÑ飬¿ÉÈ·¶¨XÈÜÒºÖÐÒ»¶¨´æÔÚµÄÀë×ÓÊÇ                 ¡£

ÉÐδȷ¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÊÇ             £¬ÇëÉè¼ÆÒ»¸ö¼òµ¥µÄºóÐøʵÑéÀ´È·¶¨¸ÃÀë×ÓÊÇ·ñ´æÔÚ£¬ÄúÉè¼ÆµÄʵÑéÊÇ                     ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011½ìɽ¶«Ê¡À³ÖÝÊÐÒ»ÖиßÈýÉÏѧÆڽ׶βâÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨16·Ö£©¢ñ.ijÎÞÉ«ÈÜÒºX£¬ÓÉK+¡¢¡¢Ba2+¡¢Al3+¡¢Fe3+¡¢¡¢ÖеÄÈô¸ÉÖÖÀë×Ó×é³É£¬È¡¸ÃÈÜÒº½øÐÐÈçÏÂʵÑ飺

£¨1£©°×É«³Áµí¼×ÊÇ         ¡£
£¨2£©ÊÔд³öʵÑé¹ý³ÌÖÐÉú³ÉÆøÌåA¡¢BµÄÀë×Ó·½³Ìʽ          ¡¢         ¡£
£¨3£©Í¨¹ýÉÏÊöʵÑ飬¿ÉÈ·¶¨XÈÜÒºÖÐÒ»¶¨´æÔÚµÄÀë×ÓÊÇ       £¬ÒªÈ·¶¨¿ÉÄÜ´æÔÚµÄÀë×Ó£¬Ðè²¹¼ÓµÄʵÑéÊÇ                                           ¡£
¢ò.A¡¢B¡¢CÈýÖÖÇ¿µç½âÖÊ£¬ËüÃÇÔÚË®ÖеçÀë³öµÄÀë×ÓÈçϱíËùʾ£º

ÏÂͼËùʾװÖÃÖУ¬¼×¡¢ÒÒ¡¢±ûÈý¸öÉÕ±­ÒÀ´Î·Ö±ðÊ¢·Å×ãÁ¿µÄAÈÜÒº¡¢×ãÁ¿µÄBÈÜÒº¡¢×ãÁ¿µÄCÈÜÒº£¬µç¼«¾ùΪʯīµç¼«¡£

½ÓͨµçÔ´£¬¾­¹ýÒ»¶Îʱ¼äºó£¬²âµÃÒÒÖÐcµç¼«ÖÊÁ¿Ôö¼ÓÁË16g¡£³£ÎÂϸ÷ÉÕ±­ÖÐÈÜÒºµÄpHÓëµç½âʱ¼ätµÄ¹ØϵͼÈçÉÏ¡£¾Ý´Ë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©MΪµçÔ´µÄ       ¼«£¨Ìîд¡°Õý¡±»ò¡°¸º¡±£©µç¼«bÉÏ·¢ÉúµÄµç¼«·´Ó¦Îª         ¡£
£¨2£©¼ÆËãµç¼«eÉÏÉú³ÉµÄÆøÌåÔÚ±ê×¼×´¿öϵÄÌå»ý                   £»
£¨3£©Ð´³öÒÒÉÕ±­µÄµç½â³Ø·´Ó¦                        ¡£
£¨4£©Èç¹ûµç½â¹ý³ÌÖÐBÈÜÒºÖеĽðÊôÀë×ÓÈ«²¿Îö³ö£¬´Ëʱµç½âÄÜ·ñ¼ÌÐø½øÐУ¬ÎªÊ²Ã´£¿
                                                                           
£¨5£©Èô¾­¹ýÒ»¶Îʱ¼äºó£¬²âµÃÒÒÖÐcµç¼«ÖÊÁ¿Ôö¼ÓÁË16g£¬ÒªÊ¹±û»Ö¸´µ½Ô­À´µÄ״̬£¬²Ù×÷ÊÇ                                                ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010Äêɽ¶«Ê¡¸ßÈýÉÏѧÆÚµÚÒ»´ÎÔ¿¼£¨»¯Ñ§£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨8·Ö£©Ä³ÎÞÉ«ÈÜÒºX£¬ÓÉK+¡¢NH+4¡¢Ba2+¡¢Al3+¡¢Fe3+¡¢CO2-3¡¢SO2-4ÖеÄÈô¸ÉÖÖÀë×Ó×é³É£¬È¡¸ÃÈÜÒº½øÐÐÈçÏÂʵÑ飺

£¨1£©°×É«³Áµí¼×ÊÇ                     £»

£¨2£©ÊÔд³öʵÑé¹ý³ÌÖÐÉú³ÉÆøÌåA¡¢BµÄÀë×Ó·½³Ìʽ                    ¡¢

                             £»

£¨3£©Í¨¹ýÉÏÊöʵÑ飬¿ÉÈ·¶¨XÈÜÒºÖÐÒ»¶¨´æÔÚµÄÀë×ÓÊÇ               £¬ÉÐδȷ¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÊÇ               ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸